I have been trying to get the data from this link to be usable
url <- "https://www.sec.gov/Archives/edgar/data/1061165/0001567619-21-010580.txt"
that should be the same information as the one on this link
https://www.sec.gov/Archives/edgar/data/1061165/000156761921010580/xslForm13F_X01/form13fInfoTable.xml
I have been able to download the file into a .txt, but can not get the data
Thanks
The file appears to be two nested XML files. We can extract each of the components into lists with this code:
txt <- readLines("https://www.sec.gov/Archives/edgar/data/1061165/0001567619-21-010580.txt")
grep("</?XML>", txt)
# [1] 46 101 109 719
txt[grep("</?XML>", txt)]
# [1] "<XML>" "</XML>" "<XML>" "</XML>"
A brief inspection of the file informed that grep, suggesting that an XML file started and stopped, and then another started/stopped. If we stay within that, we can extract most of the data with
library(xml2)
first <- as_list(read_xml(paste(txt[47:100], collapse = "")))
str(first)
# List of 1
# $ edgarSubmission:List of 2
# ..$ headerData:List of 2
# .. ..$ submissionType:List of 1
# .. .. ..$ : chr "13F-HR"
# .. ..$ filerInfo :List of 4
# .. .. ..$ liveTestFlag :List of 1
# .. .. .. ..$ : chr "LIVE"
# .. .. ..$ flags :List of 3
# .. .. .. ..$ confirmingCopyFlag :List of 1
# .. .. .. .. ..$ : chr "false"
# .. .. .. ..$ returnCopyFlag :List of 1
# .. .. .. .. ..$ : chr "true"
# .. .. .. ..$ overrideInternetFlag:List of 1
# .. .. .. .. ..$ : chr "false"
# .. .. ..$ filer :List of 1
# .. .. .. ..$ credentials:List of 2
# .. .. .. .. ..$ cik:List of 1
# .. .. .. .. .. ..$ : chr "0001061165"
# .. .. .. .. ..$ ccc:List of 1
# .. .. .. .. .. ..$ : chr "XXXXXXXX"
# .. .. ..$ periodOfReport:List of 1
# .. .. .. ..$ : chr "03-31-2021"
# ..$ formData :List of 3
and the second batch:
second <- as_list(read_xml(paste(txt[110:718], collapse = "")))
str(second)
# List of 1
# $ informationTable:List of 38
# ..$ infoTable:List of 7
# .. ..$ nameOfIssuer :List of 1
# .. .. ..$ : chr "ADOBE SYSTEMS INCORPORATED"
# .. ..$ titleOfClass :List of 1
# .. .. ..$ : chr "COM"
# .. ..$ cusip :List of 1
# .. .. ..$ : chr "00724F101"
# .. ..$ value :List of 1
# .. .. ..$ : chr "1246613"
# .. ..$ shrsOrPrnAmt :List of 2
# .. .. ..$ sshPrnamt :List of 1
# .. .. .. ..$ : chr "2622406"
# .. .. ..$ sshPrnamtType:List of 1
# .. .. .. ..$ : chr "SH"
# .. ..$ investmentDiscretion:List of 1
# .. .. ..$ : chr "SOLE"
# .. ..$ votingAuthority :List of 3
# .. .. ..$ Sole :List of 1
# .. .. .. ..$ : chr "2622406"
# .. .. ..$ Shared:List of 1
# .. .. .. ..$ : chr "0"
# .. .. ..$ None :List of 1
# .. .. .. ..$ : chr "0"
# ..$ infoTable:List of 7
I'm not certain offhand how to extract the front-matter, I hope this is a good enough start.
Related
I want to know how can I access, extract, and reference values from a plotly figure in R.
