view of the return value in spyder - console

related to this question:
"Return" does not return anything in Spyder. It works fine with other IDE
def test():
return 2
test()
is it possible to see the value of "2" somewhere without the print-statement? Like in the Variable explorer or in the console 1/A?
I think I miss a setting or check in a checkbox?
I use Spyder 4.0.1 and Python 3.7

(Spyder maintainer here) You need to enclose you last statement (i.e. test()) in a print to see its return value printed in the console:
print(test())
Or you can assign test() to a variable to see its result in the Variable Explorer:
a = test()

Related

Julia print statement not working in certain cases

I've written a prime-generating function generatePrimes (full code here) that takes input bound::Int64 and returns a Vector{Int64} of all primes up to bound. After the function definition, I have the following code:
println("Generating primes...")
println("Last prime: ", generatePrimes(10^7)[end])
println("Primes generated.")
which prints, unexpectedly,
Generating primes...
9999991
Primes generated.
This output misses the "Last prime: " segment of the second print statement. The output does work as expected for smaller inputs; any input at least up to 10^6, but somehow fails for 10^7. I've tried several workarounds for this (e.g. assigning the returned value or converting it to a string before calling it in a print statement, combining the print statements, et cetera) and discovered some other weird behaviour: if the "Last prime", is removed from the second print statement, for input 10^7, the last prime doesn't print at all and all I get is a blank line between the first and third print statements. These issues are probably related, and I can't seem to find anything online about why some print statements wouldn't work in Julia.
Thanks so much for any clarification!
Edit: Per DNF's suggestion, following are some reductions to this issue:
Removing the first and last print statements doesn't change anything -- a blank line is always printed in the case I outlined and each of the cases below.
println(generatePrimes(10^7)[end]) # output: empty line
Calling the function and storing the last index in a variable before calling println doesn't change anything either; the cases below work exactly the same either way.
lastPrime::Int = generatePrimes(10^7)[end]
println(lastPrime) # output: empty line
If I call the function in whatever form immediately before a println, an empty line is printed regardless of what's inside the println.
lastPrime::Int = generatePrimes(10^7)[end]
println("This doesn't print") # output: empty line
println("This does print") # output: This does print
If I call the function (or print the pre-generated-and-stored function result) inside a println, anything before the function call (that's also inside the println) isn't printed. The 9999991 and anything else there may be after the function call is printed only if there is something else inside the println before the function call.
# Example 1
println(generatePrimes(10^7)[end]) # output: empty line
# Example 2
println("This first part doesn't print", generatePrimes(10^7)[end]) # output: 9999991
# Example 3
println("This first part doesn't print", generatePrimes(10^7)[end], " prints") # output: 9999991 prints
# Example 4
println(generatePrimes(10^7)[end], "prime doesn't print") # output: prime doesn't print
I could probably list twenty different variations of this same thing, but that probably wouldn't make things any clearer. In every single case version of this issue I've seen so far, the issue only manifests if there's that function call somewhere; println prints large integers just fine. That said, please let me know if anyone feels like they need more info. Thanks so much!
Most likely you are running this code from Atom Juno which recently has some issues with buffering standard output (already reported by others and I also sometimes have this problem).
One thing you can try to do is to flush your standard output
flush(stdout)
Like with any unstable bug restarting Atom Juno also seems to help.
I had the same issue. For me, changing the terminal renderer (File -> Settings -> Packages -> julia-client -> Terminal Options) from webgl to canvas (see pic below) seems to solve the issue.
change terminal renderer
I've also encountered this problem many times. (First time, it was triggered after using the debugger. It is probably unrelated but I have been using Julia+Juno for 2 weeks prior to this issue.)
In my case, the code before the println statement needed to have multiple dictionary assignation (with new keys) in order to trigger the behavior.
I also confirmed that the same code ran in Command Prompt (with same Julia interpreter) prints fine. Any hints about how to further investigate this will be appreciated.
I temporarily solve this issue by printing to stderr, thinking that this stream has more stringent flush mechanism: println(stderr, "hello!")

Zsh function does not terminate when ${name:?word} fails

(Question already posted on Unix Forum, but didn't get any response)
I have in my .zshrc the following function definition (simplified example):
function foo {
local p=${1:?parameter missing}
echo continue ....
}
Running the function by just typing foo produces, as expected, the message parameter missing, but it also outputs continue. I had expected that the function terminates when the :? check fails, but it continues to run. Why is this the case?
The man-page zshexpn says about :?:
... otherwise, print word and exit from the shell. Interactive shells instead return to the prompt.
I found that the behaviour I am experiencing depends on the presence or absence of the local specifier. If I remove local, the function works as expected, i.e. returns from the function immediately, if no parameter is passed.
Since I need local in my application, I rewrote the function like this:
function foo {
: ${1:?parameter missing}
local p=$1
echo continue ....
}
This works fine, but I still am curious to know, why the presence of local in combination with a :? causes this difference in behaviour.
UPDATE : I posted the issue also on the Zsh mailing list, and the zsh developers confirmed that this is a bug in Zsh.

