R - Help to build time column from 0? - r

I need to create a 'time' column, starting at 0 and adding increments of 0.0005. The length of the column should be dependent on the length of existing columns. What I have tried at so far is below.
So in my head, the below script says: create a column with 0 and 0.0005 as data points 1 and 2, cumulatively add the difference between data points 1 and 2 and repeat for length of specified column. This doesn't really work, hence why I am posting here. If anyone has some sage advice, it would be greatly appreciated.
df$time = c(0,0.0005, cumsum(diff(df$time [1:2], lag = 1)), length(df$other.column))
Expected outcome
time
0
0.0005
0.001
0.0015
0.002
0.0025
0.003
0.0035
0.004
0.0045
0.005
0.0055
0.006
0.0065
0.007
0.0075
0.008
0.0085
0.009
0.0095
etc

We can multiply the 0.00005 with the sequence of rows
df$time <- (seq_len(nrow(df)) - 1) * 0.0005
data
df <- data.frame(a = 1:10)

It sounds like you just want the following sequence:
seq(0, 0.1, by=0.0005)
You may replace the from and to values to whatever you want via:
seq(from, to, by=0.0005)

You could use seq by specifying length.out parameter as number of rows of dataframe.
df <- data.frame(a = 1:10)
df$time <- seq(0, by = 0.0005, length.out = nrow(df))
df
# a time
#1 1 0.0000
#2 2 0.0005
#3 3 0.0010
#4 4 0.0015
#5 5 0.0020
#6 6 0.0025
#7 7 0.0030
#8 8 0.0035
#9 9 0.0040
#10 10 0.0045

Related

Using rle function with condition on a column in r

My dataset has 523 rows and 93 columns and it looks like this:
data <- structure(list(`2018-06-21` = c(0.6959635416667, 0.22265625,
0.50341796875, 0.982942708333301, -0.173828125, -1.229259672619
), `2018-06-22` = c(0.6184895833333, 0.16796875, 0.4978841145833,
0.0636718750000007, 0.5338541666667, -1.3009207589286), `2018-06-23` = c(1.6165364583333,
-0.375, 0.570800781250002, 1.603515625, 0.5657552083333, -0.9677734375
), `2018-06-24` = c(1.3776041666667, -0.03125, 0.7815755208333,
1.5376302083333, 0.5188802083333, -0.552966889880999), `2018-06-25` = c(1.7903645833333,
0.03125, 0.724609375, 1.390625, 0.4928385416667, -0.723074776785701
)), row.names = c(NA, 6L), class = "data.frame")
Each row is a city, and each column is a day of the year.
After calculating the row average in this way
data$mn <- apply(data, 1, mean)
I want to create another column data$duration that indicates the average length of a period of consecutive days where the values are > than data$mn.
I tried with this code:
data$duration <- apply(data[-6], 1, function(x) with(rle`(x > data$mean), mean(lengths[values])))
But it does not seem to work. In particular, it appears that rle( x > data$mean) fails to recognize the end of a row.
What are your suggestions?
Many thanks
EDIT
Reference dataframe has been changed into a [6x5]
The main challenge you're facing in your code is getting apply (which focuses on one row at a time) to look at the right values of the mean. We can avoid this entirely by keeping the mean out of the data frame, and doing the comparison data > mean to the whole data frame at once. The new columns can be added at the end:
mn = rowMeans(data)
dur = apply(data > mn, 1, function(x) with(rle(x), mean(lengths[values])))
dur
# 1 2 3 4 5 6
# 3.0 1.5 2.0 3.0 4.0 2.0
data = cbind(data, mean = mn, duration = dur)
print(data, digits = 2)
# 2018-06-21 2018-06-22 2018-06-23 2018-06-24 2018-06-25 mean duration
# 1 0.70 0.618 1.62 1.378 1.790 1.2198 3.0
# 2 0.22 0.168 -0.38 -0.031 0.031 0.0031 1.5
# 3 0.50 0.498 0.57 0.782 0.725 0.6157 2.0
# 4 0.98 0.064 1.60 1.538 1.391 1.1157 3.0
# 5 -0.17 0.534 0.57 0.519 0.493 0.3875 4.0
# 6 -1.23 -1.301 -0.97 -0.553 -0.723 -0.9548 2.0

How to calculate the Bonferroni Lower and Upper limits in R?

