I have used scss variables in all of my code, like this:
$primary: royalblue;
body {
background: $primary;
color: black;
}
.list-item {
// some code
span, a {
background: black;
color: $primary;
}
}
now, I want to create an animation for body background color:
#keyframes bganimation {
from {
$primary: royalblue;
}
to {
$primary: tomato;
}
}
but I know scss is a language that compiles to css... is there any other way to do that?
I can't rewrite the code, help please.
I guess you first have to understand how SCSS Variables actually work:
When compiling SCSS to CSS the variables are replaced with the actual current value of the variable so in the end there won't be any variables anymore.
That said your keyframes block will simply be an empty block in the end.
If you want to have real variables, you would have to use actual CSS Variables
--some-variable: red;
(Notice that this won't work out of the box in "browsers" like IE)
There are more things you should fix in your code:
- There is no animation set for any of the elements (via animation attribute)
- In the keyframes block you have to define which attribute should animate and what value they should take while animation
eg:
#keyframes bganimation {
from {
background-color: red;
}
to {
background-color: blue;
}
}
So you would have to rewrite the code at least a bit for it to work.
You have to animate the background-color property, so it should be:
#keyframes bganimation {
from {
background-color: $primary;
}
to {
background-color: tomato;
}
}
Related
I'm searching a way to use a particular color depending on a class on the body tag.
I have a main scss file like this
// variables.scss
$bg-main: white;
$color-first: red;
$color-second: green;
And in my other files, I use the colors
// content.scss
.content {
.some-selector: {
// some styles
color: $color-second;
}
a:hover {
// some styles
color: $color-second;
}
}
// and same goes for menu.scss etc.
Now I have a dynamic class on the body, that changes depending on the current selected menu. I would like $color-second to be different for each body classes, and I don't know how to do that. The only solution I found was to move all the $color-second from each files into one single file, like this:
.body-1 {
.content a:hover, .content .some-selector {
color: green;
}
}
.body-2 {
.content a:hover, .content .some-selector {
color: blue;
}
}
.body-1 {
.content a:hover, .content .some-selector {
color: black;
}
}
So I don't need to write the color in each files. This works well, but if I need to set this $color-second to some other selector, I need to put that in this big file.
Is this possible to do this an other way?
I already checked these answers, but it didn't helped me much:
SASS set variable depending on CSS class
Creating or referencing variables dynamically in Sass
Merge string and variable to a variable with SASS
There are multiple ways to do this. The most obvious two which come to mind are mixins and loops:
Mixins
Just put everything you want into a single mixin, and then use it for every body class:
#mixin colored-content($color) {
.content a:hover, .content .some-selector {
color: $color;
}
/* Any other rules which use $color here */
}
.body-1 {
#include colored-content(green);
}
.body-2 {
#include colored-content('#FF0000');
}
.body-3 {
#include colored-content(darken(red, 20));
}
You can extend this example with any number of arguments (for example, $textColor and $bgColor), conditions or rules.
With this approach you will not have SCSS code repetitions, and any updates will be introduced easily.
Loop
Another way is to use a simple loop:
$body_themes: (
"body-1": green,
"body-2": #FF0000,
"body-3": darken(red, 2)
);
#each $body_class, $color in $body_themes {
.#{$body_class} {
.content a:hover, .content .some-selector {
color: $color;
}
/* Any other rules which use $color here */
}
}
It is even shorter, but imho it is less readable.
P.S. It is possible to combine mixins and loops, by the way :)
Assuming that I have the following HTML:
<div class="navigation__item">
<span class="navigation__item__icon"></span>
</div>
I want to apply some rules to an icon, when hovering an item, which can be described with the following CSS:
.navigation__item__icon {
color: black;
}
.navigation__item:hover .navigation__item__icon {
color: white;
}
I can achieve this using the following SCSS:
.navigation__item {
&:hover {
.navigation__item__icon { <-- here
color: white;
}
}
&__icon {
color: black;
}
}
Here, is there any way to avoid writing navigation__item? Something like "parent rule \ element".
I like Sass for logical structure so that if I want to rename the whole navigation block with elements, I can simply change navigation class name in the root, and everything is renamed. This case breaks this advantage.
Update: Actually, I have found a way to do this without using {} braces. & can be repeated more than once:
.navigation__item {
&:hover &__icon {
color: white;
}
&__icon {
color: black;
}
}
It is great, but it doesn't make much sense if I have many rules and rules for &:hover itself. The question is still open - is this possible to access sibling element definition from within the {} block.
In Stylus there is a Partial reference but I don't know anything similar in SASS. One solution could be using a variable for the parent selector:
.navigation__item {
$selector: &;
&:hover {
#{$selector}__icon {
color: white;
}
}
&__icon {
color: black;
}
}
Is usefull is you change navigation__item class for another.
EDIT: I had used a wrong example, it's OK now.
For a responsive layout I am trying to switch the color with the background-color and vice versa on defined occasions.
