I'm using qtgrace for MacOS and when I plotted two data in qtgrace I got something like this:
Overlapping data sets
However, I would like to plot something like this:
Non-overlapping data sets
My data 1:
0 14
0.1 6
0.2 14
0.3 14
0.4 14
0.5 14
0.6 14
0.7 14
0.8 6
0.9 6
1 6
1.1 6
1.2 6
1.3 6
1.4 6
1.5 6
1.6 6
1.7 6
1.8 6
1.9 6
2 6
2.1 6
2.2 6
2.3 6
2.4 6
2.5 6
2.6 6
2.7 6
2.8 6
2.9 6
3 6
3.1 6
3.2 6
3.3 6
3.4 6
3.5 6
3.6 6
3.7 6
3.8 6
3.9 6
4 6
4.1 6
4.2 6
4.3 6
4.4 6
4.5 6
4.6 6
4.7 6
4.8 6
4.9 6
5 6
5.1 6
5.2 6
5.3 6
5.4 6
5.5 6
5.6 6
5.7 6
5.8 6
5.9 6
6 6
6.1 6
6.2 6
6.3 6
6.4 6
6.5 6
6.6 6
6.7 6
6.8 6
6.9 6
7 6
7.1 6
7.2 6
7.3 2
7.4 6
7.5 2
7.6 2
7.7 2
7.8 2
7.9 6
8 2
8.1 6
8.2 2
8.3 2
8.4 6
8.5 6
8.6 6
8.7 2
8.8 6
8.9 19
9 19
9.1 6
9.2 6
9.3 6
9.4 2
9.5 2
9.6 2
9.7 2
9.8 2
9.9 2
10 2
10.1 2
10.2 2
10.3 2
10.4 2
10.5 2
10.6 2
10.7 2
10.8 2
10.9 2
11 2
11.1 2
11.2 2
11.3 2
11.4 2
11.5 2
11.6 2
11.7 2
11.8 2
11.9 2
12 2
12.1 2
12.2 2
12.3 2
12.4 2
12.5 2
12.6 2
12.7 2
12.8 2
12.9 2
13 2
13.1 2
13.2 2
13.3 2
13.4 2
13.5 2
13.6 2
13.7 2
13.8 2
13.9 2
14 2
14.1 2
14.2 2
14.3 2
14.4 2
14.5 2
14.6 2
14.7 2
14.8 2
14.9 2
15 2
15.1 2
15.2 2
15.3 2
15.4 2
15.5 2
15.6 2
15.7 2
15.8 2
15.9 2
16 2
16.1 2
16.2 2
16.3 2
16.4 2
16.5 2
16.6 2
16.7 2
16.8 2
16.9 2
17 2
17.1 2
17.2 2
17.3 2
17.4 2
17.5 2
17.6 2
17.7 2
17.8 2
17.9 2
18 2
18.1 2
18.2 2
18.3 2
18.4 2
18.5 2
18.6 2
18.7 2
18.8 2
18.9 2
19 2
19.1 2
19.2 2
19.3 2
19.4 2
19.5 2
19.6 2
19.7 2
19.8 2
19.9 2
20 2
20.1 2
20.2 2
20.3 2
20.4 2
20.5 2
20.6 2
20.7 2
20.8 2
20.9 2
21 2
21.1 2
21.2 2
21.3 2
21.4 2
21.5 2
21.6 2
21.7 2
21.8 7
21.9 2
22 2
22.1 2
22.2 2
22.3 7
22.4 7
22.5 7
22.6 7
22.7 7
22.8 2
22.9 2
23 7
23.1 7
23.2 7
23.3 7
23.4 7
23.5 2
23.6 2
23.7 2
23.8 2
23.9 2
24 2
24.1 2
24.2 2
24.3 2
24.4 2
24.5 2
24.6 2
24.7 2
24.8 2
24.9 2
25 2
. .
. .
. .
