lets just say theoreticaly, that I have
Rectangle {
id: testRect
width: 100
}
and once i start the timer with interval tick 50ms, it should just extend the width of Rect:
Timer {
id: testTimer
interval: 50
onTriggered: testRect.width += 50
}
which works fine, but even when its onlz 50ms, its still seems to be quite not smooth transition.
Any idea how to smoothen the width change?
Please note this is only for learning purposes, what I will learn here will use in different situations, therefore please dont ask what is the puspose of the code...
Thank you!
You should rely on the animation features available in QtQuick to animate property changes.
In your case, you can define different states, with transitions between states where you define how an item should behave when going from one state to another. (See relevant documentation about states)
import QtQuick 2.9
import QtQuick.Window 2.2
Window {
visible: true
width: 640
height: 480
Rectangle {
id: rect
anchors.left: parent.left
anchors.top: parent.top
anchors.margins: 100
height: 200
color: "red"
state: "default"
states: [
State {
name: "default"
PropertyChanges {
target: rect
width: 200
}
},
State {
name: "bigger"
PropertyChanges {
target: rect
width: 250
}
}
]
transitions: Transition {
NumberAnimation {
duration: 500 //ms
target: rect
properties: "width"
}
}
// Just there to trigger the state change by clicking on the Rectangle
MouseArea {
anchors.fill: parent
onClicked: {
if (rect.state === "default")
rect.state = "bigger"
else
rect.state = "default"
}
}
}
}
Or you can define a behavior, which is more simple to define when you only act on a single property:
import QtQuick 2.9
import QtQuick.Window 2.2
Window {
visible: true
width: 640
height: 480
Rectangle {
id: rect
anchors.left: parent.left
anchors.top: parent.top
anchors.margins: 100
height: 200
width: 200
color: "red"
Behavior on width {
NumberAnimation {
duration: 500 //ms
}
}
// Just there to trigger the width change by clicking on the Rectangle
MouseArea {
anchors.fill: parent
onClicked: {
if (rect.width === 200)
rect.width = 250
else
rect.width = 200
}
}
}
}
Finally, if you really want a smooth animation, you can use SmoothedAnimation instead of NumberAnimation (which is a linear animation by default)
Related
I'm being tasked with creating a customized title bar for our application. It needs to have rounded corners and a settings button, amongst other things. It will run exclusively on windows.
Our application uses Qt and QML for the front end.
So the only way I could find how to do this is by making the application window frameless and creating the title bar from scratch.
This is my test code:
import QtQuick 2.12
import QtQuick.Window 2.12
import QtQuick.Controls 2.0
ApplicationWindow {
id: mainWindow
visible: true
visibility: Window.Maximized
title: qsTr("Hello World")
flags: Qt.FramelessWindowHint | Qt.Window | Qt.WA_TranslucentBackground
//flags: Qt.Window | Qt.WA_TranslucentBackground
color: "#00000000"
TitleBar {
id: mainTitleBar
width: mainWindow.width;
height: mainWindow.height*0.018
color: "#aaaaaa"
onCloseApplication: {
Qt.quit();
}
onMinimizeApplication: {
mainWindow.visibility = Window.Minimized
}
}
Component.onCompleted: {
console.log("Size: " + mainWindow.width + "x" + mainWindow.height)
mainTitleBar.width = mainWindow.width
mainTitleBar.height = mainWindow.height*0.023;
}
Rectangle {
id: content
width: mainWindow.width
height: mainWindow.height - mainTitleBar.height
anchors.top: mainTitleBar.bottom
anchors.left: mainTitleBar.left
color: "#00ff00"
}
}
And
Here is the title bar code (TitleBar.js file):
import QtQuick 2.0
import QtQuick.Controls 2.0
Rectangle {
/*
* Requires setting up of
* -> width
* -> height
* -> title text
* -> icon path.
* -> Background color.