What's the cleanest way to swap the values of the color and background-color when using sass? Pure CSS doesn't work in this case, does it?
Something like
p {
#media … {
[swap currentTextColor and currentBgColor]
}
}
You could create a mixin:
#mixin swapColors($textColor, $bgColor) {
background-color: $bgColor;
color: $textColor;
#media ... {
background-color: $textColor;
color: $bgColor;
}
}
.tree {
#include swapMobile(red, black);
}
Besides from that i'm not aware of anything built in that could do such a thing.
I want to add scope to my selectors.
A good way to achieve it in my opinion is to select css selector and return mySelector + oldSelector
For example I have .old { background: black; }, I would transform it into .mySelector .old { background: black; }
Let's say I have this CSS
.a
{
background: red;
}
#b {
background: green;
}
input {
background: blue;
}
[type=custom] {
background: white;
}
I would do .+?{, but it selects not needed parts. Inverse of {.+?} would work, but I don't know how to inverse it. Any ideas ?
I figured out I can use String.match({.+?}) to get all rules and String.split({.+?}) to get selectors in JavaScript.
Also I've found a library to easily parse CSS in JavaScript https://github.com/reworkcss/css
Is there a way to add scope to sass variables?
I want to be able to attach a class to my body element. The class will refer to a set of colours that the rest of the stylesheets can access.
I have tried:
#mixin theme_one{
$color: #000;
}
.theme_one{
#include theme_one;
}
and
.theme_one{
$color: #000;
}
I've just come across the same issue myself. I wanted to have different colour themes for different sections of my site.
Using a mixin seems like the best way to go. It's nicely DRY, and easy to use. The trick is not setting your colours in your main styles blocks, but rather using only the mixin for this.
I've set up the theme colours as variables at the top so they can be edited nicely, and I've set them as lists so that multiple values can be passed without hordes of variable being defined.
So:
// Variable Definitions
$defaultColor: black white grey;
$color2: blue green brown;
$color3: red white blue;
#mixin colorSet($color: $defaultColor) {
$link: nth($color, 1);
$border: nth($color, 2);
$background: nth($color, 3);
border-color: $border;
background-color: $background;
.column {
border-color: lighten($border, 10%);
}
a {
color: $link;
&:hover {
color: darken($link, 15%);
}
}
}
// Default colours
body {
#include colorSet();
}
// Scoped colours
.my-theme-3 {
#include colorSet($color3);
}
.my-theme-2 {
#include colorSet($color2);
}
Will produce something like this:
body {
border-color: white;
background-color: grey; }
body .column {
border-color: white; }
body a {
color: black; }
body a:hover {
color: black; }
.my-theme-3 {
border-color: white;
background-color: blue; }
.my-theme-3 .column {
border-color: white; }
.my-theme-3 a {
color: red; }
.my-theme-3 a:hover {
color: #b30000; }
.my-theme-2 {
border-color: green;
background-color: brown; }
.my-theme-2 .column {
border-color: #00b300; }
.my-theme-2 a {
color: blue; }
.my-theme-2 a:hover {
color: #0000b3; }
Edit: Updated to use default mixin values.
In your case no need to use mixin, If you have set of many styles then use mixin,
ie. if you have
#mixin theme_one{
$color: #000;
height: 50px;
}
then use Mixin
otherwise for single property use only variable
$color: #fff;
.some_class01{
color: $color;
background: $color;
}
.some_class22{
border-color: $color;
}
IMP: Variable should assign at the top of your code, it means don't use it after/below where you assigned it :)
Not sure if this is what you are looking for. It looks like you may have tried something similar to this,
which should probably work. (it may just be a matter of using !default)
Your body tag with a class on it..
<body class="theme_one">
</body>
Sass variables defined in stylesheet..
//THEME ONE VARIABLES
.theme_one{
$borderColor:#333 !default;
$fontColor:#999 !default;
}
//THEME TWO VARIABLES
.theme_two{
$borderColor:#CCC !default;
$fontColor:#000 !default;
}
Pre-existing CSS which will be overwritten depending on which class is used on the body tag.
h1.someheader {
color:$fontColor;
border-bottom:1px solid;
border-color:$borderColor;
}
Otherwise you could maybe try something like this. It looks like you may have tried something similar, however there seems to be an error with your mixin ... see note below.
//mixin used to set variables for properties
#mixin themeOne($fontColor,$borderColor) {
color:$fontColor;
border-color:$borderColor;
}
#include themeOne(#000,#CCC);
Pre-existing CSS
h1.someheader {
color:$fontColor
border-color:$borderColor;
border-bottom:1px solid;
}
Also note in your mixin example you are using $color:#000; ... This won't be interpreited properly as it should be color:#000; You can't use variables as selectors
unless you do something like #{$color}:#000;
I haven't quite tested this yet, so some things might need to be adjusted. If this doesn't solve your problem I hope it at least gives you some ideas.