I need only one unique result in Oracle sdo_nn Update sentence , - oracle11g

I need Only one unique result from tableB.Field to tableA.Field
I am using sdo operator sdo_nn, this is the code:
UPDATE table1 t1
SET t1.fieldA = (SELECT T2.fieldB,SDO_NN_DISTANCE(1) distance
FROM table1 T1, table2 T2
WHERE
(sdo_nn(t1.geometry,t2.geometry,'SDO_NUM_RES=1',1)= 'TRUE')
ORDER BY DIST
)
WHERE EXISTS(
SELECT 1
FROM table2 t2
WHERE sdo_nn(t1.geometry, t2.geometry,'SDO_NUM_RES=1',1)='TRUE'
AND(t2.cell_name = 'string1' or t2.cell_name = string2')AND t1.fieldA = NULL
);
In the select sentence of the subquery i get an error because i only use one field(t1.fieldA), but in the sentence i use the operator SDO_NN_DISTANCE(1) and the sql developer count this operator like another field. What is the correct way to write this sentence? I only use sql because i need to insert this code in vba
Thanks!!!

Obviously, you can't (simplified)
set t1.fieldA = (t2.fieldB, distance) --> you want to put two values into a single column
Therefore, get fieldB alone from the subquery which uses analytic function (row_number) to "sort" rows by sdo_nn_distance(1) desc; then get the first row's fieldB value.
Something like this (I hope I set the parenthesis right):
UPDATE table1 t1
SET t1.fieldA =
(SELECT x.fieldB --> only fieldB
FROM (SELECT T2.fieldB, --> from your subquery
SDO_NN_DISTANCE (1) distance,
ROW_NUMBER ()
OVER (ORDER BY sdo_nn_distance (1) DESC) rn
FROM table1 T1, table2 T2
WHERE (sdo_nn (t1.geometry,
t2.geometry,
'SDO_NUM_RES=1',
1) = 'TRUE')) x
WHERE rn = 1) --> where RN = 1
WHERE EXISTS
(SELECT 1
FROM table2 t2
WHERE sdo_nn (t1.geometry,
t2.geometry,
'SDO_NUM_RES=1',
1) = 'TRUE'
AND ( t2.cell_name = 'string1'
OR t2.cell_name = 'string2')
AND t1.fieldA IS NULL);

Related

PL SQL nested subquery

I'm trying to get the result into a variable (is it possible to do it as a %rowtype of an existing table? probably not because of conflicting columns) where it would display me all the values where the two refs overlap and the i_ref(which is inputted ) also overlaps with the ref from t1.
select *
into aRow
from table1 t1
where t1.ref = i_ref
and (select * from table2 t2 where t1.ref = t2.ref);
What am I doing wrong with my select?
You can join tables instead of nested subquery:
select t1.*
into aRow
from table1 t1 join table2 t2 on t1.ref = t2.ref
where t1.ref = i_ref

SELECT SUM of each row and the next row

Table three columns id, numers1 and numbers2. We need to summarize numers1 and numbers2 but the first row to the second row numers1 numers2 the second with the third and forth etc.:
CREATE TABLE tb1 (id INTEGER PRIMARY KEY AUTOINCREMENT,numbers1,numbers2);
INSERT INTO tb1 (numbers1,numbers2) values(1,10);
INSERT INTO tb1 (numbers1,numbers2) values(2,20);
INSERT INTO tb1 (numbers1,numbers2) values(3,30);
INSERT INTO tb1 (numbers1,numbers2) values(4,40);
INSERT INTO tb1 (numbers1,numbers2) values(5,50);
I want to get as:
21
32
43
54
with the reference of getting the correct row index per record here:
How to use ROW_NUMBER in sqlite
I was able to create the required result with the following query:
SELECT
num1 + coalesce(b_num2, 0)
FROM(
SELECT
num1,
(select count(*) from test as b where a.id >= b.id) as cnt
FROM test as a) as a
LEFT JOIN
(SELECT num2 as b_num2,
(select count(*) from test as b where a.id >= b.id) as cnt
FROM test as a
) as b
ON b.cnt = a.cnt + 1
Explanation:
by joining two same table of similar record index, then merge the next record with the current record and then sum num1 of current record with num2 of next record, I do not know how you want to deal with the last row as it does not have a next row so I assume it to add nothing to have a result of just the value of num1
Result:
For one row with a specific ID x, you can get values from the next row by searching for ID values larger than x, and taking the first such row:
SELECT ...
FROM tb1
WHERE id > x
ORDER BY id
LIMIT 1;
You can then use this as a correlated subquery to get that value for each row:
SELECT numbers1 + (SELECT T2.numbers2
FROM tb1 AS T2
WHERE T2.id > T1.id
ORDER BY T2.id
LIMIT 1) AS sum
FROM tb1 AS T1
WHERE sum IS NOT NULL; -- this omits the last row, where the subquery returns NULL

