paramiko operating network firewall meet some question,Any suggestions? [duplicate] - paramiko

I'm having a problem with a ShoreTel voice switch, and I'm trying to use Paramiko to jump into it and run a couple commands. What I believe the problem might be, is that the ShoreTel CLI gives different prompts than the standard Linux $. It would look like this:
server1$:stcli
Mitel>gotoshell
CLI> (This is where I need to enter 'hapi_debug=1')
Is Python still expecting that $, or am I missing something else?
I thought it might be a time thing, so I put those time.sleep(1) between commands. Still doesn't seem to be taking.
import paramiko
import time
keyfile = "****"
User = "***"
ip = "****"
command1 = "stcli"
command2 = "gotoshell"
command4 = "hapi_debug=1"
ssh = paramiko.SSHClient()
print('paramikoing...')
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(hostname = ip, username = User, key_filename = keyfile)
print('giving er a go...')
ssh.invoke_shell()
stdin, stdout, stderr = ssh.exec_command(command1)
time.sleep(1)
stdin, stdout, stderr = ssh.exec_command(command2)
time.sleep(1)
stdin, stdout, stderr = ssh.exec_command(command4)
time.sleep(1)
print(stdout.read())
ssh.close()
print("complete")
What I would expect from the successful execution of this code, would be for the hapi_debug level to be 1. Which means that when I SSH into the thing, I would see those HAPI debugs populating. When I do, I do not see those debugs.

I assume that the gotoshell and hapi_debug=1 are not top-level commands, but subcommands of the stcli. In other words, the stcli is kind of a shell.
In that case, you need to write the commands that you want to execute in the subshell to its stdin:
stdin, stdout, stderr = ssh.exec_command('stcli')
stdin.write('gotoshell\n')
stdin.write('hapi_debug=1\n')
stdin.flush()
If you call stdout.read afterwards, it will wait until the command stcli finishes. What it never does. If you wanted to keep reading the output, you need to send a command that terminates the subshell (typically exit\n).
stdin.write('exit\n')
stdin.flush()
print(stdout.read())

Related

About Asterisk VOIP

Helo guys ! Can we stop a dns server or starts the dhcp service by using the server asterisk ?? (When the user calls the server he'll receive a response of a part of the server "press button 1 to stop the dns service,2 to restart the server dns".
Sure, you can do that using system comand in dialplan. Or using AGI script.
Please note, asterisk's SIP protocol may not work while no DNS server(new calls).
System()
Execute a system (Linux shell) command Description
System(command) – System command alone System(command arg1 arg2 etc) – Pass in some arguments System(command|args) – Use the standard asterisk syntax to pass in arguments Technical Info
Executes a command by using system(). System() passes the string unaltered to system(3). Running “man 3 system” will show exactly what system(3) does:
system() executes a command specified in string by calling /bin/sh -c string, and returns after the command has been completed.
Therefore System(command arg1 arg2 etc) can be used to pass along arguments. Return codes
System(command): Executes a command by using system(). If the command fails, the console should report a fallthrough. If you need to return a specific value (string) to the dialplan then use either AGI or Asterisk func shell as introduced in Asterisk 1.6.0.
Result of execution is returned in the SYSTEMSTATUS channel variable:
FAILURE Could not execute the specified command SUCCESS Specified command successfully executed APPERROR Triggered for example when you try to delete a file but the file was not there. NOTE – not documented, but can also return APPERROR NOTE – I don’t seem to be able to create a situation when FAILURE will be returned.

paramiko and nohup ''

