using character to definition of input function in r - r

I want to write a function. However, the assumption is that I don't know the input arguments of the function. I just have a character vector to define input arguments of the function. Consider the following code:
f <- expression(exp(-d^2/s^2) )
fx <- function(d, s){ eval( f[[1]] ) }
In the above code, I know the parameters of expression and easily define a calculative function for it. But I get the expression from the user and I don't know what are the parameters. So, I want something like this:
f <- expression(exp(-d^2/s^2) )
v = all.vars(f)
#"d" "s"
fx <- function(?){ eval( f[[1]] ) }
I want to convert v to d and s on input function instead of ?. Is there any way?

There are a few ways to construct functions programmatically, one being:
body <- quote(exp(-d^2/s^2))
arg_names <- all.vars(body)
args <- setNames(rep(NA,length(arg_names)),all.vars(body))
fx <- as.function(c(args,body))
> fx(1,1)
[1] 0.3678794

Related

Evaluate listed strings to create function object in r

I need a function created by a list of commands to fully evaluate so that it is identical to the "manual" version of the function.
Background: I am using ScaleR functions in Microsoft R Server and need to apply a set of transformations as a function. ScaleR is very picky about needing to be passed a function that is phrased exactly as specified below:
functionThatWorks <- function(data) {
data$marital_status_p1_ismarried <- impute(data$marital_status_p1_ismarried)
return(data)
}
I have a function that creates this list of transformations (and hundreds more, hence the need to functionalize its writing).
transformList <- list ("data$ismarried <- impute(data$ismarried)",
"data$issingle <- impute(data$issingle)")
This line outputs the evaluated string that I want to the console, but I am unaware of a way to move it from console output to being used in a function:
cat(noquote(unlist(bquote( .(noquote(transformList[1]))))))
I need to evaluate functionIWant so that it is identical to functionThatWorks.
functionIWant <- function(data){
eval( cat(noquote(unlist(bquote( .(noquote(transformList[1])))))) )
return(data)
}
identical(functionThatWorks, functionIWant)
EDIT: Adding in the answer based on #dww 's code. It works well in ScaleR. It is identical, minus meaningless spacing.
functionIWant <- function(){}
formals(functionIWant) <- alist(data=NULL)
functionIWant.text <- parse(text = c(
paste( bquote( .(noquote(transformList[1]))), ";", "return(data)\n")
))
body(functionIWant) <- as.call(c(as.name("{"), functionIWant.text))
Maybe something like this?
# 1st define a 'hard-coded' function
f1 <- function (x = 2)
{
y <- x + 1
y^2
}
f1(3)
# [1] 16
# now create a similar function from a character vector
f2 <- function(){}
formals(f2) <- alist(x=2)
f2.text <- parse(text = c('y <- x + 1', 'y^2'))
body(f2) <- as.call(c(as.name("{"), f2.text))
f2(3)
# [1] 16

R function to process multiple expressions

I'm trying to create a function that can evaluate multiple independent expressions. My goal is to input many expressions at once like myfunction(x = 2, y = c(5,10,11) , z = 10, ...), and use each expression's name and value to feed other functions inside of it. The transform() function works kind of like that: transform(someData, x = x*2, y = y + 1).
I know I can get the name and the value of an expression using:
> names(expression(x=2))
[1] "x"
> eval(expression(x=2))
[1] 2
However, I don't know how to pass those expressions through a function. Here is some of my work so far.
With unquoted expression (x=2) I could not pass it using the dots (...).
> myfunction <- function(...) { names(expression(...)) }
> myfunction(x=2)
expression(...)
Now, using quotes. It gets the value but not the name. Parse structure is different from the tradicional expression. See class(expression(x=2)) and class(parse(text="x=2")), then str(expression(x=2)) and str(parse(text="x=2")).
> myfunction <- function(...) {
assign("temp",...)
results <- parse(text=temp)
cat(names(results))
cat(eval(results))
}
> myfunction("x=2")
> 2
So, any ideas?
It's unclear exactly what you want the return of your function to be. You can get the names and expressions passed to a function using
myfunction <- function(...) {
x<-substitute(...())
#names(x)
x
}
myfunction(x = 2, y = c(5,10,11) , z = 10)
Here you get a named list and each of the items is an unevaluated expression or language object that you can evaluate later if you like.

