Setup an oozie that stops after a few runs - oozie

I need to setup an Oozie job that runs every 1 hour from 9am till 5pm and then stop for the day. And then do the same for all week days. I know how to set up something that starts at a given time and does that, but not able to figure out how to make it stop at 5pm. Appreciate the help!

I figured out that, Oozie frequency syntax is no different from Crontab. So, I did something like this to make it happen.
frequency="00 09-17 * * *"

Related

Are airflow monthly dags delayed by a day or a month?

I am trying to set an airflow dag that runs on second day of each month. Based on my research, the schedule interval should be set to:
schedule_interval = '0 0 2 * *'
Now what worries my is the stuff discussed in airflow documentation. Based on what's discussed there:
Note that if you run a DAG on a schedule_interval of one day, the run
stamped 2016-01-01 will be trigger soon after 2016-01-01T23:59. In
other words, the job instance is started once the period it covers has
ended.
Let’s Repeat That The scheduler runs your job one schedule_interval
AFTER the start date, at the END of the period.
Does this mean that for monthly dags, everything will be delayed by one month? So for example the 2020-11-02 job will run on 2020-12-01 2359? If yes, how can I make sure that it runs exactly when it's supposed to?
Your interpretion is right, the DAG Run with execution_date=2020-11-02 will be triggered approximately on 2020-12-01 23:59. However, I think you don't need to be worried that the DAG is delayed or something, it still has a monthly schedule and will run every month. You rather need to take this logic into account when running a operator.
You can also simply work with other variables if you don't want to adapt the logic, for whatever reason:
{{ next_execution_date }} - the next execution date.

preventing autosys job to run on certain timing of the certain day

I have a job which runs everyday 4 times in an hour (total 48 times).
I want to prevent it from running only between 7 AM to 9 AM Sunday. How can I achieve it without creating two different jobs. I want to accomplish it in a single job. Please help.
Mention all the time the job should run in start_times like below
*replace .. with missing times
start_times: "00:00, 00:15, .... 06:30, 06:45, 9:15, 9:30, .. 23:45"
I suggest to create a calender defined as Every Sunday 07:00 till 09:00.
And then in the Job defination assign this calender to job attribute exclude_calendar along with your run_calendar.

Control-M avoid cyclic job from run before prev day's complete

I have a Control-M job that runs every 20 min. Everything works great during that day's run. The issue is when we auto-order the next days jobs. If the current day's jobs are running we get 2 copies of the jobs running at the same time.
Is there a way to not start the new job if the previous day's job is executing?
The job starts every 20 minutes, but how long does it run? Set the end window for "submit between" time a few minutes before the new day build.
Let's say your new day builds at 0400. Since the job is intended to run every 20 minutes, you can have it run as late as 0340. Set the "to" time in Activity Window to 0340 and the job won't autosubmit after that time. The new day will build at 0400 and the new version of the job will start then - 20 minutes after the previous start.
You can also add a control resource to the job to prevent two of them from running at the same time. I don't know another way to do it. That's not a can of worms I'd open unless the activity period settings just won't work the way you want them to.
If you're referring to last day's job execution bleeding into current day, causing resource contention, your best bet (as Rob pointed out) is to define a resource with max count of 1 to be required by the job, so next day job instance cannot start until prev day job completes and release the resource. Alternatively you can have the job post a Condition for order date + 1, and have order date condition also be an In condition for the job.

i want execute my previous days unexecute job first rather than today in Control-M

i am trying ordering my jobs into planing until jobs gets success,but when previous days jobs for that particular CTM table run then only today order jobs need to be run , i have added keep active for 10 days for each job.
thanks in advance
You can try adding an IN-CONDITION of the same job with PREV date, so that todays job will run only when yesterday's job has completed its run successfully.
If you want to run todays job even when yesterdays job fails, you can add a DO-STEP on failure, to create a condition which can be used by todays job to start running.

Running an Alfresco Action after one week a rule is executed

I wrote a script to run for an Alfresco rule. but I want the script to run after specific time ( I need the script to run after 1 week). any solution?
I read about Scheduled_Actions , is this feature useful?
Yes, in fact a Scheduled Action is likely your only option for for running something after a certain amount of time has elapsed.
At a high level your solution should look something like:
Your rule sets some aspect/property on the relevant node, say ruleDate, which is the date the original rule ran.
A scheduled action runs every day and detects nodes with a ruleDate 7 days or more in the past.
The scheduled action does whatever changes are required.
The scheduled action removes the ruleDate aspect/property.
Yes it is useful. You need to set up cron job to run scheduled task.
You can find more details on this link.

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