For example, a table like this:
name | age | gender
alice | 23 | female
bob | 21 | male
irfan | 24 | male
......
I get a sentence like "Hi, bob and alice!", I want to know the sentence if include the name in the table and return them. What should I do？
Like:
"Hi, bob and alice!" -> return the bob's value and alice value in the table
How to write SQL statements？
Something like
SELECT *
FROM yourtable
WHERE 'Hi, bob and alice!' LIKE '%' || name || '%';
is a start.
Related
I'm not sure how to word the title properly so sorry if it wasn't clear at first.
What I want to do is to find users that have logged into a specific page, but not the other.
The table I have looks like this:
Users_Logins
------------------------------------------------------
| IDLogin | Username | Page | Date | Hour |
|---------|----------|-------|------------|----------|
| 1 | User_1 | Url_1 | 2019-05-11 | 11:02:51 |
| 2 | User_1 | Url_2 | 2019-05-11 | 14:16:21 |
| 3 | User_2 | Url_1 | 2019-05-12 | 08:59:48 |
| 4 | User_2 | Url_1 | 2019-05-12 | 16:36:27 |
| ... | ... | ... | ... | ... |
------------------------------------------------------
So as you can see, User 1 logged into Url 1 and 2, but User 2 logged into Url 1 only.
How should I go about finding users that logged into Url 1, but never logged into Url 2 during a certain period of time?
Thanks in advance!
I will try to improve the title of your question later, but for the time being, this is how I accomplished what you are asking for:
Query:
select distinct username from User_Logins
where page = 'Url_1'
and username not in
(select username from User_Logins
where Page = 'Url_2')
and date BETWEEN '2019-05-12' AND '2019-05-12'
and hour BETWEEN '00:00:00' AND '12:00:00';
Returns:
User_2
Comments:
I basically used a sub query to filter out the usernames you don't care about. :)
The time range is getting only 1 result, which you can test by removing the "distinct" in the first line of the query. If you then remove the time range from the query, you'll get 2 results.
You can do it with group by username and apply the conditions in a HAVING clause:
select username
from User_Logins
where
date between '..........' and '..........'
and
hour between '..........' and '..........';
group by username
having
sum(page = 'Url_1') > 0
and
sum(page = 'Url_2') = 0
Replace the dots with the date/time intervals you want.
Table is the following:
CREATE TABLE UserLog(uid TEXT, clicks INT, lang TEXT)
Where uid field should be unique.
Here is some sample data:
| uid | clicks | lang |
----------------------------------------
| "898187354" | 4 | "ru" |
| "898187354" | 4 | "ru" |
| "123456789" | 1 | <null> |
| "123456789" | 10 | "en" |
| "140922382" | 13 | <null> |
As you can see, I have multiple rows with where the uid field is now duplicated. I would like for those rows to be merged in a following way:
clicks fields are added, and lang fields are updated if their previous value was null.
For the data shown above, it would look something like this:
| uid | clicks | lang |
---------------------------------------
| "898187354" | 8 | "ru" |
| "123456789" | 11 | "en" |
| "140922382" | 13 | <null> |
It seems that I can find many ways to simply delete duplicate data, which I do not necessarily want to do. I'm unsure how I can introduce logic in SQL statements that does this.
First update:
update userlog
set
clicks = (select sum(u.clicks) from userlog u where u.uid = userlog.uid),
lang = (select max(u.lang) from userlog u where u.uid = userlog.uid)
where not exists (
select 1 from userlog u
where u.uid = userlog.uid and u.rowid < userlog.rowid
);
and then delete the duplicate rows that are not needed:
delete from userlog
where exists (
select 1 from userlog u
where u.uid = userlog.uid and u.rowid < userlog.rowid
);
Lets say I have a table with columns id and content:
id | content
________________________
1 | abc abr abc as abs
2 | abc arc cre arc
3 | agr ann agd agd agd
What I want is output like this:
{"abc":2,"abr":1,"as":1, "abs":1} # for id 1
{"abc":1,"arc":2,"cre":1} # for id 2
{"agr":1,"agd":3,"ann":1} # for id 3
How could the task be done using Hive?
You'll need this library. It's pretty straightforward to build.
Query:
ADD JAR /path/to/jar/brickhouse-0.7.1.jar;
CREATE TEMPORARY FUNCTION COLLECT AS 'brickhouse.udf.collect.CollectUDAF';
SELECT id
, COLLECT(words, c) AS count_map
FROM (
SELECT id
, words
, COUNT(*) AS c
FROM (
SELECT id, words
FROM db.tbl
LATERAL VIEW EXPLODE(SPLIT(content, ' ')) exptbl AS words ) x
GROUP BY id, words ) y
GROUP BY id
Output:
+----+---------------------------------+
|id |count_map |
+----+---------------------------------+
|1 |{"as":1,"abs":1,"abc":2,"abr":1} |
+----+---------------------------------+
|2 |{"cre":1,"arc":2,"abc":1} |
+----+---------------------------------+
|3 |{"ann":1,"agr":1,"agd":3} |
+----+---------------------------------+
I have two tables
Names
id | name
---------
5 | bill
15 | bob
10 | nancy
Entries
id | name_id | added | description
----------------------------------
2 | 5 | 20140908 | i added this
4 | 5 | 20140910 | added later on
9 | 10 | 20140908 | i also added this
1 | 15 | 20140805 | added early on
6 | 5 | 20141015 | late to the party
I'd like to order Names by the first of the numerically-lowest added values in the Entries table, and display the rows from both tables ordered by the added column overall, so the results will be something like:
names.id | names.name | entries.added | entries.description
-----------------------------------------------------------
15 | bob | 20140805 | added early on
5 | bill | 20140908 | i added this
10 | nancy | 20140908 | i also added this
I looked into joins on the first item (e.g. SQL Server: How to Join to first row) but wasn't able to get it to work.
Any tips?
Give this query a try:
SELECT Names.id, Names.name, Entries.added, Entries.description
FROM Names
INNER JOIN Entries
ON Names.id = Entries.name_id
ORDER BY Entries.added
Add DESC if you want it in reverse order i.e.: ORDER BY Entries.added DESC.
This should do it:
SELECT n.id, n.name, e.added, e.description
FROM Names n INNER JOIN
(SELECT name_id, description, Min(added) FROM Entries GROUP BY name_id, description) e
ON n.id = e.name_id
ORDER BY e.added
Hi I have an Access Table like this.
----------------------------------------------------------------
| firstname | surname | address |
----------------------------------------------------------------
| Joan | Rivers | 123 Fake St. |
| Michael | Jackson | 69 Balls Head St. |
| Justin | Bieber | None |
----------------------------------------------------------------
I'm wondering if it is possible, over ODBC, to construct a query that allows me to match my input to any column.
Something like this:
SELECT * FROM NEMESISES WHERE '%value%' LIKE firstname or surname or address;
and when value is plugged in for example: '%bie%', it outputs the Justin Bieber row or when '%st%' is plugged in it outputs the Joan Rivers and Michael Jackson row.
Thank You!
You can divide it into 3 matchings:
SELECT * FROM NEMESISES
WHERE firstname LIKE '%value%'
OR surname LIKE '%value%'
OR address LIKE '%value%';
Or you can match joined values of columns:
SELECT * FROM NEMESISES
WHERE firstname || surname || address LIKE '%value%';
I would prefer first solution: database have less to do.