I need the result of the first query to pass it as an input parameter to my second query. and also want to know to write multi queries.
In my use case, the second query can be traversed only using the result of the first query and that too using loop(which is similar to for loop)
const query1 =g.V().hasLabel('Province').has('code',market').inE('partOf').outV().has('type',state).values('code').as('state')
After executing query1,the result is
res=[{id1},{id2},........]
query2 = select('state').repeat(has('code',res[0]).inE('partOf').outV().has('type',city).value('name')).times(${res.length-1}).as('city')
I made the assumptions that your first query tries to finds "states by market" where the market is a variable you intend to pass to your query. If that is correct then your first query simplifies to:
g.V().hasLabel('Province').has('code',market).
in('partOf').
has('type','state').values('code')
so, prefer in() to inE().outV() when no filtering on edge properties is needed.
Your second query doesn't look like valid Gremlin, but maybe you were just trying to provide an example of what you wanted to do. You wrote:
select('state').
repeat(has('code',res[0]).
inE('partOf').outV().
has('type',city).value('name')).
times(${res.length-1}).as('city')
and I assume that means you want to use the states found in the first query to find their cities. If that's what you're after you can simplify this to a single query of:
g.V().hasLabel('Province').has('code',market).
in('partOf').has('type','state').
in('partOf').has('type','city').
values('name')
If you need data about the state and the city as part of the result then consider project():
g.V().hasLabel('Province').has('code',market).
in('partOf').has('type','state').
project('state','cities').
by('code').
by(__.in('partOf').has('type','city').
values('name').
fold())
Related
Is it possible to query just part of the name and get the data
Like I have data 12345678
can I somehow just search for 1234?
data.whereEqualsto("data", 1234);
This is needed because the last numbers changes and the first ones doesn't.
Is it possible to query just part of the name and get the data Like I have data 12345678 can I somehow just search for 1234?
Sure it is. When it comes to Firestore, you can simply use .startAt() as seen in the following query:
db.collection("collName").orderBy("data").startAt(1234);
When it comes to the Realtime Database, you can use .startAt() too, but as seen below:
db.child("nodeName").orderByChild("data").startAt(1234);
But remember, both queries will return elements that are greater than 1234. Since 12345678 is greater, it will be present in the result set.
I want to return a node where the node has a property as a specific uuid and I just want to return one of them (there could be several matches).
g.V().where('application_uuid', eq(application_uuid).next()
Would the above query return all the nodes? How do I just return 1?
I also want to get the property map of this node. How would I do this?
You would just do:
g.V().has('application_uuid', application_uuid).next()
but even better would be the signature that includes the vertex label (if you can):
g.V().has('vlabel', 'application_uuid', application_uuid).next()
Perhaps going a bit further if you explicitly need just one you could:
g.V().has('vlabel', 'application_uuid', application_uuid).limit(1).next()
so that both the graph provider and/or Gremlin Server know your intent is to only next() back one result. In that way, you may save some extra network traffic/processing.
This is a very basic query. You should read more about gremlin. I can suggest Practical Gremlin book.
As for your query, you can use has to filter by property, and limit to get specific number of results:
g.V().has('application_uuid', application_uuid).limit(1).next()
Running your query without the limit will also return a single result since the query result is an iterator. Using toList() will return all results in an array.
I wrote the simple query below to traversal between Person to Country but it’s not returning any results.
g.V().hasLabel("Person").as("p").out("from").hasLabel("Country").as("c").select("p", "c")
In the actual data, only Person vertices exists and no Country vertices or from edges exist. I expected to at least return p - basically I want to do a left outer join. However, if I have Country and from data as well, the query returns results.
I tried another query using match as well but still no results unless there are actual data:
g.V().hasLabel("Person").has("name","bob").match(__.as("p").out("from").hasLabel("Country").as("c")).select("p", "c")
I'm running these queries against Datastax Enterpise Graph.
Any idea why it’s returning no results?
The result you are getting is expected. If there are no "from" edges then the traverser essentially dies and does not proceed any further. Perhaps you could consider using project():
g.V().hasLabel("Person").
project('name','country').
by('name')
by(out('from').hasLabel('Country').values('name').fold())
With the "modern" toy graph in TinkerPop, the output looks like this:
gremlin> g.V().hasLabel('person').project('name','knows').by().by(out('knows').values('name').fold())
==>[name:v[1],knows:[vadas,josh]]
==>[name:v[2],knows:[]]
==>[name:v[4],knows:[]]
==>[name:v[6],knows:[]]
In the future, when you submit questions about Gremlin, please include a Gremlin script that can be pasted into a Gremlin Console which makes it easier to try to more directly answer your specific question.
I am running the following query on Google BigQuery web interface, for data provided by Google Analytics:
SELECT *
FROM [dataset.table]
WHERE
hits.page.pagePath CONTAINS "my-fun-path"
I would like to save the results into a new table, however I am obtaining the following error message when using Flatten Results = False:
Error: Cannot query the cross product of repeated fields
customDimensions.value and hits.page.pagePath.
This answer implies that this should be possible: Is there a way to select nested records into a table?
Is there a workaround for the issue found?
Depending on what kind of filtering is acceptable to you, you may be able to work around this by switching to OMIT IF from WHERE. It will give different results, but, again, perhaps such different results are acceptable.
The following will remove entire hit record if (some) page inside of it meets criteria. Note two things here:
it uses OMIT hits IF, instead of more commonly used OMIT RECORD IF).
The condition is inverted, because OMIT IF is opposite of WHERE
The query is:
SELECT *
FROM [dataset.table]
OMIT hits IF EVERY(NOT hits.page.pagePath CONTAINS "my-fun-path")
Update: see the related thread, I am afraid this is no longer possible.
It would be possible to use NEST function and grouping by a field, but that's a long shot.
Using flatten call on the query:
SELECT *
FROM flatten([google.com:analytics-bigquery:LondonCycleHelmet.ga_sessions_20130910],customDimensions)
WHERE
hits.page.pagePath CONTAINS "m"
Thus in the web ui:
setting a destination table
allowing large results
and NO flatten results
does the job correctly and the produced table matches the original schema.
I know - it is old ask.
But now it can be achieved by just using standard SQL dialect instead of Legacy
#standardSQL
SELECT t.*
FROM `dataset.table` t, UNNEST(hits.page) as page
WHERE
page.pagePath CONTAINS "my-fun-path"
I am trying to perform queries using the OR operator as following:
MapReduceResult result = riakClient.
mapReduce("some_bucket", "Name:c1 OR c2").
addMapPhase(new NamedJSFunction("Riak.mapValuesJson"), true).
execute();
I only get the 1st object in the query (where name='c1').
If I change the order of the query (i.e. Name:c2 OR c1) again I get only the first object in query (where name='c2').
is the OR operator (and other query operators) supported in the java client?
I got this answer from Basho engeneer, Sean C.:
You either need to group the terms or qualify both of them. Without a field identifier, the search query assumes that the default field is being searched. You can determine how the query will be interpreted by using the 'search-cmd explain' command. Here's two alternate ways to express your query:
Name:c1 OR Name:c2
Name:(c1 OR c2)
both options worked for me!