SASS mixin outputs function in compiled CSS - css

Question

My compiled CSS when viewed has a SASS function in it that was never compiled. This is presumably caused by the mixin I'm using to auto generate classes. I have no idea how to fix it.
SASS code:
$rsColors: (
main: (
base: #333030,
lighter:#827a7a,
light:#5a5555,
dark:#0c0b0b,
darker:#000000,
red: #211010,
accent:#999595,
border: #666666
),
link: (
base: #c42727,
lighter:#eb9999,
light:#de5959,
dark:#841a1a,
darker:#440e0e,
hover:#841a1a,
bg:rgba(80, 80, 80, 0.8),
bgHover: #cccccc
)
}
#mixin modifiers($map, $attribute, $prefix: '-', $hover: 'false', $separator: '-',$base: 'base', $type: 'darken', $perc: '15%') {
#each $key, $value in $map {
&#{if($key != $base, #{$prefix}#{$key}, '')} {
#if type-of($value) == 'map' {
#include modifiers($value, $attribute, $separator, $hover);
}
#else {
#{$attribute}: $value;
#if $hover == 'true' {
&:hover {
$function: get-function($type);
#{$attribute}: call($function,$value,$perc);
}
}
}
}
}
}
.rsBg {
#include modifiers($rsColors, 'background', $hover: 'true');
}
Compiled CSS (as viewed from style editor in Firefox inspector):
...
.rsBg-yellow-700 {
background: #b7791f;
}
.rsBg-yellow-700:hover {
background: darken(#b7791f, 15%);
}
...
How can I fix the compiled CSS so it's rendered correctly? I figure the mixin is to blame since it's outputting what I'm telling it to. Why it's not compiling before being output to CSS?
Expected Output:
...
.rsBg-yellow-700 {
background: #b7791f;
}
.rsBg-yellow-700:hover {
background: #915300; //assuming 15% darken
}
...
**Edit**
After some testing I have found I needed to add the ```get-function()``` method to get ```call()``` to work. However, no matter what I try I can not get the ```$perc``` variable in such a way as to not throw a "not a number" error. I can hard code percentages and it will compile without errors.. but I'd rather not have to do that.

Answer 1

The problem actually comes from the way you call the function and not the mixin. Instead of:
#{$attribute}: unquote(#{$type}($value, #{unquote($perc)}));
You should use the built-in function call() as below:
#{$attribute}: call($type, $value, $perc);
You also need to remove the quotation marks for the parameter $perc or you will get an error such as: $amount: "15%" is not a number for 'darken'. I tried to remove them with unquote() but it doesn't seem to work.

Answer 2

The answer to this issue was the use of '' in the arguments. Specifically the $lightness variable (which was changed from the #perc variable). Once I removed the quotes and just let it hang there, everything compiled and worked fine.
I removed the $type variable and changed the function to scale_color as it seemed to fit better with what I wanted. I should probably change the argument variable to a different name so not to be confused with the scale_color() argument. A task for a different day though.
PLEASE NOTE: I am accepting #Arkellys answer because it set me on the right path to this answer, and I feel really weird about accepting my own answer. I just added this answer so if another comes along it might help. Thank you #Arkellys for your help!
The final mixin
#mixin modifiers($map, $attribute, $prefix: '-', $hover: 'false', $separator: '-',$base: 'base', $lightness: -15%) {
#each $key, $color in $map {
&#{if($key != $base, #{$prefix}#{$key}, '')} {
#if type-of($color) == 'map' {
#include modifiers($color, $attribute, $separator, $hover);
}
#else {
#{$attribute}: $color;
#if $hover == 'true' {
&:hover {
#{$attribute}: scale_color($color,$lightness: $lightness);
}
}
}
}
}
}
.rsBg {
#include modifiers($rsColors, 'background', $hover: 'true', $lightness: -20%);
}