I found a way to exclude a specified file extension from JGit diff in this way:
val excludePath = PathSuffixFilter.create(".designer.cs").negate()
val df = new DiffFormatter(DisabledOutputStream.INSTANCE)
df.setPathFilter(excludePath);
What should I do for multiple file extensions?
There is an OrTreeFilter and an AndTreeFilter to combine multiple TreeFilters.
To exclude multiple file endings, combine the single path filters with an AndTreeFilter and use this to configure the diff formatter:
val fooFilter = PathSuffixFilter.create(".foo").negate()
val barFilter = PathSuffixFilter.create(".bar").negate()
val treeFilter = AndTreeFilter.create(fooFilter, barFilter);
...
diffFormatter.setPathFilter(treeFilter);
Related
I have a folder (~/PATH/MYFOLDER) with a lot of subfolders and files.
Subfolders are named, for example, as: LClass_orgx, LClass_orgy, LClass_phyw, LClass_detz, LClass_appq
Inside each subfolder has a lot of image files (*.png and/or *.jpg)
In ~/PATH/ I have folders with part of the name of subfolders, as: orgx, orgy, phyw, detz, appq
I would to copy image files of subfolders: LClass_orgx, LClass_orgy, LClass_phyw, LClass_detz, LClass_appq, to respective folders: orgx, orgy, phyw, detz, appq
Any help would be great.
Thanks all.
You can use sub to remove "MYFOLDER/Lclass_" from the file names. Something like this:
from = list.files(
path = "~/PATH/MYFOLDER",
pattern = "(png|jpg)$",
recursive = TRUE,
full.names = TRUE
)
to = sub(x = from, pattern = "MYFOLDER/Lclass_", replacement = "", fixed = TRUE)
file.copy(from = from, to = to)
This should take input from list.files like "~/PATH/MYFOLDER/LClass_orgx/file.jpg" (from) and change it to "~/PATH/orgx/file.jpg" (to), and then copy it accordingly. You could then use file.remove to delete the old ones. (Potentially you could do this all at once with file.rename, but it seems safer to copy and take a minute to check that things look right before deleting the old ones.)
If you need to be more specific in the sources, you could modify the list.files(pattern) to specify the source directories you mention, LClass_orgx, LClass_orgy, LClass_phyw, LClass_detz, LClass_appq.
I'm trying to write a quick script to open a family document, change the parameter group of 2 specified parameters, and then close and save the document. I've done multiple tests and I am able to change the parameter groups of the specified parameters, but the changes of the groups don't save back to the family file. When I open the newly saved family, the parameter groups revert back to their original group.
This is with Revit 2017.2.
The same script, when run in RPS in Revit 2018 will do as desired.
import clr
import os
clr.AddReference('RevitAPI')
clr.AddReference('RevitAPIUI')
from Autodesk.Revit.DB import *
from Autodesk.Revit.UI import UIApplication
from System.IO import Directory, SearchOption
searchstring = "*.rfa"
dir = r"C:\Users\dboghean\Desktop\vanity\2017"
docs = []
if Directory.Exists(dir):
files = Directory.GetFiles(dir, searchstring, SearchOption.AllDirectories)
for f in files:
name, extension = os.path.splitext(f)
name2, extension2 = os.path.splitext(name)
if extension2:
os.remove(f)
else:
docs.append(f)
else:
print("Directory does not exist")
doc = __revit__.ActiveUIDocument.Document
app = __revit__.Application
uiapp = UIApplication(app)
currentPath = doc.PathName
pgGroup = BuiltInParameterGroup.PG_GRAPHICS
for i in docs:
doc = app.OpenDocumentFile(i)
paramList = [i for i in doc.FamilyManager.Parameters]
t = Transaction(doc, "test")
t.Start()
for i in paramList:
if i.Definition.Name in ["Right Sidesplash Edge line", "Left Sidesplash Edge line"]:
i.Definition.ParameterGroup = pgGroup
t.Commit()
doc.Close(True)
Any ideas?
Thanks!
I can confirm that this happens in Revit 2017. Strange!
A simple way around it is to arbitrarily rename the parameter using doc.FamilyManager.RenameParameter, then rename it back to the original name.
So in your case this would be three additional lines of code after changing the Parameter group:
originalName = i.Definition.Name
doc.FamilyManager.RenameParameter(i, "temp")
doc.FamilyManager.RenameParameter(i, originalName)
Doesnt get to the root problem, but works around it
"/D/data_DataAnalysis/Progrm/datset1/set2/genus/Huttenhower_LC8_genus_reported.tsv"
"/c/bioinfoTools/data/mock/test/truth/file_sets/genus/Huttenhower_LC8_TRUTH.txt"
I want "Huttenhower_LC8" from two file name using R.
