I have a format 0.00% and 1.99% but would like to convert to 0.00 and 1.99. I have used Format(number, "#,##0.00") but no luck. Can someone please help?
Since the column values contain the char % this means that its data type is TEXT, so you can use REPLACE():
REPLACE(number, '%', '')
or if needed:
TRIM(REPLACE(number, '%', ''))
and if you want it as a number use also VAL():
VAL(REPLACE(number, '%', ''))
Related
I have an SQLite file containing words and their phonetic transcription as follows:
Source (sɔɹs)
Song (sɔŋ)
Daughter (ˈdɔtəɹ)
...
I want to change every 'ɔ' character with 'a' character if 'ɔ' isn't followed by "ŋ" or "ɹ"
My code so far:
UPDATE words
SET phonetictranscription_ame = replace(phonetictranscription_ame, "ɔ", "a")
WHERE phonetictranscription_ame NOT IN ("ɔŋ", "ɔɹ")
This code replaces the 'ɔ' character with 'a' character but it also replaces the 'ɔ's with words including "ɔŋ" and "ɔɹ". Is something wrong with my code?
First, replace all occurrences of 'ɔŋ' and 'ɔɹ' with symbols that you are sure do not exist in the column (I chose '|1' and '|2' but I'm not a linguist, so you can change them).
Then replace all 'ɔ's to 'a's.
Finally restore back the 'ɔŋ's and 'ɔɹ's:
UPDATE words
SET phonetictranscription_ame =
REPLACE(
REPLACE(
REPLACE(
REPLACE(
REPLACE(
phonetictranscription_ame, 'ɔŋ', '|1'
), 'ɔɹ', '|2'
), 'ɔ', 'a'
), '|1', 'ɔŋ'
), '|2', 'ɔɹ'
)
WHERE phonetictranscription_ame LIKE '%ɔ%';
See the demo.
Hi I am trying to convert some xml to csv using xquery and found a previous post that helped me get to this point:
for $b in /root/Result
return
concat(escape-html-uri(string-join(($b/HolidayEndDate,
$b/HolidayType,
$b/FirstName,
$b/AllowanceRemainingDays,
$b/HolidayStartDate,
$b/EmployeeId,
$b/AllowanceDays,
$b/LastName,
$b/HolidayDurationDays
)
/normalize-space(),
",")
),
codepoints-to-string(10))
This returns all of the data as required but no Header row. Is there a simple addition to the above code that would also return the header row? Thanks. :)
Since your query returns a sequence of lines, you can just prepend another line before the FLWOR expression:
"HolidayEndDate,HolidayType,FirstName,AllowanceRemainingDays,HolidayStartDate,EmployeeId,AllowanceDays,LastName,HolidayDurationDays
",
for $b in /root/Result
return
concat(escape-html-uri(string-join(($b/HolidayEndDate,
$b/HolidayType,
$b/FirstName,
$b/AllowanceRemainingDays,
$b/HolidayStartDate,
$b/EmployeeId,
$b/AllowanceDays,
$b/LastName,
$b/HolidayDurationDays
)
/normalize-space(),
",")
),
codepoints-to-string(10))
Because nested sequences are flattened (i.e. concatenated) in XQuery, this results in one output sequence including the header. Note also that I used a character entity '
' for the newline character, which is much shorter than codepoints-to-string(10).
concat("HolidayEndDate,HolidayType,FirstName,AllowanceRemainingDays,HolidayStartDate,EmployeeId,AllowanceDays,LastName,HolidayDurationDays
",
string-join(
for $b in /root/Result
return
concat(escape-html-uri(string-join(($b/HolidayEndDate,
$b/HolidayType,
$b/FirstName,
$b/AllowanceRemainingDays,
$b/HolidayStartDate,
$b/EmployeeId,
$b/AllowanceDays,
$b/LastName,
$b/HolidayDurationDays
)
/normalize-space(),
",")
),
codepoints-to-string(10)), "")
)
I am checking if a string contains any special characters. This is what I have, and its not working,
if(grepl('^\\[:punct:]', val))
So if anybody can tell me what I am missing, that will be helpful.
Special characters
~ ` ! ## $ % ^ & * | : ; , ." |
As #thelatemail pointed out in the comments you can use:
grepl('[^[:punct:]]', val)
which will result in TRUE or FALSE for each value in your vector. You can add sum() to the beginning of the statement to get the total number of these cases.
You can also use:
grepl('[^[:alnum:]]', val)
which will check for any value that is not a letter or a number.
I have the following strings:
F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_East_A.dat
F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_Froemke-Hoy.dat
and from each I want to extract the three variables, 1. SWIR32 2. the date and 3. the text following the date. I want to automate this process for about 200 files, so individually selecting the locations won't exactly work for me.
so I want:
variable1=SWIR32
variable2=2005210
variable3=East_A
variable4=SWIR32
variable5=2005210
variable6=Froemke-Hoy
I am going to be using these to add titles to graphs later on, but since the position of the text in each string varies I am unsure how to do this using strmid
I think you want to use a combination of STRPOS and STRSPLIT. Something like the following:
s = ['F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_East_A.dat', $
'F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_Froemke-Hoy.dat']
name = STRARR(s.length)
date = name
txt = name
foreach sub, s, i do begin
sub = STRMID(sub, 1+STRPOS(sub, '\', /REVERSE_SEARCH))
parts = STRSPLIT(sub, '_', /EXTRACT)
name[i] = parts[0]
date[i] = parts[1]
txt[i] = STRJOIN(parts[2:*], '_')
endforeach
You could also do this with a regular expression (using just STRSPLIT) but regular expressions tend to be complicated and error prone.
Hope this helps!
I'm working to grab two different elements in a string.
The string look like this,
str <- c('a_abc', 'b_abc', 'abc', 'z_zxy', 'x_zxy', 'zxy')
I have tried with the different options in ?grep, but I can't get it right, 'm doing something like this,
grep('[_abc]:[_zxy]',str, value = TRUE)
and what I would like is,
[1] "a_abc" "b_abc" "z_zxy" "x_zxy"
any help would be appreciated.
Use normal parentheses (, not the square brackets [
grep('_(abc|zxy)',str, value = TRUE)
[1] "a_abc" "b_abc" "z_zxy" "x_zxy"
To make the grep a bit more flexible, you could do something like:
grep('_.{3}$',str, value = TRUE)
Which will match an underscore _ followed by any character . three times {3} followed immediately by the end of the string $
this should work: grep('_abc|_zxy', str, value=T)
X|Y matches when either X matches or Y matches
In this case just doing:
str[grep("_",str)]
will work... is it more complicated in your specific case?