CSS: Changing width/height after rotation in one direction only - css

My end goal is a draggable, resizable, Scalable, and rotatable element, just like the example on: https://daybrush.com/moveable/ only by using css width,height, and transform: rotate, translate.
Say I have a div with following css:
.rect {
background-color: red;
width: 200px;
height: 100px;
top:100px;
left:100px;
position: absolute;
transform: rotate(0deg);
}
<div class="rect"></div>
If I want to resize the div horizontally to the left, I just change the width by x pixels. If I want to change it to the right I just change the width by x pixels, and translate(-xpx, 0).
But what if I change the angle? From trying a lot of stuff, I found some of the x and y values for translate to the respective angle, however I feel like there is a more straight forward way than just guessing. E.g: For 90deg, if I want to resize to the left by x px I do translate(-x0.5px, x0.5px).
More: what if I want to change both the width & height at the same time?
P.S.: I would rather avoid using libraries, transform: scale or svg
P.P.S:Example to further demonstrate the problem, just changing the width:
.rect {
background-color: red;
width: 200px;
height: 100px;
top:100px;
left:100px;
position: absolute;
transform: rotate(45deg);
animation: expand 5s infinite
}
#keyframes expand {
from {width: 200px;}
to {width: 2000px;}
}
<div class="rect"></div>
Fixed, stretching the left side of the original rectagle (now up since rotated 90deg):
.rect {
background-color: red;
width: 200px;
height: 100px;
top:100px;
left:100px;
position: absolute;
transform: rotate(90deg);
animation: expand 3s infinite
}
#keyframes expand {
from {
width: 200px;
}
to {
width: 800px;
transform: rotate(90deg) translate(-300px, 300px);
}
}
<div class="rect"></div>

You can apply several transformations to the same object and they will be composed in the order that you specify. Move then rotate, is different than rotate then move.
.rect {
background-color: red;
width: 200px;
height: 100px;
top:100px;
left:100px;
position: absolute;
}
.t1 {
background-color: #40d04080;
/* green shaded rectangle: rotate after translation */
transform: translate(2cm, 0) rotate(30deg);
}
.t2 {
background-color: #f0404080;
transform: rotate(30deg);
}
.t3 {
background-color: #4040f080;
/* blue shaded rectangle: translate after rotation */
transform: rotate(30deg) translate(2cm, 0) ;
}
<div class="rect t1"></div>
<div class="rect t2"></div>
<div class="rect t3"></div>

Related

I have one SVG that is rotate around a svg but is not fixed

<!--BG Photo-->
<div class="pic1"><img src="1.svg"></div>
<!--SVG that will rotate-->
<div class="pic2"><img src="img/vec/gz4.svg" alt=""></div>
.pic1 img{/*Bg Photo*/
width: 100%;
height: auto;
top: 0;
left: 0;
}
.pic2{
position: absolute;
transform: translate(45px,-75px);
}
.pic2 img{
transform-origin:center;
width: 50px;
height: 50px;
animation: rotation 2s infinite linear;
}
#keyframes rotation {
from {
transform: rotate(0deg);
}
to {
transform: rotate(359deg);
}
}
The problem is what when i zoon out/in or resize the brower .pic2
is moving not stay fixed on his original point
Your idea is right yet both SVG images will adjust to the proportion of the available space (do you have only viewBox defined in them, removing the height and width attributes?). So the second image (pic2) will always "bounce" when resizing (but how many web users really do that?).
Maybe define styles for both SVGs in their DIV parent (or "container" element if you wish) by using vw and vh units - instead of pixels, possibly percentages as well - and this will at least give you more predictable result:
<style>
body {
border: 0;
margin: 0;
}
.pic1 {
position: absolute;
width: 100%;
border: 0;
margin: 0;
}
.pic1 img{/*Bg Photo*/
width: 100%;
height: auto;
top: 0;
left: 0;
}
.pic2{
position: absolute;
z-index: -1;
transform: translate(2.5vw,88vh);
}
.pic2 img{
transform-origin:center;
width: 50px;
height: 50px;
animation: rotation 2s infinite linear;
}
#keyframes rotation {
from {
transform: rotate(0deg);
}
to {
transform: rotate(359deg);
}
}
</style>
<body>
<!--BG Photo-->
<div class="pic1"><img src="1.svg"></div>
<!--SVG that will rotate-->
<div class="pic2"><img src="img/vec/gz4.svg" alt=""></div>
</body>

CSS Animation - drawing line from left to right on mouseenter, then disappearing left to right on mouseleave

