I'm receiving this "$100.00 - $209.00" that comes from this handlebar (see 2nd line of code)
(that's a price range)
I need to format it, so it only shows the lowest price.
Unfortunately, I cannot format the original code and I need to format the code on HTML or something similiar.
My question is: Is there any way to format it after I receive it?
Thank you
<span class="price after_special>
{{price<?php echo $priceKey; ?>_formated}}
</span>
That code returns $100.00 - $209.00
I need to have just $100
Thanks.
You can format the string using javascript's String.match() function. In below code regex will match:
^ - beginning of string
\$ - $ sign (needs to be escaped)
[0-9]* - numbers from 0-9, * matches 0 or more numbers
The returned item is an array, so you need to get the first value using [0].
let price = '$100.00 - $209.00';
const regex = /^\$[0-9]*/;
let min = price.match(regex)[0];
console.log(min);
If you need to do it inside a template register a helper
Handlebars.registerHelper('getMinPrice', function(value) {
return value.match(/^\$[0-9]*/)[0];
});
var t = Handlebars.compile($('#t').html());
$('body').append(t({
_min_price: "$100.00 - $200.00"
}));
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/handlebars.js/4.1.2/handlebars.min.js"></script>
<script id="t" type="text/x-handlebars">
Before: {{_min_price}}
After: {{getMinPrice _min_price}}
</script>
Related
Quite simply, this is my code:
http://jsfiddle.net/NibblyPig/k9zb4ysp/
moment.locale('en-GB');
var d = moment('22/12/2019');
alert(d);
I would expect this to parse, however it says invalid date.
I have referenced moment.js and the locale/en-gb.js
I'm writing a global control so the date may come in in a variety of formats.
If I put in a variety of American dates they all work, for example 12/12/2019, 12/12/2019 23:04 etc.
However the locale command does not appear to do anything and I cannot get a single date to parse. What am I doing wrong?
You need to pass the format as the second argument for moment(), as discussed here:
moment.locale('en-GB');
var d = moment('22/12/2019', 'DD/MM/YYYY');
alert(d);
https://jsfiddle.net/a4gu6kfz/
From the docs:
If you know the format of an input string, you can use that to parse a
moment.
moment("12-25-1995", "MM-DD-YYYY");
I think that there is no need to write your own complex logic to parse your input, you can use moment(String, String) (or moment(String, String[], String, Boolean)), as suggested by Thales Minussi's answer.
moment(String) is the good choice only if your input is in ISO 8601 or RFC 2822 compliant form.
In your case, you can probably use Localized formats listed in the format section of the docs. If you have a list of possible formats, I think that the best choice is tho use moment(String, String[]).
Please note that, by default: Moment's parser is very forgiving, so using default Forgiving Mode will handle "any" character as separator.
Here a live sample:
moment.locale('en-GB');
['22/12/2019', '22/12/2019 15:00',
'22-12-2019', '22-12-2019 15:00',
'1-3-2019', '1-12-2019', '22-1-2019'
].forEach((elem) => {
var d = moment(elem, 'L LT');
console.log(d.format());
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/locale/en-gb.js"></script>
Still hoping there's a nice moment js way to do this but in the meantime I just bashed this together. Pretty nasty and it will probably go wrong in 80 years or so.
http://jsfiddle.net/NibblyPig/k9zb4ysp/22/
var a = "23/03/19 12:42:21.123";
var datePart = a.substring(0, a.indexOf(" "));
var timePart = a.substring(a.indexOf(" ") + 1);
var dateParts = datePart.split("/");
if (dateParts[0].length == 1) dateParts[0] = "0" + dateParts[0];
if (dateParts[1].length == 1) dateParts[1] = "0" + dateParts[1];
if (dateParts[2].length == 2) {
var threshold = parseInt(new Date().getFullYear().toString().substring(2)) + 10;
if (parseFloat(dateParts[2]) > threshold ) {
dateParts[2] = "19" + dateParts[2];
}
else
{
dateParts[2] = "20" + dateParts[2];
}
}
alert (parseFloat(dateParts[2] + dateParts[1] + dateParts[0] + timePart.replace(/:/g, "").replace(/\./g, "")));
This won't solve every usecase, but in your specific example if you want just a simple date (with no time component) auto-parsed in UK format you can just use the 'L' format string having set the locale to 'en-GB'
Your example with this change (your jsfiddle also)
moment.locale('en-GB');
// just pass 'L' i.e. local date format as a parsing format here
var d = moment('22/12/2019', 'L');
alert(d);
It's quite nice because you get the auto parsing of various formats you wanted for free. For instance this works just the same:
var d = moment('22-12-2019', 'L');
You can return a date using moment.js in a desired format -
return moment(aDateVar).format('DD/MM/YYYY');
From a linter provider, I receive a Point compatible array(line, column) where the error occured. Now I would like to hightlight the word surrounding that point, basically the result one would get if that exact point was double-clicked in the editor. Something like
const range = textEditor.getWordAtPosition(point)
Is what I hoped for, but couldn't find in the documentation.
Thanks for your help!
