I have a menu function, in which I input a question and two options, then the user choses one. It works just fine everytime but one ; I call
if (menu("ou est le corps?","interieur ","exterieur")==1)
{
but instead of printing "interieur " It shows "p?"
it works just fine without the space, but I need to make a space and \n does quite the same thing.
I have another call of this function, with \n which works fine so I have no idea about why this wouldn't work. Anyone has got an idea?
PS : the value of choix1 is then sent via bluetooth, and there it stays intact.
PPS : tell me if something is unclear, I'm not naturally english
PPPS(sorry) : tried to run the same code again, it seems to print a random character followed by "?", I had twice "p?", once "?" and once " '?"
[updates] once "#?"
int menu (String texte, String choix1, String choix2)
{
envoye = 0;
rxValue = "0";
while (digitalRead(M5_BUTTON_HOME) != LOW && rxValue == "0")
{
heure();
M5.Lcd.setTextSize(2);
M5.Lcd.print(texte);
M5.Lcd.printf("\n");
if (selec == 0)
{
M5.Lcd.printf("->%s %s", choix1, choix2);
}
else
{
M5.Lcd.printf(" %s ->%s", choix1, choix2);
}
if (M5.BtnB.read() != 0)
{
if (selec == 0)
{
selec = 1;
}
else
{
selec = 0;
}
while (M5.BtnB.read() != 0)
{
if(digitalRead(M5_BUTTON_HOME) == LOW)
{
M5.Lcd.fillScreen(BLACK);
delay(1000);
if(digitalRead(M5_BUTTON_HOME) == LOW)
{
choix=50;
heure();
delay(1000);
return 1;
}
}
}
}
if (deviceConnected && envoye == 0)
{
sendchoix(texte, choix1, choix2);
envoye++;
}
}
if (rxValue != "0")
{
recuble = &rxValue[0];
selec = atoi(recuble) - 1;
rxValue = "0";
}
M5.Lcd.fillScreen(BLACK);
delay(300);
return selec;
}
int menu (String texte, String choix1, String choix2) {
[...]
M5.Lcd.printf("->%s %s", choix1, choix2);
You cannot treat String objects as const char*, which is what the format specifier %s is expecting. String is an Arduino class for storing.. strings/character data, but an object of this class is not equivalent to the raw pointer to the data.
For that, you need to call the c_str() method on the String object to get the C-String pointer to the data, as shown in the documentation [1].
[..]
M5.Lcd.printf("->%s %s", choix1.c_str(), choix2.c_str());
[..]
[1] https://www.arduino.cc/reference/en/language/variables/data-types/string/functions/c_str/
Related
I just started learning C# and while loops are confusing me. Unlike Java, where I can use a while loop to loop a program if a user entered a invalid input, it's not acting the same way in C#.
using System;
namespace first {
class Program {
static void Main(string[] args) {
Console.WriteLine("Hi! What is your name");
string userName = Console.ReadLine();
Console.WriteLine("oh! you are:" + userName);
Console.WriteLine("let play a game");
string answer="Y";
while (answer == "Y") {
Random random = new Random();
int correntNumber = random.Next(1, 2);
int guess = 0;
Console.WriteLine("Guess a number");
while (guess != correntNumber) {
string userGuess = Console.ReadLine();
//validate input method 1
try {
guess = int.Parse(userGuess);
} catch (Exception e) {
Console.WriteLine("Invalid inout", e);
}
//validate input method 2
//if(!int.TryParse(userGuess, out guess)) {
// Console.WriteLine("invalid input");
//}
if (guess != correntNumber) {
Console.WriteLine("try again!");
}
}
Console.WriteLine("Yes! corrector");
Console.WriteLine("Play again?");
//string answer;
answer = Console.ReadLine().ToUpper();
if(answer == "Y") {
continue;
} else if (answer == "N") {
Console.WriteLine("bye");
return;
} else if (answer != "Y" || answer != "N") {
Console.WriteLine("y or n");
answer = Console.ReadLine().ToUpper();
continue;
}
}
}
}
}
When I enter a value other than y or n, the message appears,Console.WriteLine("Y or n only");, but the game restarts while it shouldn't.
I am sorry this is a simple and rather silly question, but I can't pin point where I am going wrong.
the problem is that after printing to the user "y or n only" message you take the input but you don't actually do anything with it
so the loop just restarts regardless of the input , to fix this issue you could replace the last if part with this code
while(answer != 'Y' && answer != 'N'){
Console.WriteLine("y or n only");
answer = Convert.ToChar(Console.ReadLine().ToUpper());
}
if(answer == 'Y')
{
continue;
}
else if(answer == 'N')
{
Console.WriteLine("goodbye");
return;
}
so after you read the first input answer of him for repeating or no you check if it's a valid input or not and if it's not you keep asking him for "y or n only" till he enters "Y" or "N" and then you process this answer for whether it's a "Y" or "N" in the if part
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 8 years ago.