Choosing Single Row from multiple rows - Teradata

I have a requirement below to choose latest status.
Table 1:
Table2:
Results Expected:
Below is the logic we need.
SELECT
Table1.ID,
,CASE WHEN (Table1.hub=Table2.hub) THEN Table2.Status ELSE NULL END AS Original_Status
,CASE WHEN (Table1.hub<>Table2.hub AND Table2.Status like 'Found%' ) THEN Table2.hub ELSE NULL END AS Derived_Hub
,CASE WHEN (Table1.hub<>Table2.hub AND Table2.Status like 'Found%' ) THEN Table2.Status ELSE NULL END AS Derived_Status
from
Table1
Join Table2
ON (Table1.ID=Table2.ID)
With this code, I am getting 3 rows. If I put max in the above case statements, I am getting Hub3 instead of Hub2.
Could you please let me know how I can merge everything into single row. Please note that I want to show latest found Status from Table 2 even if there are 2 hubs with found status.
Let me know if you need any further information.
I think your best bet is to join into Table 2 twice. The first time, much like you are doing here, but using a LEFT OUTER JOIN on both id and hub. Then the second time on a derived version of table2 where you only select the top 1 records when sorted by timestamp in descending order:
SELECT
t1.id,
t1.hub as "Original Hub"
t2.status as "Original Hub Status",
t3.hub as "Found Hub",
t3.status as "Found Hub Status"
FROM
Table1 t1
LEFT OUTER JOIN Table2 t2 ON
t1.id = t2.id AND
t1.hub = t2.hub
LEFT OUTER JOIN
(
--Select a hub with the same id, that doesn't share the same hub number
--Only choose the top record when sorted by timestamp in descending order
SELECT TOP 1 id, hub, status
FROM table2
WHERE t1.hub <> table2.hub
ORDER BY TimeStamp Desc
) t3 ON
t1.id = t3.id
That subquery that has alias t3 is using a correlated subquery by referencing the t1.hub value in it's WHERE statement.
In TD14.10 you can utilize LAST_VALUE to access data from the "last" row. The CASEs are based on your query:
SELECT
t2.ID,
CASE WHEN t1.Hub = t2.Hub THEN t2.Hub END AS Original_Hub,
CASE WHEN t1.Hub = t2.Hub THEN t2.Status END AS Original_Status,
-- get the last Hub
LAST_VALUE(CASE WHEN t1.Hub <> t2.Hub AND Table2.Status like 'Found%'
THEN t2.Hub
END)
OVER (PARTITION BY t1.ID
ORDER BY CASE WHEN t1.Hub = t2.Hub THEN 0 ELSE 1 END, t2.TS
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) AS Derived_Hub,
-- get the last Status
LAST_VALUE(CASE WHEN t1.Hub <> t2.Hub AND Table2.Status like 'Found%'
THEN t2.Status
END)
OVER (PARTITION BY t1.ID
ORDER BY CASE WHEN t1.Hub = t2.Hub THEN 0 ELSE 1 END, t2.TS
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) AS Derived_Status
FROM
Table1 AS t1
JOIN Table2 AS t2
ON (t1.ID=t2.ID)
QUALIFY
ROW_NUMBER () -- return the 1st row only
OVER (PARTITION BY t1.ID
ORDER BY CASE WHEN t1.Hub = t2.Hub THEN 0 ELSE 1 END, t2.TS) = 1
EXPLAIN should combine all OVER into a single STATS-step as they use the same PARTITION BY and ORDER BY.