Consider, for example, the Sankey diagram from plotly's own site of which there is an abbreviated version here:
library(plotly)
fig <- plot_ly(
type = "sankey",
node = list(
label = c("A1", "A2", "B1", "B2", "C1", "C2"),
color = c("blue", "blue", "blue", "blue", "blue", "blue"),
line = list()
),
link = list(
source = c(0,1,0,2,3,3),
target = c(2,3,3,4,4,5),
value = c(8,4,2,8,4,2)
)
)
fig
If I do View(fig) in Rstudio, a new tab opens titled . (I don't know why this instead of 'fig'). In this tab I can go to x > visdat > 'strig of letters and numbers that is a function?' > attrs > node > x (as shown bellow).
Here all the x coordinates for the Sankey nodes appear.
I want to access these values so I can use them somewhere else. How do I do this? If I click on the right side of the Rsutudio tab to copy the code to console I get:
environment(.[["x"]][["visdat"]][["484c3ec36899"]])[["attrs"]][["node"]][["x"]]
which obviously doesn't work as there is no object named ..
In this case I have tried fig$x$visdat$`484c3ec36899`() but I cant do fig$x$visdat$`484c3ec36899`()$attr, and I don't know what else to do.
So, how can I access any value from a plotly object? Any documentation referencing this topic would also be helpful.
Thanks.
You can find the documentation of the data structure of plotly in R here: https://plotly.com/r/figure-structure/
To check the data structure you can use str(fig):
List of 8
$ x :List of 6
..$ visdat :List of 1
.. ..$ a3b8795a4:function ()
..$ cur_data: chr "a3b8795a4"
..$ attrs :List of 1
.. ..$ a3b8795a4:List of 6
.. .. ..$ node :List of 3
.. .. .. ..$ label: chr [1:6] "A1" "A2" "B1" "B2" ...
.. .. .. ..$ color: chr [1:6] "blue" "blue" "blue" "blue" ...
.. .. .. ..$ line : list()
.. .. ..$ link :List of 3
.. .. .. ..$ source: num [1:6] 0 1 0 2 3 3
.. .. .. ..$ target: num [1:6] 2 3 3 4 4 5
.. .. .. ..$ value : num [1:6] 8 4 2 8 4 2
.. .. ..$ alpha_stroke: num 1
.. .. ..$ sizes : num [1:2] 10 100
.. .. ..$ spans : num [1:2] 1 20
.. .. ..$ type : chr "sankey"
..$ layout :List of 3
.. ..$ width : NULL
.. ..$ height: NULL
.. ..$ margin:List of 4
.. .. ..$ b: num 40
.. .. ..$ l: num 60
.. .. ..$ t: num 25
.. .. ..$ r: num 10
..$ source : chr "A"
..$ config :List of 1
.. ..$ showSendToCloud: logi FALSE
..- attr(*, "TOJSON_FUNC")=function (x, ...)
$ width : NULL
$ height : NULL
$ sizingPolicy :List of 6
..$ defaultWidth : chr "100%"
..$ defaultHeight: num 400
..$ padding : NULL
..$ viewer :List of 6
.. ..$ defaultWidth : NULL
.. ..$ defaultHeight: NULL
.. ..$ padding : NULL
.. ..$ fill : logi TRUE
.. ..$ suppress : logi FALSE
.. ..$ paneHeight : NULL
..$ browser :List of 5
.. ..$ defaultWidth : NULL
.. ..$ defaultHeight: NULL
.. ..$ padding : NULL