*/
id: vmWindowTitleBar
border.width: 0
x: 0
y: 0
radius: 20
signal closeApplication();
signal minimizeApplication();
// The purpose of this rectangle is to erase the bottom rounded corners
Rectangle {
width: parent.width
height: parent.height/2;
anchors.bottom: parent.bottom
anchors.left: parent.left
border.width: 0
color: parent.color
}
Text {
id: titleBarText
text: "This is The Title Bar"
anchors.verticalCenter: parent.verticalCenter
anchors.leftMargin: parent.width*0.018
}
Button {
id: minimizeButton
width: height
height: vmWindowTitleBar.height*0.8
anchors.right: closeButton.right
anchors.verticalCenter: parent.verticalCenter
anchors.rightMargin: parent.width*0.018
background: Rectangle {
id: btnMinimizeRect
color: vmWindowTitleBar.color
anchors.fill: parent
}
onPressed:{
minimizeApplication()
}
scale: pressed? 0.8:1;
contentItem: Canvas {
id: btnMinimizeCanvas
contextType: "2d"
anchors.fill: parent
onPaint: {
var ctx = btnMinimizeCanvas.getContext("2d");
var h = minimizeButton.height;
var w = minimizeButton.width;
ctx.reset();
ctx.strokeStyle = minimizeButton.pressed? "#58595b": "#757575";
ctx.lineWidth = 6;
ctx.lineCap = "round"
ctx.moveTo(0,h);
ctx.lineTo(w,h);
ctx.closePath();
ctx.stroke();
}
}
}
Button {
id: closeButton
//hoverEnabled: false
width: height
height: vmWindowTitleBar.height*0.8
anchors.right: parent.right
anchors.verticalCenter: parent.verticalCenter
anchors.rightMargin: parent.width*0.018
background: Rectangle {
id: btnCloseRect
color: vmWindowTitleBar.color
anchors.fill: parent
}
onPressed:{
closeApplication()
}
scale: pressed? 0.8:1;
Behavior on scale{
NumberAnimation {
duration: 10
}
}
contentItem: Canvas {
id: btnCloseCanvas
contextType: "2d"
anchors.fill: parent
onPaint: {
var ctx = btnCloseCanvas.getContext("2d");
var h = closeButton.height;
var w = closeButton.width;
ctx.reset();
ctx.strokeStyle = closeButton.pressed? "#58595b": "#757575";
ctx.lineWidth = 2;
ctx.lineCap = "round"
ctx.moveTo(0,0);
ctx.lineTo(w,h);
ctx.moveTo(w,0);
ctx.lineTo(0,h);
ctx.closePath();
ctx.stroke();
}
}
}
}
Now the problem comes with minimizing the application. The first thing I realize is that when using the Qt.FramelessWindowHint flag, the icon does not appear in the Windows Taskbar. Furthermore if I minimize it this happens:
And If I click on it, it doesn't restore.
So my question is, is there a way to reproduce regular minimize behavior when pressing the minimize button?
Or alternatively, is there a way I can completely customize the title bar of the application so that I can achieve the look and feel set by our UI designer?
NOTE: The current look is just a quick test. I have not set the gradient, font, or the aforementioned settings button.
As for me, playing with frameless windows and transparent background is kind of workaround. As I know, the only way to apply a custom shape to the window is QWindow::setMask. Sinse Window is derived from QWindow you can do that in this way.
For example, in the main.cpp:
QWindow *wnd = qobject_cast<QWindow *>(engine.rootObjects().at(0));
auto f = [wnd]() {
QPainterPath path;
path.addRoundedRect(QRectF(0, 0, wnd->geometry().width(), wnd->geometry().height()), 30, 30);
QRegion region(path.toFillPolygon().toPolygon());
wnd->setMask(region);
};
QObject::connect(wnd, &QWindow::widthChanged, f);
QObject::connect(wnd, &QWindow::heightChanged, f);
f();
Since you 'cut' the shape from the window itself, excluding title bar and frames you can leave the window flags as is.
Look at this way, I try to create something that you do but change completely your code.
the problem that makes change in your window size after you minimize the window is that you didn't set the initial width and height for the window so when you minimize the app it shows in the minimum width and height.
so you need to add just this in main.qml and set the initial width and height to the maximum.
width: maximumWidth
height:maximumHeight
but In the code below I change something else too.
