hi I has date format and I want converted to correct GMT date :
<YYMMDDhhmmssNNN><C|D|G|H>
Sample value on that date:
210204215026000C
I get this explanation for part NNN :
NNN If flag is C or D then NNN is the number of hours relativeto GMT,
if flag is G or H, NNN is the number of quarter hours relative to GMT
C|D|G|H C and G = Ahead of GMT, D and H = Behind GMT
but I did not get how number of hours relative to GMT can present on 3 digits ? it should be in 2 digit as i knew the offset for hours related to GMT is from 0 to 23 , and also what quarter hours relative to GMT mean ?
I want to use Scala or Java.
I don’t know why they set 3 digits aside for the offset. I agree with you that 2 digits suffice for all cases. Maybe they just wanted to be very sure they would never run of out space, and maybe they even overdid this a bit. 3 digits is not a problem as long as the actual values are within the range that java.time.ZoneOffset can handle, +/-18 hours. In your example NNN is 000, so 0 hours from GMT, which certainly is OK and trivial to handle.
A quarter hour is a quarter of an hour. As Salman A mentioned in a comment, 22 quarter hours ahead of Greenwich means an offset of +05:30, currently used in Sri Lanka and India. If the producer of the string wants to use this option, they can give numbers up to 72 (still comfortably within 2 digits). 18 * 4 = 72, so 18 hours equals 72 quarter hours. To imagine a situation where 2 digits would be too little, think an offset of 25 hours. I wouldn’t think it realistic, on the other hand no one can guarantee that it will never happen.
Java solution: how to parse and convert to GMT time
I am using these constants:
private static final Pattern DATE_PATTERN
= Pattern.compile("(\\d{12})(\\d{3})(\\w)");
private static final DateTimeFormatter FORMATTER
= DateTimeFormatter.ofPattern("uuMMddHHmmss");
private static final int SECONDS_IN_A_QUARTER_HOUR
= Math.toIntExact(Duration.ofHours(1).dividedBy(4).getSeconds());
Parse and convert like this:
String sampleValue = "210204215026000C";
Matcher matcher = DATE_PATTERN.matcher(sampleValue);
if (matcher.matches()) {
LocalDateTime ldt = LocalDateTime.parse(matcher.group(1), FORMATTER);
int offsetAmount = Integer.parseInt(matcher.group(2));
char flag = matcher.group(3).charAt(0);
// offset amount denotes either hours or quarter hours
boolean quarterHours = flag == 'G' || flag == 'H';
boolean negative = flag == 'D' || flag == 'H';
if (negative) {
offsetAmount = -offsetAmount;
}
ZoneOffset offset = quarterHours
? ZoneOffset.ofTotalSeconds(offsetAmount * SECONDS_IN_A_QUARTER_HOUR)
: ZoneOffset.ofHours(offsetAmount);
OffsetDateTime dateTime = ldt.atOffset(offset);
OffsetDateTime gmtDateTime = dateTime.withOffsetSameInstant(ZoneOffset.UTC);
System.out.println("GMT time: " + gmtDateTime);
}
else {
System.out.println("Invalid value: " + sampleValue);
}
Output is:
GMT time: 2021-02-04T21:50:26Z
I think my code covers all valid cases. You will probably want to validate that the flag is indeed C, D, G or H, and also handle the potential DateTimeException and NumberFormatException from the parsing and creating the ZoneOffset (NumberFormatException should not happen).
formatCalendarDate = function (dateTime) {
return moment.utc(dateTime).format('LLL');
};
It displays: "28 februari 2013 09:24"
But I would like to remove the time at the end. How can I do that?
I'm using Moment.js.
Sorry to jump in so late, but if you want to remove the time portion of a moment() rather than formatting it, then the code is:
.startOf('day')
Ref: http://momentjs.com/docs/#/manipulating/start-of/
Use format('LL')
Depending on what you're trying to do with it, format('LL') could do the trick. It produces something like this:
Moment().format('LL'); // => April 29, 2016
The correct way would be to specify the input as per your requirement which will give you more flexibility.
The present definition includes the following
LTS : 'h:mm:ss A',
LT : 'h:mm A',
L : 'MM/DD/YYYY',
LL : 'MMMM D, YYYY',
LLL : 'MMMM D, YYYY h:mm A',
LLLL : 'dddd, MMMM D, YYYY h:mm A'
You can use any of these or change the input passed into moment().format().
For example, for your case you can pass moment.utc(dateTime).format('MMMM D, YYYY').
