I read the glmmTMB package vignettes (https://cran.r-project.org/web/packages/glmmTMB/vignettes/covstruct.html) and have the following questions:
In the vignetts, they fit the model using
glmmTMB(y~ar1(times+0|group),data=dat0)
and mentioned that the time+0 correspondes to a design matrix Z linking observation vector y (rows) with a random effects vector u(columns)"
What's the meaning of +0? Is there any difference with (times|group), (times+1|group) and (1|group)?
Are there any comprehensive summary about the syntax of the covariance structure?
If I want to fit a Negtive binomial model when outcome y_{ij} is generated from R function: rnbinom(mu=x_{ij}beta+b_i+e_{ij},size=1), where i is the group index and j is the individual index, and b_i～N(0,1), e_{ij}~N(0,1). Would the following code correctly specify to model?
dat <- data.frame(y,x,group)
glmmTMB(y~x+(1|group),data=dat,family=nbinom2)
Any suggestion and help is appreciated. Thanks in advance for your help!
Related
My response variable is Yijk corresponding to the recovery time of
patient i (i=1,...,I)
with treatment j (j=1,...,J)
and measured at time k (k=1,...,K)
I would like to fit the following model:Model equation, where:
μ is a global fixed intercept
αj is a fixed effect for the treatment
bik is a random effect with the following covariance structure. Denote bi the K-dimensional vector of effect for the patient i, then its variance-covariance matrix would have the following AR(1) structure.
Variance covariance matrix
uijk is the usual error term with variance σ²
Consider the following line of command:
lme(recovery ~ treatment, method="REML", random=~1|patient, correlation=corAR1,form=~time|patient,data=data)
Several questions:
What does this correlation argument correspond to? The structure of covariance of what? Is that the var-cov matrix which I defined as R?
Does the line actually do what I would like to?
If not, what does it do?
If not, is there a way to do what I would like to?
Thank you in advance!
First, you have a command lme, I will assume that is meant to be nlme because a) lme isn't an R command in any package that I know of or that R could find and b) correlation isn't an option in lme4
Second, in the documentation for nlme they have this:
an optional corStruct object describing the within-group correlation
structure. See the documentation of corClasses for a description of
the available corStruct classes. Defaults to NULL, corresponding to no
within-group correlations.
and in corClasses it says
corAR1 autoregressive process of order 1.
So, the answers to your first two questions appears to be "Yes".
I am currently trying to fit a linear model to count data, where the errors are following a poisson distribution. Namely I would like to minimize the following
where I have i samples. β is a vector with m coefficients and x is consisting of m independent (explanatory) variables. β should sum up to 1 and each coefficient should be larger than 0.
I am using R and I tried the package glmc without much success. The only example in the documentation is only confusing me, as I don't get how the constraint matrix Amat is enforcing a constraint on the coefficients. Is there any other example I could have a look at or another package?
I also tried solving this analytically with medium success.
Any help is appreciated!
kind regards, Lena
I'm new to R and statistical modelling, and am looking to use the lmmlasso library in r to fit a mixed effects model, selecting only the best fixed effects out of ~300 possible variables.
For this model I'd like to include both a fixed intercept, a random effect, and a random intercept. Looking at the manual on CRAN, I've come across the following:
x: matrix of dimension ntot x p including the fixed-effects
covariables. An intercept has to be included in the first column as
(1,...,1).
z: random effects matrix of dimension ntot x q. It has to be a matrix,
even if q=1.
While it's obvious what I need to do for the fixed intercept I'm not quite sure how to include both a random intercept and effect. Is it exactly the same as the fixed matrix, where I include (1...1) in my first column?
In addition to this, I'm looking to validate the resulting model I get with another dataset. For lmmlasso is there a function similar to predict in lme4 that can be used to compute new predictions based on the output I get? Alternatively, is it viable/correct to construct a new model using lmer using the variables with non-zero coefficients returned by lmmlasso, and then use predict on the new model?
Thanks in advance.
I am a newbie in R and I am trying to do my best to create my first model. I am working in a 2- classes random forest project and so far I have programmed the model as follows:
library(randomForest)
set.seed(2015)
randomforest <- randomForest(as.factor(goodkit) ~ ., data=training1, importance=TRUE,ntree=2000)
varImpPlot(randomforest)
prediction <- predict(randomforest, test,type='prob')
print(prediction)
I am not sure why I don't get the overall prediction for my model.I must be missing something in my code. I get the OOB and the prediction per case in the test set but not the overall prediction of the model.
library(pROC)
auc <-roc(test$goodkit,prediction)
print(auc)
This doesn't work at all.
I have been through the pROC manual but I cannot get to understand everything. It would be very helpful if anyone can help with the code or post a link to a good practical sample.
Using the ROCR package, the following code should work for calculating the AUC:
library(ROCR)
predictedROC <- prediction(prediction[,2], as.factor(test$goodkit))
as.numeric(performance(predictedROC, "auc")#y.values))
Your problem is that predict on a randomForest object with type='prob' returns two predictions: each column contains the probability to belong to each class (for binary prediction).
You have to decide which of these predictions to use to build the ROC curve. Fortunately for binary classification they are identical (just reversed):
auc1 <-roc(test$goodkit, prediction[,1])
print(auc1)
auc2 <-roc(test$goodkit, prediction[,2])
print(auc2)
I have fit my discrete count data using a variety of functions for comparison. I fit a GEE model using geepack, a linear mixed effect model on the log(count) using lme (nlme), a GLMM using glmer (lme4), and a GAMM using gamm4 (gamm4) in R.
I am interested in comparing these models and would like to plot the expected (predicted) values for a new set of data (predictor variables). My goal is to compare the predicted effects for each model under particular conditions (x variables). Of particular interest is the comparison between marginal (GEE) and conditional estimates.
I think my main problem might be getting the new data in the correct form with the correct labels and attributes and such. I am still very much an R novice and struggle with this stuff (no course on this at my university unfortunately).
I currently have fitted models
gee1 lme1 lmer1 gamm1
and can extract their fixed effect coefficients and standard errors without a problem. I also don't have a problem converting them from the log scale or estimating confidence intervals accounting for the random effects.
I also have my new dataframe newdat which has 365 observations of 23 variables (average environmental data for each day of the year).
I am stuck on how to predict new count estimates from this. I played around with the model.matrix function but couldn't get it to work. For example, I tried:
mm = model.matrix(terms(glmm1), newdat) # Error in model.frame.default(object,
# data, xlev = xlev) : object is not a matrix
newdat$pcount = mm %*% fixef(glmm1)
Any suggestions or good references would be greatly appreciated. Can anyone help with the error above?
Getting predictions for lme() and lmer() is documented on http://glmm.wikidot.com/faq