To compute the beginning ledger balance, I've this query:
select
case when DrControl = 7 then sum(Amount) end Debit,
case when CrControl = 7 then sum(Amount) end Credit
from Transactions
where 7 in (DrControl, CrControl)
and Date < '2020-05-31'
group BY DrControl --, CrControl
and it returns two row:
Debit Credit
------------------
900000 NULL
NULL 40000
I've to compute balance by subtracting one from the other in my Application code. What I really need in this case is Debit - Credit (900000 - 40000) = 860000.
You don't need group by ..., just conditional aggregation:
select
sum(case when DrControl = 7 then Amount end) -
sum(case when CrControl = 7 then Amount end)
from Transactions
where 7 in (DrControl, CrControl) and Date < '2020-05-31'
Just in case there are no rows with DrControl = 7 or CrControl = 7 use also COALESCE() to return 0 instead of null:
select
coalesce(sum(case when DrControl = 7 then Amount end), 0) -
coalesce(sum(case when CrControl = 7 then Amount end), 0)
from Transactions
where 7 in (DrControl, CrControl) and Date < '2020-05-31'
Related
I have 3 columns(CustomerId, Amount, ProcessDate) in a table (Customer).
Values are inserted daily in this table.
I want to get all the rows whose current day Amount is greater than previous day Amount.
CustomerId Amount Process_date
1 20 12/05/2021
2 30 12/05/2021
1 40 13/05/2021
2 25 13/05/2022
We have to print (1 40 13/05/2021) as 20 (previous day amount) is smaller than 40 (next day amount).
Query which I tried :-
select b.customerId, b.amount, b.process_date from customer a
join (select customerId, amount, process_date from customer where process_date = current_date ) as b
on
a.customerId = b.customerId and
a.process_date = current_date - 1 and a.amount < b.amount
I have gone through a similar post in Stack overflow...
but my query is :
If my table generates a flag in run time execution,then how can I increase Grp_number(generate run time) every time my flag changes.
my Oracle query:
Select emp_id,
Case when MOD(rownum/3)=1 and rownum>1 then 'Y' else 'N' as flag
from Transaction_table
Desired o/p Data format:
emp_id Flag GRP_number
1 N 1
2 N 1
3 N 1
4 Y 2
5 N 2
6 N 2
7 Y 3
You cannot reference a column in another column in the same select list. You need to use sub query to avoid INVALID IDENTIFIER error.
Do it like -
WITH DATA AS(
SELECT emp_id,
CASE
WHEN MOD(rownum/3)=1
AND rownum >1
THEN 'Y'
ELSE 'N' AS flag
FROM Transaction_table
)
SELECT emp_id, flag, SUM(gap) over (PARTITION BY person
ORDER BY DAY) grp
FROM(
SELECT emp_id, flag,
CASE WHEN flag = lag(flag) over (PARTITION BY person
ORDER BY DAY)
THEN 0
ELSE 1
END gap
FROM DATA)
I have a calendar table in which there are all the dates in the future and a workday field:
fld_date / fld_workday
2014-01-01 / 1
2014-01-02 / 1
2014-01-03 / 0
...
I want select a date which are n workday far from another date. I tried two ways, but i failed:
The 5th workday from 2014-11-07:
1.
SELECT n1.fld_date FROM calendar as n1 WHERE n1.fld_workday=1 AND
(select count(*) FROM calendar as n2 WHERE n2.fld_date>='2014-11-07' AND n2.fld_workday=1)=5
It gave back 0 row.
2.
SELECT fld_date FROM calendar WHERE fld_date>='2014-11-07' AND fld_workday=1 LIMIT 1 OFFSET 5
It's ok, but i would like to change the 5 days constant to a field, and it's cannot (it would be inside a bigger select statement):
SELECT fld_date FROM calendar WHERE fld_date>='2014-11-07' AND fld_workday=1 LIMIT 1 OFFSET fld_another_field
Any suggestion?
In the first query, the subquery does not refer to the row in n1.
You need a correlated subquery:
SELECT fld_Date
FROM Calendar AS n1
WHERE fld_WorkDay = 1
AND (SELECT COUNT(*)
FROM Calendar AS n2
WHERE fld_Date BETWEEN '2014-11-07' AND n1.fld_Date
AND fld_WorkDay = 1
) = 5
LIMIT 1
The subquery is extremly inefficient if there is no index on the fld_Date column.
You can avoid executing the subquery for every row in n1 by adding another condition with an estimate of the result date (assuming that there are between about four to five work days per week, and using a few extra days to be sure):
...
WHERE fldDate BETWEEN date('2014-11-07', (5 * 4/7 - 10) || ' days')
AND date('2014-11-07', (5 * 5/7 + 10) || ' days')
AND fldWorkDay = 1
AND (SELECT ...