With the following data, I am trying to calculate the Chi Square and Bonferroni lower and upper Confidence intervals. The column "Data_No" identifies the dataset (as calculations needs to be done separately for each dataset).
Data_No Area Observed
1 3353 31
1 2297 2
1 1590 15
1 1087 16
1 817 2
1 847 10
1 1014 28
1 872 29
1 1026 29
1 1215 21
2 3353 31
2 2297 2
2 1590 15
3 1087 16
3 817 2
The code I used is
library(dplyr)
setwd("F:/GIS/July 2019/")
total_data <- read.csv("test.csv")
result_data <- NULL
for(i in unique(total_data$Data_No)){
data <- total_data[which(total_data$Data_No == i),] data <- data %>%
mutate(RelativeArea = Area/sum(Area), Expected = RelativeArea*sum(Observed), OminusE = Observed-Expected, O2 = OminusE^2, O2divE = O2/Expected, APU = Observed/sum(Observed), Alpha = 0.05/2*count(Data_No),
Zvalue = qnorm(Alpha,lower.tail=FALSE), lower = APU-Zvalue*sqrt(APU*(1-APU)/sum(Observed)), upper = APU+Zvalue*sqrt(APU*(1-APU)/sum(Observed)))
result_data <- rbind(result_data,data) }
write.csv(result_data,file='final_result.csv')
And the error message I get is:
Error in UseMethod("summarise_") : no applicable method for
'summarise_' applied to an object of class "c('integer', 'numeric')"
The column that I am calling "Alpha" is the alpha value of 0.05/2k, where K is the number of categories - in my example, I have 10 categories ("Data_No" column) for the first dataset, so "Alpha" needs to be 0.05/20 = 0.0025, and it's corresponding Z value is 2.807. The second dataset has 3 categories (so 0.05/6) and the third has 2 categories (0.05/4) in my example table (Data_No" column). Using the values from the newly calculated "Alpha" column, I then need to calculate the ZValue column (Zvalue = qnorm(Alpha,lower.tail=FALSE)) which I then use to calculate the lower and upper confidence intervals.
From the above data, here are the results that I should get, but note that I have had to manually calculate Alpha column and Zvalue, rather than insert those calculations within the R code:
Data_No Area Observed RelativeArea Alpha Z value lower upper
1 3353 31 0.237 0.003 2.807 0.092 0.247
1 2297 2 0.163 0.003 2.807 -0.011 0.033
1 1590 15 0.113 0.003 2.807 0.025 0.139
1 1087 16 0.077 0.003 2.807 0.029 0.146
1 817 2 0.058 0.003 2.807 -0.011 0.033
1 847 10 0.060 0.003 2.807 0.007 0.102
1 1014 28 0.072 0.003 2.807 0.078 0.228
1 872 29 0.062 0.003 2.807 0.083 0.234
1 1026 29 0.073 0.003 2.807 0.083 0.234