R decorator to change both input and output

I am trying to refactor this. In Python, I would use a decorator. What's the 'R'tful way to do this? Say, we have this pattern
good_input <- format_input( bad_input )
bad_output <- use_this_func( good_input )
good_output <- format_output( bad_output )
And then again,
good_input <- format_input( bad_input )
bad_output <- use_this_other_func( good_input )
good_output <- format_output( bad_output )
As you can imagine, this proliferates like wild mushroom. I want something close to this solution
use_this_robust_func <- wrapper( use_this_func ) # Or wrapper( use_this_other_func )
good_output <- use_this_robust_func( bad_input )
I'm trying to wrap the call to use_this_func and use_this_other_func (and related functions) with format_input and format_output. Using in part this question, so far I have
wrapper <- function( func_not_robust ){
func_robust <- function( ... ){
# This is the bit I haven't figured out
... format_input( ) ... # supposed to convert bad input - the function argument - to good
bad_output <- func_not_robust( ... ) # supposed to take good input as argument
good_output <- format_output( bad_output )
return( good_output )
}
return( func_robust )
}
Sorry for the pseudo-code. Note I am not sure that this is the way to go in R. I'm not wedded to the sketch of the solution above, which is born from translating Python - and badly at that - to R. How would a R native do this? Thanks in advance.
I think you are pretty much there. Here's an example where the first stage of cleaning is to replace negative input values with NAs, and the output cleaning is simple to negate everything:
format_input <- function(x){
x[x<0] <- NA
return(x)
}
format_output <- function(x){
return(-x)
}
wrapper <- function(f){
force(f)
g = function(bad_input){
good_input = format_input(bad_input)
bad_output = f(good_input)
good_output = format_output(bad_output)
return(good_output)
}
g
}
Then:
> wrapper(sqrt)(c(-2,2))
[1] NA -1.414214
wrapper(sqrt) returns a "closure", which is a function with enclosed data. The function f has the value of the function sqrt as part of that enclosure.
The force call is needed since f doesn't get evaluated when g is created, and in some cases without it then f won't get found when running the wrapped version due to R's lazy evaluation or "promises" or something. I'm never exactly sure when this happens but adding a force call to unevaluated arguments to closure generators is zero-overhead. Its a bit cargo-cult programming but never a problem.
A more flexible solution might be to specify the input and output cleaning functions as functions to the closure generator, with defaults:
wrapper <- function(f, fi=format_input, fo=format_output){
force(f) ; force(fi); force(fo)
g = function(bad_input){
good_input = fi(bad_input)
bad_output = f(good_input)
good_output = fo(bad_output)
return(good_output)
}
g
}
Then I can wrap sqrt with different input and output formatters. For example to change that negative function with a positive one:
> make_pos = function(x){abs(x)}
> wrapper(sqrt,fo=make_pos)(c(-2,2))
[1] NA 1.414214
An even more flexible solution is to spot that you are generating chains of functions here. Your output is format_output(sqrt(format_output(bad_input))). This is function composition and there's a function in the functional package to do that:
> require(functional)
> w = Compose(format_input, sqrt, format_output)
> w(c(-2,2))
[1] NA -1.414214
This perhaps gets more useful when you have more than three functions in your composition, you could for example have a list of functions and compose them all together using do.call....
Once you see patterns in functional programming its addictive. I'll stop now.