OK so I have paramiko v2.2.1 and I am trying to login to a machine and restart a service. Inside the service scripts it basically starts a process via nohup. However if I allow paramiko to disconnect as soon as it is done the process started terminates with a PIPE signal when it writes to stdout.
If I start the service by ssh'ing into the box and manually starting it there is no issue and it runs in the background fine. Also if I add long sleep 10 before disconnecting (close) paramiko it also seems to work just fine.
The service is started via a init.d script via a line like this:
env LD_LIBRARY_PATH=$bin_path nohup $bin_path/ServerLoop.sh \
"$bin_path/Service service args" "$#" &
Where ServerLoop.sh simply calls the service forever in a loop like this so it will never die:
SERVER=$1
shift
ARGS=$#
logger $ARGS
while [ 1 ]; do
$SERVER $ARGS
logger "$SERVER terminated with exit code: $STATUS. Server has been restarted"
sleep 1
done
I have noticed when I start the service by ssh'ing into the box I get a nohup.out file written to the root. However when I run through paramiko I get no nohup.out written anywhere on the system ... ie this after I manually ssh into the box and start the service:
root#ts4700:/mnt/mc.fw/bin# find / -name "nohup*"
/usr/bin/nohup
/usr/share/man/man1/nohup.1.gz
/nohup.out
And this is after I run through paramiko:
root#ts4700:/mnt/mc.fw/bin# find / -name "nohup*"
/usr/bin/nohup
/usr/share/man/man1/nohup.1.gz
As I understand it nohup will only redirect the output to nohup.out if "If standard output is a terminal" (from the manual), otherwise it thinks it is saving the output to a file so it does not redirect. Hence I tried the following:
In [43]: import paramiko
In [44]: paramiko.__version__
Out[44]: '2.2.1'
In [45]: ssh = paramiko.SSHClient()
In [46]: ssh.set_missing_host_key_policy(AutoAddPolicy())
In [47]: ssh.connect(ip, username='root', password=not_for_so_sorry, look_for_keys=False, allow_agent=False)
In [48]: stdin, stdout, stderr = ssh.exec_command("tty")
In [49]: stdout.read()
Out[49]: 'not a tty\n'
So I am thinking that nohup is not redirecting to nohup.out when I run it through paramiko because tty is not returning a terminal. I don't know why adding a sleep(10) would fix this though as the service if run on the command line is quite verbose.
I have also noticed that if the service is started from a manual ssh its tty in the ps ax output is still set to the ssh tty ... however if the process is started by paramiko its tty in the ps ax output is set to "?" .. since both processes are run through nohup I would have expected this to be the same.
If the problem is that nohup is indeed not redirecting the output to nohup.out because of the tty is there a way to force this to happen or a better way to run this sort of command via paramiko?
Thanks all, any help with this would be great :)

Script calling another script, stdout/stderr redirection

Problem
Have a multi_exec.pl that shall handle timed-out execution of command provided.
And we call this multi_exec.pl at various places in our legacy applciation.
Sample call :
$grab = `multi_exec.pl -1 'bcp_cmd-1' 'bcp_cmd-2' ... 'bcp_cmd-n'`
want to understand how to achieve the below using STDOUT[ERR] re-directions
capture bcp STDOUT[ERR] of individual BCP commands on the terminal
while need to capture failure messages on STDERR from multi_exec.pl
STDOUT of multi_exec.pl needs to go to /dev/null ( don't want to capture STDOUT
)
while need to capture failure messages on STDERR from multi_exec.pl
Nothing special needs to be done for this - STDERR of the parent script as well as the individual commands will go to the terminal by default
STDOUT of multi_exec.pl needs to go to /dev/null (don't want to capture STDOUT)
capture bcp STDOUT[ERR] of individual BCP commands on the terminal
These are conflicting requirements because STDOUT of the parent script as well as the individual bcp commands will end up on the terminal by default. There is no way to bifurcate just one of them to be sent to /dev/null. You could modify multi_exec.pl so that it writes its own output to a file, if specified. If no file is specified, it shouldn't write anything to stdout at all. So, it is ensured the STDOUT of multi_exec.pl is always from bcp commands.

How do I use the nohup command without getting nohup.out?