1 1215 21 0.086 0.003 2.807 0.049 0.181
2 3353 31 0.463 0.008 2.394 0.481 0.811
2 2297 2 0.317 0.008 2.394 -0.027 0.111
2 1590 15 0.220 0.008 2.394 0.152 0.473
3 1087 16 0.571 0.013 2.241 0.723 1.055
3 817 2 0.429 0.013 2.241 -0.055 0.277
Please note that I only included some of the columns generated from the code.
# You need to check the closing bracket for lower c.f. sqrt value. Following code should work.
data <- read.csv("test.csv")
data <- data %>% mutate(RelativeArea =
Area/sum(Area), Expected = RelativeArea*sum(Observed), OminusE =
Observed-Expected, O2 = OminusE^2, O2divE = O2/Expected, APU =
Observed/sum(Observed), lower =
APU-2.394*sqrt(APU*(1-APU)/sum(Observed)), upper =
APU+2.394*sqrt(APU*(1-APU)/sum(Observed)))
#Answer to follow-up question.
#Sample Data
Data_No Area Observed
1 3353 31
1 2297 2
2 1590 15
2 1087 16
#Code to run
total_data <- read.csv("test.csv")
result_data <- NULL
for(i in unique(total_data$Data_No)){
data <- total_data[which(total_data$Data_No == i),]
data <- data %>% mutate(RelativeArea =
Area/sum(Area), Expected = RelativeArea*sum(Observed), OminusE =
Observed-Expected, O2 = OminusE^2, O2divE = O2/Expected, APU =
Observed/sum(Observed), lower =
APU-2.394*sqrt(APU*(1-APU)/sum(Observed)), upper =
APU+2.394*sqrt(APU*(1-APU)/sum(Observed)))
result_data <- rbind(result_data,data)
}
write.csv(result_data,file='final_result.csv')
#Issue in calculating Alpha. I have updated the code.
library(dplyr)
setwd("F:/GIS/July 2019/")
total_data <- read.csv("test.csv")
#Creating the NO_OF_CATEGORIES column based on your question.
total_data$NO_OF_CATEGORIES <- 0
total_data[which(total_data$Data_No==1),]$NO_OF_CATEGORIES <- 10
total_data[which(total_data$Data_No==2),]$NO_OF_CATEGORIES <- 3
total_data[which(total_data$Data_No==3),]$NO_OF_CATEGORIES <- 2
#Actual code
result_data <- NULL
for(i in unique(total_data$Data_No)){
data <- total_data[which(total_data$Data_No == i),]
data <- data %>%
mutate(RelativeArea = Area/sum(Area), Expected = RelativeArea*sum(Observed), OminusE = Observed-Expected, O2 = OminusE^2, O2divE = O2/Expected, APU = Observed/sum(Observed), Alpha = 0.05/(2*(unique(data$NO_OF_CATEGORIES))),
Zvalue = qnorm(Alpha,lower.tail=FALSE), lower = APU-Zvalue*sqrt(APU*(1-APU)/sum(Observed)), upper = APU+Zvalue*sqrt(APU*(1-APU)/sum(Observed)))
result_data <- rbind(result_data,data) }
write.csv(result_data,file='final_result.csv')