Okay, so I know I'm way late to the party. Like 6 years late but this was something I needed to figure out and have it formatted YYYY-MM-DD.
moment().format(moment.HTML5_FMT.DATE); // 2019-11-08
You can also pass in a parameter like, 2019-11-08T17:44:56.144.
moment("2019-11-08T17:44:56.144").format(moment.HTML5_FMT.DATE); // 2019-11-08
https://momentjs.com/docs/#/parsing/special-formats/
You can also use this format:
moment().format('ddd, ll'); // Wed, Jan 4, 2017
formatCalendarDate = function (dateTime) {
return moment.utc(dateTime).format('LL')
}
Look at these Examples.
Format Dates
moment().format('MMMM Do YYYY, h:mm:ss a'); // December 7th 2020, 9:58:18 am
moment().format('dddd'); // Monday
moment().format("MMM Do YY"); // Dec 7th 20
moment().format('YYYY [escaped] YYYY'); // 2020 escaped 2020
moment().format(); // 2020-12-07T09:58:18+05:30
Relative Time
moment("20111031", "YYYYMMDD").fromNow(); // 9 years ago
moment("20120620", "YYYYMMDD").fromNow(); // 8 years ago
moment().startOf('day').fromNow(); // 10 hours ago
moment().endOf('day').fromNow(); // in 14 hours
moment().startOf('hour').fromNow(); // an hour ago
Calendar Time
moment().subtract(10, 'days').calendar(); // 11/27/2020
moment().subtract(6, 'days').calendar(); // Last Tuesday at 9:58 AM
moment().subtract(3, 'days').calendar(); // Last Friday at 9:58 AM
moment().subtract(1, 'days').calendar(); // Yesterday at 9:58 AM
moment().calendar(); // Today at 9:58 AM
moment().add(1, 'days').calendar(); // Tomorrow at 9:58 AM
moment().add(3, 'days').calendar(); // Thursday at 9:58 AM
moment().add(10, 'days').calendar(); // 12/17/2020
Multiple Locale Support
moment.locale(); // en
moment().format('LT'); // 9:58 AM
moment().format('LTS'); // 9:58:18 AM
moment().format('L'); // 12/07/2020
moment().format('l'); // 12/7/2020
moment().format('LL'); // December 7, 2020
moment().format('ll'); // Dec 7, 2020
moment().format('LLL'); // December 7, 2020 9:58 AM
moment().format('lll'); // Dec 7, 2020 9:58 AM
moment().format('LLLL'); // Monday, December 7, 2020 9:58 AM
moment().format('llll'); // Mon, Dec 7, 2020 9:58 AM
Whenever I use the moment.js library I specify the desired format this way:
moment(<your Date goes here>).format("DD-MMM-YYYY")
or
moment(<your Date goes here>).format("DD/MMM/YYYY")
... etc I hope you get the idea
Inside the format function, you put the desired format. The example above will get rid of all unwanted elements from the date such as minutes and seconds
With newer versions of moment.js you can also do this:
var dateTime = moment();
var dateValue = moment({
year: dateTime.year(),
month: dateTime.month(),
day: dateTime.date()
});
See: http://momentjs.com/docs/#/parsing/object/.
You can use this constructor
moment({h:0, m:0, s:0, ms:0})
http://momentjs.com/docs/#/parsing/object/
console.log( moment().format('YYYY-MM-DD HH:mm:ss') )
console.log( moment({h:0, m:0, s:0, ms:0}).format('YYYY-MM-DD HH:mm:ss') )
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>
For people like me want the long date format (LLLL) but without the time of day, there's a GitHub issue for that: https://github.com/moment/moment/issues/2505. For now, there's a workaround:
var localeData = moment.localeData( moment.locale() ),
llll = localeData.longDateFormat( 'llll' ),
lll = localeData.longDateFormat( 'lll' ),
ll = localeData.longDateFormat( 'll' ),
longDateFormat = llll.replace( lll.replace( ll, '' ), '' );
var formattedDate = myMoment.format(longDateFormat);
Try this:
moment.format().split("T")[0]
The thing is - you can run into an issue with timezones. For example, if you parse date like this: '2022-02-26T00:36:21+01:00' it may turn into '25/02/2022' As a solution if your date is in ISO format you can just cut off the time portion from the string, like this:
moment('2022-02-26T00:36:21+01:00'.split('T')[0]).utc().format('DD/MM/YYYY')
This solution is quite blunt, so be careful with string format.
