I have the time as the following 103400 with string type I need to convert it into 10:34:00 in a time format using pyspark only.
suppose that the name of the data frame is u and the name of the column is hhmm_utente
Related
Date Column in Excel
Date
2021-02-19 10:05:03
2021-02-19 09:47:19
2021-02-19 10:53:19
Date column importing in R
Date
44245.5487615741
44245.6650578704
4246.42021990744
How do I change this date back in timestamp
First it would be good to know how you load the data.
For converting the Excel number to date this might help you How to convert Excel date format to proper date in R
If you use openxlsx::read.xlsx() you probably want to use the detectDates parameter.
I transfer the data into Tera Data with fastload now in one column 'ENDDATE' There are 2 values stored 'NULL' and Timestamp value like format
YYYY-MM-DDBHH:MI:SS
I want to transfer both values into new table
I want to NULL value replace with something and other Timestamp data to date format like
YYYY-MM-DD
How to transfer both values into table?
I have a xpt data frame that I read into RStudio with a DateTimePOSIX column that looks like this:
ID DateTime
1 2017-01-06T06:02
1 2017-01-30T08:02
2 2017-01-30T15:02
How can I convert the DateTime column into DateTimePOSIX?
I need the as.POSIXct formatted DateTime for further calculations of time differences etc.
I have a data frame with a time column, the format is like dd/mm/yyyy and I want to
convert dd/mm/yyyy to a number mmyyyy and store it in a new column
then create another two new columns for mm and yyyy separately and create a new data frame with my original data frame and these 2 columns
How can I do it? Thanks!
If the time column is not character you can use:
format(timecolumn,"%m%Y")
format(timecolumn,"%m")
format(timecolumn,"%Y")
If it is character:
paste0(substr(timecolumn,4,5),substr(timecolumn,7,10))
substr(timecolumn,4,5)
substr(timecolumn,7,10)
Format a date from CSV into a date R can use.
I have a time series data file. I want to load it into R, and cast the Date column to be something usable by R. Can I specify the input format to as.Date(), or use another function that will correctly cast a Date such as 1/1/14?
In other languages I'm used to passing in a format string that tells the caster exactly how to format it, e.g. toDate('1/1/1', '%d/%m/%y'). I haven't found this function yet for R.
my_time_series.csv
Date Value
1/1/14 123
1/2/14 128.56
1/3/14 129.14
1/4/14 130.13
1/5/14 137.97
1/6/14 141.05
1/7/14 141.35
1/8/14 142.14
1/9/14 142.14
1/10/14 149.89
Now I can import it into R:
$ R
> dat = read.csv("time series test.csv", header = TRUE)
> dat
Date Value
1 1/1/14 123.0000
2 1/2/14 128.5693
3 1/3/14 129.1474
4 1/4/14 130.1361
5 1/5/14 137.9758
6 1/6/14 141.0548
7 1/7/14 141.3517
8 1/8/14 142.1449
9 1/9/14 142.1479
10 1/10/14 149.8912
Ok now I need to format those dates as actual dates. The as.Date() casting function looks promising, but returns an incorrect date:
> as.Date('1/10/14')
[1] "0001-10-14"
So I searched for whether I can specify an input format for as.Date(), but it only has a second parameter format for the output format.
I tried to work around this in Excel before saving the CSV, but it doesn't have any formats that seem to work by default with as.Date().
I'm an idiot, was just typing in the wrong formatter. This works fine.
> as.Date('1/10/14', '%m/%d/%y')
[1] "2014-01-10"
So if I have any arbitrary date format in the future, just rearrange the format string.