Combine multiple array based on composite key in xquery - xquery

Question

I am facing an issue while combining element array based on two key that is docNo and item_no in xquery version 1.0
Below is the given xml sample input and output
sample XML Request:
<text>
<element>
<docNo>11111</docNo>
<item_no>001</item_no>
<text_line>SUPER PROFILE</text_line>
</element>
<element>
<docNo>1111</docNo>
<item_no>001</item_no>
<text_line>TOP SPOTS</text_line>
</element>
<element>
<docNo>1111</docNo>
<item_no>002</item_no>
<text_line>SUPER PROFILE</text_line>
</element>
<element>
<docNo>1111</docNo>
<item_no>002</item_no>
<text_line>TOP SPOTS</text_line>
</element>
<element>
<docNo>2222</docNo>
<item_no>002</item_no>
<text_line>PROILE</text_line>
</element>
output :
<text>
<element>
<docNo>11111</docNo>
<item_no>001</item_no>
<text>
<text_line>SUPER PROFILE</text_line>
<text_line>TOP SPOTS</text_line>
</text>
</element>
<element>
<docNo>11111</docNo>
<item_no>002</item_no>
<text>
<text_line>SUPER PROFILE</text_line>
<text_line>TOP SPOTS</text_line>
</text>
</element>
<element>
<docNo>2222</docNo>
<item_no>002</item_no>
<text>
<text_line>PROFILE</text_line>
</text>
</element>
I am using distinct-values in but it is merging both with item_no 001 and 002.
Thanks

Answer 1

In XQuery 3 you would use the group by clause with two grouping keys:
/*/element { node-name(.) } {
for $e at $pos in element
group by $dn := $e/docNo, $in := $e/item_no
order by head($pos)
return
<element>
{
head($e) ! (docNo, item_no),
<text>
{
$e/text_line
}
</text>
}
</element>
}
In XQuery 1 you can use distinct-values on a key concatenated from the two elements:
/*/element { node-name(.) } {
for $key in distinct-values(for $e in element return concat($e/docNo, '|', $e/item_no))
let $group := element[concat(docNo, '|', item_no) = $key]
return
<element>
{
$group[1]/(docNo | item_no),
<text>
{
$group/text_line
}
</text>
}
</element>
}