.. ..$ fill : logi TRUE
.. ..$ external : logi FALSE
..$ knitr :List of 3
.. ..$ defaultWidth : NULL
.. ..$ defaultHeight: NULL
.. ..$ figure : logi TRUE
$ dependencies :List of 5
..$ :List of 10
.. ..$ name : chr "typedarray"
.. ..$ version : chr "0.1"
.. ..$ src :List of 1
.. .. ..$ file: chr "htmlwidgets/lib/typedarray"
.. ..$ meta : NULL
.. ..$ script : chr "typedarray.min.js"
.. ..$ stylesheet: NULL
.. ..$ head : NULL
.. ..$ attachment: NULL
.. ..$ package : chr "plotly"
.. ..$ all_files : logi FALSE
.. ..- attr(*, "class")= chr "html_dependency"
..$ :List of 10
.. ..$ name : chr "jquery"
.. ..$ version : chr "1.11.3"
.. ..$ src :List of 1
.. .. ..$ file: chr "lib/jquery"
.. ..$ meta : NULL
.. ..$ script : chr "jquery.min.js"
.. ..$ stylesheet: NULL
.. ..$ head : NULL
.. ..$ attachment: NULL
.. ..$ package : chr "crosstalk"
.. ..$ all_files : logi TRUE
.. ..- attr(*, "class")= chr "html_dependency"
..$ :List of 10
.. ..$ name : chr "crosstalk"
.. ..$ version : chr "1.1.0.1"
.. ..$ src :List of 1
.. .. ..$ file: chr "www"
.. ..$ meta : NULL
.. ..$ script : chr "js/crosstalk.min.js"
.. ..$ stylesheet: chr "css/crosstalk.css"
.. ..$ head : NULL
.. ..$ attachment: NULL
.. ..$ package : chr "crosstalk"
.. ..$ all_files : logi TRUE
.. ..- attr(*, "class")= chr "html_dependency"
..$ :List of 10
.. ..$ name : chr "plotly-htmlwidgets-css"
.. ..$ version : chr "1.52.2"
.. ..$ src :List of 1
.. .. ..$ file: chr "htmlwidgets/lib/plotlyjs"
.. ..$ meta : NULL
.. ..$ script : NULL
.. ..$ stylesheet: chr "plotly-htmlwidgets.css"
.. ..$ head : NULL
.. ..$ attachment: NULL
.. ..$ package : chr "plotly"
.. ..$ all_files : logi FALSE
.. ..- attr(*, "class")= chr "html_dependency"
..$ :List of 10
.. ..$ name : chr "plotly-main"
.. ..$ version : chr "1.52.2"
.. ..$ src :List of 1
.. .. ..$ file: chr "htmlwidgets/lib/plotlyjs"
.. ..$ meta : NULL
.. ..$ script : chr "plotly-latest.min.js"
.. ..$ stylesheet: NULL
.. ..$ head : NULL
.. ..$ attachment: NULL
.. ..$ package : chr "plotly"
.. ..$ all_files : logi FALSE
.. ..- attr(*, "class")= chr "html_dependency"
$ elementId : NULL
$ preRenderHook:function (p, registerFrames = TRUE)
$ jsHooks : list()
- attr(*, "class")= chr [1:2] "plotly" "htmlwidget"
- attr(*, "package")= chr "plotly"
You could extract the coordinates with:
unlist(fig$x$attrs)
Differently from my collegue, after I load the tweets with R and I try to see the structure with str() the data appears in a messy way with a lot of dots, rather than being organized as a table, which is what happens with my collegue's computer, even if the codes are the same. I can't understand what is the problem, we have the same packages installed and the same R version.