Data 2:
0 4
0.1 4
0.2 4
0.3 4
0.4 4
0.5 4
0.6 4
0.7 4
0.8 4
0.9 4
1 2
1.1 4
1.2 4
1.3 4
1.4 4
1.5 4
1.6 4
1.7 4
1.8 4
1.9 4
2 4
2.1 4
2.2 4
2.3 4
2.4 4
2.5 4
2.6 4
2.7 4
2.8 4
2.9 4
3 4
3.1 4
3.2 4
3.3 4
3.4 4
3.5 4
3.6 4
3.7 4
3.8 4
3.9 4
4 4
4.1 4
4.2 4
4.3 4
4.4 4
4.5 4
4.6 4
4.7 4
4.8 4
4.9 4
5 4
5.1 4
5.2 4
5.3 4
5.4 4
5.5 4
5.6 4
5.7 4
5.8 4
5.9 4
6 4
6.1 4
6.2 4
6.3 4
6.4 4
6.5 4
6.6 4
6.7 4
6.8 4
6.9 4
7 4
7.1 4
7.2 4
7.3 4
7.4 4
7.5 4
7.6 4
7.7 4
7.8 4
7.9 4
8 4
8.1 4
8.2 4
8.3 4
8.4 2
8.5 4
8.6 4
8.7 4
8.8 4
8.9 4
9 4
9.1 4
9.2 4
9.3 4
9.4 4
9.5 4
9.6 4
9.7 4
9.8 4
9.9 4
10 4
10.1 4
10.2 4
10.3 4
10.4 4
10.5 2
10.6 2
10.7 4
10.8 2
10.9 2
11 2
11.1 2
11.2 4
11.3 4
11.4 2
11.5 2
11.6 2
11.7 2
11.8 2
11.9 2
12 2
12.1 2
12.2 2
12.3 2
12.4 4
12.5 4
12.6 2
12.7 2
12.8 4
12.9 2
13 2
13.1 4
13.2 4
13.3 4
13.4 4
13.5 10
13.6 2
13.7 2
13.8 2
13.9 2
14 2
14.1 2
14.2 2
14.3 10
14.4 2
14.5 2
14.6 4
14.7 2
14.8 2
14.9 4
15 2
15.1 10
15.2 2
15.3 2
15.4 2
15.5 2
15.6 2
15.7 2
15.8 2
15.9 2
16 2
16.1 2
16.2 2
16.3 2
16.4 2
16.5 2
16.6 2
16.7 2
16.8 2
16.9 2
17 2
17.1 2
17.2 2
17.3 2
17.4 2
17.5 2
17.6 2
17.7 2
17.8 2
17.9 2
18 2
18.1 2
18.2 2
18.3 2
18.4 2
18.5 2
18.6 2
18.7 2
18.8 2
18.9 2
19 2
19.1 2
19.2 2
19.3 2
19.4 2
19.5 2
19.6 2
19.7 2
19.8 2
19.9 2
20 2
20.1 2
20.2 2
20.3 2
20.4 2
20.5 2
20.6 2
20.7 2
20.8 2
20.9 2
21 2
21.1 2
21.2 2
21.3 2
21.4 2
21.5 2
21.6 2
21.7 2
21.8 2
21.9 2
22 2
22.1 2
22.2 2
22.3 2
22.4 2
22.5 2
22.6 2
22.7 2
22.8 2
22.9 2
23 2
23.1 2
23.2 2
23.3 2
23.4 2
23.5 2
23.6 2
23.7 2
23.8 2
23.9 2
24 2
24.1 2
24.2 2
24.3 2
24.4 2
24.5 2
24.6 2
24.7 2
24.8 2
24.9 2
25 2
. .
. .
. .
The data are in two separate xvg file from GROMACS cluster analysis. I wanna plot five different sets in a manner which I can see all data without superposing.
Thank you!
