Create a dataframe looping a function's results - r

Question

So this is a simplification of my problem.
I have a dataframe like this:
df <- data.frame(name=c("lucas","julio","jack","juan"),number=c(1,15,100,22))
And I have a function that creates new values for every name, like this:
var_number <- function(x) {
example <- df %>%
filter(name %in% unique(df$name)[x]) %>%
select(-name) %>%
mutate(value1=number/2^5, value2=number^5)
(example)
}
var_number(1)
0.03125 1
Now I have two new values for every name and I would like to create a loop to save each result in a new dataframe.
I know how to solve this particular problem, but I need a general solution that allows me to save the results of all functions into a dataframe.
I'm looking for an automatic way to do something like this:
result<- bind_rows(var_number(1),var_number(2),var_number(3),var_number(4))
Since I would have to apply var_number around 1000 times and the lenght would change with every test i do.
There is anyway I can do something like this? I was thinking about doing it with "for", but I'm not really sure about how to do it, I have just started with R and I am a total newbie.

Answer 1

This answers my problem:
library(tidyverse) # contains purrr library
#an arbitrary function that always outputs a dataframe
# with a consistent number of columns, in this case 3
myfunc <- function(x){
data.frame(a=x*2,
b=x^2,
c=log2(x))
}
# iterate over 1:10 as inputs to myfunc, and
# combine the results rowwise into a df
purrr::map_dfr(1:10,
~myfunc(.))

Answer 2

Why do you want to apply var_number function for each name, create a new dataframe for each and then combine all of them together?
Do it only once in the same dataframe.
library(dplyr)
df1 <- df %>%
mutate(value1=number/2^5,value2=number^5) %>%
select(-name)
If you want to do it only for specific names, you can filter them first before applying the above.