library(rtweet)
library(ggplot2)
library(dplyr)
library(tibble)
library(tidytext)
library(stringr)
library(stringi)
library(igraph)
library(ggraph)
library(readr)
library(lubridate)
library(zoo)
appname <- ""
key <- ""
secret <- ""
twitter_token <- create_token( app = "", consumer_key = "", consumer_secret = "", access_token = "", access_secret = "")
tweets <- search_tweets(q = "#water + #climatechange", n = 10000, lang = "en", include_rts = FALSE)
str(tweets)
.. ..$ media :'data.frame': 1 obs. of 11 variables:
.. .. ..$ id : num 1.57e+18
.. .. ..$ id_str : chr "1573815153484759040"
.. .. ..$ indices :List of 1
.. .. .. ..$ :'data.frame': 1 obs. of 2 variables:
.. .. .. .. ..$ start: int 241
.. .. .. .. ..$ end : int 264
.. .. .. ..- attr(*, "class")= chr "AsIs"
.. .. ..$ media_url : chr "http://pbs.twimg.com/media/FddQiy2WAAAl59Q.jpg"
.. .. ..$ media_url_https: chr "https://pbs.twimg.com/media/FddQiy2WAAAl59Q.jpg"
.. .. ..$ url : chr "https
.. .. ..$ display_url : chr "pic.twitter.com/iFJTkF1S9S"
.. .. ..$ expanded_url : chr "https://twitter.com/TreeBanker/status/1573815156768968706/photo/1"
.. .. ..$ type : chr "photo"
.. .. ..$ sizes :List of 1
.. .. .. ..$ :'data.frame': 4 obs. of 4 variables:
.. .. .. .. ..$ w : int [1:4] 1096 680 150 1096
.. .. .. .. ..$ h : int [1:4] 733 455 150 733
.. .. .. .. ..$ resize: chr [1:4] "fit" "fit" "crop" "fit"
.. .. .. .. ..$ type : chr [1:4] "large" "small" "thumb" "medium"
.. .. ..$ ext_alt_text : logi NA
..$ :List of 5
.. ..$ media :'data.frame': 1 obs. of 11 variables:
.. .. ..$ id : num 1.57e+18
.. .. ..$ id_str : chr "1573815153484759040"
.. .. ..$ indices :List of 1
.. .. .. ..$ :'data.frame': 1 obs. of 2 variables:
I am trying to read in a geojson file (https://www.svz-bw.de/fileadmin/verkehrszentrale/RadNETZ-BW_Daten_GeoJSON_2018-20.zip) in R.
I have tried different packages but my knowledge is too limited to find the errors and solve them. Im new to spatial data in R, especially reading geojson file format.
Googling and searching in stackoverflow hasnt helped.
geojsonR::FROM_geojson("../Sonstiges/RadNETZ.geojson")
Error in unlink(x) : file name conversion problem -- name too long?
geojsonR::FROM_GeoJson("../Sonstiges/RadNETZ.geojson")
Error in export_From_geojson(url_file_string, Flatten_Coords,
Average_Coordinates, : invalid GeoJson geometry object -->
geom_OBJ() function
Your file does not comply with the current GeoJSON standards; it uses a projected coordinate reference system, which goes against RFC 7946 - https://www.rfc-editor.org/rfc/rfc7946#page-12
This may, and may not, be the reason why geojson specific packages have hard time interpreting it.
In order to process your file I suggest using {sf}, which is - via GDAL and PROJ - able to digest the file.
library(dplyr)
library(sf)
asdf <- st_read("RadNETZ.geojson") %>%
st_transform(4326) # safety of unprojected CRS
plot(st_geometry(asdf))
As #Jindra Lacko mentioned your 'RadNETZ.geojson' file does not comply with the RFC 7946 that's why you receive the error. If you don't have GDAL installed on your Operating System besides the 'sf' package you can use either the geojsonR::shiny_from_JSON (which does not follow the RFC and is meant to be used in shiny applications),
dat = geojsonR::shiny_from_JSON("../Sonstiges/RadNETZ.geojson")
str(dat)
List of 4
$ crs :List of 2
..$ properties:List of 1
.. ..$ name: chr "urn:ogc:def:crs:EPSG::31467"
..$ type : chr "name"
$ features:List of 70097
..$ :List of 3
.. ..$ geometry :List of 2
.. .. ..$ coordinates:List of 6
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3563993
.. .. .. .. ..$ : num 5353055
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3564002
.. .. .. .. ..$ : num 5353070
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3564009
.. .. .. .. ..$ : num 5353087
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3564013
.. .. .. .. ..$ : num 5353103
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3564016
.. .. .. .. ..$ : num 5353109
.. .. .. ..$ :List of 2
.. .. .. .. ..$ : num 3564030
.. .. .. .. ..$ : num 5353121
.. .. ..$ type : chr "LineString"
.. ..$ properties:List of 24
.....
or the jsonlite::fromJSON function,
dat = jsonlite::fromJSON("../Sonstiges/RadNETZ.geojson")
str(dat)
List of 4
$ type : chr "FeatureCollection"
$ name : chr "sql_statement"
$ crs :List of 2
..$ type : chr "name"
..$ properties:List of 1
.. ..$ name: chr "urn:ogc:def:crs:EPSG::31467"
$ features:'data.frame': 70097 obs. of 3 variables:
..$ type : chr [1:70097] "Feature" "Feature" "Feature" "Feature" ...
