How to get parameters in POST request - http

Question

I am trying to get the parameters made in a POST request, but I am not able to make it, my code is:
package main
import (
"fmt"
"log"
"net/http"
)
func main() {
http.HandleFunc("/", hello)
fmt.Printf("Starting server for testing HTTP POST...\n")
if err := http.ListenAndServe(":8080", nil); err != nil {
log.Fatal(err)
}
}
func hello(w http.ResponseWriter, r *http.Request) {
if r.URL.Path != "/" {
http.Error(w, "404 not found.", http.StatusNotFound)
return
}
switch r.Method {
case "POST":
// Call ParseForm() to parse the raw query and update r.PostForm and r.Form.
if err := r.ParseForm(); err != nil {
fmt.Fprintf(w, "ParseForm() err: %v", err)
return
}
name := r.Form.Get("name")
age := r.Form.Get("age")
fmt.Print("This have been received:")
fmt.Print("name: ", name)
fmt.Print("age: ", age)
default:
fmt.Fprintf(w, "Sorry, only POST methods are supported.")
}
}
I am making the POST request in the terminal as follows:
curl -X POST -d '{"name":"Alex","age":"50"}' localhost:8080
And then the output is:
This have been received:name: age:
Why it is not taking the parameters? What I am doing wrong?

Answer 1

As you pass your body as a json object, you better define a Go struct matching that object and decode the request body to the object.
type Info struct {
Name string
Age int
}
info := &Info{}
if err := json.NewDecoder(r.Body).Decode(info); err != nil {
http.Error(w, err.Error(), http.StatusInternalServerError)
return
}
_ = json.NewEncoder(w).Encode(info)
You can find the whole working code here.
$ curl -X POST -d '{"name":"Alex","age":50}' localhost:8080
This POST request is working fine now.
You could modify the Go struct and also the response object as you like .