I'm trying to pull some financial earning data from marketwatch website.
No matter how i try i can't seem to do a cell referencing(say cell B2) for this formula.
Desperately need some help, thank you very much!!
=IMPORTHTML("https://www.marketwatch.com/investing/stock/AIG/financials","table",1)
it will need to look like this (note the double quote placement):
=IMPORTHTML("https://www.marketwatch.com/investing/stock/quote.ashx?t="&B3, "table", 1)
Related
I want to calculate diversity indices of different sampling sites in R. I have sites in the first row and the different species in the first column. However, R is reading the first column as normal data (not as a header so to speak).
Pics:
https://imgur.com/a/iBsFtbe
Code:
>Macro<-read.csv("C:\\Users\\Carly\\OneDrive\\Desktop\\Ecology >Projects\\Macroinvertebrates & Water >Quality\\Macro_RData\\Macroinvert\\MacroR\\MacroCSV.csv", header = T)
You need to add row.names = 1 to your command. This will indicate that row names are stored in column number 1.
Macro <- read.csv("<...>/MacroCSV.csv", header = TRUE, row.names = 1)
I sense that you are frustrated. As r2evans said, it is easier for people to help you if you provide them with the data in text form and not with screenshots - because we can't recreate the problem or try to solve it by loading a screenshot into R.
CSV files are just text, so you can open them with a text editor such as NotePad and copy and paste it here. You don't need the whole text - the columns and lines needed to reproduce the problem are enough. This was what we were looking for:
Site,Aeshnidae,Amnicolidae,Ancylidae,Asellidae
AN0119A,0,0,0,6,0
AN0143,0,0,0,0,0
Programming for many people is very frustrating when they start out, don't let this discourage you!
It looks like your data is in the wrong orientation for analysis in vegan - your species are the rows, and sites are columns. From your pics, it looks like you've spotted this issue and tried transposing, but are having issues with the placement of the headers.
Try reading your csv in, and specifying that the first column should be row names:
MacroDataDataFinal <- read.csv("Path/to/file.csv",
row.names=1)
Then transpose the data
MacroDataDataFinal_transposed <- t(MacroDataDataFinal)
Then try running the specaccum function:
library(vegan)
speccurve <- specaccum(comm=MacroDataDataFinal_transposed,
method="random",
permutation=1000)
Hopefully this will work. If you get any errors please let us know the code you typed, and the precise error message.
I have salary data table from 10 years period. Every column has properly set data type (date for "B", number for "C" and "E".
I'm trying to write a formula to calculate average salary for every year. In column "E" I've manually entered all possible years and in column "F" should be an yearly average, according to year from "E".
So, my best try is this formula: =AVERAGEIF(YEAR(B2:B133);"="&E2;C2:C133)
Trying so calculate an average from column C, where year in date from column B equals a year in column E
But all I get is an error Err:504. Figured out, that problem is in YEAR(interval) part, but can't get what exactly...
Can someone point that out?
Thank you!
There are actually many possibilities to solve this.
#JvdV answer;
using an array formula with #JvdV solution;
using an array formula with a combination of AVERAGE() and IF();
using the SUMPRODUCT() function;
and surely many other solutions that I don't know about!
Please beware: I use , instead of ; as formula separator, according to my locale; adapt to your needs.
A side note on "array formulas"
This kind of formulas are applied by mandatory pressing the Ctrl + Shift + Enter key combination to insert them, not only Enter or Tab or mouse-clicking elsewhere on the sheet.
The resulting formula is shown between brackets {}, which are not inserted by the user but are automatically shown by the software to inform that this is actually an array formula.
More on array formulas i.e. on the LibreOffice help system.
Usually you cannot drag and drop array formulas, you have to copy-paste them instead.
Array formula with #JvdV solution
The solution of JvdV could be slighly modified like this, and then inserted as an array formula:
=AVERAGEIFS(C$2:C$133,YEAR($B$2:$B$133),"="&E2)
When you insert this formula with the Ctrl + Shift + Enter key combination, the software puts the formula into brackets, so that you see it like this: {=AVERAGEIFS(C$2:C$133,YEAR($B$2:$B$133),"="&E2)}
You cannot simply drag the formula down, but you can copy-paste it.