I have a problem with the nohup command.
When I run my job, I have a lot of data. The output nohup.out becomes too large and my process slows down. How can I run this command without getting nohup.out?
The nohup command only writes to nohup.out if the output would otherwise go to the terminal. If you have redirected the output of the command somewhere else - including /dev/null - that's where it goes instead.
nohup command >/dev/null 2>&1 # doesn't create nohup.out
Note that the >/dev/null 2>&1 sequence can be abbreviated to just >&/dev/null in most (but not all) shells.
If you're using nohup, that probably means you want to run the command in the background by putting another & on the end of the whole thing:
nohup command >/dev/null 2>&1 & # runs in background, still doesn't create nohup.out
On Linux, running a job with nohup automatically closes its input as well. On other systems, notably BSD and macOS, that is not the case, so when running in the background, you might want to close input manually. While closing input has no effect on the creation or not of nohup.out, it avoids another problem: if a background process tries to read anything from standard input, it will pause, waiting for you to bring it back to the foreground and type something. So the extra-safe version looks like this:
nohup command </dev/null >/dev/null 2>&1 & # completely detached from terminal
Note, however, that this does not prevent the command from accessing the terminal directly, nor does it remove it from your shell's process group. If you want to do the latter, and you are running bash, ksh, or zsh, you can do so by running disown with no argument as the next command. That will mean the background process is no longer associated with a shell "job" and will not have any signals forwarded to it from the shell. (A disowned process gets no signals forwarded to it automatically by its parent shell - but without nohup, it will still receive a HUP signal sent via other means, such as a manual kill command. A nohup'ed process ignores any and all HUP signals, no matter how they are sent.)
Explanation:
In Unixy systems, every source of input or target of output has a number associated with it called a "file descriptor", or "fd" for short. Every running program ("process") has its own set of these, and when a new process starts up it has three of them already open: "standard input", which is fd 0, is open for the process to read from, while "standard output" (fd 1) and "standard error" (fd 2) are open for it to write to. If you just run a command in a terminal window, then by default, anything you type goes to its standard input, while both its standard output and standard error get sent to that window.
But you can ask the shell to change where any or all of those file descriptors point before launching the command; that's what the redirection (<, <<, >, >>) and pipe (|) operators do.
The pipe is the simplest of these... command1 | command2 arranges for the standard output of command1 to feed directly into the standard input of command2. This is a very handy arrangement that has led to a particular design pattern in UNIX tools (and explains the existence of standard error, which allows a program to send messages to the user even though its output is going into the next program in the pipeline). But you can only pipe standard output to standard input; you can't send any other file descriptors to a pipe without some juggling.
The redirection operators are friendlier in that they let you specify which file descriptor to redirect. So 0<infile reads standard input from the file named infile, while 2>>logfile appends standard error to the end of the file named logfile. If you don't specify a number, then input redirection defaults to fd 0 (< is the same as 0<), while output redirection defaults to fd 1 (> is the same as 1>).
Also, you can combine file descriptors together: 2>&1 means "send standard error wherever standard output is going". That means that you get a single stream of output that includes both standard out and standard error intermixed with no way to separate them anymore, but it also means that you can include standard error in a pipe.
So the sequence >/dev/null 2>&1 means "send standard output to /dev/null" (which is a special device that just throws away whatever you write to it) "and then send standard error to wherever standard output is going" (which we just made sure was /dev/null). Basically, "throw away whatever this command writes to either file descriptor".
When nohup detects that neither its standard error nor output is attached to a terminal, it doesn't bother to create nohup.out, but assumes that the output is already redirected where the user wants it to go.
The /dev/null device works for input, too; if you run a command with </dev/null, then any attempt by that command to read from standard input will instantly encounter end-of-file. Note that the merge syntax won't have the same effect here; it only works to point a file descriptor to another one that's open in the same direction (input or output). The shell will let you do >/dev/null <&1, but that winds up creating a process with an input file descriptor open on an output stream, so instead of just hitting end-of-file, any read attempt will trigger a fatal "invalid file descriptor" error.
nohup some_command > /dev/null 2>&1&
That's all you need to do!
Have you tried redirecting all three I/O streams:
nohup ./yourprogram > foo.out 2> foo.err < /dev/null &
You might want to use the detach program. You use it like nohup but it doesn't produce an output log unless you tell it to. Here is the man page:
NAME
detach - run a command after detaching from the terminal
SYNOPSIS
detach [options] [--] command [args]
Forks a new process, detaches is from the terminal, and executes com‐
mand with the specified arguments.
OPTIONS
detach recognizes a couple of options, which are discussed below. The
special option -- is used to signal that the rest of the arguments are
the command and args to be passed to it.
-e file
Connect file to the standard error of the command.
-f Run in the foreground (do not fork).
-i file
Connect file to the standard input of the command.
-o file
Connect file to the standard output of the command.
-p file
Write the pid of the detached process to file.
EXAMPLE
detach xterm
Start an xterm that will not be closed when the current shell exits.
AUTHOR
detach was written by Robbert Haarman. See http://inglorion.net/ for
contact information.
Note I have no affiliation with the author of the program. I'm only a satisfied user of the program.
Following command will let you run something in the background without getting nohup.out:
nohup command |tee &
In this way, you will be able to get console output while running script on the remote server:
sudo bash -c "nohup /opt/viptel/viptel_bin/log.sh $* &> /dev/null" &
Redirecting the output of sudo causes sudo to reask for the password, thus an awkward mechanism is needed to do this variant.
If you have a BASH shell on your mac/linux in-front of you, you try out the below steps to understand the redirection practically :
Create a 2 line script called zz.sh
#!/bin/bash
echo "Hello. This is a proper command"
junk_errorcommand
The echo command's output goes into STDOUT filestream (file descriptor 1).
The error command's output goes into STDERR filestream (file descriptor 2)
Currently, simply executing the script sends both STDOUT and STDERR to the screen.
./zz.sh
Now start with the standard redirection :
zz.sh > zfile.txt
In the above, "echo" (STDOUT) goes into the zfile.txt. Whereas "error" (STDERR) is displayed on the screen.
The above is the same as :
zz.sh 1> zfile.txt
Now you can try the opposite, and redirect "error" STDERR into the file. The STDOUT from "echo" command goes to the screen.
zz.sh 2> zfile.txt
Combining the above two, you get:
zz.sh 1> zfile.txt 2>&1
Explanation:
FIRST, send STDOUT 1 to zfile.txt
THEN, send STDERR 2 to STDOUT 1 itself (by using &1 pointer).
Therefore, both 1 and 2 goes into the same file (zfile.txt)
Eventually, you can pack the whole thing inside nohup command & to run it in the background:
nohup zz.sh 1> zfile.txt 2>&1&
You can run the below command.
nohup <your command> & > <outputfile> 2>&1 &
e.g.
I have a nohup command inside script
./Runjob.sh > sparkConcuurent.out 2>&1

