Thanks again for the help everyone. I went with the script below...
SELECT beginning, end,
(SELECT SUM(sale) FROM sales_log WHERE date BETWEEN beginning AND `end` ) AS sales
FROM performance
and I added a salesperson column to both the performance table and sales_log but it winds up crashing DB Browser. What is the issue here? New code below:
SELECT beginning, end, salesperson
(SELECT SUM(sale) FROM sales_log WHERE (date BETWEEN beginning AND end) AND sales_log.salesperson = performance.salesperson ) AS sales
FROM performance
I believe that the following may do what you wish or be the basis for what you wish.
WITH sales_log_cte AS
(
SELECT substr(date,(length(date) -3),4)||'-'||
CASE WHEN length(replace(substr(date,instr(date,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(date,instr(date,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(date,1,instr(date,'/') -1)) < 2 THEN '0' ELSE '' END||substr(date,1,instr(date,'/') -1) AS date,
CAST(sale AS REAL) AS sale
FROM sales_log
),
performance_cte AS
(
SELECT substr(beginning,(length(beginning) -3),4)||'-'||
CASE WHEN length(replace(substr(beginning,instr(beginning,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(beginning,instr(beginning,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(beginning,1,instr(beginning,'/') -1)) < 2 THEN '0' ELSE '' END||substr(beginning,1,instr(beginning,'/') -1)
AS beginning,
substr(`end`,(length(`end`) -3),4)||'-'||
CASE WHEN length(replace(substr(`end`,instr(`end`,'/')+1,2),'/','')) < 2 THEN '0' ELSE '' END
||replace(substr(`end`,instr(`end`,'/')+1,2),'/','')||'-'||
CASE WHEN length(substr(`end`,1,instr(`end`,'/') -1)) < 2 THEN '0' ELSE '' END||substr(`end`,1,instr(`end`,'/') -1)
AS `end`
FROM performance
)
SELECT beginning, `end` , (SELECT SUM(sale) FROM sales_log_cte WHERE date BETWEEN beginning AND `end` ) AS sales
FROM performance_cte
;
From your data this results in :-
As can be seen the bulk of the code is converting the dates into a format (i.e. YYYY-MM-DD) that is usable/recognisable by SQLite for the BETWEEN clause.
Date And Time Functions
I don't believe that you want a join between performance (preformance_cte after reformatting the dates) and sales_log (sales_log_cte) as this will be a cartesian product and then sum will sum all the results within the range.
The use of end as a column name is also awkward as it is a KEYWORD requiring it to be enclosed (` grave accents used in the above).
The above works by using 2 CTE's (Common Table Expresssions), which are temporary tables who'd life time is for the query in which they are used.
The first sales_log_cte is simply the sales_log table but with the date reformatted. The second, likewise, is simply the performace table with the dates reformatted.
If the tables already has suitable date formatting then all of the above could simply be :-
SELECT beginning, `end` , (SELECT SUM(sale) FROM sales_log WHERE date BETWEEN beginning AND `end` ) AS sales FROM performance;
Related
I am using the below query to pivot my data and generate a CSV but the problem is I have a dataset in which the data points are coming in a scattered way with each timestamp.
with map_date as (
SELECT
vin,
epoch,
timestamp,
date,
map_agg(signalName, value) as map_values
from hive.vehicle_signals.vehicle_signals_flat
where date(date) = date('2020-03-12')
and date(cast(from_unixtime(epoch) as timestamp) - interval '0' hour) = current_date - interval '2' day
and vin = '000011'
and signalName in ('timestamp','epoch','msgId','usec','vlan','vin','msgName','value')
GROUP BY vin, epoch, timestamp, date
order by timestamp desc
)
SELECT
epoch
, timestamp
, CASE WHEN element_at(map_values, 'value') IS NOT NULL THEN map_values['value'] ELSE NULL END AS value
, vin
, current_date - interval '2' day AS date
from map_date
I get the following CSV as a result. Is there a way I can carry forward the value until a new value is found at a newer timestamp? Like in the image below the value '14.3' comes and the next value '16.5' comes after a few timestamps, How can I carry the value '14.3' till row 7th and repeat the logic on the entire column. How can I make my output field look like column 'G' in the image using Presto?