How to quit/exit from file included in the terminal

What can I do within a file "example.jl" to exit/return from a call to include() in the command line
julia> include("example.jl")
without existing julia itself. quit() will just terminate julia itself.
Edit: For me this would be useful while interactively developing code, for example to include a test file and return from the execution to the julia prompt when a certain condition is met or do only compile the tests I am currently working on without reorganizing the code to much.
I'm not quite sure what you're looking to do, but it sounds like you might be better off writing your code as a function, and use a return to exit. You could even call the function in the include.
Kristoffer will not love it, but
stop(text="Stop.") = throw(StopException(text))
struct StopException{T}
S::T
end
function Base.showerror(io::IO, ex::StopException, bt; backtrace=true)
Base.with_output_color(get(io, :color, false) ? :green : :nothing, io) do io
showerror(io, ex.S)
end
end
will give a nice, less alarming message than just throwing an error.
julia> stop("Stopped. Reason: Converged.")
ERROR: "Stopped. Reason: Converged."
Source: https://discourse.julialang.org/t/a-julia-equivalent-to-rs-stop/36568/12
You have a latent need for a debugging workflow in Julia. If you use Revise.jl and Rebugger.jl you can do exactly what you are asking for.
You can put in a breakpoint and step into code that is in an included file.
If you include a file from the julia prompt that you want tracked by Revise.jl, you need to use includet(.
The keyboard shortcuts in Rebugger let you iterate and inspect variables and modify code and rerun it from within an included file with real values.
Revise lets you reload functions and modules without needing to restart a julia session to pick up the changes.
https://timholy.github.io/Rebugger.jl/stable/
https://timholy.github.io/Revise.jl/stable/
The combination is very powerful and is described deeply by Tim Holy.
https://www.youtube.com/watch?v=SU0SmQnnGys
https://youtu.be/KuM0AGaN09s?t=515
Note that there are some limitations with Revise, such as it doesn't reset global variables, so if you are using some global count or something, it won't reset it for the next run through or when you go back into it. Also it isn't great with runtests.jl and the Test package. So as you develop with Revise, when you are done, you move it into your runtests.jl.
Also the Juno IDE (Atom + uber-juno package) has good support for code inspection and running line by line and the debugging has gotten some good support lately. I've used Rebugger from the julia prompt more than from the Juno IDE.
Hope that helps.
#DanielArndt is right.
It's just create a dummy function in your include file and put all the code inside (except other functions and variable declaration part that will be place before). So you can use return where you wish. The variables that only are used in the local context can stay inside dummy function. Then it's just call the new function in the end.
Suppose that the previous code is:
function func1(...)
....
end
function func2(...)
....
end
var1 = valor1
var2 = valor2
localVar = valor3
1st code part
# I want exit here!
2nd code part
Your code will look like this:
var1 = valor1
var2 = valor2
function func1(...)
....
end
function func2(...)
....
end
function dummy()
localVar = valor3
1st code part
return # it's the last running line!
2nd code part
end
dummy()
Other possibility is placing the top variables inside a function with a global prefix.
function dummy()
global var1 = valor1
global var2 = valor2
...
end
That global variables can be used inside auxiliary function (static scope) and outside in the REPL
Another variant only declares the variables and its posterior use is free
function dummy()
global var1, var2
...
end

How to get the value of system()?

How do I get the current value of system() in premake5?
(and more generally functions like architecture() or platform())
I tried to print it, but it's a function, and when I try to print the return value of system(), I get "bad argument #1 to 'tostring' (value expected)".
Premake doesn't work that way, there is no "current" version of the data. You have to specify the context in which you'd like the current set of filters to be applied; take a look at src/base/oven.lua to see how the final data sets are built.
If you just want to drop the value of system (or architecture or platform) into an expression later in the process (and you're using Premake 5), check out tokens:
targetdir "bin/%{cfg.system}/%{cfg.architecture}"
Tokens can also evaluate arbitrary Lua expressions.
my_system_map = { -- must be global, so token evaluator can find it
windows = "Win32",
linux = "Posix",
macosx = "Mac"
}
targetdir "bin/%{my_system_map[cfg.system]}"
Helpful?

using an exists statement in R

I have made a progress bar using the winProgressBar method in R. What I want to do is if someone instantiates my program while it is doing all of its processing, I want the current progress bar to close. I tried using a statement that says
if(exists(progressBar)) {
close(progressBar);
}
but I get an error from the console that says
Error in exists(progressBar) : object 'progressBar' not found
I know that it will not exist during the first iteration of my program, but there is no reason that I can find that would make an if statement cause the program to crash.
If you read the help for exists you will see the following under Arguments
x a variable name (given as a character string).
So
exists('progressBar')
will return TRUE or FALSE.

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