Drupal 8 - Get All Nodes With a Part of Url Alias - drupal

Question

I try to find a way to get all nodes by a part of the url alias in the nodes. I know i get a specific node by the complete url alias. For example:
$path = \Drupal::service('path.alias_manager')->getPathByAlias('/this-is-the-alias');
if(preg_match('/node\/(\d+)/', $path, $matches)) {
$node = \Drupal\node\Entity\Node::load($matches[1]);
}
And I know I can find multiple nodes by entity query:
$nids = \Drupal::entityQuery('node')
->condition('type','page')
->condition('status',1)
->sort('created', 'DESC')
->range(0, 20)
->execute();
But I want to know how I can implement an additional condition to filter nodes by a part of the URL alias for example "/news/*". I need all nodes with this url fragment.

Answer 1

Can try this-
Reference https://www.jonkamke.com/blog/2019/5/load-a-node-via-url-alias
<?php
/** #var Drupal\Core\Url $url */
$url = $variables['url'];
if ($url instanceof Drupal\Core\Url) {
$nid = $url->getRouteParameters()['node'];
/** #var \Drupal\node\Entity\Node $node */
$node = Node::load($nid);
if ($node instanceof Node) {
$type = $node->getType();
}
}

Answer 2

$input = '/this-is-the-alias';
$node_query_result = [];
$path_query = \Drupal::database()->select('path_alias', 'a');
$path_query->addField('a', 'path');
$path_query->condition('a.alias', '%' . $input . '%', 'LIKE');
$path_query_result = str_replace('/node/', '', $path_query->execute()->fetchCol());
if ($path_query_result) {
$node_query = \Drupal::database()->select('node_field_data', 'n');
$node_query->addField('n', 'nid');
$node_query->addField('n', 'type');
$node_query->addField('n', 'title');
$node_query->condition('n.status', NodeInterface::PUBLISHED);
$node_query->condition('nid', $path_query_result, 'IN');
$node_query_result = $node_query->execute()->fetchAll(\PDO::FETCH_ASSOC);
}
return $node_query_result;