How to make animated, gradient filled, SVG donut chart - css

I was trying to find clean simple solution to create SVG kind of donut charts with gradient fill going along the edge of the circle with the possibility to animate it from 0% to x% and I found out that there's no easy way and no ready copy & paste solution. Most solution used one linear gradient, which didn't help in my case or were over complicated.
The kind of (static) result I expected to get was:

So after some research and work I created this solution which I decided to share it with you.
It is based on the prozorov's solution. His circle wasn't 360deg and lacked the needed animation part. It isn't true gradient going with the stroke around the edge of the circle (which is not easy to do with SVG) but rather two linear gradients put together, but for most cases that trick does it.
And here's the complete solution:
.animated {
animation: dash 5s infinite;
}
#keyframes dash {
0% {
stroke-dashoffset: 0;
}
50% {
stroke-dashoffset: 1570;
}
100% {
stroke-dashoffset: 0;
}
}
<svg xmlns="http://www.w3.org/2000/svg" version="1.1" height="800" width="800">
<defs>
<linearGradient id="Gradient1" gradientTransform="rotate(90)">
<stop offset="0%" stop-color="#ff0000"/>
<stop offset="100%" stop-color="#00ff00"/>
</linearGradient>
<linearGradient id="Gradient2" gradientTransform="rotate(90)">
<stop offset="0%" stop-color="#0000ff"/>
<stop offset="100%" stop-color="#00ff00"/>
</linearGradient>
<pattern id="Pattern" x="0" y="0" width="600" height="600" patternUnits="userSpaceOnUse">
<g transform="rotate(0, 300, 300)">
<rect shape-rendering="crispEdges" x="0" y="0" width="300" height="600" fill="url(#Gradient1)"/>
<rect shape-rendering="crispEdges" x="300" y="0" width="300" height="600" fill="url(#Gradient2)"/>
</g>
</pattern>
</defs>
<path id='arc5' class="animated"
style="stroke: url(#Pattern);" fill='transparent'
stroke-dasharray="1570 1570"
stroke-dashoffset="0"
stroke-width='60'
d='M 300 58 A 250 250 0 1 1 299.99 58'/>
</svg
And link to JS Fiddle

Related

Rotating the stroke but not the filling of a svg circle

I've followed this tuto in order to implement a progress ring for my Vue application. I still have an extra requirement: fill the circle with an image. That's the point I've reached to, using a pattern (copy pasted from my browser in order to avoid adding the extra complexity of Vue property evaluations):
HTML
<div>
<svg
height="600"
width="600">
<defs>
<pattern id="service" x="0%" y="0%" height="100%" width="100%"
viewBox="0 0 100 100">
<image x="5" y="5" width="90" height="90" href="https://upload.wikimedia.org/wikipedia/commons/thumb/7/7a/Selfie_icon.svg/2000px-Selfie_icon.svg.png"></image>
</pattern>
<linearGradient id="gradient">
<stop offset="0%" stop-color="#f6921e"/>
<stop offset="100%" stop-color="#f6921e88"/>
</linearGradient>
</defs>
<circle
stroke="url(#gradient)"
stroke-dasharray="1709.0264035528476 1709.0264035528476"
style="stroke-dashoffset: 512.708;"
stroke-linecap="round"
stroke-width="14"
fill="url(#service)"
r="272"
cx="300"
cy="300"
/>
</svg>
</div>
CSS
circle {
transition: stroke-dashoffset 0.35s;
transform: rotate(-90deg);
transform-origin: 50% 50%;
}
However, I find that rotating the circle obviously rotates its filling too.
Is there any way to overcome this problem? Why does the example rotate the entire SVG to make the circle gap be in the upside?
Codepen
You can use another circle in your SVG, one for the border and one for the background, then rotate just the circle with the border:
.circle-border {
transition: stroke-dashoffset 0.35s;
transform: rotate(-90deg);
transform-origin: 50% 50%;
}
<!-- begin snippet: js hide: false console: true babel: false -->
<div>
<svg height="600" width="600">
<defs>
<pattern id="service" x="0%" y="0%" height="100%" width="100%" viewBox="0 0 100 100">
<image x="5" y="5" width="90" height="90" href="https://upload.wikimedia.org/wikipedia/commons/thumb/7/7a/Selfie_icon.svg/2000px-Selfie_icon.svg.png"></image>
</pattern>
<linearGradient id="gradient">
<stop offset="0%" stop-color="#f6921e"/>
<stop offset="100%" stop-color="#f6921e88"/>
</linearGradient>
</defs>
<circle
stroke="url(#gradient)"
stroke-dasharray="1709.0264035528476 1709.0264035528476"
style="stroke-dashoffset: 512.708;"
stroke-linecap="round"
stroke-width="14"
fill="transparent"
class="circle-border"
r="272"
cx="300"
cy="300"
/>
<circle
stroke-width="0"
fill="url(#service)"
class="circle-bg"
r="272"
cx="300"
cy="300"
/>
</svg>
</div>

