I have a label in my asp.net web site that will shows the time. I want the output like here. in the morning like this: 08:26 and after 12 am,it shows 15:28
My code does not work. It only supports the first part.
DateTime tim = DateTime.Now;
int hh = p.GetHour(tim);
int mm = p.GetMinute(tim);
Label7.Text = DateTime.Now.ToString("hh:mm");
According to the Custom date and time format strings docs page - you can see:
"hh" The hour, using a 12-hour clock from 01 to 12.
"HH" The hour, using a 24-hour clock from 00 to 23.
So in your case - just use the capitalized HH for your formatting:
Label7.Text = DateTime.Now.ToString("HH:mm");
and you should get what you're looking for.
Related
hi I has date format and I want converted to correct GMT date :
<YYMMDDhhmmssNNN><C|D|G|H>
Sample value on that date:
210204215026000C
I get this explanation for part NNN :
NNN If flag is C or D then NNN is the number of hours relativeto GMT,
if flag is G or H, NNN is the number of quarter hours relative to GMT
C|D|G|H C and G = Ahead of GMT, D and H = Behind GMT
but I did not get how number of hours relative to GMT can present on 3 digits ? it should be in 2 digit as i knew the offset for hours related to GMT is from 0 to 23 , and also what quarter hours relative to GMT mean ?
I want to use Scala or Java.
I don’t know why they set 3 digits aside for the offset. I agree with you that 2 digits suffice for all cases. Maybe they just wanted to be very sure they would never run of out space, and maybe they even overdid this a bit. 3 digits is not a problem as long as the actual values are within the range that java.time.ZoneOffset can handle, +/-18 hours. In your example NNN is 000, so 0 hours from GMT, which certainly is OK and trivial to handle.
A quarter hour is a quarter of an hour. As Salman A mentioned in a comment, 22 quarter hours ahead of Greenwich means an offset of +05:30, currently used in Sri Lanka and India. If the producer of the string wants to use this option, they can give numbers up to 72 (still comfortably within 2 digits). 18 * 4 = 72, so 18 hours equals 72 quarter hours. To imagine a situation where 2 digits would be too little, think an offset of 25 hours. I wouldn’t think it realistic, on the other hand no one can guarantee that it will never happen.
Java solution: how to parse and convert to GMT time
I am using these constants:
private static final Pattern DATE_PATTERN
= Pattern.compile("(\\d{12})(\\d{3})(\\w)");
private static final DateTimeFormatter FORMATTER
= DateTimeFormatter.ofPattern("uuMMddHHmmss");
private static final int SECONDS_IN_A_QUARTER_HOUR
= Math.toIntExact(Duration.ofHours(1).dividedBy(4).getSeconds());
Parse and convert like this:
String sampleValue = "210204215026000C";
Matcher matcher = DATE_PATTERN.matcher(sampleValue);
if (matcher.matches()) {
LocalDateTime ldt = LocalDateTime.parse(matcher.group(1), FORMATTER);
int offsetAmount = Integer.parseInt(matcher.group(2));
char flag = matcher.group(3).charAt(0);
// offset amount denotes either hours or quarter hours
boolean quarterHours = flag == 'G' || flag == 'H';
boolean negative = flag == 'D' || flag == 'H';
if (negative) {
offsetAmount = -offsetAmount;
}
ZoneOffset offset = quarterHours
? ZoneOffset.ofTotalSeconds(offsetAmount * SECONDS_IN_A_QUARTER_HOUR)
: ZoneOffset.ofHours(offsetAmount);
OffsetDateTime dateTime = ldt.atOffset(offset);
OffsetDateTime gmtDateTime = dateTime.withOffsetSameInstant(ZoneOffset.UTC);
System.out.println("GMT time: " + gmtDateTime);
}
else {
System.out.println("Invalid value: " + sampleValue);
}
Output is:
GMT time: 2021-02-04T21:50:26Z
I think my code covers all valid cases. You will probably want to validate that the flag is indeed C, D, G or H, and also handle the potential DateTimeException and NumberFormatException from the parsing and creating the ZoneOffset (NumberFormatException should not happen).
How to get the current time and 15 min ago time in iso 8601 format (YYYY-MM-DDTHH:mm:ss) in groovy?
You can use java time's Instant and the toString() format
import java.time.*
def now = Instant.now()
def fifteenAgo = now.minus(Duration.ofMinutes(15))
println "Now is ${now} and 15 mins ago was ${fifteenAgo}"
Prints:
Now is 2020-06-30T19:53:17.445039Z and 15 mins ago was 2020-06-30T19:38:17.445039Z
You can formast the date in any way you want in Groovy, by doing e.g.
println new Date().format("yyyy-MM-dd HH.mm.ss.SSSSS Z")
Then, you can do calculations on the date, like this:
new Date(System.currentTimeMillis()-91*60*1000)
which will minus 91 minutes (91min * 60sec * 1000ms).
