Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 2 years ago.
Improve this question
I am trying to use the air dataset from the dummies package.
I tried:
library(dummies)
dumair<-air[c(5:18)]
but that throws the following error:
Error in `[.data.frame`(air, c(5:18)) : undefined columns selected
How can I overcome this?
You need to specify which columns you want to select. When selecting rows and columns from a dataframe, you need to specify them like this:
df[rows, columns]
If you need all columns, leave the "columns" field empty. Same if you want all rows but only some columns!
I believe you want to select all columns, but only the rows from 5 to 18, right?
So doing:
dumair <- air[c(5:18), ]
Should work!
Related
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 1 year ago.
Improve this question
I need help how to compare 2 columns in r studio but only in the first 5 observations
code used first was
damgeByage<-table(test$Vehicle_Age,test$Vehicle_Damage)
damgeByage
which give me all 186 observation but only want the first 10 oobservation of both columns
I
We can subset the data with row index
table(test[1:10, c("Vehicle_Age", "Vehicle_Damage")])
akrun's answer works or you can also use:
table(test$Vehicle_Age[1:10],test$Vehicle_Damage[1:10])
the table is also subsettable if you just wanted the first 10 rows of the results:
damgeByage<-table(test$Vehicle_Age,test$Vehicle_Damage)
damgeByage[1:10,]
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 4 years ago.
Improve this question
When I use correlation function in RstudioThis I get below error message:
The dataset that I have imported is show below and V1,V2 are given by default to the columns:
There are two ways:
1) Attaching the data:
attach(data1)
And then this code should work:
cor(V1, V2)
2) Using $ for accesing columns in a dataframe
cor(data1$V1, data1$V2)
So, if I got you correctly, you want to find correlation between variables V1 and V2 in the dataframe data1. To refer to the column in the dataframe a $ sign is used. Then your code will look like:
cor(data1$V1,data1$V2)
or, if you want, you can also use with() function, which would narrow down the namespace to particular dataframe data1:
with(data1, cor(V1, V2))
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 5 years ago.
Improve this question
I need to replace number values with something that makes more sense to the reader.
Value “-0.95197” represents “18-24” age group in the given table.
What would be the best way to go about this for all columns?
Your question is a little unclear. Are you trying to rename the header of each column in a data.frame? If so, try this, where df is the name of your data.frame. You need one piece of text for each column.
names(df) <- c("your", "header", "names", "go", "here")
If this is not what you want, then you need to provide more info.
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 5 years ago.
Improve this question
I am trying to convert factors from a data-frame to numeric using the commands
data[] <- lapply (data, function(x) as.numeric(as.character(x))
But it keeps asking me for more coding. What am I doing wrong?
The data-frame is named data and it consists of 50 rows and 2 columns. Will this command change every variable in numeric right? Or shall I do something else?
screenshot after using 'dput' at http://imgur.com/Sde9QSk.png
Shouldn't you add ) at the end of your code?
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 8 years ago.
Improve this question
I have a data frame that has some empty entries. I set the
options(stringsAsFactors = FALSE)
so that I can change the empty cells. I then wrote the following code:
apply(my_data[,6:65],2, function(x) x[which(x=='')]<-0)
, hoping that it replaces all the empty cells with zeros. But it isn't working!
Note that my_data has 65 columns and columns 1:5 contain string.
Thanks in advance
No need to use apply, just use [<- with logical indexing
my_data[my_data==""] <- 0