For example, you didn't need to emit signals and then catch them in main.qml
you have access to mainWindow in TitleBar.qml.
in TitleBar.qml :
import QtQuick 2.0
import QtQuick.Controls 2.0
Rectangle {
anchors.fill: parent
height: 30
Row {
id: row
anchors.fill: parent
Label {
id: label
text: qsTr("Title ")
}
Button {
id: button
x: parent.width -80
text: qsTr("close")
onClicked:
{
mainWindow.close()
}
}
Button {
id: button1
x: parent.width -160
width: 90
text: qsTr("Minimized")
onClicked:
{
mainWindow.showMinimized()
}
}
}
}
and in main.qml :
import QtQuick 2.12
import QtQuick.Window 2.12
import QtQuick.Controls 2.0
import "."
Window {
id: mainWindow
visible: true
visibility: Window.FullScreen
title: qsTr("Hello World")
flags: Qt.FramelessWindowHint | Qt.Window | Qt.WA_TranslucentBackground
width: maximumWidth
height:maximumHeight
Rectangle {
id: content
anchors.fill: parent
x: 0
y: 20
width: mainWindow.width
height: mainWindow.height - mainTitleBar.height
anchors.top: mainTitleBar.bottom
anchors.left: mainTitleBar.left
color: "#00ff00"
}
TitleBar {
id: mainTitleBar
color: "#aaaaaa"
anchors.bottomMargin: parent.height -40
anchors.fill: parent
}
}
In my QML application I'm trying to create a grid of items that can be flipped at the press of a button. The backside of such an item should then fill a major part of the screen until it is flipped back.
Let's say I start off with the following view of my application
When I press the question mark button of the item in the center then the item is flipped and moved slightly. What I would expect to see after this is the following
The blue box is the backside of my item and it covers most of the screen. Pressing the 'X'-Button on the top right would again flip the item back.
However what I actually see after flipping the first time is the following
You can see that parts of the items in my grid are covered by my flipped item and parts are not.
The code I'm using is as follows
import QtQuick 2.9
import QtQuick.Controls 1.4
import QtQuick.Layouts 1.2
import QtQuick.Window 2.2
Window {
id: main
width: 640
height: 480
visible: true
title: qsTr("Hello World")
function absolutePos(item) {
var my_x = item.x
var my_y = item.y
if (item.parent !== null) {
var parent_pos = absolutePos(item.parent)
my_x += parent_pos.x
my_y += parent_pos.y
}
return {x: my_x, y: my_y}
}
GridLayout {
columns: 5; rows: 3
Repeater {
model: 15
delegate: Item {
width: main.width / 5 - 10
height: main.height / 3 - 10
Flipable {
id: flipable
anchors.fill: parent
property bool flipped: false
front: Rectangle {
anchors.fill: parent
border.color: "black"
border.width: 2
}
back: Rectangle {
id: backSide
width: 580; height: 400
property var absolute_pos: absolutePos(this)
border.color: "blue"
border.width: 2
Button {
anchors.top: parent.top
anchors.right: parent.right
text: "X"
width: 30; height: 30
onClicked: {
flipable.flipped = !flipable.flipped
}
}
}
transform: [
Rotation {
id: rotation
origin.x: flipable.width / 2
origin.y: flipable.height / 2
axis.x: 0; axis.y: 1; axis.z: 0
angle: 0
},
Translate {
id: translation
x: 0; y: 0
}
]
states: State {
name: "back"
PropertyChanges {
target: rotation
angle: 180
}
PropertyChanges {
target: translation
x: 490 - backSide.absolute_pos.x
}
PropertyChanges {
target: translation
y: 40 - backSide.absolute_pos.y
}
when: flipable.flipped
}
transitions: Transition {
ParallelAnimation {
NumberAnimation {
target: rotation
property: "angle"; duration: 300
}
NumberAnimation {
target: translation
property: "x"; duration: 300
}
NumberAnimation {
target: translation
property: "y"; duration: 300
}
}
}
}
Button {
anchors.top: parent.top
anchors.right: parent.right
text: "?"
width: 30; height: 30
onClicked: {
flipable.flipped = !flipable.flipped
}
}
}
}
}
}
I was already trying to achieve the effect by manually setting the parent of my Flipable to Window.contentItem so that it will always be above any other items. However this also doesn't fix the problem since the item will still cover the siblings following the current item.
Also I'm still hoping, there is a solution which doesn't require manipulating the z-order of my items in some arcane way.
