zsh function case condition parse error near `)' - zsh

I'm following this blog to setup a zsh function to switch aws cli profiles
: https://mads-hartmann.com/2017/04/27/multiple-aws-profiles.html
This is the zsh function in the blog:
function aws-switch() {
case ${1} in
"")
clear)
export AWS_PROFILE=""
;;
*)
export AWS_PROFILE="${1}"
;;
esac
}
#compdef aws-switch
#description Switch the AWS profile
_aws-switch() {
local -a aws_profiles
aws_profiles=$( \
grep '\[profile' ~/.aws/config \
| awk '{sub(/]/, "", $2); print $2}' \
| while read -r profile; do echo -n "$profile "; done \
)
_arguments \
':Aws profile:($(echo ${aws_profiles}) clear)'
}
_aws-switch "$#"
I added these lines to my ~/.zshrc, when I run source ~/.zshrc
It gives /.zshrc:4: parse error near `)'
I read the zsh function doc but still not very good at understanding the syntax and how could I fix this.

Have a look at the zsh man page (man zshmisc):
case word in [ [(] pattern [ | pattern ] ... ) list (;;|;&|;|) ] ... esac
As you see, you have to separate multiple pattern by |:
case $1 in
|clear)
....

Related

Pass variable from bash to R with commandArgs

I'm having a terrible go trying to pass some variables from the shell to R. I am hesitant to post this because I can't figure out a reasonable way to make this reproducible, since it involves a tool that has to be downloaded, and really it's more of a general methodology issue that I don't think needs to be reproducible, if you can just suspend your disbelief and bear with me for a quick minute.
I have arguments that are defined in a bash script: $P, $G, and $O.
I have some if/then statements and everything is fine until I get to the $O options.
This is the first part of the $O section and it works fine. It grabs data from $P and passes it to the twoBitToFa utility from UCSC's genome project and outputs the data correctly in a .fa file. Beautiful. (Although I think using 'stdout' and '>' is perhaps redundant?)
if [ "$O" = "fasta" ]
then
awk '{print $0" "$1":"$2"-"$3}' "$P" |
twoBitToFa -bed=stdin -udcDir=. "$twobit" stdout > "${P%.bed}".fa
fi
The next section is where I am stuck. If the $O option is "bed", then I want to invoke the Rscript command and pass my stuff over to R. I am able to pass my $P, $G, and $O variables without issue, but now I also need to pass the output from the twoBitToFa function. I could add a step and make the .fa file and then pick that up in R, but I am trying to skip the .fa file creation step and output a different file type instead (.bed). Here are some things I have tried:
# try saving twoBitToFa output to variable and including it in the variables passed to R:
if [ "$O" = "bed" ]
then
awk '{print $0" "$1":"$2"-"$3}' "$P" |
myvar=$(twoBitToFa -bed=stdin -udcDir=. "$twobit" stdout) \
Rscript \
GetSeq_R.r \
$P \
$G \
$O \
$myvar
fi
To check what variables come through, my GetSeq_R.r script starts with:
args = commandArgs(trailingOnly=TRUE)
print(args)
and with the above code, the output only includes my $P, $G, and $O variables. $myvar doesn't make it. $P is the TAD-1 file, $G is "hg38", and $O is "bed".
[1] "TAD-1_template.bed" "hg38" "bed"
I am not sure if the way I am trying to pass the data in the variable is wrong. From everything I've read, it seems like it should work. I've also tried using tee to see what is in my stdout at that step like so:
if [ "$O" = "bed" ]
then
awk '{print $0" "$1":"$2"-"$3}' "$P" |
twoBitToFa -bed=stdin -udcDir=. "$twobit" stdout | tee \
Rscript \
GetSeq_R.r \
$P \
$G \
$O
fi
And the data I want to pass to R is correctly shown in my console by using tee. I've tried saving stdout and tee to a variable and passing that variable to R, thinking maybe it's something about twoBitToFa that refuses to be put inside a variable, but was unsuccessful. I've spent hours looking up info about tee, stdout, and passing variables from bash to R. I feel like I'm missing something fundamental, or trying to do something impossible, and would really appreciate some other eyes on this.
Here's the whole bash script, in case that's illuminating. Do I need to define a variable in "$#" for what I am trying to pass to R, even though it's not something I want the user to be aware of? Am I capturing the variable with $myvar incorrectly? Can I get the contents of stdout or tee to show up in R?
Thanks in advance.
for arg in "$#"; do
shift
case "$arg" in
"--path") set -- "$#" "-P" ;;
"--genome") set -- "$#" "-G" ;;
"--output") set -- "$#" "-O" ;;
"--help") set -- "$#" "-h" ;;
*) set -- "$#" "$arg"
esac
done
while getopts ":P:G:O:h" OPT
do
case $OPT in
P) P=$OPTARG;;
G) G=$OPTARG;;
O) O=$OPTARG;;
h) help ;;
\?)
echo "Invalid option: -$OPTARG" >&2
usage
exit 1
;;
:)
echo "Option -$OPTARG requires an argument." >&2
usage
exit 1
;;
esac
done
num_col=$(cat "$P" | awk "{print NF; exit}")
if [ "$num_col" = 3 ]
then
echo -e "\n\n3 column bed file detected; no directional considerations for sequences \n\n"
if [ "$G" = "hg38" ]
then
twobit="https://hgdownload.cse.ucsc.edu/goldenpath/hg38/bigZips/hg38.2bit"
fi
if [ "$G" = "hg19" ]
then
twobit="https://hgdownload.cse.ucsc.edu/goldenpath/hg19/bigZips/hg19.2bit"
fi
if [ "$O" = "fasta" ]
then
awk '{print $0" "$1":"$2"-"$3}' "$P" |
twoBitToFa -bed=stdin -udcDir=. "$twobit" stdout > "${P%.bed}".fa
fi
if [ "$O" = "bed" ]
then
awk '{print $0" "$1":"$2"-"$3}' "$P" |
#myvar=$(twoBitToFa -bed=stdin -udcDir=. "$twobit" stdout) \
Rscript \
GetSeq_R.r \
$P \
$G \
$O \
$myvar
fi
fi

