I am using aspx to initialize the whatsApp click to chat feature to share a link.
The aspx code is :
The link was working fine. I was able to share the link. But in the recent months i am not able to share the link as i get a message from whatsapp in my mobile displayed as
Couldn't open link
Screen Shot:
NOTE: I am able to share from web browser but not from my mobile.
Is there anything wrong in the syntax or has whatsapp updated their feature, but i dont think so as their docs are still having the same info ?
Edit: The output url looks like this in chrome inspector:
https://wa.me/?text=https%3a%2f%2fwww.website.com%2fblog%2fPageName.aspx%3fblog%3dtitleword-your-titleword-system-using-titleword%26id%3d10%26temp%3dq
For computers, you will want to use this link...
https://api.whatsapp.com/send?text=YourTextHere
Otherwise, if you use wa.me, you will get an error page, unless you have the phone number included. For example, this links to an error: https://wa.me/?text=SomeTexttoShare
Typically, you don't know the number, and you want the user to specify. In that case, you MUST use the api.whatsapp.com domain.
I tried the same link in different android browser(FireFox) and it was working fine.
For chrome i changed the link to this -> whatsapp://send?text=
My code:
string WhatsappShareURL = "whatsapp://send?text=" + Request.Url.AbsoluteUri;
hlWhatsappMobile.NavigateUrl = Server.UrlEncode(WhatsappShareURL);
For Computers:
I use this link -> https://wa.me/?text=
My code:
string WhatsappShareURL = "https://wa.me/?text=" + Request.Url.AbsoluteUri;
hlWhatsappWeb.NavigateUrl = Server.UrlEncode(WhatsappShareURL);
Then i toggle them in jquery:
$(document).ready(function () {
if ($(window).width() < 520) {
//Show mobile link
}
else {
//Show Web link
}
});
Related
We're using AddThis Social Share functionality with our Sitecore/MVC application. The problem we're facing is that the LinkedIn share always opens in new window. On Inspect, we can see the target=_blank in code, which is not being added in our code.
Any help?
Thanks,
Chandana
The behavior of each share button is as per the website to which the page is being shared. If you test each button (say Facebook, G+, Twitter, LinkedIn, etc.) you will notice that they all work differently. It's not AddThis choice. This is because each website has its own API and that's the way that website decided it would work with their system. LinkedIn happens to open a separate window... Pinterest first opens a popup within your page and then another window after you selected the image you wanted to share. G+ and Facebook open a new tab. And the popups/windows all look quite different, but the users should recognize each respective brand as a result...
I suspect that this is a problem with the AddThis Social Share functionality. To share on LinkedIn, all you need is the following URL format...
https://www.linkedin.com/sharing/share-offsite/?url={url}
Then you can setup your <a href="..."> element however you like, with target="_blank" or not.
Source: Official LinkedIn Sharing Documentation.
Can try out below JavaScript code, which will overwrite addthis functionality, and make linkedIn as popup,
setInterval make sure click event attached to dynamically generated anchor tag
$(document).ready(function () {
var clickinterval = setInterval(setclickevent, 500);
function setclickevent() {
if ($('.at-svc-linkedin').length > 0) {
$('.at-svc-linkedin').on('click', function () {
window.open('https://www.linkedin.com/sharing/share-offsite/?url=' + fixedEncodeURIComponent(window.location.href), 'popup', 'width=600,height=600');
e.preventDefault();
return false;
});
clearInterval(clickinterval);
}
}
function fixedEncodeURIComponent(str) {
return encodeURIComponent(str).replace(/[!'()*]/g, function (c) {
return '%' + c.charCodeAt(0).toString(16);
});
}
});
I've got a webpage I want to hook in to my Adobe Air app. It's running JavaScript, so I can't open it in the app, but I'm trying to launch it in the default system browser.
Here's the code that's supposed to be launching the page:
public function beginModule():void {
var loader:HTMLLoader = new HTMLLoader();
var gameURL:URLRequest = new URLRequest("file:///path/to/file.html");
loader.navigateInSystemBrowser = true;
loader.load(gameURL);
}
I've also tried using
flash.net.navigateToURL(gameURL);
but that had no effect.
Every time I hit the above method, that block executes but nothing happens other than a quick cursor change-- no browser opened, no change in the app. What am I missing here?
Before you start, check if the HTML page is properly running in the browser.
To open a HTML page in flex, use the HTML tag: <mx:HTML></mx:HTML>
Something like this: https://snipt.net/anishnair/flex-show-html-page/?key=28838d54ac287180032dee000ce33a74
Thank you.
Regards,
Anish
Simply use :
navigateToURL(url,"_blank");
to navigate to the url in the web-browser.
I have an Google apps script and I want to call this Google apps script on my web page?How can I achieve this?This is my Google apps Script code for creating a google doc on my drive.
function createAndSendDocument() {
var doc = DocumentApp.create('Hello World');
doc.appendParagraph('This document was created by my first Google Apps Script.');
doc.saveAndClose();
var url = doc.getUrl();
var emailAddress = Session.getActiveUser().getEmail();
GmailApp.sendEmail(emailAddress,
'Hello '+ url);
}
and I want to call this function when I click on a button on my web page.But I don't know how to call this function on my button click.And one more thing I also save this script and change this version number and deploy as a web app and get the URL of this Google apps Script.
UPDATE: (added incorrectly in an answer)
Actually i am using this line like this.
btnClick.addEventListener("click", function () {
Page.ClientScript.RegisterStartupScript(this.GetType(), "GoogleFunction", "createAndSendDocument()", true);
}
So please now tell me what's wrong in that?When i run my application then it's show me an error like "The Page is not defined".