Thanks in advance!!
You can use a mysql #variable to store the last value, for example:
SELECT
epoch
, timestamp
, CASE WHEN element_at(map_values, 'value') IS NOT NULL THEN #last_value:= map_values['value'] ELSE #last_value END AS value
, vin
, current_date - interval '2' day AS date
from map_date, (select #last_value:=0) v
The last part, (select #last_value:=0) v is to initialize the #last_value variable.
A basic tutorial
https://www.mysqltutorial.org/mysql-variables/
More advanced tutorial with additional info
https://www.xaprb.com/blog/2006/12/15/advanced-mysql-user-variable-techniques/
SQLITE3
Task: get a data set that contains the following data - SEE NOTES BESIDE COLUMNS
SELECT DISTINCT DateTime(Rounded, 'unixepoch') AS RoundedDate, -- Rounded DateTime to the floor hour
Count() AS Count, -- Count of items that registered within the above time
CAST (avg(Speed) AS INT) AS AverageSpeed, -- Average table.Speed column data within the defined datetime
Count() AS SpeederCount -- ?? WTF? [pseudo constraints: if Speed > Speedlimit then +1]
FROM RawSpeedLane AS sl
INNER JOIN
SpeedLaneSearchData AS slsd ON slsd.ParentId = sl.Id
INNER JOIN
Projects AS p ON p.ProjectId = sl.ProjectId
WHERE sl.ProjectId = 72
GROUP BY RoundedDate;
The SQL above is currently gives me all the data I need, EXECPT for the last column.
This last column is supposed to be the count of records where that pass specific criteria. The only way I have found to successfully do this is to build a sub query... Cool? okay, but the problem is the sub query takes 4 minutes to run because well... I suck at SQL :P No matter how many different ways I've tried to write it, it still takes forever.
Here is the long, but working version.
SELECT DISTINCT RoundedDate,
Count() AS Count,
CAST (avg(Speed) AS INT) AS AverageSpeed,
(
SELECT count()
FROM RawSpeedLane AS slr
WHERE slr.ProjectId = 72 AND
datetime( ( (strftime('%s', Start) - (strftime('%M', Start) * 60 + strftime('%S', Start) ) ) ), 'unixepoch') = sl.RoundedDate AND
Speed > p.SpeedLimit
)
AS SpeederCount
FROM SpeedLaneReportDataView AS sl
INNER JOIN
Projects AS p ON p.ProjectId = sl.ProjectId
WHERE sl.ProjectId = 72
GROUP BY RoundedDate;
I currently just tried this for the last column
(select Count() where sl.Speed > p.SpeedLimit)
but as expected, i got 1s and 0s im not really sure on what to do here. Any hints or help that lead me in the right direction is very much appreciated.
I don't think SQLite has an IIF but CASE works.
This is a response to Backs answer, but I can't comment yet.
SELECT DISTINCT DateTime(Rounded, 'unixepoch') AS RoundedDate, -- Rounded DateTime to the floor hour
Count() AS Count, -- Count of items that registered within the above time
CAST (avg(Speed) AS INT) AS AverageSpeed, -- Average table.Speed column data within the defined datetime
SUM(CASE WHEN Speed > SpeedLimit THEN 1 ELSE 0 END) AS SpeederCount
FROM RawSpeedLane AS sl
With SUM and IIF:
SELECT DISTINCT DateTime(Rounded, 'unixepoch') AS RoundedDate, -- Rounded DateTime to the floor hour
Count() AS Count, -- Count of items that registered within the above time
CAST (avg(Speed) AS INT) AS AverageSpeed, -- Average table.Speed column data within the defined datetime
SUM(IIF(Speed > SpeedLimit, 1, 0)) AS SpeederCount
FROM RawSpeedLane AS sl
I am stuck with this requirement -
I have some data in the format
(Entries now show data for both periods (Jan. 2011) and (Feb. 2011) on the same line as apposed to appearing separately).
At the end I need to print the data using dbms_output.put_line command.
I am using Oracle 10.2g.