I'm trying to animate a line that underlines from left to right on 'mouseenter' and then to disappear from left to right on 'mouseleave' instead of the current behaviour where it disappears right to left.
Example of what I'm trying to achieve (but with animations not transitions):
https://jsfiddle.net/1gyksyoa/
I have tried to reverse the 'draw' animation but this doesn't achieve what I'm trying to accomplish.
#keyframes draw-reverse {
100% {
width: 0;
background-color: red;
}
0% {
width: 47px;
background-color: red;
}
}
I have put together this to give a better understanding of the problem;
https://jsfiddle.net/Lq560be9/
Currently, I have the line animating from left to right as desired on 'mouseenter', but on 'mouseleave' it disappears from right to left, whereas I am trying to get the line to also disappear from left to right.
But the problem isn't animation's ability it's the properties that you're animating. Instead of animating the width of an object you should animate its "X" position using translate. (this is much more performant too)
Simply put you need to MOVE the bar from left to center to right instead of trying to scale it.
(there's lots of code here to show the different states the only one you really need to follow is .ex4)
document.querySelector('#animate').addEventListener('mouseenter', function(){
this.classList.toggle('over');
})
document.querySelector('#animate').addEventListener('mouseleave',function(){
this.classList.toggle('out');
})
.example {
margin: 30px auto;
padding: 10px;
background: #dadada;
max-width: 50%;
position: relative;
}
.example:after {
content:'';
position: absolute;
width: 50%;
height: 5px;
background-color: #333;
left:0;
bottom:0;
}
.ex1:after {
transform: translateX(-100%);
}
.ex3:after {
transform: translateX(200%);
}
.ex4 {
overflow: hidden;
}
.ex4:after {
transform: translateX(-100%);
}
.ex4.over:after {
animation: animate-in 1s ease-in-out 1 normal forwards;
}
.ex4.out:after {
animation: animate-out 1s ease-in-out 1 normal forwards;
}
#keyframes animate-in {
0% {
transform: translateX(-100%);
}
100% {
transform: translateX(0);
}
}
#keyframes animate-out {
0% {
transform: translateX(0);
}
100% {
transform: translateX(200%);
}
}
<div class="example ex1">Object State 1</div>
<div class="example ex2">Object State 2</div>
<div class="example ex3">Object State 3</div>
<div id="animate" class="example ex4">Full example (hover)</div>
As a follow on from above, an alternative solution without using the translate property.
The new animation for mouseleave is;
#keyframes draw-reverse {
0% {
width: 47px;
}
25% {
width: calc(100% - 16px);
}
26% {
width: auto;
right: 8px;
left: 8px;
}
100% {
width: auto;
right: 8px;
left: calc(100% - 8px);
}
}
Full solution can be seen here - https://jsfiddle.net/1wq25tg7/

Transform and Stacking Order

I am trying to understand what is really happening “3d” world of CSS.
I made a simple example
Particularly the code which bugs me the most is:
.back {
background-color: tomato;
transform: rotateY(180deg);
z-index: 1;
}
The thing which is not clear to me is why when you hover over .inner, its background color (gold) is not visible?? If you remove the transform property from .back or if you set the rotateY to 0deg then the gold background color of the .inner is clearly visible.
Why is the transform property of .back changing the stacking order?
Logically it makes sense that children(.front and .back) should appear in front of their parent(.inner).
Also, I would like to know what really happens when you set transform-style to flat? Does that make parent and all of its children collapse into single “unit” where element with highest stacking order takes priority/visibility?
in your code :
.outer {
display: block;
width: 200px;
height: 200px;
border: 2px solid gold;
perspective: 1000px;
padding: 10px;
margin: 0 auto;
}
.inner {
position: relative;
height: 100%;
width: 100%;
transition: transform 2s linear;
transform-style: preserve-3d;
background-color: gold;
backface-visibility: visible;
transform: rotateY(50deg);
}
.sides {
position: absolute;
width: 100%;
height: 100%;
left: 0;
top: 0;
color: white;
backface-visibility: hidden;
}
.front {
background-color: blue;
transform: translateZ(20px)
}
.back {
background-color: tomato;
transform: rotateY(180deg) translateZ(10px);
}
.inner:hover {
transform: rotateY(180deg)
}
<div class="outer">
<div class="inner">
<div class="sides front">Front Side</div>
<div class="sides back">Back Side</div>
</div>
</div>
you are using
transform: rotateY(180deg) translateZ(10px);
The transforms are applied right to left, so first it goes to the front 10px. But after that, it rotates 180deg. (around the transform-origin that is constant). That makes the previous 10px go towards the back instead of to the front.
if the order is the inverse
transform: translateZ(10px) rotateY(180deg);
now the rotation is done first, and so the translation is unafected by it and goes to the front.
and No, sorry, z-index is not a substitute for 3-d transforms, if you want to use 3d transforms, translation is the only way to go ....
In your first example, z-index is useless, as can be seen easily
codepen with z-index removed
This works because you are setting
backface-visibility: hidden;
So only the face that is facing front will be visible

