Convert map[string][]string into a yaml structure - dictionary

Question

I try to convert a make(map[string]string) into a yaml like that:
Yaml Output desire:
items:
keys1:value1
keys2:value2
keys3:value3
keys4:value4
The keys,values are this listKey map of string. J = string = {"key1":"value1","key2":"value2" }
type Items struct {
items string
ItemsValues map[string][]string
}
func ConvertToYelm(j string){
y := Items{}
var dataJson map[string]string
err := json.Unmarshal([]byte(j), &dataJson)
if err != nil {
fmt.Println(err)
return
}
listKey := make(map[string]string)
for k := range dataJson{
listKey[k] = k
}
yelm, err := yaml.Marshal(listKey)
if err != nil {
fmt.Println(err)
return
}
err = yaml.Unmarshal(yelm, Items)
if err != nil {
fmt.Println(err)
return
}
yeml2, err := yaml.Marshal(&yelm)
fmt.Printf ("%s", string(yeml2))
To be honest, I'm a little bit lost here, thank you for the help

Answer 1

To get the exact YAML from your post:
items:
keys1:value1
keys2:value2
keys3:value3
keys4:value4
You can do this (Go Playground):
package main
import (
"fmt"
"gopkg.in/yaml.v2"
)
type ItemsStruct struct {
Items map[string]string `yaml:"items"`
}
func main() {
itms := &ItemsStruct{Items: map[string]string{
"keys1": "value1",
"keys2": "value2",
"keys3": "value3",
"keys4": "value4"}}
yamlBytes, err := yaml.Marshal(itms)
if err != nil {
//handle error
}
fmt.Println(string(yamlBytes))
}
And just to add, I see your code is decoding this JSON {"key1":"value1", "key2":"value2", ... } and then encoding it as YAML in your specified format. Here is the Go Playground for that.