After looking around for a while, there seems to be no API method for the given need. I ended up writing a small helper function based upon this answer:
function getWordAtPosition(line, pos) {
// Perform type conversions.
line = String(line);
pos = Number(pos) >>> 0;
// Search for the word's beginning and end.
const left = Math.max.apply(null, [/\((?=[^(]*$)/,/\)(?=[^)]*$)/, /\,(?=[^,]*$)/, /\[(?=[^[]*$)/, /\](?=[^]]*$)/, /\;(?=[^;]*$)/, /\.(?=[^.]*$)/, /\s(?=[^\s]*$)/].map(x => line.slice(0, pos).search(x))) + 1
let right = line.slice(pos).search(/\s|\(|\)|\,|\.|\[|\]|\;/)
// The last word in the string is a special case.
if (right < 0) {
right = line.length - 1
}
// Return the word, using the located bounds to extract it from the string.
return str.slice(left, right + pos)
}
Here, the beginning of the word is determined by the latest occurance of one of the characters (),.[]; or a blank.
The end of the word is determined by the same characters, however here the first occurance is taken as a delimeter.
Given the original context, the function can the be called using the API method ::lineTextForBufferRow and the desired postion (column) as follows:
const range = getWordAtPosition(textEditor.lineTextForBufferRow(bufferRow), 10)
Happy New Year to All!
I am learning XQuery with BaseX and face the following problem now.
I am parsing the factbook.xml file which is the part of the distribution.
The following query runs ok:
for $country in db:open('factbook')//country
where $country/#population < 1000000 and $country/#population > 500000
return <country name="{$country/name}" population="{$country/#population}">
{
for $city in $country/city
let $pop := number($city/population)
order by $pop descending
return <city population="{$city/population/text()}"> {$city/name/text()}
</city>
}
</country>
but while trying to generate a html running the second query - if I try to put the "{$country/#population}" in the <h2>Country population: </h2> tag I see an error message "Attribute must follow the root element".
<html><head><title>Some Countries</title></head><body>
{
for $country in db:open('factbook')//country
let $pop_c := $country/#population
where $pop_c < 1000000 and $pop_c > 500000
return
<p>
<h1>Country: {$country/name/text()}</h1>
<h2>Country population: #error comes if I put it here!#</h2>
{
for $city in $country/city
let $pop := number($city/population)
order by $pop descending
return ( <h3>City: {$city/name/text()}</h3>,
<p>City population: {$city/population/text()}</p>
)
}
</p>
}
</body></html>
Where is my mistake?
Thank you!
Just using:
{$country/#population}
copies the attribute population in the result. An attribute should follow immediately an element (or other attributes that follow the element) -- but this one follows a text node and this causes the error to be raised.
Use:
<h2>Country population: {string($country/#population)} </h2>
When you write {$country/#population}, you do not insert the text of the population attribute, but the attribute itself. If you did not had the "Country population text before it", using {$country/#population} would create something like`
If you want its value, use:
{data($country/#population)}
Or
{data($pop_c)}
since you have already have it in a variable. (the number or string functions can also be used instead of data, but I think data is the fastest)
How do you strip (HTML) tags from a String in Flex 4.5 / 4.6?
I don't think there's an inbuilt function to strip the tags like in php.
However, you could use a regular expression to remove all text between < and >
var r:RegExp=/<\/??.*?\/??>/g;
I gotta run now, but if you could follow my line of thought:
While the string tests positive for the regexp, replace the occurrence with an empty string
That should remove all occurrences of this type:
<tag>
<tag />
</tag>
EDIT
var h:String="<html><head><title>Hello World</title></head><body><h1>Hello</h1>Hey there, what's new?</body></html>";
var r:RegExp=/<\/??.*?\/??>/s; //s=dotall to match . to newline also
while(r.test(h)) {
h=h.replace(r, ""); //Remember, strings are immutable, so you h.replace will not change the value of h, so you need to reassign the return to h
}
trace(h);
OUTPUT:
Hello WorldHelloHey there, what's new?
i need a Regular Expression to convert a a string to a link.i wrote something but it doesnt work in asp.net.i couldnt solve and i am new in Regular Expression.This function converts (bkz: string) to (bkz: show.aspx?td=string)
Dim pattern As String = "<bkz[a-z0-9$-$&-&.-.ö-öı-ış-şç-çğ-ğü-ü\s]+)>"
Dim regex As New Regex(pattern, RegexOptions.IgnoreCase)
str = regex.Replace(str, "<font color=""#CC0000"">$1</font>")
Generic remarks on your code: beside the lack of opening parentheses, you do redundant things: $-$ isn't incorrect but can be simplified into $ only. Same for accented chars.
Everybody will tell you that font tag is deprecated even in plain HTML: favor span with style attribute.
And from your question and the example in the reply, I think the expression could be something like:
\(bkz: ([a-z0-9$&.öışçğü\s]+)\)
the replace string would look like:
(bkz: <span style=""color: #C00"">$1</span>)
BUT the first $1 must be actually URL encoded.
Your regexp is in trouble because of a ')' without '('
Would:
<bkz:\s+((?:.(?!>))+?.)>
work better ?
The first group would capture what you are after.
Thanks Vonc,Now it doesnt raise error but also When i assign str to a Label.Text,i cant see the link too.Forexample after i bind str to my label,it should be viewed in view-source ;
<span id="Label1">(bkz: here)</span>
But now,it is in viewsource source;
<span id="Label1">(bkz: here)</span>