This format works pretty fine
const date = new Date();
const myFormat= 'YYYY-MM-DD';
const myDate = moment(date, 'YYYYMMDDTHHmmss').format(myFormat);
Try
new Date().toDateString()
Result - "Fri Jun 17 2022"
This worked perfectly for me:
moment().format('YYYY-MM-DD')
moment(date).format(DateFormat)
Here DateFormat should be DateFormat = 'YYYY-MM-DD'
I'm working on a Parser which Parses log files from a game so I can do analysis on auctions made within the game, however the date format that's being written by the logger seems to be causing problems as the format seems to be custom written for the logger, an example datetime stamp looks like: [Wed Nov 23 23:26:10 2016] I try to Parse it with:
func (r *AuctionReader) extractSaleInformation(line string) {
fmt.Println("Extracting information from: ", line)
// Format mask for output
layout := "DD-MM-YYYY hh:mm:ss"
// Replace the square brackets so we're just left with the date-time string
date := strings.TrimSpace(strings.Replace((strings.Split(line, "]")[0]), "[", "", -1))
fmt.Println(time.Parse(date, layout))
}
When I attempt to Parse the above date-time string I get the following error:
0001-01-01 00:00:00 +0000 UTC parsing time "DD-MM-YYYY hh:mm:ss" as "Wed Nov 23 23:26:10 2016": cannot parse "DD-MM-YYYY hh:mm:ss" as "Wed Nov "
How am I able to get the parser to recognise this seemingly custom format, I will be saving this data to Mongo so I don't want to store the auction time as a string as I want to query the timestamps individually.
Golang handle all date formatting in a unique way - it uses the reference time Mon Jan 2 15:04:05 MST 2006 (01/02 03:04:05PM '06 -0700) to show the pattern with which to format/parse a given time/string.
So, to read the format "Wed Nov 23 23:26:10 2016" you would put the reference date into that format: "Mon Jan 2 15:04:05 2006", and then do:
t, _ := time.Parse("Mon Jan 2 15:04:05 2006", "Wed Nov 23 23:26:10 2016")
Then, to output it in the given format, if you wanted the format DD-MM-YYYY hh:mm:ss, you would put the reference time into that format: 02-01-2006 15:04:05, and then do:
t.Format("02-01-2006 15:04:05")
https://play.golang.org/p/VO5413Z7-z
So basically, the main change is
// Format mask for output
layout := "DD-MM-YYYY hh:mm:ss"
should be
// Format mask for output
layout := "02-01-2006 15:04:05"
and
time.Parse(date, layout)
should be
time.Parse(layout, date)
Actually in my Flex Application DataGrid column getting one value like Sat Sep 1 00:00:00 GMT+0530 2012
how to convert this String as Date like 2012/09/01
i'm doing converting String Date but it giving null value...hear is my sample code
var startDS:String = saveDataGrid.selectedItem.startDate;
var sDate:Date=DateField.stringToDate(startDs,"YYYY/MM/DD");
Alert.show(sDate+"--===--"+startDS);//Alert giving null--===--Sat Sep 1 00:00:00 GMT+0530 2012
please help...
var startDS:String = "10022008";
var sDate:Date=DateField.stringToDate(startDS,"MMDDYYYY");
Alert.show(sDate+"--===--"+startDS);
You might also need to have a glance at http://livedocs.adobe.com/flex/3/html/help.html?content=formatters_4.html
output will be, "Thu Oct 2 00:00:00 GMT+0530 2008--===--10022008"
OK so for example, today is Tuesday, Feb 02. Well the equivalent "Tuesday" from last year was on Feb 03.
How can I find this out programmatically?
Thanks!!
According to Google, there are 604,800,000 milliseconds in a week. That times 52 should give you the same day of the week a year later (right?).
For example:
var date:Date = new Date(2010, 1, 2);
trace(date);
date.setMilliseconds(date.milliseconds - 604800000 * 52);
trace(date);
Output:
Tue Feb 2 00:00:00 GMT-0800 2010
Tue Feb 3 00:00:00 GMT-0800 2009
Just my two cents. I don't like the idea, that the second answer assumes 52 weeks in a year, it will work for a single year, but is a solution to only this exact problem - eg. if you want to check the same thing moving back 10 years it won't work. I'd do it like this:
var today:Date = new Date();
// Here we store the day of the week
var currentDay:int = today.day;
trace (today);
const milisecondsInADay:uint = 1000*60*60*24;
// Here we move back a year, but we can just as well move back 10 years
// or 2 months
today.fullYear -= 1;
// Find the closest date that is the same day of the week as current day
today.time -= milisecondsInADay*(today.day-currentDay);
trace (today);
returns:
Tue Feb 2 21:13:18 GMT+0100 2010
Tue Feb 3 21:13:18 GMT+0100 2009