Shine/Sheen effect on hover for SVG?

I'm new to SVG animation and I was hoping someone could help me achieve an effect.
I have two questions actually:
1.) As you can see in this codepen. I have an CSS keyframe animation that draws out a shape, fill a flat color then ends in a SVG gradient. However it doesn't properly transition to that gradient (it just kinda 'pops' to that state at the end)
CSS Animation
#-webkit-keyframes dash {
0% {stroke-dashoffset: 900; fill:#FFF;}
85% {stroke-dashoffset: 0; fill:#FFF;}
90% {fill:#fce669;}
100% {fill:url(#glow);}
}
SVG '#Glow' gradient
<defs>
<linearGradient id = "glow" x1 = "0%" y1 = "0%" x2 = "100%" y2 = "100%">
<stop stop-color = "#fce669" offset = "0%"/>
<stop stop-color = "#fff" offset = "100%"/>
</linearGradient>
</defs>
Is it possible to transition between these states?
Okay that aside, here's my real question:
2.) Ideally, after the drawing animation is complete, I'd like there to be a sheen effect that is also triggered on hover. Like this codepen. I tried animating the color stops on the gradient to achieve this effect and it's pretty terrible.
http://codepen.io/StuffieStephie/pen/eJdWeJ
I really have no idea how to proceed with this. Can someone point me in the right direction?
You seem to came in some hard place here...
I am not sure about the specs recommendations for this, but from tests, it seems that svg's linearGradient can't be animated through CSS. I guess that it's because it is seen as an image, just like CSS gradients are seen as background-image.
Note that Firefox won't even execute the animation if you place a <funcIRI> into it (url(#yourElement)). Once again, I couldn't find the specs about this, so can't tell for sure if that's a bug, but since Chrome is deprecating SMIL, that will probably become an issue quite soon.
But for today, the only workaround I can give you, is to use SMIL.
You can use <animate> elements to animate your linearGradient. In the example above, I do animate only one stop-color of the #glow gradient.
I also used an other animated linear-gradient to the shine effect. This linear-gradient is then applied as the fill attribute of a mask, making the black part of the gradient the only masking of the <mask> element.
Note that chrome only do render offset's animation if you do use absolute values...
svg {
max-width: 100%;
max-height: 100%;
position: absolute;
top: 0;
left: 0;
right: 0;
bottom: 0;
margin: auto;
}
.st0 {
stroke-dasharray: 900;
stroke-dashoffset: 0;
fill: url(#glow);
animation: dash 4s linear alternate;
-webkit-animation: dash 4s linear alternate;
}
#keyframes dash {
0% {
stroke-dashoffset: 900;
}
85% {
stroke-dashoffset: 0;
}
}
#-webkit-keyframes dash {
0% {
stroke-dashoffset: 900;
}
85% {
stroke-dashoffset: 0;
}
}
.st2 {
fill: #FFF;
}
<svg version="1.1" id="starmoon" class="icon" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" viewBox="0 0 254.7 220.8" style="enable-background:new 0 0 254.7 220.8;" xml:space="preserve">
<style type="text/css">
.st0 {
stroke: #EFA441;
stroke-miterlimit: 10;
}
</style>
<defs>
<linearGradient id="glow" x1="0%" y1="0%" x2="100%" y2="100%">
<stop stop-color="#FFF" offset="0%">
<animate id="color" attributeName="stop-color" from="#fff" to="#fce669" dur="0.8s" begin="3.2s" fill="freeze" />
</stop>
<stop stop-color="#fff" offset="100%" />
</linearGradient>
<!-- the gradient used by the mask -->
<linearGradient id="shine" x1="0%" y1="0%" x2="100%" y2="100%">
<stop stop-color="white" offset="-10%">
<animate attributeName="offset" values="-.05;.95" dur="2s" begin="color.end" />
</stop>
<stop stop-color="black" offset="-5%">
<animate attributeName="offset" values="0;1" dur="2s" begin="color.end" />
</stop>
<stop stop-color="white" offset="0%">
<animate attributeName="offset" values=".05;1.05" dur="2s" begin="color.end" />
</stop>
</linearGradient>
<mask id="myShiningMask">
<rect x="0" y="0" width="100%" height="100%" fill="url(#shine)" />
</mask>
</defs>
<path fill="url(#glow)" class="st0 icon" d="M169,69.1l5.4-5.4c1.6-1.6,0.8-4.3-1.5-4.7l-42.6-7.6c-0.9-0.2-1.6-0.7-2-1.5l-19.7-38.4c-1-2-3.9-2-5,0
L83.5,49.4c-0.4,0.8-1.2,1.3-2,1.4l-42.7,6.5c-2.2,0.3-3.2,3.1-1.6,4.7L67.3,93c0.6,0.6,0.9,1.5,0.8,2.4l-6.7,42.3
c-0.4,2.2,1.9,3.9,4,3l38.9-18.7c0.8-0.4,1.7-0.4,2.5,0l38.6,19.7c2,1,4.4-0.6,4-2.9l-6.1-42.5c-0.1-0.9,0.2-1.8,0.8-2.4l15.2-15
c10,9.6,16.2,23.1,16.2,38.1c0,29.3-23.7,53-53,53c-10,0-19.3-2.8-27.3-7.6c10.8,21.4,33,36.1,58.6,36.1c36.2,0,65.6-29.4,65.6-65.6
C219.1,102,197.7,76.1,169,69.1z" mask="url(#myShiningMask)" />
<circle class="st2" cx="87.9" cy="67.3" r="12.4" fill="white" />
</svg>