..$ properties:'data.frame': 70097 obs. of 24 variables:
.. ..$ gid : int [1:70097] 4 15 23 22 45 72 60 74 13072 75 ...
.. ..$ lrvn_kat: int [1:70097] 3 1 1 3 1 1 3 1 3 1 ...
.....
For the record I'm the author / maintainer of the geojsonR package
I am trying to subset thead/tbody without directly calling rowlist$td$list$item$table$thead or rowlist[[td]][[list]][[item]][[table]][[thead]]. This
unlist(rowlist, use.names=FALSE )[ grepl( "tbody", names(unlist(rowlist)))] serves my purpose except I need it as multiple rows (e.g. two tr's in tbody)(i can split it but seems counter intuitive .
I know there should be a better way to work with HTML/XML but this is got I got for now.
str(rowlist)
List of 1
$ td:List of 1
..$ list:List of 1
.. ..$ item:List of 1
.. .. ..$ table:List of 2
.. .. .. ..$ thead:List of 1
.. .. .. .. ..$ tr:List of 7
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Test"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Outcome"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Subset"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Cups"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Bowls"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Plates"
.. .. .. .. .. ..$ th:List of 1
.. .. .. .. .. .. ..$ : chr "Jars"
.. .. .. ..$ tbody:List of 2
.. .. .. .. ..$ tr:List of 7
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "test1"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "High"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Low"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Gold"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Blue"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Green"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "red"
.. .. .. .. .. ..- attr(*, "ID")= chr "id_511"
.. .. .. .. ..$ tr:List of 7
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "test2"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Low"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "High"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Pink"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Blue"
.. .. .. .. .. ..$ td:List of 1
.. .. .. .. .. .. ..$ : chr "Purple"
.. .. .. .. .. ..$ td: list()
.. .. .. .. .. ..- attr(*, "ID")= chr "id_512"
.. ..- attr(*, "styleCode")= chr "none"
List looks like this
rowlist<-list(td = structure(list(list = structure(list(item = list(table = list(
thead = list(tr = list(
th = list("Test"), th = list("Outcome"), th = list("Set"), th = list("Cups"), th = list("Bowls"), th = list( "Plates"), th = list("Jars"))),
tbody = list(tr = structure(
list(td = list("test1"), td = list("High"), td = list("Low"), td = list("Gold"), td = list("Blue"), td = list("Green"), td = list("Red")), ID = "id_511"),
tr = structure(
list(td = list("test2"), td = list("Low"), td = list("High"), td = list("Pink"), td = list("Blue"), td = list("Purple"), td = list()), ID = "id_512"))))), styleCode = "none")), colspan = "20"))
If the object has to be handled as a nested list, one approach is to use rrapply in the rrapply-package (extension of base rapply):
library(rrapply) ## v1.2.1
out <- rrapply(rowlist,
classes = "list",
condition = function(x, .xname) .xname %in% c("thead", "tbody"),
how = "flatten")
str(out, list.len = 2)
#> List of 2
#> $ thead:List of 1
#> ..$ tr:List of 7
#> .. ..$ th:List of 1
#> .. .. ..$ : chr "Test"
#> .. ..$ th:List of 1
#> .. .. ..$ : chr "Outcome"
#> .. .. [list output truncated]
#> $ tbody:List of 2
#> ..$ tr:List of 7
#> .. ..$ td:List of 1
#> .. .. ..$ : chr "test1"
#> .. ..$ td:List of 1
#> .. .. ..$ : chr "High"
#> .. .. [list output truncated]
#> .. ..- attr(*, "ID")= chr "id_511"
#> ..$ tr:List of 7
#> .. ..$ td:List of 1
#> .. .. ..$ : chr "test2"
#> .. ..$ td:List of 1
#> .. .. ..$ : chr "Low"
#> .. .. [list output truncated]
#> .. ..- attr(*, "ID")= chr "id_512"
Here, the condition function returns only nodes with names thead or tbody, how = "flatten" returns the nodes in a flat list (how = "prune" would prune the nodes keeping the original list structure), and classes = "list" does not skip intermediate list nodes (as would be the case with base rapply()).