I think the best approach would be to write a script that takes the original files and spits out new files with shifted y values. However, since you have asked for a qt/xmgrace solution, here is how you do it:
Load up all the datasets into qtgrace
Open the "Data -> Transformations -> Evaluate expression..." dialog
Select in the left and right columns a dataset and in the textbox below enter the formula y = y + 0.1. Click "apply". This will shift the dataset up by 0.1
Select the next dataset in the same way and use the formula y = y + 0.2. Click apply
Rinse and repeat for all the datasets (changing the shift accordingly)
Related
I have SVG & it is of size 1326 x 745.
SVG looks like:
import React from 'react'
export const Wave = (props: React.SVGProps<SVGSVGElement>) => {
return (
<svg viewBox="0 0 16 9" {...props}>
<path
d="M0 8L0.2 7.8C0.3 7.7 0.7 7.3 1 7.2C1.3 7 1.7 7 2 6.8C2.3 6.7 2.7 6.3 3 6C3.3 5.7 3.7 5.3 4 5.7C4.3 6 4.7 7 5 7.5C5.3 8 5.7 8 6 7.5C6.3 7 6.7 6 7 5.7C7.3 5.3 7.7 5.7 8 5.8C8.3 6 8.7 6 9 6.2C9.3 6.3 9.7 6.7 10 6.8C10.3 7 10.7 7 11 6.7C11.3 6.3 11.7 5.7 12 5.7C12.3 5.7 12.7 6.3 13 6.5C13.3 6.7 13.7 6.3 14 6.3C14.3 6.3 14.7 6.7 15 6.8C15.3 7 15.7 7 15.8 7L16 7L16 10L15.8 10C15.7 10 15.3 10 15 10C14.7 10 14.3 10 14 10C13.7 10 13.3 10 13 10C12.7 10 12.3 10 12 10C11.7 10 11.3 10 11 10C10.7 10 10.3 10 10 10C9.7 10 9.3 10 9 10C8.7 10 8.3 10 8 10C7.7 10 7.3 10 7 10C6.7 10 6.3 10 6 10C5.7 10 5.3 10 5 10C4.7 10 4.3 10 4 10C3.7 10 3.3 10 3 10C2.7 10 2.3 10 2 10C1.7 10 1.3 10 1 10C0.7 10 0.3 10 0.2 10L0 10Z"
strokeLinecap="round"
strokeLinejoin="miter"
fill="currentColor"
></path>
</svg>
)
}
It takes so much space. I want it to be really small. Only take up wave space.
I made this Wave SVG on https://app.haikei.app/
I tried all configurations but I can't get it to be small.
All I want is width to be 100% no matter which device I'm on & it should have a proportional height. What do I need to do to change it?
I have a character array dat which I want to convert to a data frame df but it is not working
head(dat)
[1] " 1931 1 5.0 0.6 11 78.4 43.4"
[2] " 1931 2 6.7 0.7 7 48.9 63.6"
[3] " 1931 4 10.4 3.1 3 44.6 110.1"
[4] " 1931 5 13.2 6.1 1 63.7 167.4"
[5] " 1931 6 15.4 8.0 0 87.8 150.3"
[6] " 1931 7 17.3 10.6 0 121.4 111.2"
> df<-as.data.frame(dat)
> head(df)
dat
1 1931 1 5.0 0.6 11 78.4 43.4
2 1931 2 6.7 0.7 7 48.9 63.6
3 1931 4 10.4 3.1 3 44.6 110.1
4 1931 5 13.2 6.1 1 63.7 167.4
5 1931 6 15.4 8.0 0 87.8 150.3
6 1931 7 17.3 10.6 0 121.4 111.2
df[,c(3)]
Error in [.data.frame(df, , c(3)) : undefined columns selected
Reading with read.table: You can rename as desired.
df<-read.table(text = " dat
1 1931 1 5.0 0.6 11 78.4 43.4
2 1931 2 6.7 0.7 7 48.9 63.6
3 1931 4 10.4 3.1 3 44.6 110.1
4 1931 5 13.2 6.1 1 63.7 167.4
5 1931 6 15.4 8.0 0 87.8 150.3
6 1931 7 17.3 10.6 0 121.4 111.2",
header=F,fill=T,as.is=T,skip = 1)
df[3]
V3
1 1
2 2
3 4
4 5
5 6
6 7
If dat is as shown reproducibly in the Note at the end then as.data.frame(dat) creates a data frame with one column called dat and then when there is an attempt to take the 3rd column an error results since there is only one column.
