Find the final redirected url using Python - http

Question

I am trying to use python to find the final redirected URL for a url. I tried various solutions from stackoverflow answers but nothing worked for me. I am only getting the original url.
To be specific, I tried requests, urllib2 and urlparse libraries and none of them worked as they should. Here are some of the codes I tried:
Solution 1:
s = requests.session()
r = s.post('https://www.boots.com/search/10055096', allow_redirects=True)
print(r.history)
print(r.history[1].url)
Result:
[<Response [301]>, <Response [302]>]
https://www.boots.com/search/10055096
Solution 2:
import urlparse
url = 'https://www.boots.com/search/10055096'
try:
out = urlparse.parse_qs(urlparse.urlparse(url).query)['out'][0]
print(out)
except Exception as e:
print('not found')
Result:
not found
Solution 3:
import urllib2
def get_redirected_url(url):
opener = urllib2.build_opener(urllib2.HTTPRedirectHandler)
request = opener.open(url)
return request.url
print(get_redirected_url('https://www.boots.com/search/10055096'))
Result:
HTTPError: HTTP Error 302: The HTTP server returned a redirect error that would lead to an infinite loop.
The last 30x error message was:
Found
Expected URL below is the final redirected page and that is what I want to return.
Original URL: https://www.boots.com/search/10055096
Expected URL: https://www.boots.com/gillette-fusion5-razor-blades-4pk-10055096
Solution #1 was the closest one. At least it returned 2 responses but second respond wasn't the final page, it seems like it was the loading page looking at the content of it.

Answer 1

The first request returns with a html file which contains a JS to update the site and Java scripts are not processed by requests . You can find the updated link by using
import requests
from bs4 import BeautifulSoup
import re
r = requests.get('https://www.boots.com/search/10055096')
soup = BeautifulSoup(r.content,'html.parser')
reg = soup.find('input',id='searchBoxText').findNext('script').contents[0]
print(re.search(r'ht[\w\://\.-]+', reg).group())