Look also at this documentation and also this one, everything is clearly explained .
you can add the div and the code in your page as you needed. also you need to add the javascript codes inside your head if it exists.
hi you can use this code on button click after adding a script manager in the form
Page.ClientScript.RegisterStartupScript(this.GetType(),"GoogleFunction","createAndSendDocument()",true);
I'm trying to duplicate the behaviour of the "Share on Facebook" button from Youtube. Basically, inside a Flex app I'll have a button and when I click it I want a popup that enables me to post something on the wall.
While it is possible to make a call to javascript to open the pop-up I want to be able to set the images and the text of my posting.
Do you know how I could set the images or text as a paramter to the sharer window?
Thank you!
This is fairly straightforward to do. Youtube uses the Facebook API which pops up a new window (Info on Facebook sharer API).
To do this in flex,
Create a button that onClick will call a javascript method, ExternalInterface.call("fbLink", "www.yahoo.com");
In your HTML file (most likely index.template.html) add the JavaScript method, fbLink which does the following:
function fbLink(url) {
window.popup("http://www.facebook.com/sharer.php?u=" + url, {height:440, width:620, scrollbars:true})
}
Now when a user clicks on the button they will be sharing the link "yahoo.com" with facebook account.
as I understood you asking for some help in accessing js popup in html page of facebook share button, so you should use ExternalInterface in this casa and access needed DOM node using getElementById function in your js interface.
In other case I want propose you to read another one way http://www.riaxe.com/blog/flex/publish-into-facebook-wall-from-flex/
It seems that you want to have a button on the flash application and once clicked it opens the facebook page that shares the video/image that pertains to the clicked button. What you want to do is simply create a button that on click opens a new website to facebook using their share api which has the following format:
var facebookShare:String = "http://www.facebook.com/share.php?u=' + encodedVideoLink + '&t='+ encodedVideoText";
Where the u parameter stands for the link that you wish to share, and the t parameter stands for the title of the piece that you want to share, whether it be a picture or video.
You want to add an event listener on MouseEvent.CLICK that has as its callback function a method that handles the opening of the facebook page passing the facebookShare variable as shown above. To open another page on your browser you can use this AS3 Class called URLNavigator: http://www.danishmetal.dk/project/source/com/zorked/URLNavigator.as
To sum it up, something along these lines would do:
var facebookShare:String = "http://www.facebook.com/share.php?u=' + encodedVideoLink + '&t='+ encodedVideoText";
facebookButton.addEventListener(MouseEvent.CLICK, this._goToUrl(facebookShare));
private function _goToUrl(link:String):Function {
var window:String = "_blank",
feats = "",
thisOverlay:Object = this; // to not lose scope when returning a func
return function (e:MouseEvent):void {
trace("Opening link to:"+link);
try { URLNavigator.ChangePage(link, window, feats); }
catch (e:Error) { trace("error launching "+link+" in "+window+" with feature set "+feats); }
}
}
I hope that helps. If you have questions regarding the code please let me know.
How do I POST to a web page using Firebug?
You can send POST request to any page by opening console (e.g. in FireFox ctrl + shift + k) and typing simple JS:
var formPost = document.createElement('form');
formPost.method = 'POST';
formPost.action = 'https://www.google.com'; //or any location you want
document.body.appendChild(formPost);
formPost.submit();
AFAIK Firebug can't do this. However, there is a very useful Firefox extension, in the spirit of Firebug, called Tamper Data. This should be able to do what you want.
It allows you to monitor each request made by the browser, and you can turn on an option that allows you to look at, and edit, every single request before it gets sent.
Firefox 27 (maybe earlier versions too, never checked) has built-in developer tools to modify and resend requests. If you don't have Firebug installed, the console is available by pressing the F12 key. If Firebug is installed, press Ctrl+Shift+K instead.
I know this is an old question, but I recently stumbled upon the same problem and wanted to share the method I am using.
Assuming the web site you want to POST to has a form with method="POST" (a very likely scenario), you can use Firebug's JavaScript command line to programmatically submit a POST request. Just click the "Show Command Line" icon in Firebug and enter something like this in the narrow text box at the very bottom of the window:
document.forms[0].submit()
Maybe this helps someone.
Another simple solution is to load any webpage that uses jQuery, and type up a $.post() in the console.
HTTP resource test is a firefox plugin that can do this.
Another powerful Firefox plugin to perform post request and some more features is the Hackbar.
Related:
To resend a POST already made, right click the POST request in the Net/XHR view and click "Resend".
Using Firebug 1.12.0:
Got here looking for a Firebug way of doing this. Then I realized that I could use Fiddler. This is the most powerful tool I know when it comes to debugging web requests.
Fiddler The free web debugging proxy for any browser, system or
platform
Click the Composer tab and write your request as desired - then click Execute.
NO NEED of plugins !!
Just drag any url in BOOKMARK BAR, then right click and EDIT, and insert javascript code:
javascript:var my_params=prompt("Enter your parameters","var1=aaaa&var2=bbbbb"); var Target_LINK=prompt("Enter destination", location.href); function post(path, params) { var form = document.createElement("form"); form.setAttribute("method", "post"); form.setAttribute("action", path); for(var key in params) { if(params.hasOwnProperty(key)) { var hiddenField = document.createElement("input"); hiddenField.setAttribute("name", key); hiddenField.setAttribute("value", params[key]); form.appendChild(hiddenField); } } document.body.appendChild(form); form.submit(); } parsed_params={}; my_params.substr(1).split("&").forEach(function(item) {var s = item.split("="), k=s[0], v=s[1]; parsed_params[k] = v;}); post(Target_LINK, parsed_params); void(0);
then enter the target site-link, and click that button in BOOKMARK BAR! That's all!
( source: https://stackoverflow.com/a/38643171/2377343 )