Possible to invert the randomForest function in R? - r

I computed a random forest to predict a target value in a large data structure.
The matrix contains some thousand rows, about 20 input variables and one output/target/response variable.
For example, the dataframe df is like:
| V1 | V2 | V3 | V4 | ... | Rsp |
---------------------------------
| 1 | 8 | 2 | 3 | ... | 1.5 |
| 2 | 4 | 3 | 4 | ... | 1.3 |
| 5 | 7 | 6 | 3 | ... | 1.4 |
| 2 | 8 | 8 | 4 | ... | 1.9 |
| 9 | 3 | 1 | 6 | ... | 2.1 |
. . . . . .
I calculated the forest:
df.r <- randomForest(Rsp ~ . , data = df , subset = train , mtry = 50, ntree=200)
p <- predict(df.r, df[-train,])
I want to minimize the response in order to get the best combinations of input variables. But because the input and output are noisy, I cannot directly take the variables at the minimum response value.
So my question is: Is it possible to go the tree bottom-up? Is it possible to get the combinations of variables which give me a low response value?

Related

Data preparation before running exact logistic (elrm in R)

I started out using Firth's logistic (logistf) to deal with my small sample size (n=80), but wanted to try out exact logistic regression using the elrm package. However, I'm having trouble figuring out how to create the "collapsed" data required for elrm to run. I have a csv that I import into R as a dataframe that has the following variables/columns. Here is some example data (real data has a few more columns and 80 rows):
+------------+-----------+-----+--------+----------------+
| patien_num | asymmetry | age | female | field_strength |
+------------+-----------+-----+--------+----------------+
| 1 | 1 | 25 | 1 | 1.5 |
| 2 | 0 | 50 | 0 | 3 |
| 3 | 0 | 75 | 1 | 1.5 |
| 4 | 0 | 33 | 1 | 3 |
| 5 | 0 | 66 | 1 | 3 |
| 6 | 0 | 99 | 0 | 3 |
| 7 | 1 | 20 | 0 | 1.5 |
| 8 | 1 | 40 | 1 | 3 |
| 9 | 0 | 60 | 1 | 3 |
| 10 | 0 | 80 | 0 | 1.5 |
+------------+-----------+-----+--------+----------------+
Basically my data is one line per patient (not a frequency table). I'm trying to run a regression with asymmetry as the dependent variable and age (continuous), female (binary), and field_strength (factor) as independent variables. I'm trying to understand how to collapse this into the appropriate format so I can get that "ntrials" part required for the elrm formula.
I've looked at https://stats.idre.ucla.edu/r/dae/exact-logistic-regression/ but they start with data in a different format than mine, and having trouble. Any help appreciated!