How can I keep running a unix program in the background even if I log out?

I want to run a Perl script with some while(1) loop in the background on a unix machine until I kill it.
This is a remote computer to which I don't have administrative permissions (so for some reason, I can't use Daemon::Generic::While1), I log to it through SSH, and I want it to continue to run after I log out.
One way I found out is write something like this to bash:
nohup ./my_script.pl &
Is there some other, more preferable way to do it?
Editing the crontab is forbidden on that computer (while running background and long-lasting processes isn't).
My preferred method, and arguably the easiest, is using screen:
screen -d -m ./myProcess
You need to close stdout, stderr, stdin, otherwise you are still bound to that specific TTY
./my_script.pl >/dev/null 2>&1 </dev/null &
This should do the trick.
I believe this should work from within your perl script.
$SIG{ HUP } = 'IGNORE';
Note the man page doc for nohup says:
To do this, nohup sets the SIGHUP
signal(3) (``terminal line hangup'')
to be ignored, then executes utility
along with any arguments.
Snippet is in perldoc perlipc:
use POSIX 'setsid';
sub daemonize {
chdir '/' or die "Can't chdir to /: $!";
open STDIN, '/dev/null' or die "Can't read /dev/null: $!";
open STDOUT, '>/dev/null'
or die "Can't write to /dev/null: $!";
defined(my $pid = fork) or die "Can't fork: $!";
exit if $pid;
setsid or die "Can't start a new session: $!";
open STDERR, '>&STDOUT' or die "Can't dup stdout: $!";
}
But I'm not sure whether setsid will work if you're not root. If not, try to double-fork after closing standard handles.
some links: howto, daemonize
use Proc::Daemon;
Proc::Daemon::Init;
That's what I use for my Sendmail filter program and probably the easiest way to go. The module is available via CPAN.
Running the job in the background from the shell is fine, depending on how much manual labor you wish to put into making sure it's running continuously.
I would use crontab's #reboot (and possibly a regular checkup as well). But then you need to take into consideration that the process might be started multiple times. Simplest way to handle that is having a lock-file. If the file is locked, exit, else continue to the task. Remember to use non-blocking checks, else you risk hogging unnecessary system resources with dead processes.
screen is also an option if it's available.
crontab + screen can be combined.

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