i have about 30 padronized large list and i want to extract elements that are organized in the same way in all of them.
> df[[2]][[1]][[4]][[1]][[1]][[1]][[1]][[3]][[1]]
[1] "Non-histaminic angioedema"
> df[[2]][[1]][[4]][[1]][[1]][[2]][[1]][[3]][[1]]
[1] "Rare urticaria"
> df[[2]][[1]][[4]][[1]][[1]][[3]][[1]][[3]][[1]]
[1] "Rare allergic respiratory disease"
i want a loop to extract all these info to a data.frame. I tried to use lapply, but i'm having trouble with the right function to use.
i never used the apply family, so i would be very grateful with some tips
-----------------edit
str(df)
$ Availability:List of 1
..$ Licence:List of 3
.. ..$ FullName :List of 2
.. .. ..$ text : chr "Creative Commons Attribution 4.0 International"
.. .. ..$ .attrs: Named chr "en"
.. .. .. ..- attr(*, "names")= chr "lang"
.. ..$ ShortIdentifier: chr "CC-BY-4.0"
.. ..$ LegalCode : chr "https://creativecommons.org/licenses/by/4.0/legalcode"
$ DisorderList:List of 2
..$ Disorder:List of 5
.. ..$ OrphaNumber : chr "98050"
.. ..$ ExpertLink :List of 2
.. .. ..$ text : chr "http://www.orpha.net/consor/cgi-bin/OC_Exp.php?lng=en&Expert=98050"
.. .. ..$ .attrs: Named chr "en"
.. .. .. ..- attr(*, "names")= chr "lang"
.. ..$ Name :List of 2
.. .. ..$ text : chr "Rare allergic disease"
.. .. ..$ .attrs: Named chr "en"
.. .. .. ..- attr(*, "names")= chr "lang"
.. ..$ ClassificationNodeList:List of 2
.. .. ..$ ClassificationNode:List of 1
.. .. .. ..$ ClassificationNodeChildList:List of 5
.. .. .. .. ..$ ClassificationNode:List of 2
.. .. .. .. .. ..$ Disorder :List of 4
.. .. .. .. .. .. ..$ OrphaNumber: chr "658"
.. .. .. .. .. .. ..$ ExpertLink :List of 2
.. .. .. .. .. .. .. ..$ text : chr "http://www.orpha.net/consor/cgi-bin/OC_Exp.php?lng=en&Expert=658"
.. .. .. .. .. .. .. ..$ .attrs: Named chr "en"
.. .. .. .. .. .. .. .. ..- attr(*, "names")= chr "lang"
.. .. .. .. .. .. ..$ Name :List of 2
.. .. .. .. .. .. .. ..$ text : chr "Non-histaminic angioedema"
.. .. .. .. .. .. .. ..$ .attrs: Named chr "en"
.. .. .. .. .. .. .. .. ..- attr(*, "names")= chr "lang"
.. .. .. .. .. .. ..$ .attrs : Named chr "8618"
.. .. .. .. .. .. .. ..- attr(*, "names")= chr "id"
.. .. .. .. .. ..$ ClassificationNodeChildList:List of 3
.. .. .. .. .. .. ..$ ClassificationNode:List of 2
.. .. .. .. .. .. .. ..$ Disorder :List of 4
.. .. .. .. .. .. .. .. ..$ OrphaNumber: chr "91378"
.. .. .. .. .. .. .. .. ..$ ExpertLink :List of 2
.. .. .. .. .. .. .. .. .. ..$ text : chr "http://www.orpha.net/consor/cgi-bin/OC_Exp.php?lng=en&Expert=91378"
.. .. .. .. .. .. .. .. .. ..$ .attrs: Named chr "en"
.. .. .. .. .. .. .. .. .. .. ..- attr(*, "names")= chr "lang"
