python re data structure - r

Question

The dataset file in assets/grades.txt contains a line separated list of people with their grade in a class. Create a regex to generate a list of just those students who received a B in the course.
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
for line in grades:
line = line.rstrip()
if re.search('^X\S*: [0-9.]+', line):
print(line)
assert len(grades()) == 16
The easy solution is to add the following regular expression '([A-Z][a-z]+ [A-Z][a-z]+): B'.
this solution is provided from abd-elrhman-mohey

Answer 1

I can see where you did go wrong my friend
first of all
grades it's the lines u don't need the for loop to get them
second of all, I don't know why did u use '^X\S*: [0-9.]+' as it seems out of what u want
you need to see if the grades ar numbers or normal grades (A B C D)
and appears from the question that u need to get B
so we can say the final code will be
for the find
'([A-Z][a-z]+ [A-Z][a-z]+): B'
and final code I guess will be
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
w = '([A-Z][a-z]+ [A-Z][a-z]+): B'
grades = re.findall(w , grades)
return grades

Answer 2

import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
list_of_grades = grades.split('\n')
print(list_of_grades)
list_of_students = [ li.split()[0] + ' ' + li.split()[1] for li in list_of_grades if li.split()[-1] == 'B']
print(list_of_students)
return list_of_students

Answer 3

this works for me well as a piece of cake
import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
# YOUR CODE HERE
result = re.findall(': B', grades)
return result
grades()
len(grades())

Answer 4

This has worked well for me
import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
# YOUR CODE HERE
pattern=re.findall('([A-Za-z]+ [A-Za-z]+): B',grades)
return pattern
#raise NotImplementedError()
You can check by running the following code
assert len(grades()) == 16
To learn more about regex, visit: https://docs.python.org/3/library/re.html#module-re

Answer 5

This is what I did
import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
# YOUR CODE HERE
result = re.findall('\w* \w*: B',grades )
return result
print(grades())

Answer 6

#Here is my code:
` import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
a=re.findall("([\w ]*)(?=\:\sB)",grades)
return a
# YOUR CODE HERE
raise NotImplementedError()
#the output looks like a this:
#['Bell Kassulke',
'',
'Simon Loidl',
'',
'Elias Jovanovic',
'',
'Hakim Botros',
'',
'Emilie Lorentsen',#
i want the output to return only names and not the spaces.

Answer 7

def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
pattern=re.findall("[\w ]*)(\:\ B)",grades)
return pattern
grades()

Answer 8

import re
def grades():
with open ("assets/grades.txt", "r") as file:
grades = file.read()
only_B_grades = re.findall("[A-Z][a-z]* [A-Z][a-z]*\: [B]",grades)
person = [grade_B.split(':')[0] for grade_B in only_B_grades]
return person
raise NotImplementedError()
grades()