Is it possible to specify the hyperlink color within the main CSS properties statement like below? I have tried several variations and no luck.
width: 100%;
color: #FFF;
background-color: #693F18;
a.link-color: #fff;
There are several different ways to style a hyperlink: a for the link itself, along with the following pseudo-classes:
a:link - a normal, unvisited link
a:visited - a link the user has visited
a:hover - a link when the user mouses over it
a:active - a link the moment it is clicked
To change the colour, you're looking for the color property.
This can be seen in the following:
a {
color: cyan;
}
a:link {
color: blue;
}
a:visited {
color: red;
}
a:hover {
color: green;
}
a:active {
color: purple;
}
Link
Related
My Firefox is not showing the color for visited links:
a:link {
color: blue;
text-decoration: none;
}
a:visited {
color: green;
text-decoration: none;
}
a:hover {
color: cyan;
text-decoration: underline;
}
a:active {
color: yellow;
text-decoration: underline;
}
Test
The Link text is shown in blue, hitting it with the cursor changes to magenta, clicking it for a short time yellow - and after that blue again.
Where to find the problem?
Thank you.
It is related on the browser's chronic: This option must be activated, to see different colors! It's not really logical, as in an active session the pages visited can be seen by Menu > Chronic, even if that option is INactiv. Anyway, now it works!
I want my link only to change color after I click on it. I have added the appropriate a:link and a:visited pseudo-classes in the correct order. However, my link changes color when I refresh the page too and I don't want this.
I created a simple example for you
If you've never visited the link before, it will be black (default color)
If you've visited the link before, it will be blue
If you hover the link, it will be red
https://jsfiddle.net/ykrfqucw/1/
HTML:
emrerothzerg.com
CSS:
a{
color: black;
}
a:visited {
color: blue;
}
a:hover {
color: red;
}
a:active {
color: yellow;
}
SASS (if you like to have):
a {
color: black;
&:visited {
color: blue;
}
&:hover {
color: red;
}
&:active {
color: yellow;
}
}
#style {
background-color: red;
}
#style:focus {
background-color:yellow;
}
#style:visited {
background-color:yellow;
}
#style:active {
background-color:yellow;
}
Several ways to do it below. Hope it helps
Problem with Chrome when displaying my css styles:
The horizontal nav should have background grey and
text color black but on Chrome get maroon and text white.
On I.E 9 works fine but on Chrome not.
The style for the second nav looks ok.How do I resolve these conflicting styles.
Here is my codepen:
http://cdpn.io/uCgyF
add the shiv to your head
<script src="http://html5shiv.googlecode.com/svn/trunk/html5.js"></script>
Add id to the ul and style accordingly as in this fiddle
<ul id="firstNav">
nav #firstNav a:link,a:visited{
color: black;
background-color:grey;
display: block;
}
(skip to the bottom for tl;dr)
When I first loaded your pen, I saw things correctly. But then I clicked on one of the header links and saw the behavior you describe. That tells us that a :visited selector is probably the issue. Take a look at your css code (I removed some to help illustrate the point):
nav#navigation a:link, a:visited {
background-color:grey;
color: black;
}
aside a:link, a:visited {
background-color: maroon;
color: white;
}
the comma (,) doesn't do what you think it does. the comma in css is shorthand for writing the same definition twice, so if we didn't have that shorthand, your css would look like this:
nav#navigation a:link {
background-color:grey;
color: black;
}
a:visited { /* <-- oops! */
background-color:grey;
color: black;
}
aside a:link {
background-color: maroon;
color: white;
}
a:visited { /* <-- oops! */
background-color: maroon;
color: white;
}
with your css, every visited link on the entire site (whether it is in your nav or not) will be white on maroon.
as a general rule of thumb, add a new-line after each comma in css. It will help you see these errors more easily.
tl;dr: do this:
nav#navigation a:link,
nav#navigation a:visited {
background-color:grey;
color: black;
}
aside a:link,
aside a:visited {
background-color: maroon;
color: white;
}
Is there a way of styling links using a id or a class without having to create a new selector for each individual element? for example
something like this or close to this would be preferable
#logo {
a: link {color: black}
a: visited{color: black}
a: hover{color: black}
}
However, the above syntax does not work instead all i can find is
#logo a:hover {
color: black;
}
#logo a:visited {
color: white
}
I feel like there's an easier way than this.
Heres how to do it to all links
I believe it should work:
#logo a:link,
#logo a:visited,
#logo a:hover {
color: black;
}
Not all browser support the above methodology of separating the tag styles with class or ID when you are dealing with different style in CSS with tag in single page.
One can follow below method:
**If using ID with Field**
a:link#myID {
color: green;
background-color: transparent;
text-decoration: none;
}
a:visited#myID {
color: pink;
background-color: transparent;
text-decoration: none;
}
a:hover#myID {
color: red;
background-color: transparent;
text-decoration: underline;
}
a:active#myID {
color: yellow;
background-color: transparent;
text-decoration: underline;
}
Click Here
**If using Class with Field**
a:link.myClass {
color: green;
background-color: transparent;
text-decoration: none;
}
a:visited.myClass {
color: pink;
background-color: transparent;
text-decoration: none;
}
a:hover.myClass {
color: red;
background-color: transparent;
text-decoration: underline;
}
a:active.lx {
color: yellow;
background-color: transparent;
text-decoration: underline;
}
Click Here
Not directly in css, but there are some projects that extend css
Check out sass:
http://sass-lang.com
I also believe current CSS syntax is not all that optimal. My personal choice is to go with something like LESS where you get much more intuitive and compact syntax to style your work.
With pure CSS you must specify each pseudo-selector but you can group them to apply the same style attributes;
#logo a:link,
#logo a:visited,
#logo a:hover {
color: black;
}
Beware that The order of link pseudo-classes matters.
I've a button and I wanted to know if it is possible to make the css bellow shorter.
.button a:link, .button a:visited, .button a:hover, .button a:active {
color: #000;
text-decoration: none;
}
I mean maybe:
.button a:* {
color: #000;
text-decoration: none;
}
Maybe there isn't any shorter way, but I just wanted to know.
I found something like this out:
.button a:link:visited:hover:active {
color: #000;
text-decoration: none;
}
But it wasn't working, don't know why..
For information - I've general css for a in the top of the file:
a:link {
color: #DA5632;
}
a:visited {
color: #CE3408;
}
a:hover {
color: #289BF8;
}
a:active {
color: #CE3408;
}
So the button class a should overwrite the main a css.
.button a is all you need
I always set a default style on a, and target pseudo classes only when I need to have a different effect.
Edit to include fix from comments:
Because a default style for the a element is declared like:
a:link {
color: #DA5632;
}
a:visited {
color: #CE3408;
}
a:hover {
color: #289BF8;
}
a:active {
color: #CE3408;
}
at the top of the stylesheet, we need to make it body .button a by increasing selectivity we increase the importance of the styles applied.
Here are some things to try
make sure that your stylesheet has a rule for ".button a" - also make sure this stylesheet is included after the global one defining rules for "a".
If that doesn't work, try being more specific, as in: ".button > a", only selecting direct descendants.
If THAT doesn't work, while it's bad practice, you could always mark your styles as important, like so:
color: #fff !important;
this will demand that they are parsed last.