I am facing difficulty in understanding the below date command and its output in Unix if pass the value of 'end' as 130?
Thanks in advance.
date --date='{{ end }} day' +%s
The date will give the current date time.
With --date='{{ end }} day' you are adding end number of days to current date time.
The +%s outputs the overall Unix timestamp after adding end number of days.
Refer here for more options.
You specify intended date format with --date option:
Which accepts rich set of format options : Please go through this
If you put 130 as value of end unix variable then you will get Date and time after 130 days followed by seconds as well because +%s prints seconds.
Related
i'm using Robot Framework Keyword Subtract Date From Date to test that a date is between 2 dates(For example 11/06/2020 is between 07/06/2020 and 20/06/2020), but i'm getting an error in my log file ValueError: Invalid timestamp. The date is a String extracted from a Span Text and i convert it to date This is my code :
${date}= Get Current Date result_format=datetime
${postdate}= Get Text xpath://app-post[1]//div[1]//div[1]//div[1]//div[2]//div[1]//div[2]//div[1]//div[2]//span[2]
${postdate}= Convert Date ${postdate} date_format=%d/%m/%y
${date}= Convert Date ${date} result_format=%d/%m/%y
${temp} = Subtract Date From Date ${postdate} ${date}
Should Be True ${temp}>=0
The problem is you don't follow the allowed format for the keyword Subtract Date From Date mentioned here: https://robotframework.org/robotframework/latest/libraries/DateTime.html#Date%20formats
%y will give you 20, but that obviously is not enough. If I change it to %Y, it will give me 2020 for the current year, and the keyword Subtract Date From Date doesn't complain anymore about invalid timestamp. You'd also need to change it to something like date_format=%Y/%m/%d, that is to change the order of %Y, %m, and %d.
EDIT:
I can now see you're also using date_format as well as result_format with Convert Date. That's another bug in your code, you need to use result_format with both.
EDIT 2:
The full working example:
(And you're not using BuiltIn library here, these datetime keywords are from DateTime library)
The below script worked (Used the static PAST_DATE to check the sample run ):
${date}= Set Variable 21
${month}= Set Variable 12
${year}= Set Variable 2019
${PAST_DATE}= BuiltIn.Catenate SEPARATOR=/ ${year} ${month} ${date}
Log ${PAST_DATE}
${CURRENT_DATE}= Get Current Date result_format=%Y/%m/%d
Log ${CURRENT_DATE}
${DIFFERNCE_IN_DAYS}= Subtract Date from Date ${CURRENT_DATE} ${PAST_DATE} verbose
Log ${DIFFERNCE_IN_DAYS}
#{total_days}= Split String ${DIFFERNCE_IN_DAYS}
${final_days}= Set Variable ${total_days[0]}
Log ${final_days}
Should be true ${final_days} >= 0
My demand is really so silly, so basically I need to go back in time 24 hours in a timestamp column in Hive.
So far, I have tried two different ways but it's not going thru:
select
recordDate, --original date
cast(date_sub(cast(recorddate as timestamp),1) as timestamp), -- going one day behind without hour
cast((cast(cast(recorddate as timestamp) AS bigint)-1*3600) as timestamp) -- crazy year
from mtmbuckets.servpro_agents_events limit 10;
My output looks:
I appreciate the support you can give me.
thanks
There is not straight forward function in hive .
1 Create UDF to do so .
or
Convert date in no of second and do you calculation( -24 *60*60) sec then change back int to data.
use from_unixtime and unix_timestamp to achieve below code.
select from_unixtime(unix_timestamp(recorddate) - 86400)
from mtmbuckets.servpro_agen ts_events limit 10;;
From_unixtime
Convert time string with given pattern to Unix time stamp (in seconds) The result of this function is in seconds.
Unix_timestamp
Converts time string in format yyyy-MM-dd HH:mm:ss to Unix timestamp (in seconds), using the default timezone and the default locale, return 0 if fail: unix_timestamp('2009-03-20 11:30:01') = 1237573801
I'm trying to figure out the cleanest way to do a comparison in Teradata SQL Assistant. I have the scheduled start date (TimeStamp), the Schedule start time (varchar), actual start and end times (TimeStamp). I need to consolidate the scheduled start date and time and be able to compare it to the actual start and end date and time without modifying the original data (because it's not mine). I realize that the Scheduled Start Time [SST] is in a 24 hour time format with a AM/PM suffix, but like I said before, I can't change that.
I tried to do select cast(substr(scheduled_start_date,1,5) as TIMESTAMP(0)) from DB.TBL but am getting the "Invalid timestamp" error. There is example table data below.
