Initialization of dynamically allocated structures using shared pointer - initialization

Question

I dont understand why initialization of dynamically allocated structure needs to be done like this (using shared ptr)
Just to notify that I am using C++11
If we have struct like this
struct Meme {
std::string s;
Meme* p;
}
and later in code, I need to dynamically allocated memory for this structure using shared_ptr, but I need to do instant initialization of structure.
Why it is done like this?
std::shared_ptr<Meme> novi=std::make_shared<Meme>(Meme{imena.at(i),nullptr});
part that confuses me is this one :
std::make_shared<Meme>(Meme{imena.at(i),nullptr});
If we set that shared_ptr points to struct Meme, why we need to specify again that initialization list is for struct Meme, by saying
(Meme{imena.at(i),nullptr})
Why this would not work:
std::shared_ptr<Meme> novi=std::make_shared<Meme>({imena.at(i),nullptr});
Is this maybe that initialization list cannot deduct that it should like convert to struct Meme because there is no direct usage of struct Meme(even though make_shared points to struct Meme) ?

Answer 1

make_shared forwards arguments to constructor.
Make shared_ptr
Allocates and constructs an object of type T passing args to its constructor, and returns an object of type shared_ptr that owns and stores a pointer to it (with a use count of 1).
This calls the copy constructor of Meme from new instance you create with Meme{imena.at(i),nullptr}.
std::shared_ptr<Meme> novi=std::make_shared<Meme>(Meme{imena.at(i),nullptr});
The correct way to construct it with make_shared from forwarded arguments is to create constructor in struct:
struct Meme {
std::string s;
Meme* p;
Meme(const std::string& s, Meme* p) : s(s), p(p) {}
};
std::shared_ptr<Meme> novi = std::make_shared<Meme>(imena.at(i),nullptr);
Also you can create an instance with (default) empty constructor and then set its members:
struct Meme {
std::string s;
Meme* p = nullptr;
};
std::shared_ptr<Meme> novi = std::make_shared<Meme>;
novi->s = imena.at(i);