Query based on where clauses in Firebase database [duplicate] - firebase

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Firebase query if child of child contains a value
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Many to Many relationship in Firebase
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Closed 1 year ago.
I have a database like below, I want to query the accounts based on user ID.
"accounts": [
{
"applications": [
{
"appId": "sfdsfsfsfsfsfsfsfweufisfsfsfshwfkwjkf",
"creationDate": "dadasffsfsfsfsfsfsfsfsfsf",
"name": "Application one",
"users": [
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5hy3k1C2"
},
{
"userId": "0Mo0J6Y7aUXdhwUwszYrP5hy3k1C2qqqqqq"
},
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5hy3kqqqqqqq1C2qqqqqq"
}
]
},
{
"appId": "sfdsfsfsfsfsfsfsfweufisfsfsfshwfkwjkf",
"creationDate": "dadasffsfsfsfsfsfsfsfsfsf",
"name": "Application two",
"users": [
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5hy3k1C2"
},
{
"userId": "0Mo0J6Y7aUXdhwUwszYrP5hy3k1C2qqqqqq"
},
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5hy3kqqqqqqq1C2qqqqqq"
}
]
}
],
"id": "ahdagjhjfsfjgsfguwuwiuwireij",
"name": "Account ONE"
},
{
"applications": [
{
"appId": "sfdssfsfs242fsfsfsfsfsfsfweufihwfkwjkf",
"creationDate": "dadasffsfsfsfsfsfsfsfsfsf",
"name": "application one",
"users": [
{
"userId": "dadassfsfs24242424ffsfsfsfsfsfsfsfsfsf"
},
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5hyaaaaaaaa3k1C2qqqqqq"
},
{
"userId": "0Mo0J6Y7aUXdhwUszYrP5haaaay3kqqqqqqq1C2qqqqqq"
}
]
}
],
"id": "ahdagjhjfsfjgsfguwuwiuwireij",
"name": "Account TWO"
}
]
}
I am new to Firebase. How can I retrieve a result from the data above where userID = '0Mo0J6Y7aUXdhwUszYrP5hy3k1C2'?
How can I get the accounts/application object?
I tried using OrderByChild/OrderBy but did not work. like
.orderBy('userId')
.equalTo('0Mo0J6Y7aUXdhwUszYrP5hy3k1C2')
.on('child_added', function(snapshot) {
var movie = snapshot.val();
console.log(JSON.stringify(movie));
});