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I'm trying to parse a timestamp of the format:
2021-03-31T13:38:14
So I use the layout format of: 2006-02-15T15:04:05
For some reason all of my datetime objects are parsed correctly except 2021-03-31T13:38:14 and 2021-03-29T14:21:41. I get an error saying:
parsing time "2021-03-31T13:38:14": hour out of range
Why is this happening? When the hour is not out of range?
Here's the code:
const DateFormat = "2006-02-15T15:04:05"
var toParse = "2021-03-31T13:38:14"
submittedAt, err := time.Parse(DateFormat, toParse)
The format for day of the month is 02 and month is 01. So your layout format should be 2006-01-02T15:04:05
Check the other formats to see the pattern
https://golang.org/pkg/time/#pkg-constants
For instance RFC3339 is 2006-01-02T15:04:05Z07:00.
https://play.golang.org/p/ZHu6nbPtsJt
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I'm lost : i'd like to convert chararcter to date using as.Date() in R. I genuinely don't know what i missed with such a simple code. Here is an example
week_dates <- as.Date("06/20/2022", format ="%d/%m/%Y")
week_dates return only NA. Any idea what i missed ?
Thanks in advance !
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Is there a way to change the date format in R. Example, when I tried with below formula to convert, it was not showing a right result
format(as.Date("30-01-2021"), "%Y/%d/%m")
"0030/20/01"
Expected output
"2021-01-30"
The lubridate package works really well for this kind of formatting.
#Load library
library('lubridate')
# Convert date format
lubridate::dmy("30-01-2021")
The reason it is not working is because your date string is not in the default date format. The default is "%Y-%m-%d" but your string is "%d-%m-%Y". So you can fix it by specifying the input date format on the as.Date() function. Like this:
as.Date("30-01-2021", "%d-%m-%Y")
# [1] "2021-01-30"
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I'm new to R and trying to load some time series data but I'm stuck at the first hurdle.
I have a dataframe with a date column called Date. The date format of the data is: 23-May-16 (it appears like this in the R console when I print df). To read as date I'm trying:
df$Date <- as.Date(df$Date, "%dd-%bbb-%yy")
as per guidance here
which produces the value <NA> when it reads the data.
Try:
as.Date(df$Date,format="%d-%b-%y")
You only need to list those once:
as.Date("23-May-16", "%d-%b-%y")
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I am trying to parse a date string like 1/12/2014 which represents the first of december 2014. However, looking at http://www.statmethods.net/input/dates.html it looks like R would only support parsing something like 01/12/2014. Is this correct? How could I parse the date mentioned above?
Update: I used y instead of Y for the year and the date got parsed as "2020-12-01" --> everything working fine now.
No.
as.Date("1/12/2014", format="%d/%m/%Y")
See the Details section of ?strptime for an extensive list of the components of date-time that R can format.
lubridate makes handling dates easy. Use dmy for dates in day-month-year format.
library(lubridate)
dmy("1/12/2014")
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Can someone please tell me why this doesn't work:
as.Date("01/08/15", format = "%m/%d/%Y")
[1] "0015-01-08"
Thanks!
You need to use lower-case %y. Upper-case %Y requires a 4-digit year. (In my opinion, the entire command should have failed with an error message, but unfortunately it didn't.) See strptime(), which documents the format codes.
as.Date("01/08/15", format = "%m/%d/%y")
## [1] "2015-01-08"