Sch Start Date Sch Start Time Actual Start Actual End
09/11/2017 00:00:00 11:30 AM 09/11/2017 11:34:16 09/11/2017 11:58:00
05/26/2017 00:00:00 15:30 PM 05/26/2017 15:40:00 05/26/2017 15:55:15
11/06/2017 00:00:00 19:30 PM 11/06/2017 21:25:00 11/06/2017 21:45:00
Thanks!
You need to cast the schedule start time as an Interval, then you can easily add it to the start date:
scheduled_start_date
+ Cast(Substr(scheduled_start_time, 1,5) AS INTERVAL HOUR TO MINUTE)
A start date which is a timestamp seems to indicate this was ported from Oracle/SQL Server?
And a 24 hour time format with a AM/PM suffix is also quite strange.
A couple things to try:
Convert the separate Scheduled Date and Scheduled Time fields into strings, concatenate them, and feed that into a TIMESTAMP CAST. Something like:
SELECT
CAST(CAST(Scheduled_Date AS DATE) AS VARCHAR(25)) AS Date_String,
CAST(CAST(Scheduled_Time AS TIME FORMAT 'HH:MM BB') AS VARCHAR(25)) AS Time_String,
CAST(TRIM(Date_String) || ' ' || TRIM(Time_String) AS TIMESTAMP(0)) AS MyTimestamp
Cast the Scheduled Time field as a TIME data type. Cast the Scheduled Date field as a DATE data type. Then somehow combine the two into a TIMESTAMP field -- either with a CAST or some kind of timestamp constructor function (not sure if this is possible)
Option 1 should work for sure as long as you properly format the strings. Try to avoid using SUBSTRING and instead use FORMAT to cast as DATE/TIME fields. Not sure about Option 2. Take a look at these link for how to format DATE/TIME fields using the FORMAT clause:
https://www.info.teradata.com/HTMLPubs/DB_TTU_16_00/index.html#page/SQL_Reference%2FB035-1143-160K%2Fmuq1472241377538.html%23wwID0EPHKR
https://www.info.teradata.com/HTMLPubs/DB_TTU_16_00/index.html#page/SQL_Reference/B035-1143-160K/cmy1472241389785.html
Sorry, I don't have access to a TD system to test it out. Let me know if you have any luck.
The below command is used for getting the yerterdays date in Unix Ksh on HP UX
DATE_STAMP=`TZ=CST+24 date +%m/%d/%Y`
Can somebody let me know what does "CST + 24 date " in above command do?
That command sets the timezone to CST+24 and returns the date in that timezone.
if you are looking for a command to find out yesterday's date, you are better of using the TZ trick esp. if you are in a timezone that observes DST.
use perl one liner instead.
#this takes local time and substracts a day(24*60*60 seconds) and formats the time.
echo `perl -e 'use POSIX; print strftime "%m/%d/%Y%", localtime time-86400;'`
Just a guess on your command - since its yesterday at CST+24 timezone the command returns yesterday's date and if you use CST-24, it retunrs tomorrow's date since the date translates to tomorrows date at CST-24 timezone.
VARIABLE=VALUE COMMAND means that you set the environment variable VARIABLE to VALUE but not persistent but only for the executed command COMMAND.
In your example that means: Execute the date command with the environment variable TZ set to CST+24 (which is Central Standard Time plus 24 hours).
Check out this page http://www.kodkast.com/blogs/unix-shell-scripting/how-to-get-yesterdays-date where you can find out yesterday's date as well as any other previous date in unix shell scripting.
How to get the current date value in epoch i.e., number of days elapsed since 1970-1-1. I need solution in unix shell script.
The Unix Date command will display in epoch time
the command is
date +"%s"
https://linux.die.net/man/1/date
Edit: Some people have observed you asked for days, so it's the result of that command divided by 86,400
Update: The answer previously posted here linked to a custom script that is no longer available, solely because the OP indicated that date +'%s' didn't work for him. Please see UberAlex' answer and cadrian's answer for proper solutions. In short:
For the number of seconds since the Unix epoch use date(1) as follows:
date +'%s'
For the number of days since the Unix epoch divide the result by the number of seconds in a day (mind the double parentheses!):
echo $(($(date +%s) / 60 / 60 / 24))
echo $(($(date +%s) / 60 / 60 / 24))
echo `date +%s`/86400 | bc
Depending on the language you're using it's going to be something simple like
CInt(CDate("1970-1-1") - CDate(Today()))
Ironically enough, yesterday was day 40,000 if you use 1/1/1900 as "day zero" like many computer systems use.