Creating a linear gradient SVG filter

Essentially I'm trying to create an gradient alpha mask in using SVG and CSS (like this), and since the mask property is no longer on the standards track I'm exploring the filter route.
I've created a vertical alpha mask in Sketch, with the top being 0% #000000 and the bottom being 100% #000000, then exported it as an SVG and tweaked it using guidance from this O' Reilly article. It now looks like this:
<svg version="1.1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink">
<defs>
<!-- Start by creating our vertical linear gradient -->
<linearGradient x1="50%" y1="0%" x2="50%" y2="100%" id="alphaLinear">
<stop offset="0%" style="stop-color: #000000; stop-opacity: 0%;" />
<stop offset="100%" style="stop-color: #000000; stop-opacity: 100%;" />
</linearGradient>
<!-- Create a rectangle and apply the gradient as its fill -->
<rect id="boxRect" x="0" y="0" width="100%" height="200" style="fill: url(#alphaLinear);" />
<!-- Using that rectangle, we'll create a filter -->
<filter id="alphaGrad">
<feImage xlink:href="#boxRect" result="grad"/>
<feDisplacementMap scale="10" xChannelSelector="R" yChannelSelector="G" in="SourceGraphic" in2="grad"/>
</filter>
</defs>
<use id="gradientBox" fill="url(#alphaGradient)" xlink:href="#boxRect"></use>
</svg>
My knowledge of SVG isn't the greatest so I'm suspecting this is where I've gone wrong.
Next, I applied the filter using filter (and -webkit-filter) along with referencing the filter ID #alphaGrad:
-webkit-filter: url('http://blahblah.com/alphagradient.svg#alphaGrad');
But, of course, this it doesn't work. Can anyone help me get the hang of this? Or is this even possible? If not, can someone recommend a method of how to achieve this?
Thanks in advance!
Update: here's a pretty basic fiddle of what I'm doing...
There are many errors and misconceptions in your example (why did you think a displacementMap would help you?)
Why don't you start from the code below - pure SVG using an SVG mask and an SVG image.
<svg width="600px" height="600px" viewbox="0 0 600 600">
<defs>
<linearGradient id="alphaLinear">
<stop offset="0%" stop-color="#FFFFFF" stop-opacity="0%" />
<stop offset="100%" stop-color="#999999" stop-opacity="100%" />
</linearGradient>
<mask id="Mask">
<rect x="0" y="0" width="600" height="600" fill="url(#alphaLinear)" />
</mask>
</defs>
<image xlink:href="http://upload.wikimedia.org/wikipedia/commons/7/71/Anadama_bread_(1).jpg" width="600" height="600" x="0" y="0" preserveAspectRatio="xMinYMin meet" mask="url(#Mask)"/>
</svg>
Few remarks:
SVG (and CSS) opacity value is not percertentual range but 0.0 - 1.0 range.
Mentioned mask property appears to be just prefixed in Webkit and unprefixed in Gecko.
If your target environment is HTML + CSS, you might not necessarily need SVG: you could get similar effect using linear-gradient and RGBA
background-image: linear-gradient(to bottom, rgba(0,0,0,1) 0%,rgba(0,0,0,0) 50%); on some overlay (pseudo) element. pointer-events: none; could be useful then.