Conditional sorting / reordering of column values in R

I have a data set similar to the following with 1 column and 60 rows:
value
1 0.0423
2 0.0388
3 0.0386
4 0.0342
5 0.0296
6 0.0276
7 0.0246
8 0.0239
9 0.0234
10 0.0214
.
40 0.1424
.
60 -0.0312
I want to reorder the rows so that certain conditions are met. For example one condition could be: sum(df$value[4:7]) > 0.1000 & sum(df$value[4:7]) <0.1100
With the data set looking like this for example.
value
1 0.0423
2 0.0388
3 0.0386
4 0.1312
5 -0.0312
6 0.0276
7 0.0246
8 0.0239
9 0.0234
10 0.0214
.
.
.
60 0.0342
What I tried was using repeat and sample as in the following:
repeat{
df1 <- as_tibble(sample(sdf$value, replace = TRUE))
if (sum(df$value[4:7]) > 0.1000 & sum(df$value[4:7]) <0.1100) break
}
Unfortunately, this method takes quite some time and I was wondering if there is a faster way to reorder rows based on mathematical conditions such as sum or prod
Here's a quick implementation of the hill-climbing method I outlined in my comment. I've had to slightly reframe the desired condition as "distance of sum(x[4:7]) from 0.105" to make it continuous, although you can still use the exact condition when doing the check that all requirements are satisfied. The benefit is that you can add extra conditions to the distance function easily.
# Using same example data as Jon Spring
set.seed(42)
vs = rnorm(60, 0.05, 0.08)
get_distance = function(x) {
distance = abs(sum(x[4:7]) - 0.105)
# Add to the distance with further conditions if needed
distance
}
max_attempts = 10000
best_distance = Inf
swaps_made = 0
for (step in 1:max_attempts) {
# Copy the vector and swap two random values
new_vs = vs
swap_inds = sample.int(length(vs), 2, replace = FALSE)
new_vs[swap_inds] = rev(new_vs[swap_inds])
# Keep the new vector if the distance has improved
new_distance = get_distance(new_vs)
if (new_distance < best_distance) {
vs = new_vs
best_distance = new_distance
swaps_made = swaps_made + 1
}
complete = (sum(vs[4:7]) < 0.11) & (sum(vs[4:7]) > 0.1)
if (complete) {
print(paste0("Solution found in ", step, " steps"))
break
}
}
sum(vs[4:7])
There's no real guarantee that this method will reach a solution, but I often try this kind of basic hill-climbing when I'm not sure if there's a "smart" way to approach a problem.
Here's an approach using combn from base R, and then filtering using dplyr. (I'm sure there's a way w/o it but my base-fu isn't there yet.)
With only 4 numbers from a pool of 60, there are "only" 488k different combinations (ignoring order; =60*59*58*57/4/3/2), so it's quick to brute force in about a second.
# Make a vector of 60 numbers like your example
set.seed(42)
my_nums <- rnorm(60, 0.05, 0.08);
all_combos <- combn(my_nums, 4) # Get all unique combos of 4 numbers
library(tidyverse)
combos_table <- all_combos %>%
t() %>%
as_tibble() %>%
mutate(sum = V1 + V2 + V3 + V4) %>%
filter(sum > 0.1, sum < 0.11)
> combos_table
# A tibble: 8,989 x 5
V1 V2 V3 V4 sum
<dbl> <dbl> <dbl> <dbl> <dbl>
1 0.160 0.00482 0.0791 -0.143 0.100
2 0.160 0.00482 0.101 -0.163 0.103
3 0.160 0.00482 0.0823 -0.145 0.102
4 0.160 0.00482 0.0823 -0.143 0.104
5 0.160 0.00482 -0.0611 -0.00120 0.102
6 0.160 0.00482 -0.0611 0.00129 0.105
7 0.160 0.00482 0.0277 -0.0911 0.101
8 0.160 0.00482 0.0277 -0.0874 0.105
9 0.160 0.00482 0.101 -0.163 0.103
10 0.160 0.00482 0.0273 -0.0911 0.101
# … with 8,979 more rows
This says that in this example, there are about 9000 different sets of 4 numbers from my sequence which meet the criteria. We could pick any of these and put them in positions 4-7 to meet your requirement.

Using regex to set a specific digit to NA? [duplicate]

This question already has answers here:
Replace all particular values in a data frame
(8 answers)
Closed 4 years ago.
Sample of df:
LASSO_deviance LASSO_AUC
68 0.999 0.999
2 1.000 1.000
39 1.000 1.005
7 1.02 1.2
I want to set cells which contain 1.000 to either NA or 0, in preferential order.
I've tried something like: df %>% mutate_at(vars(LASSO_deviance, LASSO_AUC), funs(gsub(pattern = "1{1}[^.{1,}]", 0, x = .))) with no luck.
tt <- "LASSO_deviance LASSO_AUC
68 0.999 0.999
2 1.000 1.000
39 1.000 1.005
7 1.02 1.2"
dat <- read.table(text = tt, header = T)
No need for regex because you can simply find where your data is equal to 1.000
dat[dat == 1.000] <- NA # or dat[dat == 1.000] <- 0
dat
# LASSO_deviance LASSO_AUC
# 68 0.999 0.999
# 2 NA NA
# 39 NA 1.005
# 7 1.020 1.200

