running two LEDs with two buttons - arduino

Question

I am new to Arduino programing. I am trying to get two buttons to light two LEDs like so. press button1 turn on light 1 turn off light 2, button2 turn on light 1 and 2. like indicators for speed selection.
this is the code I have so far.
const int BUTTON1 = 2;
const int BUTTON2 = 3;
const int LED1 = 9;
const int LED2 = 10;
int BUTTONstate1 = 0;
int BUTTONstate2 = 0;
void setup()
{
pinMode(BUTTON1, INPUT);
pinMode(BUTTON2, INPUT);
pinMode(LED1, OUTPUT);
pinMode(LED2, OUTPUT);
}
void loop(1)
{
BUTTONstate1 = digitalRead(BUTTON1);
if (BUTTONstate1 == HIGH);
digitalWrite(LED1, HIGH);
digitalwrite(LED2, low);
}
void loop(2)
{
BUTTONstate2 = digitalRead(BUTTON2);
if (BUTTONstate2 == HIGH)
digitalWrite(LED1, HIGH);
digitalwrite(led2, HIGH);
}
when i run the code I get ERROR 19:10 error: variable or field 'loop' declared void. it is the line after void loop(1) and void loop(2).

Answer 1

void loop(1) and void loop(2) don't make sense.
You only implement void loop() and handle both buttons in that function.
Arduino will call loop() in an infinite loop over and over. Having two loop functions doesn't make sense and causes compiler errors.
If you want to have that functionality in two different functiosn implement them using different names and call both of them inside loop()

Answer 2

I've never seen someone uses two void loops at one time. You have to use only one void loop(). Here is an example:
void loop() {
BUTTONstate1 = digitalRead(BUTTON1);
BUTTONstate2 = digitalRead(BUTTON2);
if (BUTTONstate1 == HIGH) {
digitalWrite(LED1, HIGH);
digitalwrite(LED2, LOW);
}
if (BUTTONstate2 == HIGH) {
digitalWrite(LED1, HIGH);
digitalwrite(LED2, HIGH);
}
}
You also make another error here. Don't ever print ; after if()