Is it possible to Insert multiple rows with same user and differrent id - oracle11g

Question

I just started with Oracle-Sql and apex , I have stumbled into this code/answer that another user made (credits to the user) and tweaked it a bit. http://sqlfiddle.com/#!4/fa7342/11
this code create 'x' rows/appointments defined by the multiple conditions
what I'm trying to do is to insert into a table 'x' rows/appointments with :
same user_id(not pk)
different appointment_id( pk - sequence and incremented by 'x' appointments')
If the input is :
interval_type VARCHAR2(20) := 'daily';
start_date DATE := DATE '2021-07-15';
number_of_appointments number := 3;
appointent_id_number number := sequence.nextval;
id_client number := 1012;
output should be :
APPOINTMENT_DATE
APPOINTMENT_ID
ID_CLIENT
2021-07-16T00:00:00Z
1
1012
2021-07-17T00:00:00Z
2
1012
2021-07-18T00:00:00Z
3
1012
query :
DECLARE
interval_type VARCHAR2(20) := 'daily';
start_date DATE := DATE '2021-07-15';
number_of_appointments number := 3;
appointent_id_number number := sequence.nextval
id_client number := 1012;
BEGIN
INSERT INTO table_name (appointment_date)
SELECT CASE interval_type
WHEN 'daily'
THEN start_date + INTERVAL '1' DAY * LEVEL
WHEN 'weekly'
THEN start_date + INTERVAL '7' DAY * LEVEL
WHEN 'monthly'
THEN ADD_MONTHS( start_date, LEVEL )
END
FROM DUAL
CONNECT BY
LEVEL <= number_of_appointments;
END;
/

Answer 1

It is easier to let the database generate your primary key so you don't have to worry about that in your code. In the code below I'm using an identity column as primary key - in that case a sequence doesn't need to be created manually. However if you're really on 11g (consider upgrading - that version is very very old) identity columns won't work. Code for that case is at the bottom.
create table appointments_table (
id number generated by default on null as identity
constraint appointments_table_id_pk primary key,
appointment_date date,
id_client number
)
;
DECLARE
interval_type VARCHAR2(20) := 'daily';
start_date DATE := DATE '2021-07-15';
number_of_appointments number := 3;
l_id_client number := 1012;
BEGIN
INSERT INTO appointments_table (appointment_date, id_client)
SELECT CASE interval_type
WHEN 'daily'
THEN start_date + INTERVAL '1' DAY * LEVEL
WHEN 'weekly'
THEN start_date + INTERVAL '7' DAY * LEVEL
WHEN 'monthly'
THEN ADD_MONTHS( start_date, LEVEL )
END,
l_id_client
FROM DUAL
CONNECT BY
LEVEL <= number_of_appointments;
END;
/
select * from appointments_table;
ID APPOINTMENT ID_CLIENT
---------- ----------- ----------
1 16-JUL-2021 1012
2 17-JUL-2021 1012
3 18-JUL-2021 1012
If the version of oracle you are on does not support identity columns (available from 12.1) then this is how you can create your table:
create sequence appointments_table_seq;
create table appointments_table (
id number default appointments_table_seq.NEXTVAL
constraint appointments_table_id_pk primary key,
appointment_date_dt date,
id_client number
)
;