Instead, use read.table and get the third column like this. Omit the comma if you want a data frame result.
read.table(text = dat)[, 3]
## [1] 5.0 6.7 10.4 13.2 15.4 17.3
Note
dat <- c(" 1931 1 5.0 0.6 11 78.4 43.4",
" 1931 2 6.7 0.7 7 48.9 63.6",
" 1931 4 10.4 3.1 3 44.6 110.1",
" 1931 5 13.2 6.1 1 63.7 167.4",
" 1931 6 15.4 8.0 0 87.8 150.3",
" 1931 7 17.3 10.6 0 121.4 111.2")
Here's a tidyverse approach:
dat <- c(" 1931 1 5.0 0.6 11 78.4 43.4",
" 1931 2 6.7 0.7 7 48.9 63.6",
" 1931 4 10.4 3.1 3 44.6 110.1",
" 1931 5 13.2 6.1 1 63.7 167.4",
" 1931 6 15.4 8.0 0 87.8 150.3",
" 1931 7 17.3 10.6 0 121.4 111.2")
library(tidyverse)
str_trim(dat) %>% # trim leading space
tibble(x = .) %>% # put into tibble (data.frame)
separate(x, # separate x into 7 columns, named below
into = c("year","v1","v2","v3","v4","v5","v6"),
sep = "[ ]{1,}") # separate by one or more spaces ("[ ]{1,}")
That leads to:
# A tibble: 6 x 7
year v1 v2 v3 v4 v5 v6
<chr> <chr> <chr> <chr> <chr> <chr> <chr>
1 1931 1 5.0 0.6 11 78.4 43.4
2 1931 2 6.7 0.7 7 48.9 63.6
3 1931 4 10.4 3.1 3 44.6 110.1
4 1931 5 13.2 6.1 1 63.7 167.4
5 1931 6 15.4 8.0 0 87.8 150.3
6 1931 7 17.3 10.6 0 121.4 111.2
When I check the type, it said "integer", but has decimal point. If I change it to numeric, it become integer(no decimal point).
Because I want to do histogram, x must be numeric, but if change to numeric, all data wrong.
> typeof(data$fare_amount)
[1] "integer"
> data$fare_amount
[1] 5.5 6.5 8.0 13.5 5.5 9.5 7.5 8.0 16.0 8.0 5.5 7.0 8.0 5.0 9.5 23.0 5.0 6.0 17.5 12.0 8.5 13.0
[23] 6.5 4.5 52.0 14.5 7.5 4.5 9.0 10.0 15.0 11.5 6.0 12.5 7.5 8.0 6.5 7.5 31.5 10.0 10.0 10.0 4.0 8.5
[45] 24.0 8.5 5.5 14.0 11.0 4.5 9.0 7.5 22.0 8.5 24.0 36.5 15.0 10.5 9.5 17.0 4.5 6.0 6.5 11.5 16.0 6.5
[67] 7.0 20.0 13.5 30.0 8.0 11.0 6.5 11.5 6.5 37.0 5.5 12.5 8.5 58.5 13.5 8.5 9.0 6.0 6.5 9.0 38.0 4.5
[89] 10.0 9.0 44.5 11.0 12.0 4.5 14.5 8.5 32.0 9.5 4.5 6.0 6.5 6.0 31.5 52.0 10.5 12.0 5.5 24.5 7.0 5.5
[111] 16.5 5.0 5.5 6.5 3.5 11.5 13.0 6.0 14.0 3.5
42 Levels: 13.5 16.0 5.5 6.5 7.5 8.0 9.5 12.0 17.5 23.0 5.0 6.0 7.0 10.0 13.0 14.5 4.5 52.0 8.5 9.0 11.5 12.5 ... 3.5
> temp <- as.numeric(data$fare_amount)
> temp
[1] 3 4 6 1 3 7 5 6 2 6 3 13 6 11 7 10 11 12 9 8 19 15 4 17 18 16 5 17 20 14 23 21 12 22 5 6 4 5
[39] 24 14 14 14 28 19 27 19 3 26 25 17 20 5 31 19 27 32 23 29 7 30 17 12 4 21 2 4 13 33 1 34 6 25 4 21 4 35