How to tilt inner element forward when tilting outer back with css 3d transforms

I would like to get an effect of an outer element tilting back along the z axis and an inner element standing up out of it in a normal 2d perspective. In other words given this html
<div id="outer">
<div id="inner"></div>
</div>
I would like the outer element to tilt backwards with its side lines approaching a vanishing point while the inner element's sides are vertical.
How do I achieve this? Using the css
div {
display: inline-block;
}
#outer {
padding: 20px;
background-color: blue;
-webkit-transform: perspective(400px) rotateX(45deg)
}
#inner {
height: 150px;
width: 150px;
background-color: tomato;
background-image: url(http://www.w3schools.com/html/smiley.gif);
background-size: 100%;
}
I thought I could just do
#inner {
-webkit-transform: rotateX(-45deg);
}
but that just makes it tilt more.
Here is a jsbin
You need to set preserve 3d
#outer {
padding: 20px;
background-color: blue;
-webkit-transform: perspective(400px) rotateX(45deg);
-webkit-transform-style: preserve-3d;
}
#inner {
height: 150px;
width: 150px;
background-color: tomato;
background-image: url(http://www.w3schools.com/html/smiley.gif);
background-size: 100%;
-webkit-transform: rotateX(-45deg);
-webkit-transform-origin: bottom center;
}
jsbin

Position AFTER transform in CSS?

Consider the following attempt to rotate a paragraph 90 degrees and position it so that the corner that was initially its top-left corner (and which therefore becomes its top-right corner after the rotation) ends up located at the top-right corner of the parent block.
HTML:
<!DOCTYPE html>
<html>
<body>
<div id="outer">
<p id="text">Foo bar</p>
</div>
</body>
</html>
CSS:
#outer {
border: solid 1px red;
width:600px;
height: 600px;
position: relative;
}
#text {
transform: rotate(90deg);
position: absolute;
top: 0;
right: 0;
}
In Firefox 19.0.2 on OS X 10.6.8, it fails. This appears to be because, despite the order in which the CSS properties were given, the transformation is applied after the positioning. In other words, the browser:
places #text such that its top-right corner is located at the top-right corner of the parent block, but only then
rotates it, with the result that what is now its top-right corner is not located at the top-right corner of the parent block.
As a result, the transform-origin property isn't much use here. If, for instance, one used transform-origin: top right; then #text would need to be moved downwards by the width it had before it was rotated.
My question: is there a way to tell the browser to apply the CSS positioning properties after the rotation; and if not, then is there instead a way to move #text downwards (e.g. using top:) by the width it had before it was rotated?
NB. Ideally the solution should not require setting a fixed width: for #text, and must not require JavaScript.
You can apply more than one transform to an element, and the order does matter. This is the simplest solution: http://jsfiddle.net/aNscn/41/
#outer {
border: solid 1px red;
width:600px;
height: 600px;
position: relative;
}
#text {
background: lightBlue;
position: absolute;
top: 0;
left: 0;
right: 0;
transform: translate(100%) rotate(90deg);
transform-origin: left top;
-webkit-transform: translate(100%) rotate(90deg);
-webkit-transform-origin: left top;
}
The transform origin is the point around which a transformation is applied. For example, the transform origin of the rotate() function is the center of rotation - https://developer.mozilla.org/en-US/docs/Web/CSS/transform-origin
Rotating -90deg.
.rotate {
position:absolute;
-webkit-transform-origin: left top;
/* Safari */
-webkit-transform: rotate(-90deg) translateX(-100%);
/* Firefox */
-moz-transform: rotate(-90deg) translateX(-100%);
/* IE */
-ms-transform: rotate(-90deg) translateX(-100%);
/* Opera */
-o-transform: rotate(-90deg) translateX(-100%);
}
Solved: here
This is the code I've added:
left: 100%;
width: 100%;
-webkit-transform-origin: left top;
I've also added some prefixed transform properties so it will be cross browser
-webkit-transform:rotate(90deg);
-moz-transform:rotate(90deg);
-ms-transform:rotate(90deg);
-o-transform:rotate(90deg);
transform:rotate(90deg);
How I did it:
I've found this question and, as the name of the website says, "fiddled" with the code to obtain this behavior. I guess the solution is left: 100%; instead of right: 0;.
(the width: 100%; is there because for some reason it wasn't 100% and the text would overflow to the next line)
You may want to try using CSS3 #keyframes animation. It will allow you to rotate and reposition in any order you like. Here is a tutorial that may help: [CSS-Tricks][1]
.container {
position: relative;
width: 200px;
height: 200px;
border: 1px solid red;
}
p {
border: 1px solid blue;
position: absolute;
top: auto;
right: 0;
display: inline-block;
margin: 0;
animation: 1s rotate 1s both;
}
#keyframes rotate {
0% {
transform-origin: top left;
transform: rotate(0deg);
right:0;
}
50% {
right:0;
}
100% {
transform-origin: top left;
transform: rotate(90deg);
right: -64px;
}
}
<div class="container">
<p>some text</p>
</div>
You might want to play around with the translate option which you can apply as the second transform function after rotate and place your element at the exact position that you want to.
There is no other way I guess to tell the browser to use the position properties after the transform function is used using plain css.
See this demo - http://codepen.io/anon/pen/klImq
Place "!important" at the end of the transform line.

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