Dynamically generate a Drupal page for each row in a table - drupal

Question

Is there a way in Drupal 8 to dynamically generate a page for each row in a table in a database?
If I have a database named School, with a table Students, with these columns and rows:
ID |FirstName |LastName |Email |User |HiddenField
-------------------------------------------------------------------------
1 |Adam |Johnson |ajohnson#example.com |ajohn1 |Blah
2 |Bob |Smith |bsmith#example.com |bsmith0 |Foo
Is there a module or setting to create simple pages with these URLs with content like this:
http://mywebpage.com/students/1
First name: Adam
Last name: Johnson
Email address: ajohnson#example.com
Username: ajohn1
http://mywebpage.com/students/2
First name: Bob
Last name: Smith
Email address: bsmith#example.com
Username: bsmith0
Note that there is a HiddenField that isn't displayed, so this solution should include the ability to exclude certain columns.
I've tried using the Views module to create a new page type, but I don't see in there where to specify a table or anything like that.

Answer 1

To fetch data to an associative array with the keys named as the fields, you can write the following:
$query = \Drupal::database()->select('students')
->fields('students', [
'id',
'firstname',
'lastname',
'email',
'user'
]);
$results = $query->execute()->fetchAllAssoc();
After that, you can iterate through $results and create the pages:
foreach ($results as $result) {
// Create node object.
$node = Node::create([
'type' => 'page',
'title' => 'whatever you want',
'field_machine_name' => 'field_value',
'firstname' => $result['firstname'],
]);
$node->save();
}
Please keep in mind to use dependency injection wherever you can. Also you can check for errors like is there a bundle called 'page', and run it only if there is.