Oracle 10g does not have a PIVOT function but you can convert the rows of data into columns using an aggregate function with a CASE expression. The basic syntax would be:
select d.id,
d.site,
d.entrance,
sum(case when d.date = 'Jan.2011' then enters else 0 end) "Jan.2011",
sum(case when d.date = 'Feb.2011' then enters else 0 end) "Feb.2011"
from
(
select id, site, entrance, date, enters
from yourdata
) d
group by d.id, d.site, d.entrance;
Note: you can replace the subquery with yourdata with your current query.
I have to implement a solution where two date ranges can overlap each other. within the overlapped dates, I have to count how many days overlap each other. Once I know the overlapped days I can calculate a total figure based on the price that's attached per day.
A scenario would be that
A customer is booking a hotel
Customer booking dates - 17/02/2011 to 26/02/2011
Normal price (All year) - 01/01/2011 - 31/12/2011 (price per day :$30.00)
Special Offer 1 dates - 01/01/2011 to 19/02/2011 (price per day :$20.00)
Special Offer 2 dates - 17/02/2011 to 24/02/2011 (price per day :$10.00)
In the above scenario, the proposed algorithm should work out the cheapest offer that the date ranges overlap and work out the price for the booking. If there is no special offer available it uses the normal price.
So for the first two days the system should get the price from "special offer 1" as it's the cheapest available price. Next 5 days should be "Special offer 2 price" and for the next 2 days it'll be normal price.
I'd be grateful to see both SQL(using MS-SQL Server) or Code base answers to get the diffrenet views.
I hope the question is clear and looking foward to see the answers.
Many thanks in advance
Using the standard trick of using an auxiliary calendar table, it is simply a case of joins and grouping to get the best price each day:
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
The same query as above, including sample data using CTEs:
WITH Prices (price_start_date, price_end_date, narrative, price)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date), narrative, price
FROM (
VALUES ('2011-01-01T00:00:00', '2011-12-31T00:00:00', 'Normal price', 30),
('2011-01-01T00:00:00', '2011-02-21T00:00:00', 'Special Offer 1', 20),
('2011-02-19T00:00:00', '2011-02-24T00:00:00', 'Special Offer 2', 10)
) AS T (start_date, end_date, narrative, price)
),
CustomerBooking (booking_start_date, booking_end_date)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date)
FROM (
VALUES ('2011-02-17T00:00:00', '2011-02-26T00:00:00')
) AS T (start_date, end_date)
)
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
Let's supose that for each day you should apply lowest price.
create function price ( #fromDate date, #toDate date) returns money
as
begin
declare #iterator_day date
declare #total money
set #total = 0
set #iterator_day = #fromDate
WHILE #iterator_day < = #toDate
begin
select #total = #total + min( price )
from offers
where #iterator_day between offers.fromFay and offers.toDay
set #iterator_day = DATEADD (day , 1 , #iterator_day )
end
return #total
end
then you can call function in your query:
select
b.fromDay, b.toDay, dbo.price( b.fromDay, b.toDay )
from
booking b
I've only used ASP.net 4.0, but I can offer some SQL will give you the price for a given date:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11')
From your application you could build the query to be something like this:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '17/2/11') AND (EndDate >= '17/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '19/2/11') AND (EndDate >= '19/2/11');
This would return a dataset of tables containing a single value for the minimum price for that date (in the same order as your query)
Sounds like a good job for a Stored Procedure...
Your problem here is that you're got multiple overlapping time periods. You either need to constrain the problem slightly, or remodel the data slightly. (To get desirable performance.)
Option 1 - Constraints
A data set of 'normal' prices - that never overlap with each other
A data set of 'special' prices - that also never overlap with each other
Every bookable date has a 'normal' price
Every bookable date has a 'special' price (EVEN if it's NULL to mean 'no special price')
The last constraint is the strangest one. But it's needed to make the simple join work. When comparing date ranges, it's alot easier to form the query if the two sets of ranges are gapless and have no overlaps inside them.
This means that you should now be able to work it out with just a few joins...