Zsh completion case insensitive _multi_parts function

I have a script that takes file like arguments (multi part arguments), I am fetching the possible values and putting them in an array called raw and then using
_multi_parts / "(${raw[#]})"
to autocomplete. The problem is that this is case sensitive, how can I make it so that it I type mycommand get fo and press Tab it will autocomplete to mycommand get Foo/ if Foo is one of the things in raw.
The full completion is here for reference:
_mycommand() {
local curcontext="$curcontext" state line
_arguments "1: :->command" "*: :->label"
case $state in
command)
_arguments "1: :(add get ls rm)"
;;
*)
case $words[2] in
add|get|ls|rm)
if [ -f ~/.pts ]; then
IFS=$'\n' read -d '' -r raw <<< "$(mycommand ls)"
_multi_parts / "(${raw[#]})"
fi
;;
*)
_files
;;
esac
esac
}
_mycommand "$#"
mycommand ls outputs path like names like the following:
Foo/Bar/x
Foo/Bar/y
Derp/z
Placeholder/z
Okay I figured it out:
Change lines
IFS=$'\n' read -d '' -r raw <<< "$(mycommand ls)"
_multi_parts / "(${raw[#]})"
To
IFS=$'\n' raw=($(mycommand ls))
_multi_parts -M "m:{[:lower:][:upper:]}={[:upper:][:lower:]}" / raw

zsh completion with virtual path

I want to create a zsh completion for a tool with a virtual file tree.
e.g. my file tree looks like the following:
/
|- foo/
| |- bar
| |- baz/
| |- qux
|- foobar
My tool mycmd has a subcommand for listing the current directory:
$ mycmd ls
foo/
foobar
$ mycmd ls foo/
bar
baz/
My actual zsh completion looks like this:
_mycmd_ls() {
if [ ! -z "$words[-1]" ]; then
dir=$(dirname /$words[-1])
lastpart=$(basename $words[-1])
items=$(mycmd ls $dir | grep "^$lastpart")
else
items=$(mycmd ls)
fi
_values -s ' ' 'items' ${(uozf)items}
}
_mycmd() {
local -a commands
commands=(
'ls:list items in directory'
)
_arguments -C -s -S -n \
'(- 1 *)'{-v,--version}"[Show program\'s version number and exit]: :->full" \
'(- 1 *)'{-h,--help}'[Show help message and exit]: :->full' \
'1:cmd:->cmds' \
'*:: :->args' \
case "$state" in
(cmds)
_describe -t commands 'commands' commands
;;
(args)
_mycmd_ls
;;
(*)
;;
esac
}
_mycmd
IMHO is _values the wrong utility function. The actual behaviour is:
$ mycmd ls<TAB>
foo/ foobar
$ mycmd ls foo/<TAB> ## <- it inserts automatically a space before <TAB> and so $words[-1] = ""
foo/ foobar
I can't use the utility function _files or _path_files because the file tree is only virtual.
I would suggest to make use of compadd rather _values to get in control of the suffix character appended. Then looking at the available choices, set an empty suffix character in case a virtual directory is part of the result:
_mycmd_ls() {
if [ ! -z "$words[-1]" ]; then
dir=$(dirname /$words[-1])
lastpart=$(basename $words[-1])
items=$(mycmd ls $dir | grep "^$lastpart")
else
items=$(mycmd ls)
fi
local suffix=' ';
# do not append space to word completed if it is a directory (ends with /)
for val in $items; do
if [ "${val: -1:1}" = '/' ]; then
suffix=''
break
fi
done
compadd -S "$suffix" -a items
}