Data imputation for empty subsetted dataframes in R

I'm trying to build a function in R in which I can subset my raw dataframe according to some specifications, and thereafter convert this subsetted dataframe into a proportion table.
Unfortunately, some of these subsettings yields to an empty dataframe as for some particular specifications I do not have data; hence no proportion table can be calculated. So, what I would like to do is to take the closest time step from which I have a non-empty subsetted dataframe and use it as an input for the empty subsetted dataframe.
Here some insights to my dataframe and function:
My raw dataframe looks +/- as follows:
| year | quarter | area | time_comb | no_individuals | lenCls | age |
|------|---------|------|-----------|----------------|--------|-----|
| 2005 | 1 | 24 | 2005.1.24 | 8 | 380 | 3 |
| 2005 | 2 | 24 | 2005.2.24 | 4 | 490 | 2 |
| 2005 | 1 | 24 | 2005.1.24 | 3 | 460 | 6 |
| 2005 | 1 | 21 | 2005.1.21 | 25 | 400 | 2 |
| 2005 | 2 | 24 | 2005.2.24 | 1 | 680 | 6 |
| 2005 | 2 | 21 | 2005.2.21 | 2 | 620 | 5 |
| 2005 | 3 | 21 | 2005.3.21 | NA | NA | NA |
| 2005 | 1 | 21 | 2005.1.21 | 1 | 510 | 5 |
| 2005 | 1 | 24 | 2005.1.24 | 1 | 670 | 4 |
| 2006 | 1 | 22 | 2006.1.22 | 2 | 750 | 4 |
| 2006 | 4 | 24 | 2006.4.24 | 1 | 660 | 8 |
| 2006 | 2 | 24 | 2006.2.24 | 8 | 540 | 3 |
| 2006 | 2 | 24 | 2006.2.24 | 4 | 560 | 3 |
| 2006 | 1 | 22 | 2006.1.22 | 2 | 250 | 2 |
| 2006 | 3 | 22 | 2006.3.22 | 1 | 520 | 2 |
| 2006 | 2 | 24 | 2006.2.24 | 1 | 500 | 2 |
| 2006 | 2 | 22 | 2006.2.22 | NA | NA | NA |
| 2006 | 2 | 21 | 2006.2.21 | 3 | 480 | 2 |
| 2006 | 1 | 24 | 2006.1.24 | 1 | 640 | 5 |
| 2007 | 4 | 21 | 2007.4.21 | 2 | 620 | 3 |
| 2007 | 2 | 21 | 2007.2.21 | 1 | 430 | 3 |
| 2007 | 4 | 22 | 2007.4.22 | 14 | 410 | 2 |
| 2007 | 1 | 24 | 2007.1.24 | NA | NA | NA |
| 2007 | 2 | 24 | 2007.2.24 | NA | NA | NA |
| 2007 | 3 | 24 | 2007.3.22 | NA | NA | NA |
| 2007 | 4 | 24 | 2007.4.24 | NA | NA | NA |
| 2007 | 3 | 21 | 2007.3.21 | 1 | 560 | 4 |
| 2007 | 1 | 21 | 2007.1.21 | 7 | 300 | 3 |
| 2007 | 3 | 23 | 2007.3.23 | 1 | 640 | 5 |
Here year, quarter and area refers to a particular time (Year & Quarter) and area for which X no. of individuals were measured (no_individuals). For example, from the first row we get that in the first quarter of the year 2005 in area 24 I had 8 individuals belonging to a length class (lenCLs) of 380 mm and age=3. It is worth to mention that for a particular year, quarter and area combination I can have different length classes and ages (thus, multiple rows)!
So what I want to do is basically to subset the raw dataframe for a particular year, quarter and area combination, and from that combination calculate a proportion table based on the number of individuals in each length class.
So far my basic function looks as follows:
LAK <- function(df, Year="2005", Quarter="1", Area="22", alkplot=T){
require(FSA)
# subset alk by year, quarter and area
sALK <- subset(df, year==Year & quarter==Quarter & area==Area)
dfexp <- sALK[rep(seq(nrow(sALK)), sALK$no_individuals), 1:ncol(sALK)]
raw <- t(table(dfexp$lenCls, dfexp$age))
key <- round(prop.table(raw, margin=1), 3)
return(key)
if(alkplot==TRUE){
alkPlot(key,"area",xlab="Age")
}
}
From the dataset example above, one can notice that for year=2005 & quarter=3 & area=21, I do not have any measured individuals. Yet, for the same area AND year I have data for either quarter 1 or 2. The most reasonable assumption would be to take the subsetted dataframe from the closest time step (herby quarter 2 with the same area and year), and replace the NA from the columns "no_individuals", "lenCls" and "age" accordingly.
Note also that for some cases I do not have data for a particular year! In the example above, one can see this by looking into area 24 from year 2007. In this case I can not borrow the information from the nearest quarter, and would need to borrow from the previous year instead. This would mean that for year=2007 & area=24 & quarter=1 I would borrow the information from year=2006 & area=24 & quarter 1, and so on and so forth.
I have tried to include this in my function by specifying some extra rules, but due to my poor programming skills I didn't make any progress.
So, any help here will be very much appreciated.
Here my LAK function which I'm trying to update:
LAK <- function(df, Year="2005", Quarter="1", Area="22", alkplot=T){
require(FSA)
# subset alk by year, quarter and area
sALK <- subset(df, year==Year & quarter==Quarter & area==Area)
# In case of empty dataset
#if(is.data.frame(sALK) && nrow(sALK)==0){
if(sALK[rowSums(is.na(sALK)) > 0,]){
warning("Empty subset combination; data will be subsetted based on the
nearest timestep combination")
FIXME: INCLDUE IMPUTATION RULES HERE
}
dfexp <- sALK[rep(seq(nrow(sALK)), sALK$no_individuals), 1:ncol(sALK)]
raw <- t(table(dfexp$lenCls, dfexp$age))
key <- round(prop.table(raw, margin=1), 3)
return(key)
if(alkplot==TRUE){
alkPlot(key,"area",xlab="Age")
}
}
So, I finally came up with a partial solution to my problem and will include my function here in case it might be of someone's interest:
LAK <- function(df, Year="2005", Quarter="1", Area="22",alkplot=T){
require(FSA)
# subset alk by year, quarter, area and species
sALK <- subset(df, year==Year & quarter==Quarter & area==Area)
print(sALK)
if(nrow(sALK)==1){
warning("Empty subset combination; data has been subsetted to the nearest input combination")
syear <- unique(as.numeric(as.character(sALK$year)))
sarea <- unique(as.numeric(as.character(sALK$area)))
sALK2 <- subset(df, year==syear & area==sarea)
vals <- as.data.frame(table(sALK2$comb_index))
colnames(vals)[1] <- "comb_index"
idx <- which(vals$Freq>1)
quarterId <- as.numeric(as.character(vals[idx,"comb_index"]))
imput <- subset(df,year==syear & area==sarea & comb_index==quarterId)
dfexp2 <- imput[rep(seq(nrow(imput)), imput$no_at_length_age), 1:ncol(imput)]
raw2 <- t(table(dfexp2$lenCls, dfexp2$age))
key2 <- round(prop.table(raw2, margin=1), 3)
print(key2)
if(alkplot==TRUE){
alkPlot(key2,"area",xlab="Age")
}
} else {
dfexp <- sALK[rep(seq(nrow(sALK)), sALK$no_at_length_age), 1:ncol(sALK)]
raw <- t(table(dfexp$lenCls, dfexp$age))
key <- round(prop.table(raw, margin=1), 3)
print(key)
if(alkplot==TRUE){
alkPlot(key,"area",xlab="Age")
}
}
}
This solves my problem when I have data for at least one quarter of a particular Year & Area combination. Yet, I'm still struggling to figure out how to deal when I do not have data for a particular Year & Area combination. In this case I need to borrow data from the closest Year that contains data for all the quarters for the same area.
For the example exposed above, this would mean that for year=2007 & area=24 & quarter=1 I would borrow the information from year=2006 & area=24 & quarter 1, and so on and so forth.
I don't know if you have ever encountered MICE, but it is a pretty cool and comprehensive tool for variable imputation. It also allows you to see how the imputed data is distributed so that you can choose the method most suited for your problem. Check this brief explanation and the original package description