[77] 3 22 19 36 1 19 20 12 4 20 37 17 14 20 39 25 8 17 16 19 38 7 17 12 4 12 24 18 29 8 3 40 13 3 41 11 3 4
[115] 42 21 15 12 26 42
I want to check overlap of data, here is data
ID <- c(rep(1,3), rep(3, 5), rep(4,4),rep(5,5))
Begin <- c(0,2.5,3,7,8,7,25,25,10,15,17,20,1,NA,10,11,13)
End <- c(1.5,3.5,6,12,8,11,29,35, 12,19,NA,28,5,20,30,20,25)
df <- data.frame(ID, Begin, End)
df
ID Begin End
1 1 0.0 1.5
2 1 2.5 3.5
3 1 3.0 6.0*
4 3 7.0 12.0
5 3 8.0 8.0*
6 3 7.0 11.0*
7 3 25.0 29.0
8 3 25.0 35.0*
9 4 10.0 12.0
10 4 15.0 19.0
11 4 17.0 NA*
12 4 20.0 28.0
13 5 1.0 5.0
14 5 NA 20.0
15 5 10.0 30.0
16 5 11.0 20.0*
17 5 13.0 25.0*
* means it's overlap:
for row 3,ID = 1,Begin=3.0 is smaller than 3.5, so set Begin_New = 3.5, but
while ID = 3, it's different, row 5 Begin = 8.0 is smaller than 12.0, we set Begin_New = 12, but it keep going, if we compare Begin = 7.0 with End = 8.0, it's not correct, because now End is 12 is higher next value.
So here is my output design
ID Begin End Begin_New1
1 1 0.0 1.5 0.0
2 1 2.5 3.5 2.5
3 1 3.0 6.0 3.5*
4 3 7.0 12.0 7.0
5 3 8.0 8.0 12.0*
6 3 7.0 11.0 12.0*
7 3 25.0 29.0 25.0
8 3 25.0 35.0 29.0*
9 4 10.0 12.0 10.0
10 4 15.0 19.0 15.0
11 4 17.0 NA 19.0*
12 4 20.0 28.0 20.0
13 5 1.0 5.0 1.0
14 5 NA 20.0 NA
15 5 10.0 30.0 20.0*
16 5 11.0 20.0 30.0*
17 5 13.0 25.0 30.0*
When I use this code, I don't get the output I want, it shift only 1 row and compare each row
setDT(df)[, Begin_New := shift(End), by = ID][!which(Begin < Begin_New), Begin_New:= Begin]
ID Begin End Begin_New
1: 1 0.0 1.5 0.0
2: 1 2.5 3.5 2.5
3: 1 3.0 6.0 3.5
4: 3 7.0 12.0 7.0
5: 3 8.0 8.0 12.0
6: 3 7.0 11.0 8.0
7: 3 25.0 29.0 25.0
8: 3 25.0 35.0 29.0
9: 4 10.0 12.0 10.0
10: 4 15.0 19.0 15.0
11: 4 17.0 NA 19.0
12: 4 20.0 28.0 20.0
13: 5 1.0 5.0 1.0
14: 5 NA 20.0 NA
15: 5 10.0 30.0 20.0
16: 5 11.0 20.0 30.0
17: 5 13.0 25.0 20.0
This is the output I don't want it
I think your code is pretty much right, you just need to use cummax:
df[, Begin_New := {
high_so_far = shift(cummax(End), fill=Begin[1L])
w = which(Begin < high_so_far)
Begin[w] = high_so_far[w]
Begin
}, by=ID]
I'm calling height, diameter and age from a csv file. I'm trying to calculate the volume of the tree using pi x h x r^2. In order to calculate the radius, I'm taking dbh and dividing it by 2. Then I get this error.