SVG gradient using CSS

I'm trying to get a gradient applied to an SVG rect element.
Currently, I'm using the fill attribute. In my CSS file:
rect {
cursor: pointer;
shape-rendering: crispEdges;
fill: #a71a2e;
}
And the rect element has the correct fill color when viewed in the browser.
However, I'd like to know if I can apply a linear gradient to this element?
Just use in the CSS whatever you would use in a fill attribute.
Of course, this requires that you have defined the linear gradient somewhere in your SVG.
Here is a complete example:
rect {
cursor: pointer;
shape-rendering: crispEdges;
fill: url(#MyGradient);
}
<svg width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
<style type="text/css">
rect{fill:url(#MyGradient)}
</style>
<defs>
<linearGradient id="MyGradient">
<stop offset="5%" stop-color="#F60" />
<stop offset="95%" stop-color="#FF6" />
</linearGradient>
</defs>
<rect width="100" height="50"/>
</svg>
2019 Answer
With brand new css properties you can have even more flexibility with variables aka custom properties
.shape {
width:500px;
height:200px;
}
.shape .gradient-bg {
fill: url(#header-shape-gradient) #fff;
}
#header-shape-gradient {
--color-stop: #f12c06;
--color-bot: #faed34;
}
<svg viewBox="0 0 100 100" xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" class="shape">
<defs>
<linearGradient id="header-shape-gradient" x2="0.35" y2="1">
<stop offset="0%" stop-color="var(--color-stop)" />
<stop offset="30%" stop-color="var(--color-stop)" />
<stop offset="100%" stop-color="var(--color-bot)" />
</linearGradient>
</defs>
<g>
<polygon class="gradient-bg" points="0,0 100,0 0,66" />
</g>
</svg>
Just set a named variable for each stop in gradient and then customize as you like in css. You can even change their values dynamically with javascript, like:
document.querySelector('#header-shape-gradient').style.setProperty('--color-stop', "#f5f7f9");
Building on top of what Finesse wrote, here is a simpler way to target the svg and change it's gradient.
This is what you need to do:
Assign classes to each color stop defined in the gradient element.
Target the css and change the stop-color for each of those stops using plain classes.
Win!
Some benefits of using classes instead of :nth-child is that it'll not be affected if you reorder your stops. Also, it makes the intent of each class clear - you'll be left wondering whether you needed a blue color on the first child or the second one.
I've tested it on all Chrome, Firefox and IE11:
.main-stop {
stop-color: red;
}
.alt-stop {
stop-color: green;
}
<svg class="green" width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
<linearGradient id="gradient">
<stop class="main-stop" offset="0%" />
<stop class="alt-stop" offset="100%" />
</linearGradient>
<rect width="100" height="50" fill="url(#gradient)" />
</svg>
See an editable example here:
https://jsbin.com/gabuvisuhe/edit?html,css,output
Here is a solution where you can add a gradient and change its colours using only CSS:
// JS is not required for the solution. It's used only for the interactive demo.
const svg = document.querySelector('svg');
document.querySelector('#greenButton').addEventListener('click', () => svg.setAttribute('class', 'green'));
document.querySelector('#redButton').addEventListener('click', () => svg.setAttribute('class', 'red'));
svg.green stop:nth-child(1) {
stop-color: #60c50b;
}
svg.green stop:nth-child(2) {
stop-color: #139a26;
}
svg.red stop:nth-child(1) {
stop-color: #c84f31;
}
svg.red stop:nth-child(2) {
stop-color: #dA3448;
}
<svg class="green" width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
<linearGradient id="gradient">
<stop offset="0%" />