R: aggregating time series groups of irregular length

I think this is a split-apply-combine problem, but with a time series twist. My data consists of irregular counts and I need to perform some summary statistics on each group of counts. Here's a snapshot of the data:
And here's it is for your console:
library(xts)
date <- as.Date(c("2010-11-18", "2010-11-19", "2010-11-26", "2010-12-03", "2010-12-10",
"2010-12-17", "2010-12-24", "2010-12-31", "2011-01-07", "2011-01-14",
"2011-01-21", "2011-01-28", "2011-02-04", "2011-02-11", "2011-02-18",
"2011-02-25", "2011-03-04", "2011-03-11", "2011-03-18", "2011-03-25",
"2011-03-26", "2011-03-27"))
returns <- c(0.002,0.000,-0.009,0.030, 0.013,0.003,0.010,0.001,0.011,0.017,
-0.008,-0.005,0.027,0.014,0.010,-0.017,0.001,-0.013,0.027,-0.019,
0.000,0.001)
count <- c(NA,NA,1,1,2,2,3,4,5,6,7,7,7,7,7,NA,NA,NA,1,2,NA,NA)
maxCount <- c(NA,NA,0.030,0.030,0.030,0.030,0.030,0.030,0.030,0.030,0.030,
0.030,0.030,0.030,0.030,NA,NA,NA,0.027,0.027,NA,NA)
sumCount <- c(NA,NA,0.000,0.030,0.042,0.045,0.056,0.056,0.067,0.084,0.077,
0.071,0.098,0.112,0.123,NA,NA,NA,0.000,-0.019,NA,NA)
xtsData <- xts(cbind(returns,count,maxCount,sumCount),date)
I have no idea how to construct the max and cumSum columns, especially since each count series is of an irregular length. Since I won't always know the start and end points of a count series, I'm lost at trying to figure out the index of these groups. Thanks for your help!
UPDATE: here is my for loop for attempting to calculating cumSum. it's not the cumulative sum, just the returns necessary, i'm still unsure how to apply functions to these ranges!
xtsData <- cbind(xtsData,mySumCount=NA)
# find groups of returns
for(i in 1:nrow(xtsData)){
if(is.na(xtsData[i,"count"]) == FALSE){
xtsData[i,"mySumCount"] <- xtsData[i,"returns"]
}
else{
xtsData[i,"mySumCount"] <- NA
}
}
UPDATE 2: thank you commenters!
# report returns when not NA count
x1 <- xtsData[!is.na(xtsData$count),"returns"]
# cum sum is close, but still need to exclude the first element
# -0.009 in the first series of counts and .027 in the second series of counts
x2 <- cumsum(xtsData[!is.na(xtsData$count),"returns"])
# this is output is not accurate because .03 is being displayed down the entire column, not just during periods when counts != NA. is this just a rounding error?
x3 <- max(xtsData[!is.na(xtsData$count),"returns"])
SOLUTION:
# function to pad a vector with a 0
lagpad <- function(x, k) {
c(rep(0, k), x)[1 : length(x)]
}
# group the counts
x1 <- na.omit(transform(xtsData, g = cumsum(c(0, diff(!is.na(count)) == 1))))
# cumulative sum of the count series
z1 <- transform(x1, cumsumRet = ave(returns, g, FUN =function(x) cumsum(replace(x, 1, 0))))
# max of the count series
z2 <- transform(x1, maxRet = ave(returns, g, FUN =function(x) max(lagpad(x,1))))
merge(xtsData,z1$cumsumRet,z2$maxRet)
The code shown is not consistent with the output in the image and there is no explanation provided so its not clear what manipulations were wanted; however, the question did mention that the main problem is distinguishing the groups so we will address that.