Error in dbh/2 : non-numeric argument to binary operator
setwd("/Users/user/Desktop/")
treeg <- read.csv("treeg.csv",row.names=1)
head(treeg)
heights <- tapply(treeg$height.ft,treeg$forest, identity)
ages <- tapply(treeg$age,treeg$forest, identity)
dbh <- tapply(treeg$dbh.in,treeg$forest, identity)
radius <- dbh / 2
In the vector dbh it is storing the diameter from he csv file in terms of forest which is the ID.
How can I divide dbh by 2, while still retaining format of each value being stored by its receptive ID (which is he forest ---> treeg$forest) and treeg is the dataframe that call the csv file.
> head(treeg)
tree.ID forest habitat dbh.in height.ft age
1 1 4 5 14.6 71.4 55
2 1 4 5 12.4 61.4 45
3 1 4 5 8.8 40.1 35
4 1 4 5 7.0 28.6 25
5 1 4 5 4.0 19.6 15
6 2 4 5 20.0 103.4 107
str(dbh)
List of 9
$ 1: num [1:36] 19.9 18.6 16.2 14.2 12.3 9.4 6.8 4.9 2.6 22 ...
$ 2: num [1:60] 16.5 15.5 14.5 13.7 12.7 11.4 9.5 8 5.9 4.1 ...
$ 3: num [1:50] 18.4 17.2 15.6 13.7 11.6 8.5 5.3 2.8 13.3 10.6 ...
$ 4: num [1:81] 14.6 12.4 8.8 7 4 20 18.8 17 15.9 14 ...
$ 5: num [1:153] 28 27.2 26.1 25 23.7 21.3 19 16.7 12.2 9.8 ...
$ 6: num [1:22] 21.3 20.2 19.1 18 16.9 15.6 14.8 13.3 11.3 9.2 ...
$ 7: num [1:63] 13.9 12.4 10.6 8.1 5.8 3.4 27 25.6 23 20.2 ...
$ 8: num [1:27] 20.8 17.7 15.6 13.2 10.5 7.5 4.8 2.9 12.9 11.3 ...
$ 9: num [1:50] 23.6 20.5 16.9 14.1 11.1 8 5.1 2.9 24.1 20.9 ...
- attr(*, "dim")= int 9
- attr(*, "dimnames")=List of 1
..$ : chr [1:9] "1" "2" "3" "4" ...
Are you just trying to create a radius column that is dbh.in divided by two?
treeg <- read.table(textConnection("tree.ID forest habitat dbh.in height.ft age
1 1 4 5 14.6 71.4 55
2 1 4 5 12.4 61.4 45
3 1 4 5 8.8 40.1 35
4 1 4 5 7.0 28.6 25
5 1 4 5 4.0 19.6 15
6 2 4 5 20.0 103.4 107"), header=TRUE)
treeg$radius <- treeg$dbh.in / 2
Or do you need that dbh list for something...
dbh <- tapply(treeg$dbh.in,treeg$forest, identity)
> dbh
$`4`
[1] 14.6 12.4 8.8 7.0 4.0 20.0
lapply(dbh, function(x)x/2)
List of 1
$ 4: num [1:6] 7.3 6.2 4.4 3.5 2 10