I am not sure what you mean by "some arcane way", but changing the z property of your delegate is perfectly fine:
delegate: Item {
z: flipable.flipped ? 1 : 0
// ...
}
You will also probably want to hide the "?" button when flipped:
visible: !flipable.flipped
How do I properly change the x, y of an object so that it changes its position when the parent is resized? There is, I will introduce that if I drag the rectangle to the middle, then when the window is resized, it should remain in the middle. (middle for example only, rectangle can be moved freely)
import QtQuick 2.9
import QtQuick.Window 2.2
import QtQuick.Controls 2.3
Window {
visible: true
width: 640
height: 480
onWidthChanged: {
block.x -= block.previousWidth - width
block.previousWidth = width
}
onHeightChanged: {
block.y -= block.previousHeight - height
block.previousHeight = height
}
Rectangle {
id: block
color: "red"
width: 50
height:50
x: 100
y: 50
property int previousWidth: 0
property int previousHeight:0
Component.onCompleted: {
previousWidth = parent.width
previousHeight = parent.height
}
MouseArea {
anchors.fill: parent
drag.target: block
}
}
}
I must admit, at first I was not impressed by the question. However, when I thought about it, it represents a very interesting and valid use case. So I would be happy to provide a solution.
Solution
I would approach the problem like this:
Make the frame a child of the background image.
Instead of manually calculating the coordinates, use Item.scale to scale the image, effectively preserving the relative position of the frame with regard to the image.
Example
Here is an example I have prepared for you to demonstrate how the proposed solution could be implemented:
import QtQuick 2.15
import QtQuick.Window 2.15
Window {
visible: true
width: 640
height: 480
Image {
anchors.centerIn: parent
source: "alphabet.png"
scale: parent.width/sourceSize.width
Rectangle {
id: frame
width: parent.width/7
height: parent.height/4
border.color: "black"
color: "transparent"
antialiasing: true
MouseArea {
anchors.fill: parent
drag.target: parent
}
}
}
}
Result
The example produces the following result:
Original window
Resized window
The frame is moved
The window is resized again
As I said in my comment, the best solution is anchoring, for example:
Window {
id: root
width: 600
height: 400
title: qsTr("Parent window")
visible: true
flags: Qt.WindowStaysOnTopHint
Grid {
anchors.fill: parent
Repeater {
model: 16
Rectangle {
width: root.width / 4
height: root.height / 4
color: Qt.rgba(Math.random(),Math.random(),Math.random(),1)
}
}
}
Rectangle {
border {
width: 5
color: "black"
}
color: "transparent"
width: root.width / 4
height: root.height / 4
anchors.bottom: parent.bottom
anchors.left: parent.left
anchors.leftMargin: root.width / 4
anchors.bottomMargin: root.height / 4
}
}
I want to move a qml Item out of the left side of the app window.
While this task works perfectly for the right side of the window by defining a state like this
states: State {
name: "hidden"
when: is_hidden == true
AnchorChanges {
target: right_item_to_move
anchors.right: undefined
}
PropertyChanges {
target: right_item_to_move
x: main_window.width
}
}
and defining the appropriate Transition, I can't get it to work on the left side of the main window because negative x coordinates are not allowed.
I.e. this does not work:
states: State {
name: "hidden"
when: is_hidden == true
AnchorChanges {
target: left_item_to_move
anchors.left: undefined
}
PropertyChanges {
target: left_item_to_move
x: -left_item_to_move.width
}
}
How can I achieve this task? I'm using Qt 5.8 and QtQuick 2.0.
In my opinion, one should strive to stay true to one way of positioning, so you should either use anchors or x/y-coordinates.
Here you can find an overview how to make the right choice.
In short: When in doubt, use anchors. When the positioning is only relative to the parent (static) use x and y and if not possible otherwise do so even when not relative to the parent.
As you have chosen anchors, in my opinion you should stick to that - meaning: change the anchoring, so that instead of the left anchor line of the object, the right anchor line will be anchored to the window's left.