I am building a query within SQL Server that is calculating scores we receive for our surveys. We have a column called overall_score, where the user inputs a number from 1-5 as a rating. I am trying to create a stored procedure that will calculate ratings based off the scores.
Score rating = (Total count of scores 4 and 5)/(Total number of responses) * 100
I have three separate select statements that create results I need, but when I go to combine them together my output is 0.
Can someone please guide me on what I am doing wrong here?
Separate SQL Statements:
SELECT count(overall_score) FROM Layer1_DataMerge WHERE overall_score = 4;
SELECT count(overall_score) FROM Layer1_DataMerge WHERE overall_score = 5;
SELECT count(overall_score) FROM Layer1_DataMerge;
Combined together:
SELECT distinct
(
(
(SELECT count(overall_score) FROM Layer1_DataMerge WHERE Overall_Score = 4) +
(SELECT count(overall_score) FROM Layer1_DataMerge WHERE overall_score = 5)
) / (SELECT count(overall_score) FROM Layer1_DataMerge)
) AS CSAT
FROM Layer1_DataMerge;
Well the reason you're getting zero is because you're doing integer division. With integer division 1/3 = 0. You need to convert to floating-point arithmetic, plus you can do it all in one query:
SELECT 100.0 *
(SUM(CASE WHEN overall_score = 4 THEN 1 ELSE 0 END) +
SUM(CASE WHEN overall_score = 5 THEN 1 ELSE 0 END)) /
COUNT(overall_score)
or
SELECT 100.0 *
SUM(CASE WHEN overall_score IN (4,5) THEN 1 ELSE 0 END) /
COUNT(overall_score)
To only show 2 decimals you can either cast to a numeric type with 2 decimals:
SELECT CAST(
100.0 *
SUM(CASE WHEN overall_score IN (4,5) THEN 1 ELSE 0 END) /
COUNT(overall_score)
AS NUMERIC(5,2))
Or use STR to convert to a string:
SELECT STR(
100.0 *
SUM(CASE WHEN overall_score IN (4,5) THEN 1 ELSE 0 END) /
COUNT(overall_score)
,5,2)
The Problem: Given a day of the week (1, 2, 3, 4, 5, 6, 7), a starting date and an ending date, compute the number of times the given day of the week appears between the starting and ending dates not inclusive of a date for which there were no sales.
Context:
Table "Ticket" has the following structure and sample content:
i_ticket_id c_items_total dt_create_time dt_close_time
----------------------------------------------------------------------------
1 8.50 '10/1/2012 10:23:00' '10/1/2012 11:05:05'
2 10.50 '10/1/2012 11:00:00' '10/1/2012 11:45:05'
3 8.50 '10/2/2012 08:00:00' '10/2/2012 09:25:05'
4 8.50 '10/4/2012 08:00:00' '10/4/2012 09:25:05'
5 7.50 '10/5/2012 13:22:23' '10/5/2012 14:33:27'
.
.
233 6.75 '10/31/2012 23:20:00' '10/31/2012 23:55:39'
Details
There may or may not be any tickets for one or more days during a month. (i.e. the place was closed that/those day/s)
Days in which the business is closed are not regular. There is no predictable pattern.
Based on Get number of weekdays (Sundays, Mondays, Tuesdays) between two dates SQL,
I have derived a query which returns the number of times a given day of the week occurs between the start date and the end date:
DECLARE #dtStart DATETIME = '10/1/2013 04:00:00'
DECLARE #dtEnd DATETIME = '11/1/2013 03:59:00'
DECLARE #day_number INTEGER = 1
DECLARE #numdays INTEGER
SET #numdays = (SELECT 1 + DATEDIFF(wk, #dtStart, #dtEnd)-
CASE WHEN DATEPART(weekday, #dtStart) #day_number THEN 1 ELSE 0 END -
CASE WHEN DATEPART(weekday, #dtEnd) <= #day_number THEN 1 ELSE 0 END)
Now I just need to filter this so that any zero-dollar days are not included in the count. Any help you can provide to add this filter based on the contents of the tickets table is greatly appreciated!
If I understand correctly, you can use a calendar table to count the number of days where the day of week is n and between the start and end and is a date that has ticket sales, which I guess is when the date exists in tickets and has the sum(c_items_total) > 0
WITH cal AS
(
SELECT cast('2012-01-01' AS DATE) dt, datepart(weekday, '2012-01-01') dow
UNION ALL
SELECT dateadd(day, 1, dt), datepart(weekday, dateadd(day, 1, dt))
FROM cal
WHERE dt < getdate()
)
SELECT COUNT(1)
FROM cal
WHERE dow = 5
AND dt BETWEEN '2012-04-01' AND '2012-12-31'
AND EXISTS (
SELECT 1
FROM tickets
WHERE cast(dt_create_time AS DATE) = dt
GROUP BY cast(dt_create_time AS DATE)
HAVING sum(c_items_total) > 0
)
OPTION (MAXRECURSION 0)
SQLFiddle