Rewriting curl http request using Groovy - http

Question

Here is my test HTTP request I need to rewrite to use in groovy:
curl 'https://api-dev.test.ru/uaa/oauth/token' -H 'Authorization: Basic 1234567=' -H 'Content-Type: application/x-www-form- urlencoded' -H 'Accept: application/json, text/plain, */*' --data 'grant_type=password' --data-urlencode 'username=theLogin' --data-urlencode 'password=thePassword'
Here is the way I've rewritten it:
def httpRequest = [path : 'https://api-dev.test.ru/uaa/oauth/token',
headers : ['Authorization: Basic 1234567='
'Content-Type': 'application/x-www-form-urlencoded',
'Accept' : 'application/json, text/plain, */*'],
data : ['grant_type=password'],
data_urlencode: ['username=theLogin',
'password=thePassword']
]
It seems to be not correctly, because the test app doesn't work with the request. Have I rewritten the request correctly. If I haven't, where is my mistake?

Answer 1

You should be using Http Builder. Your code would look like:
def result = HttpBuilder,configure {
request.uri = 'https://api-dev.test.ru/uaa/oauth/token'
request.contentType = 'application/x-www-form-urlencoded'
request.headers.Accept = 'application/json, text/plain, */*'
}.post {
request.auth.basic 'admin', 'myp#$$w0rd'
request.uri.query = [ grant_type:'password' ]
request.body = [username:'theLogin', password:'thePassword']
}