Then you can put the statements together, which is why Groovy is great:
def a = new Date(System.currentTimeMillis()-91*60*1000).format("YYYY-MM-DD")
And so you can get the half before the T. And the half after the T:
def b = new Date(System.currentTimeMillis()-91*60*1000).format("HH:mm:ss")
And then concatenate them with a T:
println "91 minutes ago in iso 8601 format is: ${a}T${b}"
There are other ways of doing it, like with TimeCategory.minus, but this is a good illustration. I used 91 minutes, but you can adapt it to your own requirtement.
In the azure data explorer documentation, there is a lot of supported formats but not the one that i am looking for.
What I need is to format the datetime like "yyyy-MM-dd HH" to set the minutes and seconds as 0
Input datetime
2020-04-21T17:44:27.6825985Z
expected results
2020-04-21 17:00:00
you can use bin() to round down to the hour, and if you still need to remove the datetime parts lower than seconds, you can use substring() (or format_datetime()). e.g.:
print d = datetime(2020-04-21T17:44:27.6825985Z)
| extend h = bin(d, 1h)
| extend h2 = substring(h, 0, 19)
hmm, if you always just want the rest to be 0, can you just use string concatenation?
let d = datetime(2020-04-21T17:44:27.6825985Z);
print strcat(format_datetime(d, "yyyy-MM-dd HH"), ":00:00")
the above code will give you the result of
2020-04-21 17:00:00
I have two columns in an access 2010 database with some calculated field:
time_from time_until calculated_field(time_until-time_from)
10:45 15:00 4:15
13:15 16:00 2:45
11:10 16:00 4:50
08:00 15:00 7:00
08:00 23:00 15:00
Now so far, it is good: calculated field did its job to tell me total hours and mins...
now, I need a sum of a calculated field....
I put in an expression builder: =Sum([time_until]-[time_from])
I guess total sum should give me 33:50... but it gives me some 9:50. why is this happening? Is there a way to fix this?
update:
when I put like this:
=Format(Sum([vrijeme_do]-[vrijeme_od])*24)
I get a decimal point number... which I suppose is correct....
for example, 25hrs and 30mins is shown as 25,5
but, how do I format this 25,5 to look like 25:30?
As #Arvo mentioned in his comment, this is a formatting problem. Your expected result for the sum of calculated_field is 33:50. However that sum is a Date/Time value, and since the number of hours is greater than 24, the day portion of the Date/Time is advanced by 1 and the remainder 9:50 is displayed as the time. Apparently your total is formatted to display only the time portion; the day portion is not displayed.
But the actual Date/Time value for the sum of calculated_field is #12/31/1899 09:50#. You can use a custom function to display that value in your desired format:
? duration_hhnn(#12/31/1899 09:50#)
33:50
This is the function:
Public Function duration_hhnn(ByVal pInput As Date) As String
Dim lngDays As Long
Dim lngMinutes As Long
Dim lngHours As Long
Dim strReturn As String
lngDays = Int(pInput)
lngHours = Hour(pInput)
lngMinutes = Minute(pInput)
lngHours = lngHours + (lngDays * 24)
strReturn = lngHours & ":" & Format(lngMinutes, "00")
duration_hhnn = strReturn
End Function
Note the function returns a string value so you can't do further date arithmetic on it directly.
Similar to the answer from #HansUp, it can be done without VBA code like so
Format(24 * Int(SUM(elapsed_time)) + Hour(SUM(elapsed_time)), "0") & ":" & Format(SUM(elapsed_time), "Nn")
I guess you are trying to show the total in a text box? the correct expression would be =SUM([calculated_field_name]).
I am using FTP and I have retrieved a list of Files. In the files command line there is a datetime field.
It reads
11-13-13 11:31AM
Can anyone tell me how I can parse this. I thought this might work.
DateTime.ParseExact(date,"MM-DD-YY HH:MMtt", System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat); But i still get an exception.
day should be dd not DD
Year should be yy not YY
since hour is 12 hour format it should be hh also MM (minutes should be mm)
DateTime.ParseExact(date,"MM-dd-yy hh:mmtt",...)
eg:-
DateTime date = DateTime.ParseExact("11-13-13 11:31AM", "MM-dd-yy hh:mmtt", System.Globalization.CultureInfo.InvariantCulture);
Response.Write(date);