R: Regex to string detect date-time format in R - r

Question

What would be a solution to detect date-time format
14/07/2009 19:15:29
Is this a fullproof solution?
str_detect(s,regex("([0-9]{2}/[0-9]{2}/[0-9]{4}) [0-9]{2}:[0-9]{2}:[0-9]{2}"))
For example for the format
14.07.2009
I have written the regex to be
str_detect(date,regex("([0-9]{2}\\.[0-9]{2}\\.[0-9]{4})"))
I don't have much idea regarding regex in R or regex in general, just the very basic stuff so would appreciate an easy approach with detailed logic. Thanks in advance.

Answer 1

As a beginner, I sometimes found it helpful to assemble the pattern as follows:
c(
"[0-9]{2}", # day
"/",
"[0-9]{2}", # month
"/",
"[0-9]{4}", # year
" ",
"[0-9]{2}", # Hour
":",
"[0-9]{2}", # minute
":",
"[0-9]{2}" # second
) |> paste(collapse = "")
Returns the pattern:
[1] "[0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}:[0-9]{2}"
stringr::str_detect("14/07/2009 19:15:29",
"[0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}:[0-9]{2}")
# [1] TRUE
Update (as per comments)
Here is how you could use the lubridate package. dmy_hms() finds datetimes in your format:
lubridate::dmy_hms("14/07/2009 19:15:29")
# [1] "2009-07-14 19:15:29 UTC"
But it will not parse invalid dates:
lubridate::dmy_hms("14/07/2009 19:15:70") # invalid seconds
# [1] NA
So to validate you could do:
(! is.na(lubridate::dmy_hms("14/07/2009 19:15:29")))
# [1] TRUE