Query fails to execute after converting a column from Varchar2 to CLOB

I have a oracle query
select id from (
select ID, ROW_NUMBER() over (partition by LATEST_RECEIPT order by ID) rownumber
from Table
where LATEST_RECEIPT in
(
select LATEST_RECEIPT from Table
group by LATEST_RECEIPT
having COUNT(1) > 1
)
) t
where rownumber <> 1;
The data type of LATEST_RECEIPT was earlier varchar2(4000) and this query worked fine. Since the length of the column needs to be extended i modified it to CLOB, after which this fails. Could anyone help me fix this issue or provide a work around?
You can change your inner query to look for other rows with the same last_receipt value but a different ID (assuming ID is unique); if another row exists then that is equivalent to your count returning greater than one. But you can't simply test two CLOB values for equality, you need to use dbms_lob.compare:
select ID
from your_table t1
where exists (
select null from your_table t2
where dbms_lob.compare(t2.LATEST_RECEIPT, t1.LATEST_RECEIPT) = 0
and t2.ID != t1.ID
-- or if ID isn't unique: and t2.ROWID != t1.ROWID
);
Applying the row number filter is tricker, as you also can't use a CLOB in the analytic partition by clause. As André Schild suggested, you can use a hash; here passing the integer value 3, which is the equivalent of dbms_crypto.hash_sh1 (though in theory that could change in a future release!):
select id from (
select ID, ROW_NUMBER() over (partition by dbms_crypto.hash(LATEST_RECEIPT, 3)
order by ID) rownumber
from your_table t1
where exists (
select null from your_table t2
where dbms_lob.compare(t2.LATEST_RECEIPT, t1.LATEST_RECEIPT) = 0
and t2.ID != t1.ID
-- or if ID isn't unique: and t2.ROWID != t1.ROWID
)
)
where rownumber > 1;
It is of course possible to get a hash collision, and if that happened - you had two latest_receipt values which both appeared more than once and both hashed to the same value - then you could get too many rows back. That seems pretty unlikely, but it's something to consider.
So rather than ordering you can only look for rows which have the same lastest_receipt and a lower ID:
select ID
from your_table t1
where exists (
select null from your_table t2
where dbms_lob.compare(t2.LATEST_RECEIPT, t1.LATEST_RECEIPT) = 0
and t2.ID < t1.ID
);
Again that assumes ID is unique. If it isn't then you could still use rowid instead, but you would have less control over which rows were found - the lowest rowid isn't necessarily the lowest ID. Presumably you're using this to dine rows to delete. If you actually don't mind which row you keep and which you delete then you could still do:
and t2.ROWID < t1.ROWID
But since you are currently ordering that probably isn't acceptable, and hashing might be preferable, despite the small risk.

Update one column in table1 from value in table2

I am trying to update one column in table1 from a column in table2. Here
is what i am doing but i am getting an ORA error.
ORA-01427: single-row subquery returns more than one row.
update table1 a
set a.art_num = (
select b.art_num from table2 b
where a.comp_id = b.comp_id );
Thanks so much in advance!
This happens because your subquery returns more than one result.
You should check this one:
select b.art_num
from table2 b
where a.comp_id = b.comp_id
You could try to select DISTINCT (search for distinct in the link for documentation) on the subquery:
update table1 a
set a.art_num = (
select distinct(b.art_num)
from table2 b
where a.comp_id = b.comp_id );

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