Similer to the python code
fileName_temp = a_file.split("/")[-1]
filename = a_file.split("/")[-1][:-9]
for another_file in all_slim_files:
a_filename = another_file.split("/")[-1][:-18]
We know U-SQL supports directory and filename pattern matching while extracting the files. What I wanted to know does it support pattern matching based on date of creation of the file in ADLS (without implementing custom extractors).
Say a folder contains files created across months (filenames don't have date as part of the filename), is there a way to pull only files of a particular month.
The U-SQL EXTRACT operator is not aware of any metadata (such as create date) about a file - only the filename.
You could probably build a solution using the .NET SDK. For something rather simple you could use PowerShell to create a file which will contain all the files that meet your date time criteria. Then consume the content as desired.
# Log in to your Azure account
Login-AzureRmAccount
# Modify variables as required
$DataLakeStoreAccount = "<yourDataLakeStoreAccountNameHere>";
$DataLakeAnalyticsAccount = <yourDataLakeAnalyticsAccountNameHere>";
$DataLakeStorePath = "/Samples/Data/AmbulanceData/"; #modify as desired
$outputFile = "Samples/Outputs/ReferenceGuide/filteredFiles.csv"; #modify as desired
$filterDate = "2016-11-22";
$jobName = "GetFiles";
# Query directory and build main body of script. Note, there is a csv filter.
[string]$body =
"#initial =
SELECT * FROM
(VALUES
" +
(Get-AzureRmDataLakeStoreChildItem -Account $DataLakeStoreAccount -Path $DataLakeStorePath |
Where {$_.Name -like "*.csv" -and $_.Type -eq "FILE"} | foreach {
"(""" + $DataLakeStorePath + $_.Name + """, (DateTime)FILE.CREATED(""" + $DataLakeStorePath + $_.Name + """)), `r`n" });
# formattig, add column names
$body =
$body.Substring(0,$body.Length-4) + "
) AS T(fileName, createDate);";
# U-SQL query and OUTPUT statement
[string]$output =
"
// filter results based on desired time frame
#filtered =
SELECT fileName
FROM #initial
WHERE createDate.ToString(""yyyy-MM-dd"") == ""$filterDate"";
OUTPUT #filtered
TO ""$outputFile""
USING Outputters.Csv();";
# bring it all together
$script = $body + $output;
#Execute job
$jobInfo = Submit-AzureRmDataLakeAnalyticsJob -Account $DataLakeAnalyticsAccount -Name $jobName -Script $script -DegreeOfParallelism 1
#check job progress
Get-AzureRmDataLakeAnalyticsJob -Account $DataLakeAnalyticsAccount -JobId $jobInfo.JobId -ErrorAction SilentlyContinue;
Write-Host "You now have a list of desired files to check # " $outputFile
Currently there is no way to access or use file meta data properties. Please add your vote and use case to the following feedback item: https://feedback.azure.com/forums/327234-data-lake/suggestions/10948392-support-functionality-to-handle-file-properties-fr
it's been a while since this question was asked, and I'm not sure if this is what you were looking for originally, but now you can use the FILE.MODIFIED U-SQL function:
DECLARE #watermark string = "2018-08-16T18:12:03";
SET ##FeaturePreviews="InputFileGrouping:on";
DECLARE #file_set_path string = "adl://adls.azuredatalakestore.net/stage/InputSample.tsv";
#input =
EXTRACT [columnA] int?,
[columnB] string
FROM #file_set_path
USING Extractors.Tsv(skipFirstNRows : 1, silent : true);
#result =
SELECT *, FILE.MODIFIED(#file_set_path) AS FileModifiedDate
FROM #input
WHERE FILE.MODIFIED(#file_set_path) > DateTime.ParseExact(#watermark, "yyyy-MM-ddTHH:mm:ss", NULL);
OUTPUT #result TO "adl://ADLS.azuredatalakestore.net/stage/OutputSample.tsv" USING Outputters.Tsv(outputHeader:true);
The U-SQL built-in function is documented here:
https://msdn.microsoft.com/en-us/azure/data-lake-analytics/u-sql/file-modified-u-sql
I want to create an object in R, which will contain one string, with a few variables (in my case it is file path). When I try to use paste to concatenate the file paths I can see only one last variable instead of all variables in one string. I use next code:
for(i in seq_len(nrow(samples))) {
lib = samples$conditions[i]
txtFile = file.path(lib, "hits.txt")
testfiles = paste(txtFile, sep = ',')
}
print(testfiles)
and get something like
cond/hits.txt,
instead of
cond/hits.txt,cond1/hits.txt,cond2/hits.txt and so on
Thank you very much for help