I have to make a program that interacts with the user interface that ask a user for a number and a base to convert to binary, hex, or octo. I made a program that works but when the user types in "0 0", it is suppose to terminate and end the program. My program on the other hand doesn't do that but keep going in the while loop.
Here is the code:
import java.util.*; //for Scanner
public class BaseConversionApp {
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
String combo = numbers(console);
while(combo != "0 0") {
if(combo.length() > 0) { //breaks the string into integers to do math to it
Scanner s = new Scanner(combo);
int count = s.nextInt();
int countSecond = s.nextInt();
s.close();
conversion(count,countSecond);
System.out.println();
//now if it goes 0 0 or
String again = numbers(console);
// conversion(count,countSecond);
}
}
//prompts the user for two numbers and checks if the bases are 16, 8, 2.
public static String numbers(Scanner console) {
String combination = "";
String nothing = "0 0";
System.out.print("Enter an integer and the new base: ");
int integer = console.nextInt();
int base = console.nextInt();
if(base == 16 || base == 2 || base == 8) {
combination = integer + " " + base;
return combination;
} else if (base == 0 && integer == 0){
System.out.println("Good bye!");
return nothing;
} else {
System.out.println("Sorry, that is an invalid base. Please enter 2, 8, or 16
only.");
}
return "";
}
//converts the integers into binary, hexa, or octo.
public static void conversion (int integer, int base) {
//takes cares of the special case if the user wants to know hexidecimal
if(base <= 16) {
String calculations = Integer.toString(integer, base);
if(integer > 0 && base > 0) {
System.out.println(integer + " in binary -> " + Integer.toString(integer,
base));
}
}
}
}
You can't compare strings like that, you have to use the String object's equals() method. So, you should have:
while(!"0 0".equals(combo)) {
...
}
Notice that I've put the constant "0 0" first -- that protects you against combo being null. Otherwise you'd have !combo.equals("0 0"), and if combo were null you'd get a NullPointerException when you try to call equals() on a null value.
Try this code instead. Yours looks complicated. Btw, your code works for me.
import java.util.Scanner;
public class NewClass {
static Scanner inp = new Scanner(System.in);
static String line1 = "";
static String line2 = "";
static String exit = "exit";
public static void main(String[] args) {
System.out.println("Enter int first and then base...");
System.out
.println("Enter the word exit to exit!");
while (true) {
line1 = inp.next();
if (line1.equalsIgnoreCase(exit)) {
break;
}
line2 = inp.next();
try {
conversion(Integer.parseInt(line1), Integer.parseInt(line2));
} catch (NumberFormatException e) {
e.printStackTrace();
}
}
System.out.println("Bye...");
}
public static void conversion(int integer, int base) {
// takes cares of the special case if the user wants to know hexadecimal
if (base <= 16) {
String calculations = Integer.toString(integer, base);
if (integer > 0 && base > 0) {
System.out.println(integer + " in binary -> "
+ Integer.toString(integer, base));
}
}
}
}
is it possible to use a Kleene Operator (Kleene Star) for the Formatters?
I want to use a phoneFormatter, which puts a minus after the 5th number and afterwards it should be possible to have a variable number of numbers.
E.g.: 0172-555666999, 0160-44552 etc.
That is how I started, but I don't know which character belongs after the last hash (it is not a star, I already tried it ;-) ):
<fx:Declarations>
<mx:PhoneFormatter id="mPhoneFormat"
formatString="####-#"/>
</fx:Declarations>
The default PhoneFormatter expects the input string to have the same number of characters as the format string. They don't support regular expression patterns (like * to match the element zero or more times).
However, it's pretty easy to make your own formatter. To do this, I extended the PhoneFormatter class and overrode its format() method. I copied and pasted the original format() method and made the following modifications:
comment out the code that compared the length of the source string with the length of the format string
compare the length of the formatted string. If the original string is longer, append the remaining chars from the original string to the formatted string.
This probably won't handle all of your use cases, but it should be pretty straightforward to modify this to your needs.
package
{
import mx.formatters.PhoneFormatter;
import mx.formatters.SwitchSymbolFormatter;
public class CustomPhoneNumberFormatter extends PhoneFormatter
{
public function CustomPhoneNumberFormatter()
{
super();
}
override public function format(value:Object):String
{
// Reset any previous errors.