This would look like this:
import QtQuick 2.7
import QtQuick.Controls 2.0
ApplicationWindow {
id: myWindow
visible: true
width: 600
height: 600
color: 'white'
Rectangle {
anchors.centerIn: parent
width: 300
height: 600
color: 'green'
Button {
id: but
anchors {
verticalCenter: parent.verticalCenter
left: parent.left
}
onClicked: {
state = (state === 'left' ? '' : 'left')
}
states: [
State {
name: 'left'
AnchorChanges {
target: but
anchors.left: undefined
anchors.right: parent.left
}
}
]
transitions: [
Transition {
AnchorAnimation {
duration: 200
}
}
]
}
}
}
An example, how it might look, if you choose to modify the x value, it might look like this:
import QtQuick 2.7
import QtQuick.Controls 2.0
ApplicationWindow {
id: myWindow
visible: true
width: 600
height: 600
color: 'white'
Rectangle {
anchors.centerIn: parent
width: 300
height: 600
color: 'green'
Button {
id: but
property bool shown: true
anchors {
verticalCenter: parent.verticalCenter
}
onClicked: {
shown = !shown
}
x: (shown ? 0 : -width)
Behavior on x {
XAnimator {
duration: 200
}
}
}
}
}
I wonder how to make smooth transitions betwen image sources in QML, I try
import QtQuick 1.1
Image {
id: rect
source: "quit.png"
smooth: true
MouseArea {
id: mouseArea
anchors.fill: parent
anchors.margins: -10
hoverEnabled: true //this line will enable mouseArea.containsMouse
onClicked: Qt.quit()
}
states: State {
name: "mouse-over"; when: mouseArea.containsMouse
PropertyChanges { target: rect; scale: 0.8; source :"quit2.png" }
}
transitions: Transition {
NumberAnimation { properties: "scale, source"; easing.type: Easing.InOutQuad; duration: 1000 }
}
}
But It does not work on source as a transition just as final state change.. so I wonder how to make one image source fade into andothe and back?
You want the first image to fade out into the other? How about if you place two Image objects on top of each other, then animate the opacity property?
EDIT: This worked for me (I'm using QtQuick 1.0 because my Qt Creator installation is a bit outdated):
import QtQuick 1.0
Rectangle {
Image {
id: rect
source: "quit.png"
smooth: true
opacity: 1
MouseArea {
id: mouseArea
anchors.fill: parent
anchors.margins: -10
hoverEnabled: true //this line will enable mouseArea.containsMouse
onClicked: Qt.quit()
}
states: State {
name: "mouse-over"; when: mouseArea.containsMouse
PropertyChanges { target: rect; scale: 0.8; opacity: 0}
PropertyChanges { target: rect2; scale: 0.8; opacity: 1}
}
transitions: Transition {
NumberAnimation { properties: "scale, opacity"; easing.type: Easing.InOutQuad; duration: 1000 }
}
}
Image {
id: rect2
source: "quit2.png"
smooth: true
opacity: 0
anchors.fill: rect
}
}
To the question in your comment: you can place the image exactly on top of the other by copying the anchors thru anchors.fill: rect
Here is also a simple scroll transition between images:
import QtQuick 2.6
import QtQuick.Controls 1.4
import QtQuick.Window 2.2
Window {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
Rectangle {
id: imageRect
anchors.centerIn: parent
width: 240
height: 320
clip: true
property int currentIndex: 0
property var imageSources: [ "imageLeft.jpg", "imageCenter.jpg" ]
Repeater {
model: imageRect.imageSources
Image {
id: image
width: parent.width
height: parent.height
x: index * parent.width - imageRect.currentIndex * parent.width
fillMode: Image.PreserveAspectFit
source: imageRect.imageSources[index]
Behavior on x { SpringAnimation { spring: 2; damping: 0.2 } }
}
}
}
Button {
id: leftButton
anchors.bottom: parent.bottom
text: "left"
onClicked: if(imageRect.currentIndex > 0) imageRect.currentIndex--
}
Button {
id: rightButton
anchors.bottom: parent.bottom
anchors.left: leftButton.right
text: "right"
onClicked: if(imageRect.currentIndex < imageRect.imageSources.length - 1) imageRect.currentIndex++
}
Button {
id: addButton
anchors.bottom: parent.bottom
anchors.left: rightButton.right
text: "+"
onClicked: imageRect.imageSources = [ "imageLeft.jpg", "imageCenter.jpg" , "imageRight.jpg" ]
}
}