is `cap` a reserved word? - zsh completion?

I'm trying to create a Capistrano mutilstage completion for ZSH:
$ cap |
production staging
$ cap production |
deploy -- Deploy a new release
deploy:bundle -- Bundle
...
Completion code:
#compdef cap
#autoload
# /Users/pablo/.oh-my-zsh/custom/plugins/capistrano_custom/_capistrano_custom
local curcontext="$curcontext" state line ret=1
local -a _configs
_arguments -C \
'1: :->cmds' \
'2:: :->args' && ret=0
_cap_tasks() {
if [[ ! -f .cap_tasks~ ]]; then
echo "\nGenerating .cap_tasks~..." > /dev/stderr
cap -v --tasks | grep '#' | cut -d " " -f 2 > .cap_tasks~
fi
cat .cap_tasks~
}
_cap_stages() {
find config/deploy -name \*.rb | cut -d/ -f3 | sed s:.rb::g
}
case $state in
cmds)
if [[ -d config/deploy ]]; then
compadd `_cap_stages`
else
compadd `_cap_tasks`
fi
ret=0
;;
args)
compadd `_cap_tasks`
ret=0
;;
esac
return ret
The problem:
#compdef cap doesn't work. If I type cap and [TAB] it doesn't execute the completion, but with other words (i.e. shipit) works fine.
Any ideas?
Solution:
cap is really a reserved word and it seems that we can't use it with #compdef cap.
I'm wondering how cap and capistrano completions worked before (maybe an old version of ZSH).
Solution dotfiles code: capistrano_custom
Solution oh-my-zsh/PR: #2471
Both solutions use shipit instead of cap.
$ shipit |
production staging
$ shipit production |
deploy -- Deploy a new release
deploy:bundle -- Bundle
...
Yes, cap is a ZSH builtin. Quoting from zsh docs:
The zsh/cap module is used for manipulating POSIX.1e (POSIX.6)
capability sets. [...]. The builtins in this module are:
cap [ capabilities ] Change the shell’s process capability sets to the
specified capabilities, otherwise display the shell’s current
capabilities.

How to quote strings in file names in zsh (passing back to other scripts)

I have a script that has a string in a file name like so:
filename_with_spaces="a file with spaces"
echo test > "$filename_with_spaces"
test_expect_success "test1: filename with spaces" "
run cat \"$filename_with_spaces\"
run grep test \"$filename_with_spaces\"
"
test_expect_success is defined as:
test_expect_success () {
echo "expecting success: $1"
eval "$2"
}
and run is defined as:
#!/bin/zsh
# make nice filename removing special characters, replace space with _
filename=`echo $# | tr ' ' _ | tr -cd 'a-zA-Z0-9_.'`.run
echo "#!/bin/zsh" > $filename
print "$#" >> $filename
chmod +x $filename
./$filename
But when I run the toplevel script test_expect_success... I get cat_a_file_with_spaces.run with:
#!/bin/zsh
cat a file with spaces
The problem is the quotes around a file with spaces in cat_a_file_with_spaces.run is missing. How do you get Z shell to keep the correct quoting?
Thanks
Try
run cat ${(q)filename_with_spaces}
. It is what (q) modifier was written for. Same for run script:
echo -E ${(q)#} >> $filename
. And it is not bash, you don't need to put quotes around variables: unless you specify some option (don't remember which exactly)
command $var
always passes exactly one argument to command no matter what is in $var. To ensure that some zsh option will not alter the behavior, put
emulate -L zsh
at the top of every script.
Note that initial variant (run cat \"$filename_with_spaces\") is not a correct quoting: filename may contain any character except NULL and / used for separating directories. ${(q)} takes care about it.
Update: I would have written test_expect_success function in the following fashion:
function test_expect_success()
{
emulate -L zsh
echo "Expecting success: $1" ; shift
$#
}
Usage:
test_expect_success "Message" run cat $filename_with_spaces

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