.. .. .. .. .. .. .. .. ..$ Name :List of 2
.. .. .. .. .. .. .. .. .. ..$ text : chr "Hereditary angioedema"
.. .. .. .. .. .. .. .. .. ..$ .attrs: Named chr "en"
.. .. .. .. .. .. .. .. .. .. ..- attr(*, "names")= chr "lang"
.. .. .. .. .. .. .. .. ..$ .attrs : Named chr "12136"
.. .. .. .. .. .. .. .. .. ..- attr(*, "names")= chr "id"
.. .. .. .. .. .. .. ..$ ClassificationNodeChildList:List of 3
.. .. .. .. .. .. .. .. ..$ ClassificationNode:List of 2
.. .. .. .. .. .. .. .. .. ..$ Disorder :List of 4
.. .. .. .. .. .. .. .. .. .. ..$ OrphaNumber: chr "528623"
.. .. .. .. .. .. .. .. .. .. ..$ ExpertLink :List of 2
.. .. .. .. .. .. .. .. .. .. .. ..$ text : chr "http://www.orpha.net/consor/cgi-bin/OC_Exp.php?lng=en&Expert=528623"
this represents the structure of one of my lists, and i want to extract only what is contained in
df$DisorderList$Disorder$ClassificationNodeList$ClassificationNode$ClassificationNodeChildList$ClassificationNode$Disorder$Name$text
as you can see, this structure repeats along the file (in this case, twice, because I paste only a small part)
head(df$DisorderList$Disorder$ClassificationNodeList$ClassificationNode$ClassificationNodeChildList[1]$ClassificationNode$Disorder$Name$text)
[1] "Non-histaminic angioedema"
head(df$DisorderList$Disorder$ClassificationNodeList$ClassificationNode$ClassificationNodeChildList[2]$ClassificationNode$Disorder$Name$text)
[1] "Hereditary angioedema"
I want to extract these information in each of the 30 lists I have
We can use sapply to loop over the index of the 6th nested list and extract that component (assuming all other index are constant)
sapply(1:30, function(i) df[[2]][[1]][[4]][[1]][[1]][[i]][[1]][[3]][[1]])
It is better to check the length of the list to make this more dynamic
l1 <- length(df[[2]][[1]][[4]][[1]][[1]][[i]])
sapply(seq_len(l1), function(i) df[[2]][[1]][[4]][[1]][[1]][[i]][[1]][[3]][[1]])
Or if we use the OP's updated post with names
sapply(seq_len(l1), function(i)
df$DisorderList$Disorder$ClassificationNodeList$ClassificationNode$ClassificationNodeChildList[i]$ClassificationNode$Disorder$Name$text)
Using a reproducible example
lapply(1:3, function(i) df[[2]][[1]][[4]][[1]][[1]][[i]][[1]][[2]][[1]])
#[[1]]
#[1] 1 2 3
#[[2]]
#[1] 1 2 3
#[[3]]
#[1] 1 2 3
Or with pluck
library(purrr)
map(1:3, ~ pluck(df, 2, 1, 4, 1, 1, .x, 1, 2, 1))
#[[1]]
#[1] 1 2 3
#[[2]]
#[1] 1 2 3
#[[3]]
#[1] 1 2 3
data
df <- replicate(3, replicate(2, replicate(4, replicate(4, replicate(3, replicate(5, list( list( list( 1:3, 1:5), list( 1:3, 1:5))), simplify = FALSE), simplify = FALSE), simplify = FALSE), simplify = FALSE), simplify = FALSE), simplify = FALSE)