Array formula with a combination of AVERAGE() and IF():
For your example, put this formula in cell F2 (for the year 2010):
=AVERAGE(IF(YEAR($B$2:$B$133)=E2,$C$2:$C$133))
When you insert this formula with the Ctrl + Shift + Enter key combination, the software puts the formula into brackets, so that you see it like this {=AVERAGE(IF(YEAR($B$2:$B$133)=E2,$C$2:$C$133))}
You cannot simply drag the formula down, but you can copy-paste it.
SUMPRODUCT() formula:
My loved one...
Plenty of resources on the web to explain this formula.
In your situation, this would give:
=SUMPRODUCT($C$2:$C$133,--(YEAR($B$2:$B$133)=E2))/SUMPRODUCT(--(YEAR($B$2:$B$133)=E2))
This one you can drag down to your needs.
Unfortunately AVERAGEIF() expects a range reference instead of a calculated array. Therefor it will error out. That's the theory at least for Excel, and I expect this to be the same for LibreCalc.
One way around it is using the AVERAGEIFS() function and check against first and last days of the year, for example:
=AVERAGEIFS(C$2:C$133;B$2:B$133;">="&DATE(E2;1;1);B$2:B$133;"<="&DATE(E2;12;31))
Drag the formula down.
After a long time, I decided to come back to coding in R. As of now, I am just going through the tutorials for remembering the things I learned a year ago:D
Everything was fine until I came across with cbind and rbind function.
enter image description here
Could you please advise me what can be done to set third row name for xxbigger matrix?
I actually want to resolve this in line 23.
My question for you guys is: How to define thrid row name for xxbigger matrix in one line?
Thank you,
P.S. Don't put sarcastic comments, so I can come back to this website again:)
We could do this more simple way
xxbigger <- rbind(xxbig, `#3` = c(84, 24, 68))
Or in the OP's code, change the indexing outside the row.names
row.names(xxbigger)[3] <- "#3"
I'm wondering if it is possible to change the contents of multiple cells in a table using R?
Consider this example: Example
I need to change the values 'Femini.' to 'Feminine'. The problem is that i have a great number of cells to change... Is there some command that help me doing this?
Thanks for the help,
Luís
Say your dataframe is called df
df$Genre[df$Genre == 'Femini'] <- 'Feminine'
I'm trying to figure out how to get a count of answers inside a cell which are comma-separated in this format: Anna, peter, Hans, Otto (here it should be 4)
Need this for an assignment and nothing seems to work and my programming are very limited so I hope someone might help me out here :/
I have tried it in excel first with this formula:
=LEN(TRIM(A1))-LEN(SUBSTITUTE(TRIM(A1),",",""))+1
..which didn't work (the brackets around the first A1 and after substitute turned red - whats that telling us anyway? My search only show me entries about negative values..)
Then I tried this formula here in google spreadsheet:
=COUNTA(SPLIT(A1; ","))
..which also didn't work (here I simply get an error).
I guess it's about the values being non numeric? Any ideas?
It is possible that you need:
=LEN(TRIM(A1))-LEN(SUBSTITUTE(TRIM(A1);",";""))+1
If your Regional Settings require it. (see Scott's comment)
This should do the trick
=LEN(A1)-LEN(SUBSTITUTE(A1,",",""))+1
It just counts the commas and adds 1
Update
I just realized that's pretty much the same as what you had - just without using TRIM which isn't necessary. Your formula should work too.
In Excel, use:
=LEN(A1)-LEN(SUBSTITUTE(A1,",","")) + 1
Unless there is a chance for A having no value, then you need to expand it farther:
=IF(LEN(A1)>0,LEN(A1)-LEN(SUBSTITUTE(A1,",","")) + 1,0)
Since you also tagged Google Spreadsheets, there use:
=COUNTA( SPLIT(A1, ",", TRUE))
Same applies for the possiblity of an empty field in Google Sheets.