SELECT
CASE WHEN [sp].started > [np].started THEN [sp].started ELSE [np].started END AS [started]
CASE WHEN [sp].expired < [np].expired THEN [sp].expired ELSE [np].expired END AS [expired]
CASE WHEN [sp].price < [np].price THEN [sp].price ELSE [np].price END AS [price]
FROM
normal_prices AS [np]
LEFT JOIN
special_prices AS [sp]
ON [sp].started < [np].expired
AND [sp].expired > [np].started
AND [sp].started >= (SELECT ISNULL(MAX(started),0) FROM special_prices WHERE started <= [np].started)
-- The third condition is an optimisation for large data-sets.
WHERE
[np].started < #expired
AND [np].expired > #started
-- Note: Inclusive StartDates, Exlusive EndDate
-- For example, "all of Jan" would be "2011-01-01" to "2011-02-01"
Option 2 - Re-Model
This one is often the fastest in my experience; you increase the amount of space being used, and gain a simpler faster query...
Table Of Prices, stored by DAY rather than period...
- calendar_date
- price_code
- price
SELECT
calendar_date,
MIN(price)
FROM
prices
WHERE
calendar_date >= #started
AND calendar_date < #expired
Or, if you needed the price_code as well...
WITH
ordered_prices AS
(
SELECT
ROW_NUMBER() OVER (PARTITION BY calendar_date ORDER BY price ASC, price_code) AS price_rank,
*
FROM
prices
)
SELECT
calendar_date,
price_code,
price
FROM
ordered_prices
WHERE
calendar_date >= #started
AND calendar_date < #expired
Details.
I have the notes table having the following columns.
ID - INT(3)
Date - DateTime
Note - VARCHAR(100)
Tile - Varchar(100)
UserName - Varchar(100)
Now this table will be having NOTES along with the Titles entered by UserName on the specified date / time.
I need to calculate the DateTimeDifference between the TWO ROWS in the SAME COLUMN
For example the above table has this peice of information in the table.
64, '2010-03-26 18:16:13', 'Action History', 'sending to Level 2.', 'Salman Khwaja'
65, '2010-03-26 18:19:48', 'Assigned By', 'This is note one for the assignment of RF.', 'Salman Khwaja'
66, '2010-03-27 19:19:48', 'Assigned By', 'This is note one for the assignment of CRF.', 'Salman Khwaja'
Now I need to have the following resultset in query reports using MYSQL.
TASK - TIME Taken
ACTION History - 2010-03-26 18:16:13
Assigned By - 00:03:35
Assigned By - 25:00:00
More smarter approach would be
TASK - TIME Taken
ACTION History - 2010-03-26 18:16:13
Assigned By - 3 minutes 35 seconds
Assigned By - 1 day, 1 hour.
I would appreciate if one could give me the PLAIN QUERY along with PHP code to embed it too.
<?php
$start = new DateTime('2009-01-01 00:00:00'); // 31 days
$time_span = $start->diff(new DateTime('2009-02-01 00:00:00'));
var_dump($time_span); // returns '1 month'
$start = new DateTime('2009-02-01 00:00:00'); //28 days
$time_span = $start->diff(new DateTime('2009-03-01 00:00:01'));
var_dump($time_span); // returns '1 month'
?>
DATEDIFF()
It looks like you want to group by case number.
Using your schema and sample data, I think that this is exactly what you wanted:
SELECT t1.ID, t1.title AS task, t1.username,
IFNULL(CONCAT(TIMESTAMPDIFF(MINUTE, t2.currentDate, t1.currentDate)), t1.currentdate) AS time_taken
FROM tps_trans_support_notes t1
LEFT JOIN tps_trans_support_notes t2
ON t2.currentdate < t1.currentdate AND
t2.ID <> t1.ID AND
t2.casenumber = t1.casenumber
LEFT JOIN tps_trans_support_notes t3
ON t3.casenumber = t1.casenumber AND
t3.ID <> t1.ID AND t3.ID <> t2.ID AND
t3.currentdate > t2.currentdate AND
t3.currentdate < t1.currentdate
WHERE t3.ID IS NULL AND
t1.casenumber = '21'
ORDER BY t1.ID
First, the query gets the begin time and end time into the same row, excluding rows where there are times that occur between the two, then it displays the difference.
The query only shows the difference in minutes, but you can use the other DateTime functions to expand that.