I have a SQLite database where I need to delete records from a many-to-many table, based on query results where 2 criteria for each row must be met.
As an example, take 2 tables :
oldEvents <select_query>
user_id | event_id qry_user_id | qry_event_id
---------+---------- -------------+-------------
1 | aaa 2 | aaa
2 | aaa 3 | bbb
2 | bbb 1 | ccc
3 | bbb
1 | ccc
3 | ccc
From table oldEvents, I want to delete each row that appears in the query, so as to end up with:
oldEvents
user_id | event_id
---------+----------
1 | aaa
2 | bbb
3 | ccc
Until now, I use a cumbersome DELETE query that concatenates the qry_user_id and qry_event_id, and uses them in an EXISTS sub-clause :
DELETE FROM oldEvents
WHERE EXISTS
(
SELECT user_id||event_id AS deleteCombo
FROM oldEvents
WHERE deleteCombo IN
(
SELECT qry_user_id||qry_event_id
FROM
<select_query>
)
)
It works, but is hardly readable, and wouldn't scale once more variables enter the scene.
I can't repeat the select_query inline in an AND-clause, because it is, itsself, a rather complicated query (triple-JOIN).
I could write the query data to a temporary table, but would rather not do that.
Anyone a suggestion on how to write a DELETE that accepts multiple WHERE criteria from a query ?
Enclose your query inside a CTE like this:
WITH cte(user_id, event_id) AS (
<your query here>
)
DELETE FROM oldEvents
WHERE (user_id, event_id) IN (SELECT user_id, event_id FROM cte);
See the demo.
Results:
SELECT * FROM oldEvents;
| user_id | event_id |
| ------- | -------- |
| 1 | aaa |
| 2 | bbb |
| 3 | ccc |
Related
I am updating a table, but I keep getting follwing error
ERROR: syntax error at or near "MERGE"
LINE 3: MERGE into
when i try to use a merge statement. I don't see anything obvious wrong with the syntax. can someone point out the obivous
MERGE into Table2 t2
using (select name, max(id) max_id from Table1 t1 group by name ) t1
on (t2.project_name=t1.name)
when matched then update set projectid=max_id where status='ongoing' ;
Table1
1 | alpha | 2021 |
2 | groundwork | 2020 |
3 | NETOS | 2021 |
5 | WebOPD | 2019 |
Table2
id | name | year | status | project name | projectID
1 | john | 2021 | ongoing | alpha | 1
2 | linda | 2021 | completed | NETOS | 3
3 | pat | 2021 | WebOPD | completed | 5
4 | tom | 2021 | ongoing | alpha | 1
version : PostgreSQL 13.6
The last line in your message says you use PostgreSQL. Tag you used (plsql) means Oracle. Which one is it, after all? I presume former, but - syntax you used is Oracle.
MERGE documentation for PostgreSQL says that
INTO can't be used
no parenthesis for ON clause
WHERE clause can't be used
See if something like this helps:
MERGE Table2 t2
using (select t1.name,
max(t1.id) max_id
from Table1 t1 join table2 t2 on t2.project_name = t1.name
where t2.status = 'ongoing'
group by name
) x
on t2.project_name = x.name
when matched then update set
t2.projectid = x.max_id ;
I've a SQLite database table with the following columns:
| day | place | visitors |
-------------------------------------
| 2021-05-01 | AAA | 20 |
| 2021-05-01 | BBB | 10 |
| 2021-05-01 | CCC | 3 |
| 2021-05-02 | AAA | 5 |
| 2021-05-02 | BBB | 7 |
| 2021-05-02 | CCC | 2 |
Now I would like to introduce a column 'rank' which indicates the rank according to the visitors each day. Expected table would look like:
| day | place | visitors | Rank |
------------------------------------------
| 2021-05-01 | AAA | 20 | 1 |
| 2021-05-01 | BBB | 10 | 2 |
| 2021-05-01 | CCC | 3 | 3 |
| 2021-05-02 | AAA | 5 | 2 |
| 2021-05-02 | BBB | 7 | 1 |
| 2021-05-02 | CCC | 2 | 3 |
Populating the data for the new column Rank can be done with a program like (Pseudocode).
for each i_day in all_days:
SELECT
ROW_NUMBER () OVER (ORDER BY `visitors` DESC) Day_Rank, place
FROM mytable
WHERE `day` = 'i_day'
for each i_place in all_places:
UPDATE mytable
SET rank= Day_Rank
WHERE `Day`='i_day'
AND place = 'i_place'
Since this line by line update is quite inefficient, I'm searching how to optimize this with a SQL sub query in combination with the UPDATE.
(does not work so far...)
for each i_day in all_days:
UPDATE mytable
SET rank= (
SELECT
ROW_NUMBER () OVER (ORDER BY `visitors` DESC) Day_Rank
FROM mytable
WHERE `day` = 'i_day'
)
Typically, this can be done with a subquery that counts the number of rows with visitors greater than the value of visitors of the current row:
UPDATE mytable
SET Day_Rank = (
SELECT COUNT(*) + 1
FROM mytable m
WHERE m.day = mytable.day AND m.visitors > mytable.visitors
);
Note that the result is actually what RANK() would return, if there are ties in the values of visitors.
See the demo.
Or, you could calculate the rankings with ROW_NUMBER() in a CTE and use it in a subquery:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY day ORDER BY visitors DESC) rn
FROM mytable
)
UPDATE mytable
SET Day_Rank = (SELECT rn FROM cte c WHERE (c.day, c.place) = (mytable.day, mytable.place));
See the demo.
