Serial Print once only - arduino

Question

I am a ON/OFF program in which if I turn On it will serial print to serial monitor 1 "ON" only but still looping and turn On the outputs and if turn Off it will serial print 1 "OFF" only but still looping and turn Off the outputs .
Here's my code:
int pbuttonPin = 7;// push button
int fan = 8;
int water = 9;
int val = 0; // push value from pin 2
int lightON = 0;//light status
int pushed = 0;//push status
void setup() {
Serial.begin(9600);
pinMode(pbuttonPin, INPUT_PULLUP);
pinMode(fan, OUTPUT);
pinMode(water, OUTPUT);
digitalWrite(fan, HIGH);
digitalWrite(water, HIGH);
}
void loop() {
val = digitalRead(pbuttonPin);// read the push button value
if(val == HIGH && lightON == LOW){
pushed = 1-pushed;
delay(100);
}
lightON = val;
if(pushed == LOW){
Serial.print("ON\n");
Serial.println();
digitalWrite(fan, LOW);
digitalWrite(water, LOW);
delay(100);
}
else if(pushed == HIGH) {
Serial.print("OFF\n");
Serial.println();
digitalWrite(fan, HIGH);
digitalWrite(water, HIGH);
delay(100);
}
}

Answer 1

I guess you want something like this but i am not sure
bool buttonState = false, buttonStateBefore = false;
buttonState = !digitalRead(buttonPin); //needs to be inverted because INPUT_PULLUP
if(buttonState > buttonStateBefore) doStuff(); //Serial print and turn on/off ligths
buttonStateBefore = buttonState;
Now doStuff() is only called once when the button is pressed.
Maybe this works for you

Answer 2

Add this at last of the code Sting previousval = val at the end of the code and put a if statement which checks if the previous value has changed or not. If it is, then run the code and put this part which contains the print statement in it . basically this will be your code
if ( previousval =! val){
if(pushed == LOW){
Serial.print("ON\n");
Serial.println();
digitalWrite(fan, LOW);
digitalWrite(water, LOW);
delay(100);
}
else if(pushed == HIGH) {
Serial.print("OFF\n");
Serial.println();
digitalWrite(fan, HIGH);
digitalWrite(water, HIGH);
delay(100);
previousval = val
}
}