Create a two new column by mapping multiple column - r

Question

How to match columns in R and extract value. As an example: I want to match on the basis of Name and City columns of dataframe_one with dataframe_two and then return the output with two another column temp and ID. If it matches it should return TRUE and ID too.
My input is:
dataframe_one
Name City
Sarah ON
David BC
John KN
Diana AN
Judy ON
dataframe_two
Name City ID
Dave ON 1092
Diana AN 2314
Judy ON 1290
Ari KN 1450
Shanu MN 1983
I want the output to be
Name City temp ID
Sarah ON FALSE NA
David BC TRUE 1450
John KN TRUE 1983
Diana AN FALSE NA
Judy ON FALSE NA

Answer 1

One thing that makes answering questions of this type easier is if you at least put the data frames in R, like so:
df1 <- data.frame(stringsAsFactors=FALSE,
Name = c("Sarah", "David", "John", "Diana", "Judy"),
City = c("ON", "BC", "KN", "AN", "ON")
)
df2 <- data.frame(stringsAsFactors=FALSE,
Name = c("Dave", "Diana", "Judy", "Ari", "Shanyu"),
City = c("ON", "AN", "ON", "KN", "MN"),
ID = c(1092, 2314, 1290, 1450, 1983)
)
Then search existing Stack Overflow questions that have answered similar questions (e.g. How to join (merge) data frames (inner, outer, left, right)).
Given that neither of your original dfs contain the column "Temp" you would need to create it in the joined (merged) data frame.
We'll be able to help a lot more if you at least make a start and then the community will help you troubleshoot.
That being said, I can't for the life of me figure out how you would generate your output df from the inputs.

Answer 2

Using biomiha code to generate df1 and df2:
df1 <- data.frame(stringsAsFactors=FALSE,
Name = c("Sarah", "David", "John", "Diana", "Judy"),
City = c("ON", "BC", "KN", "AN", "ON")
)
df2 <- data.frame(stringsAsFactors=FALSE,
Name = c("Dave", "Diana", "Judy", "Ari", "Shanyu"),
City = c("ON", "AN", "ON", "KN", "MN"),
ID = c(1092, 2314, 1290, 1450, 1983)
)
you may try:
library(dplyr)
df1 %>%
left_join(df2, by = c("Name" = "Name", "City" = "City")) %>%
mutate(temp = !is.na(ID))
gives the output:
Name City ID temp
1 Sarah ON NA FALSE
2 David BC NA FALSE
3 John KN NA FALSE
4 Diana AN 2314 TRUE
5 Judy ON 1290 TRUE