Or, if your versipn of SQLite is 3.33.0+ you can use the join-like UPDATE...FROM... syntax:
UPDATE mytable AS m
SET Day_Rank = t.rn
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY day ORDER BY visitors DESC) rn
FROM mytable
) t
WHERE (t.day, t.place) = (m.day, m.place);
I am maintaining table structure like below.
sortid | id | name
1 | 1 | aa
3 | 2 | cc
4 | 3 | cc
2 | 4 | bb
5 | 5 | dd
Where sortid is maintained according to ascending order of name.
Now I want to update name 'dd' to 'aa', such way that sort id is also updated to its correct value.
Update table set name="bb" where name like "dd";
After updating my table should become like below.
sortid | id | name
1 | 1 | aa
4 | 2 | cc
5 | 3 | cc
3 | 4 | bb
2 | 5 | aa
That sortid is the number of rows that would be sorted before this row.
So you can compute it by counting rows:
UPDATE MyTable
SET sortid = (SELECT COUNT(*)
FROM MyTable AS T2
WHERE T2.name < MyTable.name) +
(SELECT COUNT(*)
FROM MyTable AS T2
WHERE T2.name = MyTable.name
AND T2.id <= MyTable.id);
(The second subquery resolves duplicate sortid values that would result from duplicate names.)
I have the following query.
SELECT a.link_field1 AS journo, count(a.link_id) as articles, AVG( b.vote_value ) AS score FROM dan_links a LEFT JOIN dan_votes b ON link_id = vote_link_id WHERE link_field1 <> '' and link_status NOT IN ('discard', 'spam', 'page') GROUP BY link_field1 ORDER BY link_field1, link_id
This query is returning a count of 3 for the first item in the list. What should be returned is
Journo | count | score
John S | 2 | 6.00
Joe B | 1 | 4
However for the first one John S, it returns a count of 3.
If I directly query
select * from dan_links where link_field1 = 'John S'
I get 2 records return as I would expect. I can't for the life of me figure out why the count is wrong, unless for some reason it is counting the records from the dan_vote table
How can I get the correct count, or is my query completely wrong?
EDIT: Contents of the tables
dan_links
link_id | link_field1 | link | source | link_status
1 | John S | http://test.com | test.com | approved
2 | John S | http://google.com | google | approved
3 | Joe B | http://facebook.com | facebook | approved
dan_votes
vote_id | link_id | vote_value
1 | 1 | 5
2 | 1 | 8
3 | 2 | 4
4 | 3 | 1
EDIT: it looks like it is counting the rows in the votes table for some reason
When you are doing a left outer join with the condition link_id = vote_link_id for every matching record one row is created, some thing like
link_id | link_field1 | link | source | link_status|vote_id|vote_value
1 | John S | http://test.com | test.com | approved|1|5
1 | John S | http://test.com | test.com | approved|2|8
2 | John S | http://google.com | google | approved|3|4
3 | Joe B | http://facebook.com | facebook | approved|4|1
Now when you do group by on link_field1, you get count as 3 for John S
Nested query might work
SELECT journo,count(linkid) as articles,AVG(score) FROM
(SELECT a.link_field1 AS journo, AVG( b.vote_value ) AS score, a.link_id as linkid
FROM dan_links a
LEFT JOIN dan_votes b
ON link_id = vote_link_id
WHERE link_field1 <> ''
and link_status NOT IN ('discard', 'spam', 'page')
GROUP BY link_id
ORDER BY link_field1, link_id) GROUP BY journo
The above query will give incorrect average as ((n1+n2)/2+n3)/2 != (n1+n2+n3)/3, so use the below query
SELECT journo,count(linkid) as articles, SUM(vote_sum)/SUM(count(linkid))
FROM
(SELECT a.link_field1 AS journo, SUM( b.vote_value ) AS vote_sum, a.link_id as linkid, count(a.link_id) as count_on_id
FROM dan_links a
LEFT JOIN dan_votes b
ON link_id = vote_link_id
WHERE link_field1 <> ''
and link_status NOT IN ('discard', 'spam', 'page')
GROUP BY link_id
ORDER BY link_field1, link_id) GROUP BY journo
Hope this helps.
I have two tables Department and Employee.
Department table looks like this:
ID DeptName
1 IT
2 CSE
3 ECE
Employee table :
ID DeptID EmployeeName Salary
1 1 John 10000
2 1 Bob 15000
3 2 Akon 12000
4 2 Smith 20000
Now I want to group the data in such a way that I get the following results which include these columns :
ID DeptName Employee
1 IT John,10000
Bob,15000
2 CSE Akon,12000
Smith,20000
Can we do something like this using SQL group functions or any other way?
Please help me.
Thanks,
Rajbir
This:
select final.deptId, d.deptName,
e3.employeename + ',' + cast(e3.salary as varchar) employee
from employee e3
left join (
select e1.id, e1.deptId from employee e1
left join employee e2
on e1.deptId = e2.deptId and e1.id > e2.id
where e2.id is null
) final on e3.id = final.id
left join department d on d.id = final.deptId
Results in:
+--------+----------+-------------+
| DEPTID | DEPTNAME | EMPLOYEE |
+--------+----------+-------------+
| 1 | IT | John,10000 |
| | | Bob,15000 |
| 2 | CSE | Akon,12000 |
| | | Smith,20000 |
+--------+----------+-------------+
Note that the "blank" values are actually filled with null values.
Let me know if you have any issue with it.