To do that we compute a new column g whose rows contain 1 for the first group, 2 for the second and so on. We also remove the NA rows since the g column is sufficient to distinguish groups.
The following code computes a vector the same length as count by first setting each NA position to FALSE and each non-NA position to TRUE. It then differences each position of that vector with the prior position. To do that it implicitly converts FALSE to 0 and TRUE to 1 and then performs the differencing. Next we convert this last result to a logical vector which is TRUE for each 1 component and FALSE otherwise. Since the first component of the vector that is differenced has no prior position we prepend 0 for that. The prepending operation implicitly converts the TRUE and FALSE values just generated to 1 and 0 respectively. Taking the cumsum fills in the first group with 1, the second with 2 and so on. Finally omit the NA rows:
x <- na.omit(transform(x, g = cumsum(c(0, diff(!is.na(count)) == 1))))
giving:
> x
returns count maxCount sumCount g
2010-11-26 -0.009 1 0.030 0.000 1
2010-12-03 0.030 1 0.030 0.030 1
2010-12-10 0.013 2 0.030 0.042 1
2010-12-17 0.003 2 0.030 0.045 1
2010-12-24 0.010 3 0.030 0.056 1
2010-12-31 0.001 4 0.030 0.056 1
2011-01-07 0.011 5 0.030 0.067 1
2011-01-14 0.017 6 0.030 0.084 1
2011-01-21 -0.008 7 0.030 0.077 1
2011-01-28 -0.005 7 0.030 0.071 1
2011-02-04 0.027 7 0.030 0.098 1
2011-02-11 0.014 7 0.030 0.112 1
2011-02-18 0.010 7 0.030 0.123 1
2011-03-18 0.027 1 0.027 0.000 2
2011-03-25 -0.019 2 0.027 -0.019 2
attr(,"na.action")
2010-11-18 2010-11-19 2011-02-25 2011-03-04 2011-03-11 2011-03-26 2011-03-27
1 2 16 17 18 21 22
attr(,"class")
[1] "omit"
You can now use ave to perform any calculations you like. For example to take cumulative sums of returns by group:
transform(x, cumsumRet = ave(returns, g, FUN = cumsum))
Replace cumsum with any other function that is suitable for use with ave.
Ah, so "count" are the groups and you want the cumsum per group and the max per group. I think in data.table, so here is how I would do it.
library(xts)
library(data.table)
date <- as.Date(c("2010-11-18", "2010-11-19", "2010-11-26", "2010-12-03", "2010-12-10",
"2010-12-17", "2010-12-24", "2010-12-31", "2011-01-07", "2011-01-14",
"2011-01-21", "2011-01-28", "2011-02-04", "2011-02-11", "2011-02-18",
"2011-02-25", "2011-03-04", "2011-03-11", "2011-03-18", "2011-03-25",
"2011-03-26", "2011-03-27"))
returns <- c(0.002,0.000,-0.009,0.030, 0.013,0.003,0.010,0.001,0.011,0.017,
-0.008,-0.005,0.027,0.014,0.010,-0.017,0.001,-0.013,0.027,-0.019,
0.000,0.001)
count <- c(NA,NA,1,1,2,2,3,4,5,6,7,7,7,7,7,NA,NA,NA,1,2,NA,NA)
maxCount <- c(NA,NA,0.030,0.030,0.030,0.030,0.030,0.030,0.030,0.030,0.030,
0.030,0.030,0.030,0.030,NA,NA,NA,0.027,0.027,NA,NA)
sumCount <- c(NA,NA,0.000,0.030,0.042,0.045,0.056,0.056,0.067,0.084,0.077,
0.071,0.098,0.112,0.123,NA,NA,NA,0.000,-0.019,NA,NA)
DT<-data.table(date,returns,count)]
DT[!is.na(count),max:=max(returns),by=count]
DT[!is.na(count),cumSum:= cumsum(returns),by=count]
#if you need an xts object at the end, then.
xtsData <- xts(cbind(DT$returns,DT$count, DT$max,DT$cumSum),DT$date)

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