if (error)
error = null;
// --value--
if (!value || String(value).length == 0 || isNaN(Number(value)))
{
error = defaultInvalidValueError;
return "";
}
// --length--
var fStrLen:int = 0;
var letter:String;
var n:int;
var i:int;
n = formatString.length;
for (i = 0; i < n; i++)
{
letter = formatString.charAt(i);
if (letter == "#")
{
fStrLen++;
}
else if (validPatternChars.indexOf(letter) == -1)
{
error = defaultInvalidFormatError;
return "";
}
}
// if (String(value).length != fStrLen)
// {
// error = defaultInvalidValueError;
// return "";
// }
// --format--
var fStr:String = formatString;
if (fStrLen == 7 && areaCode != -1)
{
var aCodeLen:int = 0;
n = areaCodeFormat.length;
for (i = 0; i < n; i++)
{
if (areaCodeFormat.charAt(i) == "#")
aCodeLen++;
}
if (aCodeLen == 3 && String(areaCode).length == 3)
{
fStr = String(areaCodeFormat).concat(fStr);
value = String(areaCode).concat(value);
}
}
var dataFormatter:SwitchSymbolFormatter = new SwitchSymbolFormatter();
var source:String = String(value);
var returnValue:String = dataFormatter.formatValue(fStr, value);
if (source.length > returnValue.length)
{
returnValue = returnValue + source.substr(returnValue.length-1);
}
return returnValue;
}
}
}
I must display very small values (capacitor) in a Flex-AdvancedDataGrid
I use spark.formatters.NumberFormatter.
If I use 3, 6 or 9 for fractionalDigits, everything is fine.
But if I use 12, because I need 12 digits after decimal separator, then the value is cut after 9 digits!
Is there a way to get more then 9 digits after separator.
Or is there a way to use a formatting like "4.7 E-12" (Must be E-9, E-12, E-15 and so on)
toPrecision and toFixed works fine up to 20 digits. Thats enough.
I will write a function on this base to get results like 4.7 E-12.
Thanks for the help
Jan
I created a custom pattern formatter class that allows you to specify how you want a string/number formatted using whatever symbols or structure you want. Depending on your requirements, this may help you. Feel free to modify this class as needed.
CustomPatternFormatter.as
package
{
import mx.formatters.Formatter;
public class CustomPatternFormatter extends Formatter
{
private static const VALID_PATTERN_CHARACTERS:String = "#,.-";
// Use # as a placeholder for a regular
// character in the input string.
// Then add other characters between the
// # symbol for the desired output format.
// ex. The pattern ##,##,##.## with input 12345678
// will output 12,34,56.78
public var formatPattern:String;
// If True, the input string must match the number
// of # characters in the formatPattern.
public var inputMustMatchPatternLength:Boolean;
//Constructor
public function CustomPatternFormatter()
{
super();
formatPattern = "";
inputMustMatchPatternLength = false;
}
// Override format().
override public function format(value:Object):String
{
// Reset error if it exists.
if (error)
error = null;
// If value is null, or empty String just return ""
// but treat it as an error for consistency.
// Users will ignore it anyway.
if (!value || (value is String && value == ""))
{
error = "Cannot convert an empty value";
return "";
}
// Check to see if the input value must match the format pattern
if (inputMustMatchPatternLength && String(value).length != countOccurrences(formatPattern, "#"))
{
error = "The input value length does not match the format pattern length.";
return "";
}
// If the value is valid, format the string.
var fStrLen:int = 0;
var letter:String;
var n:int;
var i:int;
var v:int;
// Make sure the formatString is valid.
n = formatPattern.length;
for (i = 0; i < n; i++)
{
letter = formatPattern.charAt(i);
if (letter == "#")
{
fStrLen++;
}
else if (VALID_PATTERN_CHARACTERS.indexOf(letter) == -1)
{
error = "You can only use the following symbols in the formatPattern: " + VALID_PATTERN_CHARACTERS;
return "";
}
}
var returnString:String = "";
var vStr:String = String(value).replace(".", "").split("").reverse().join("");
var fArr:Array = formatPattern.split("").reverse();
var fChar:String;
// Format the string
for (v = 0; v < vStr.length; v++) { if (fArr.length > 0)
{
do
{
fChar = fArr.shift();
if (fChar != "#")
returnString += fChar;
} while (fChar != "#" && fArr.length > 0);
}
returnString += vStr.charAt(v);
}
// Return the formatted string
return returnString.split("").reverse().join("");
}
protected function countOccurrences(str:String, char:String):int
{
var count:int = 0;
for (var i:int=0; i < str.length; i++)
{
if (str.charAt(i) == char)
{
count++;
}
}
return count;
}
}
}
i'm having 3 types of lists, and i'm trying to print them according to attribute_type.
so according attribute_type the iterator is chosen.
the problem is if for example attribute_type == "pis", the if condition is executed but when finished it returns to the upper decleration: QMapIterator it(pit.item_parameters), so this way the iterator is not valid...
how should i declare it properly ?
QMapIterator<QString, IP> it(pit.item_parameters);
if (attribute_type == "ips") {
QMapIterator<QString, IP> it(pit.item_parameters);
if (pit.item_parameters.isEmpty()) { return; }
}
else if (attribute_type == "variables") {
QMapIterator<QString, Variable> it(pit.variables);
if (pit.variables.isEmpty()) { return; }
}
else if (attribute_type == "pis") {
QMapIterator<QString, PI> it(pit.pis);
if (pit.pis.isEmpty()) { return; }
}
while(it.hasNext())
{
it.next();
text += it.key();
text += it.value().type;
}
If your types IP, PI and Variable derive from the same class ParentClass having type as public member, you can declare it that way:
QMapIterator<QString, ParentClass> it;