<stop offset="100%" />
</linearGradient>
<rect width="100" height="50" fill="url(#gradient)" />
</svg>
<br/>
<button id="greenButton">Green</button>
<button id="redButton">Red</button>
Thank you everyone,
for all your precise replys.
Using the svg in a shadow dom, I add the 3 linear gradients I need within the svg, inside a .
I place the css fill rule on the web component and the inheritance od fill does the job.
<svg viewbox="0 0 512 512" xmlns="http://www.w3.org/2000/svg">
<path
d="m258 0c-45 0-83 38-83 83 0 45 37 83 83 83 45 0 83-39 83-84 0-45-38-82-83-82zm-85 204c-13 0-24 10-24 23v48c0 13 11 23 24 23h23v119h-23c-13 0-24 11-24 24l-0 47c0 13 11 24 24 24h168c13 0 24-11 24-24l0-47c0-13-11-24-24-24h-21v-190c0-13-11-23-24-23h-123z"></path>
</svg>
<svg height="0" width="0">
<defs>
<linearGradient id="lgrad-p" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#4169e1"></stop><stop offset="99%" stop-color="#c44764"></stop></linearGradient>
<linearGradient id="lgrad-s" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#ef3c3a"></stop><stop offset="99%" stop-color="#6d5eb7"></stop></linearGradient>
<linearGradient id="lgrad-g" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#585f74"></stop><stop offset="99%" stop-color="#b6bbc8"></stop></linearGradient>
</defs>
</svg>
<div></div>
<style>
:first-child {
height:150px;
width:150px;
fill:url(#lgrad-p) blue;
}
div{
position:relative;
width:150px;
height:150px;
fill:url(#lgrad-s) red;
}
</style>
<script>
const shadow = document.querySelector('div').attachShadow({mode: 'open'});
shadow.innerHTML="<svg viewbox=\"0 0 512 512\">\
<path d=\"m258 0c-45 0-83 38-83 83 0 45 37 83 83 83 45 0 83-39 83-84 0-45-38-82-83-82zm-85 204c-13 0-24 10-24 23v48c0 13 11 23 24 23h23v119h-23c-13 0-24 11-24 24l-0 47c0 13 11 24 24 24h168c13 0 24-11 24-24l0-47c0-13-11-24-24-24h-21v-190c0-13-11-23-24-23h-123z\"></path>\
</svg>\
<svg height=\"0\">\
<defs>\
<linearGradient id=\"lgrad-s\" gradientTransform=\"rotate(75)\"><stop offset=\"45%\" stop-color=\"#ef3c3a\"></stop><stop offset=\"99%\" stop-color=\"#6d5eb7\"></stop></linearGradient>\
<linearGradient id=\"lgrad-g\" gradientTransform=\"rotate(75)\"><stop offset=\"45%\" stop-color=\"#585f74\"></stop><stop offset=\"99%\" stop-color=\"#b6bbc8\"></stop></linearGradient>\
</defs>\
</svg>\
";
</script>
The first one is normal SVG,
the second one is inside a shadow dom.
Here is how to set a linearGradient on a target element:
<style type="text/css">
path{fill:url('#MyGradient')}
</style>
<defs>
<linearGradient id="MyGradient">
<stop offset="0%" stop-color="#e4e4e3" ></stop>
<stop offset="80%" stop-color="#fff" ></stop>
</linearGradient>
</defs>

compass/css fade border at edges?

I've seen this technique used quite a lot. Like say a separator border (like bottom border for stackoverflow header) which fades at both ends. How do I achieve this with compass? I've searched their documentation and google and can't find any examples of how to do this.
I've never used Compass CSS, but how about mixing CSS and SVG?
Your SVG file:
<svg width="100%" height="100%" version="1.1" xmlns="http://www.w3.org/2000/svg">
<defs>
<linearGradient id="div" x1="0%" y1="0%" x2="0%" y2="100%">
<stop offset="0%" style="stop-color:rgb(255, 255, 225);stop-opacity:0"/>
<stop offset="50%" style="stop-color:rgb(153,153,153);stop-opacity:1"/>
<stop offset="100%" style="stop-color:rgb(255, 255, 225);stop-opacity:0"/>
</linearGradient>
</defs>
<rect x="0" y="0" width="100%" height="100%" fill="url(#div)" />
</svg>
The CSS:
div.separator
{
width: 80%;
height: 16px;
background-image: url(gradient_file.svg);
}

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