How to get a query result into a key value form in HiveQL

I have tried different things, but none succeeded. I have the following issue, and would be very gratefull if someone could help me.
I get the data from a view as several billions of records, for different measures
A)
| s_c_m1 | s_c_m2 | s_c_m3 | s_c_m4 | s_p_m1 | s_p_m2 | s_p_m3 | s_p_m4 |
|--------+--------+--------+--------+--------+--------+--------+--------|
| 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
|--------+--------+--------+--------+--------+--------+--------+--------|
Then I need to aggregate it by each measure. And so long so fine. I got this figured out.
B)
| s_c_m1 | s_c_m2 | s_c_m3 | s_c_m4 | s_p_m1 | s_p_m2 | s_p_m3 | s_p_m4 |
|--------+--------+--------+--------+--------+--------+--------+--------|
| 3 | 6 | 9 | 12 | 15 | 18 | 21 | 24 |
|--------+--------+--------+--------+--------+--------+--------+--------|
Then I need to get the data in the following form. I need to turn it into a key-value form.
C)
| measure | c | p |
|---------+----+----|
| m1 | 3 | 15 |
| m2 | 6 | 18 |
| m3 | 9 | 21 |
| m4 | 12 | 24 |
|---------+----+----|
The first 4 columns from B) would form in C) the first column, and the second 4 columns would form another column.
Is there an elegant way, that could be easily maintainable? The perfect solution would be if another measure would be introduced in A) and B), there no modification would be required and it would automatically pick up the difference.
I know how to get this done in SqlServer and Postgres, but here I am missing the expirience.
I think you should use map for this

Creation of Panel Data set in R

Programmers,
I have some difficulties in structuring my panel data set.
My panel data set, for the moment, has the following structure:
Exemplary here only with T = 2 and N = 3. (My real data set, however, is of size T = 6 and N = 20 000 000 )
Panel data structure 1:
Year | ID | Variable_1 | ... | Variable_k |
1 | 1 | A | ... | B |
1 | 2 | C | ... | D |
1 | 3 | E | ... | F |
2 | 1 | G | ... | H |
2 | 2 | I | ... | J |
2 | 3 | K | ... | L |
The desired structure is:
Panel data structure 2:
Year | ID | Variable_1 | ... | Variable_k |
1 | 1 | A | ... | B |
2 | 1 | G | ... | H |
1 | 2 | C | ... | D |
2 | 2 | I | ... | J |
1 | 3 | E | ... | F |
2 | 3 | K | ... | L |
This data structure represents the classic panel data structure, where the yearly observations over the whole period are structured for all individuals block by block.
My question: Is there any simple and efficient R-solution that changes the data structure from Table 1 to Table 2 for very large data sets (data.frame).
Thank you very much for all responses in advance!!
Enrico
You can reorder the rows of your dataframe using order():
df=df[order(df$ID,df$Year),]

R : Create a factor from two variables containing ranks and levels

Everything is in the title, I got from a database many columns, paired two-by-two containing codes and labels for some variables, I want an easy way to create half as many factors, with, for each factor levels/codes matching to the original two variables.
Here is an exemple of original data for two factors
| customer_type | customer_type_name | customer_status | customer_status_name |
|----------------------|----------------------|----------------------|----------------------|
| 1 | A | 2 | Beta |
| 2 | B | 2 | Beta |
| 3 | C | 1 | Alpha |
| 2 | B | 3 | Gamma |
| 1 | A | 4 | Delta |
| 3 | C | 2 | Beta |
i.e. a simpler way (simpler to call in a function for lots of variables) to do from dataframe "accounts"
a<-accounts[,c("customertypecode","customertypecodename")]
a<-a[!duplicated(a),]
a<-a[order(a$customertypecode),]
accounts$customertypecode<-factor(accounts$customertypecode,labels=a$customertypecodename[!is.na(a$customertypecodename)])

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