R convert text field to function

I want to use information from a field and include it in a R function, e.g.:
data #name of the data.frame with only one raw
"(if(nclusters>0){OptmizationInputs[3,3]*beta[1]}else{0})" # this is the raw
If I want to use this information inside a function how could I do it?
Another example:
A=c('x^2')
B=function (x) A
B(2)
"x^2" # this is the return. I would like to have the return something like 2^2=4.
Use body<- and parse
A <- 'x^2'
B <- function(x) {}
body(B) <- parse(text = A)
B(3)
## [1] 9
There are more ideas here
Another option using plyr:
A <- 'x^2'
library(plyr)
body(B) <- as.quoted(A)[[1]]
> B(5)
[1] 25
A <- "x^2"; x <- 2
BB <- function(z){ print( as.expression(do.call("substitute",
list( parse(text=A)[[1]], list(x=eval(x) ) )))[[1]] );
cat( "is equal to ", eval(parse(text=A)))
}
BB(2)
#2^2
#is equal to 4
Managing expressions in R is very weird. substitute refuses to evaluate its first argument so you need to use do.call to allow the evaluation to occur before the substitution. Furthermore the printed representation of the expressions hides their underlying representation. Try removing the fairly cryptic (to my way of thinking) [[1]] after the as.expression(.) result.

Create a list of functions from a vector of characters

Thanks in advance, and sorry if this question has been answered previously - I have looked pretty extensively. I have a dataset containing a row of with concatenated information, specifically: name,color code,some function expression. For example, one value may be:
cost#FF0033#log(x)+6.
I have all of the code to extract the information, and I end up with a vector of expressions that I would like to convert to a list of actual functions.
For example:
func.list <- list()
test.func <- c("x","x+1","x+2","x+3","x+4")
where test.func is the vector of expressions. What I would like is:
func.list[[3]]
To be equivalent to
function(x){x+3}
I know that I can create a function using:
somefunc <- function(x){eval(parse(text="x+1"))}
to convert a character value into a function. The problem comes when I try and loop through to make multiple functions. For an example of something I tried that didn't work:
for(i in 1:length(test.func)){
temp <- test.func[i]
f <- assign(function(x){eval(expr=parse(text=temp))})
func.list[[i]] <- f
}
Based on another post (http://stats.stackexchange.com/questions/3836/how-to-create-a-vector-of-functions) I also tried this:
makefunc <- function(y){y;function(x){y}}
for(i in 1:length(test.func)){
func.list[[i]] <- assign(x=paste("f",i,sep=""),value=makefunc(eval(parse(text=test.func[i]))))
}
Which gives the following error: Error in eval(expr, envir, enclos) : object 'x' not found
The eventual goal is to take the list of functions and apply the jth function to the jth column of the data.frame, so that the user of the script can specify how to normalize each column within the concatenated information given by the column header.
Maybe initialize your list with a single generic function, and then update them using:
foo <- function(x){x+3}
> body(foo) <- quote(x+4)
> foo
function (x)
x + 4
More specifically, starting from a character, you'd probably do something like:
body(foo) <- parse(text = "x+5")
Just to add onto joran's answer, this is what finally worked:
test.data <- matrix(data=rep(1,25),5,5)
test.data <- data.frame(test.data)
test.func <- c("x","x+1","x+2","x+3","x+4")
func.list <- list()
for(i in 1:length(test.func)){
func.list[[i]] <- function(x){}
body(func.list[[i]]) <- parse(text=test.func[i])
}
processed <- mapply(do.call,func.list,lapply(test.data,list))
Thanks again, joran.
This is what I do:
f <- list(identity="x",plus1 = "x+1", square= "x^2")
funCreator <- function(snippet){
txt <- snippet
function(x){
exprs <- parse(text = txt)
eval(exprs)
}
}
listOfFunctions <- lapply(setNames(f,names(f)),function(x){funCreator(x)}) # I like to have some control of the names of the functions
listOfFunctions[[1]] # try to see what the actual function looks like?
library(pryr)
unenclose(listOfFunctions[[3]]) # good way to see the actual function http://adv-r.had.co.nz/Functional-programming.html
# Call your funcions
listOfFunctions[[2]](3) # 3+1 = 4
do.call(listOfFunctions[[3]],list(3)) # 3^2 = 9
attach(listOfFunctions) # you can also attach your list of functions and call them by name
square(3) # 3^2 = 9
identity(7) # 7 ## masked object identity, better detach it now!
detach(listOfFunctions)

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